To determine the value of the potential 2.5 mm from a negative plate of a pair of parallel plates separated by 8.5 mm and connected to a 24 V battery, we can use the equation for the electric field between the plates:
E = V/d, where E is the electric field, V is the voltage, and d is the distance between the plates. First, let's calculate the electric field between the plates: E = V/d = 24 V / 8.5 mm. To convert the distance to meters, we divide by 1000: E = 24 V / (8.5 mm / 1000) = 24 V / 0.0085 m = 2823.53 V/m. Now, we can determine the potential at a distance of 2.5 mm from the negative plate using the equation: V2 = E * d2, where V2 is the potential and d2 is the distance from the negative plate. Plugging in the values: V2 = 2823.53 V/m * (2.5 mm / 1000) = 2823.53 V/m * 0.0025 m = 7.0588 V. Therefore, the potential 2.5 mm from the negative plate is approximately 7.0588 V.
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A cannon is placed in a boat. The boat sinks a little to displace more water. The amount of new water displaced is.
Explanation:
the amount of displace water is equal to the weight of cannon
Lee is traveling in a train moving at a constant velocity of 35 m/s to the east. If Lee is seated on the train and staring at the seat directly in front of him, how fast does the seat in front of Lee appear to be moving relative to Lee?
Answer:
0 m/s or stationary
The seat in front of Lee appear to be at rest
Explanation:
When the motion of a person or object is found by comparing the person or objects motion with regards to a stationary object or an object in motion, the result is the relative motion of the person or object to the stationary or moving object
In the question, Lee is comparing the motion of the chair in front of him with regards to the motion of the chair he his sitting on.
The speed of both chairs are the same as the speed of the train in which they are attached.
Therefore, as the seats are fixed relative to each other such that there is no change in their relative position and therefore, no or 0 m/s relative velocity with each other.
Please help me complete. The second picture is the options you have to choose from from each
This drawing helps us understand the contribution of each the magnetic field of each wire. Wire 1 will contribute with positive field for everything on its left, and with negative field for everything on its right. The opposite is true for wire 2, so, if we analyse regions I, II and III:
Region I: Wire 1 contributes with positive and Wire 2 contributes with negative. As any point on region I will be closer to Wire 1, its contribution will be more significant, and the field will be positive
Region II: Wire 1 and 2 contribute with negative field. Thus, the resulting field will be negative
Region III: Wire 1 contributes with negative field and Wire 2 contributes with positive field. As any point on region III will be closer to Wire 2, its contribution will be more significant, and the field will be positive.
Now all we have to do is calculate the value of the fields. The field on point P1 will have positive contribution from Wire 2 and negative contribution from Wire 1, which will be:
\(P1=\frac{\mu_0*I}{2\pi d}-\frac{\mu_0*I}{2\pi(2d)}=\frac{4\pi *10^{-7}}{2\pi *11.4*10^{-2}}-\frac{4\pi *10^{-7}}{4\pi *11.4*10^{-2}}=0.8772\mu T\)The field on the midpoint (distance d/2 from each wire) will be negative, as the contribution from both wires will be negative, thus:
\(P_{med}=-2*\frac{4\pi *10^{-7}*5.4}{2\pi *(\frac{11.4}{2})*10^{-2}}=-37.8947\mu T\)The field on point P2 will be positive, which can be written as:
\(P2=\frac{\mu_0I}{2\pi *2d}-\frac{\mu_0I}{2\pi *(3d)}=\frac{4\pi *10^{-7}*5.4}{2\pi *(2*11.4*10^{-2})}-\frac{4\pi *10^{-7}*5.4}{2\pi *(3*11.4*10^{-2})}\)\(P2=1.5789\mu T\)Summary:
a) Pmed = -37.8947uT into the screen
b) P1 = 0.8772uT out of the screen
c) P2 = 1.5789uT out of the screen
for a class C800 Current Transformer with a ratio of
1000/5 connected to a secondary burden of 100 ohms, how much
primary current would it take to saturate the CT?
No number one cutting-edge is required to saturate the class C800 Current Transformer in this scenario.
To determine the number one present-day required to saturate the class C800 Current Transformer (CT), we need to take into account its saturation traits. Typically, the saturation of a CT happens while the primary contemporary reaches a positive stage that causes the magnetic middle to saturate, ensuing in distorted output waveforms.
In this situation, the CT has a ratio of 100/5, which means that for every 1000Amps of number one contemporary, there could be 5Amps of secondary modern. The secondary burden is given as a hundred ohms.
To calculate the primary current required to saturate the CT, we want to consider the burden impedance, which is contemplated to the primary facet of the CT. The meditated burden impedance is calculated with the use of the turns ratio squared:
Reflected Burden Impedance = (Turns Ratio)² * Burden Impedance
In this example, the contemplated burden impedance is:
Reflected Burden Impedance = (1000/5)² * 100 = 400,000 ohms
Now, the number one modern required to saturate the CT can be determined by applying Ohm's Law:
Primary Current = Voltage / Impedance
Since the CT is connected to a present-day supply, the voltage can be taken into consideration as negligible. Therefore, the number one present-day required to saturate the CT is:
Primary Current = 0/ 400,000 = 0 Amps
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Find the force experienced by a particle with a charge of (3x10^-8 c) when it is a distance of (2x10^-2 m) away from a second particle with a charge of (6x10^-7 c)
The physical characteristic of matter that causes it to feel a force when exposed to an electromagnetic field is called electric charge. The two types of electric charges that protons and electrons most frequently carry are positive and negative charges.
