Could someone please help me find the missing X? Thank you :))) only if you know.

All the students are paid equal amount of $270. Therefore, no oneis paid more.

For student A, the amount paid for 20 hours will be:

= (67.50 / 5) × 20

= 13.50 × 20

= $270

For student B, the amount paid for 20 hours will be:

= (189/14) × 20.

= $270

For Student C, the amount paid for 20 hours will be:

p = 13.5h

where h = number of hours

p = 13.5 × 20 = $270

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Answer:

D yeyeyeye! <3

Answer:

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

(5x+37)+(3x-9)=180

8x= 152

x=19

There are 160 possibilities for area codes

We are required to find all the combinations for different area codes

It is given to us that the conditions for the tree digit area code are:

first digit could be any number from 4 through​ 8,

the second digit was either 4 5 6 or 7, and the third digit could be any number except 2 or 7

Using the conditions above, the digits which can be first digit of code = 4 through 8 =4,5,6,7,8

the digits which can be second digit of code= 4,5,6,7

the digits which can be third digit of code = 0,1,3,4,5,6,8,9

number of possibilities for first digit= 5

number of possibilities for second digit=4

number of possibilities for third digit= 8

Therefore, total number of possibilities of code   = number of possibilities of first digit x number of possibilities of second digit x number of possibilities of third digit = 5 x 4 x 8=160

Therefore, there are 160 possibilities for area codes

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False. When comparing means of two groups with equal sample sizes, we can use either a paired test or an independent samples test.

The choice between the two depends on the design of the study and the nature of the data.

A paired test is used when the data are paired or matched in some way. For example, in a pre- and post-test design, the same group of individuals is measured before and after an intervention, and the difference between the two measurements is analyzed. In this case, a paired t-test would be appropriate.

On the other hand, an independent samples test is used when the data are not paired or matched. For example, in a randomized controlled trial, individuals are randomized to receive either an intervention or a control, and the means of the two groups are compared. In this case, an independent samples t-test would be appropriate.

Therefore, the decision to use a paired test or an independent samples test depends on the research question, the design of the study, and the nature of the data.

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The arc length of the curve on the given interval is approximately 18.8496 units.

The arc length of the curve x = 3cos(t), y = 1 + 3sin(t) on the interval 0 ≤ t ≤ 2π can be found using the arc length formula.

1. First, find the derivatives of x and y with respect to t:
  dx/dt = -3sin(t) and dy/dt = 3cos(t)

2. Next, find the square of the derivatives:
  (dx/dt)² = 9sin²(t) and (dy/dt)² = 9cos²(t)

3. Sum the squares of the derivatives:
  (dx/dt)² + (dy/dt)² = 9(sin²(t) + cos²(t))

4. Since sin²(t) + cos²(t) = 1, the sum becomes 9.

5. Take the square root of the sum to find the integrand:
  √(9) = 3

6. Finally, integrate the integrand over the interval [0, 2π]:
  ∫[0, 2π] 3 dt = 3∫[0, 2π] dt = 3(t)|[0, 2π] = 3(2π) = 18.8496

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Unit vector notation is a way of representing vectors in which magnitude of vector is equal to 1. A vector is mathematical object that has both magnitude (length) and direction, and can be represented as an arrow.

In unit vector notation, a vector is represented as a combination of a scalar (a numerical value) and a unit vector (a vector with a magnitude of 1 in the same direction).

The most common notation for unit vectors is to use a hat symbol (^) to indicate that a vector is a unit vector. For example, if we have a vector v, then its corresponding unit vector in the same direction would be represented as v. The unit vector in the x-direction is typically denoted as i, and the unit vector in the y-direction is denoted as j.

Unit vector notation is useful in many applications, including physics and engineering, where it is used to describe the direction of forces, velocities, and accelerations. It is also commonly used in computer graphics and game development, where it is used to represent the direction of movement or rotation of objects in a 3D space.

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Answer:

9. The graph will shift down 2 units

10. The graph will be moved right by 4 units

11.  The graph will be vertically stretched by 2 units

Step-by-step explanation:

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Answer:'

191.49

 10.72

The answer is 180.77 I think

Step-by-step explanation:

In the equation

\(3^x = 3\cdot 2^x\)

divide both sides by \(2^x\) to get

\(\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3\)

Take the base-3/2 logarithm of both sides:

\(\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}\)

Alternatively, you can divide both sides by \(3^x\):

\(\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13\)

Then take the base-2/3 logarith of both sides to get

\(\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}\)

(Both answers are equivalent)

45 billion Korean Won is equal to 45 million US Dollars.

The formula for  (USD) is USD = KRW / 1000. To calculate 45 billion won in USD, we must first convert KRW to USD. 45 billion KRW is equal to 45,000,000,000 KRW. Using the formula above, we can calculate the amount of USD:

USD = 45,000,000,000 KRW / 1000

USD = 45,000,000 USD

Therefore, 45 billion won is equal to 45 million US Dollars.

To better understand this conversion, it is important to remember that one US Dollar is equal to 1000 Korean Won. As an example, if you have 10,000 Korean Won, you can convert that to USD by dividing 10,000 by 1000, which equals 10 USD. The same concept applies when converting larger numbers. To convert 45 billion KRW to USD, we must divide 45,000,000,000 by 1000, which equals 45,000,000 USD.

In conclusion, 45 billion Korean Won is equal to 45 million US Dollars.

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0.0945 (approx)  is the probability that exactly 12 of them are strikes.

p(x=12)

nC12(p)12 (q) (n-12)

22C12 (0.431)12 (0.569)(22-12)

=646646(0.431)12 (0.569)10

=0.094518

Probability is a branch of mathematics that quantifies the likelihood of an event occurring or the likelihood of a statement being true. The probability of an event is a number between 0 and 1, with approximately 0 indicating the improbability of the event and 1 indicating certainty.

The probability of an event can be calculated by simply dividing the number of favorable outcomes by the total number of possible outcomes using the probability formula.

probability = number of paths to success—a total number of possible outcomes. For example, the probability of flipping a coin and getting heads is ½. This is because there is one way to get heads and the total number of possible outcomes is 2 (heads or tails). We write P(heads) = ½.

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Answer:

1/2

Step-by-step explanation:

divide the numerator & denominator by 4

Answer:

7

Step-by-step explanation:

3+4 as the denoninators are the same

Answer:

\(\Longrightarrow: \boxed{\sf{\dfrac{7}{k} }}\)

Step-by-step explanation:

You have to find the numerator number by adding it to the denominator.

\(:\Longrightarrow \sf{\dfrac{3}{k}+\dfrac{4}{k}=\dfrac{?}{k} }\)

\(\Longrightarrow: \sf{\dfrac{3+4}{k}}\)

First, add the numbers from left to right.

\(\sf{\dfrac{3+4}{k}=\boxed{\sf{\dfrac{7}{k}}}\)

I hope this helps, let me know if you have any questions.

An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.

An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.

An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.

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The relationship between length and weight can be modeled by a power function.

The fact that the scatterplot of the natural logarithm of weight vs. the natural logarithm of length shows a more linear relationship suggests that the relationship between length and weight can be better modeled by a power function rather than an exponential function. This is because when the logarithms of both variables are taken, an exponential function becomes a linear function, while a power function remains a non-linear function.

In a power function, one variable is raised to a power that is not necessarily an integer, whereas in an exponential function, one variable is raised to a constant power. Therefore, it is more likely that the relationship between length and weight can be modeled by a power function.

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It seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.

To compute the flux of the vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ through the surface S given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0, oriented toward the xz-plane, we can use the surface integral.

The surface integral of a vector field F⃗ over a surface S is given by the formula:

∬S F⃗ · dS = ∬S F⃗ · (n⃗ dS)

where F⃗ is the vector field, dS is the differential area vector, and n⃗ is the unit normal vector to the surface.

In this case, the surface S is given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0. We can parameterize this surface as:

r(x, z) = xi⃗ + yj⃗ + zk⃗ = xi⃗ + (x^2+z^2)j⃗ + zk⃗

To find the normal vector n⃗ to the surface, we can take the cross product of the partial derivatives of r(x, z) with respect to x and z:

n⃗ = ∂r/∂x × ∂r/∂z

= (1i⃗ + 2xj⃗) × (0i⃗ + 2zj⃗)

= -2xz i⃗ + 2zj⃗ + 2xk⃗

Now, we can calculate the flux:

∬S F⃗ · (n⃗ dS) = ∬S (3(x+z)i⃗ + 2j⃗ + 3zk⃗) · (-2xz i⃗ + 2zj⃗ + 2xk⃗) dS

= ∬S (-6x^2z - 4xz + 6xz^2 + 6xz) dS

= ∬S (-6x^2z + 2xz + 6xz^2) dS

To evaluate this integral, we need to determine the limits of integration for x, y, and z.