Find the force experienced by a particle with a charge of (3x10^-8 c) when it is a distance of (2x10^-2 m) away from a second particle with a charge of (6x10^-7 c)
Each fee = -Q
L is the length between charges.
decreased force =
As seen above, two particles, each with a charge of Q, are locked at a distance L apart. A net electric force F acts on every atom. The initial two particles are now locked on either side of a particle with a charge of +q.
Having said that,
The pressure at either end is
...(I)
If the charge q is positioned in the middle, then
Each end charge is under a force of
....(II)
We must determine the value of q.
Equation use (II)
Fill out the formula using the value of F.
Consequently, q is valued at q/8
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What happens when heavy exercise results in too much acid in the human body? Excess H+ is absorbed by bicarbonate ions.
Bicarbonate releases one H+ to become carbonate.
H2CO3 is formed from H2O and CO2.
Bicarbonate is formed from carbonate.
Answer:
A: Excess H+ is absorbed by bicarbonate ions.
Explanation:
Predict what would happen if control rods were not used in nuclear reactors. Include the function of
control rods in your prediction.
We have that if control rods were not used in nuclear reactors, the following might occur
The fission rate control of reactor elements will not be possiblebut we shall look into what control rods functions are
A control rod functions impacts the nuclear reactor functions such as the thermal power, steam amount produced and the generated electrical energy The manipulation of rod assemblies is a function of Control rods They are then put into what we call information tubes inside a gas of reactor elements.The function of control rodThe main function of control rods has its place in a nuclear reactor and is used in the the fission rate control of reactor elements
Operation of thermal neutrons see it interact with variant reactors(Boiling water reactors, pressurized water reactors and heavy water reactors) Breeder reactors operate with fast neutrons.The manipulation of rod assemblies is a function of Control rods They are then put into what we call information tubes inside a gas of reactor elements. A control rod functions impacts the nuclear reactor functions such as the thermal power, steam amount produced and the generated electrical energy The number of control rods inserted and the distance to which they are inserted can be varied to control activity. Typical shutdown time for modern reactors such as the European Pressurized Reactor or Advanced CANDU reactor is 2 seconds for 90% reduction, limited by decay heat.As a safety measure, control rods are to the lifting gear through ability of electromagnets, as an choice than direct mechanical discharge. This talent that in the tournament of strength failure, or if manually invoked due to failure of the lifting machinery,For more information on control rod, visit
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what are the properties of gravitational force
Explanation:
It obeys the inverse square law.
It is always attractive in nature.
It is a long range force. ...
The graviton is the field particle of gravitational force.
Answer:
Gravitational force−Properties:
(1) It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.
(2) It obey inverse square law.
(3) It is the weakest force known in nature.
The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
\(a = \frac{26.8}{1.9}\)
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
\(x = x_{0} + v_{0}t + \frac{1}{2} at^{2}\)
Starting position and initial velocity both equal 0, so
\(x = \frac{1}{2} at^{2}\)
\(x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}\)
x = 25.46m
Rounded to the nearest whole number, x = 25m
Which is a unit of volume?
A) centimeter
B) meter
C) milligram
D) milliliter
Answer:
I think milligram is the correct answer.
Answer:
D. milliliter
Explanation:
Took it on usatestprep
50mg/dL or 0.05g/dL is equal to how many drinks?
To answer your question, it's important to clarify that "50 mg/dL" or "0.05 g/dL" are measurements of blood alcohol concentration (BAC) and not directly equal to a specific number of drinks.
As a result, the number of drinks required to reach a BAC of 50 mg/dL (0.05 g/dL) can differ between individuals.
Generally, one standard drink contains about 14 grams of pure alcohol, which can be found in 12 ounces of beer, 5 ounces of wine, or 1.5 ounces of distilled spirits. However, the exact number of drinks it takes to reach a BAC of 50 mg/dL (0.05 g/dL) will depend on a person's specific characteristics and how quickly the drinks are consumed.It's crucial to remember that it's not safe or legal to drive with a BAC of 0.05 g/dL or higher in many countries, as it can impair cognitive and motor functions. Always drink responsibly and arrange for a safe way home if you choose to consume alcohol. BAC levels vary depending on factors such as weight, gender, and individual metabolism.
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A student recorded the favorite dipping sauces of the 70 people in his class. He wants to plot these data in a circle graph:
What angle should the wedge for barbecue have?
A.103
B.28.5
C.75
D.206
Explanation:
There are 70 people in a class. A student wants to plot these data in a circle.
We need to find the angle should the wedge for barbecue have.
There are 20 such students that like barbecue.
So,
\(B=\dfrac{20}{70}\times 360^{\circ}\\\\B=102.85^{\circ}\)
or
B = 103°
It means that 103° on the circle shows the number of students that like barbecue .
a uniform helicopter rotor blade is 7.80 m long, has a mass of 110 kg, and is attached to the rotor axle by a single bolt. (a) what is the magnitude of the force on the bolt from the axle when the ro- tor is turning at 320 rev/min? (hint: for this calculation the blade can be considered to be a point mass at its center of mass. why?) (b) calculate the torque that must be applied to the rotor to bring it to full speed from rest in 6.70 s. ignore air resistance. (the blade cannot be considered to be a point mass for this calculation. why not? assume the mass distribution of a
This might sound like a school assignment, but it actually demonstrates the forces acting on a rotor hub. Considering that the Cof G is halfway up the blade, or 3.9 m, the G force will operate on the blade.
What does a force mean in science?Science has a particular definition for the word "force." Using the terms "push" or "pull" to describe a force at this level is perfectly acceptable. . A force from some other thing is felt by something else. A force is a force, regardless of whether anything is alive or not.
They define force and example.A body's propensity to modify to change its structure as a reaction of an external factor is referred to as "force." The body may also change in size, shape, or direction as a result of a force