Since the surface is defined by 0≤y≤16, x≥0, z≥0, we have:

0 ≤ y = x^2 + z^2 ≤ 16

Simplifying the inequality, we get:

0 ≤ x^2 + z^2 ≤ 16

From this, we can see that x and z both range from 0 to 4.

Now, we can evaluate the flux:

∬S (-6x^2z + 2xz + 6xz^2) dS = ∫∫ (-6x^2z + 2xz + 6xz^2) dA

where dA is the differential area.

Integrating over the limits 0 ≤ x ≤ 4 and 0 ≤ z ≤ 4, we can calculate the flux.

However, it seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.

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Given:

\(\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n\)

To find:

n=?

Solution:

\(\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n\\\\\to \frac{2}{5}n-\frac{7}{10}n+3n=\frac{3}{5} -3\\\\\to n(\frac{4-7+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{-3+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{27}{10})=\frac{-12}{5} \\\\\to n=\frac{-12}{5} \times \frac{10}{27} \\\\\to n=-4 \times \frac{2}{9} \\\\\to n=-\frac{8}{9} \\\\\)

Therefore, the final answer of n is "\(-\frac{8}{9} \\\\\)".

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154.3325 has two significant figures to maintain consistency with the original data.

To solve the given expression, we'll follow the order of operations (PEMDAS/BODMAS).

Multiply: 111 × 3.3447 = 370.398 (rounded to 3 significant figures).

Divide: 370.398 ÷ 2.4 = 154.3325 (rounded to 4 significant figures).

Significant figures are a way to express the precision of a measurement or calculation result. In this case, the original numbers (111, 3.3447, and 2.4) have varying significant figures.

To ensure the accuracy of the final answer, we round it to the same number of significant figures as the least precise value involved, which is 2.4 with two significant figures. Therefore, the answer, 154.3325 has two significant figures to maintain consistency with the original data.

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Answer:

These relationships are realted because the variable is multiplied by ten to get the function.

9cm: 90mm

12 1/4cm: 122.5mm

50cm: 500mm

88.49cm: 884.9mm

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Answer:

x = 1

Step-by-step explanation:

8 - 2x = -8x + 14

-2x + 8x = 14 - 8

6x = 6

x = 1

x=1 is the solution of the equation 8 - 2x = -8x + 14

Two or more expressions with an Equal sign is called as Equation.

The given equation is 8 - 2x = -8x + 14

x is the variable in the equation

Plus and minus are the operators

We have to solve for x

Take the variable terms one side and constants on other side

8x-2x=14-8

6x=6

Divide both sides by 6

x=1

Hence, x=1 is the solution of the equation 8 - 2x = -8x + 14

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Answer:

Step-by-step explanation:

8(3y + 0.5) so first we do 8 * 3 = 24y and 8 * 0.5 = 4. Then that becomes 24y = 4. so now we do 24y / 24 = y bc 24 cancels out, 4 / 24 = 0.166. So y = 0.166. HOPE THIS HELPS!!!

The radius of convergence of the Taylor series for the exponential function, e^x, centered at x = 0, is infinite.

The Taylor series expansion for the exponential function, \(e^x\), around x = 0 is given by the formula:

\(e^x = 1 + x + (x^2)/2! + (x^3)/3! + (x^4)/4! + ...\)

This series converges for all values of x because the terms in the series decrease in magnitude as the exponent increases. This means that as x approaches infinity or negative infinity, the terms in the series approach zero.

The convergence of a power series is determined by the ratio test or the root test. In the case of the exponential function, both tests yield a radius of convergence of infinity. This indicates that the series converges for all values of x. Therefore, the Taylor series expansion of e^x around x = 0 is valid for all real numbers x.

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Answer:

7.) 0.7

8.) 1

9.) 4.24

Step-by-step explanation:

Answer:

4.24

Step-by-step explanation: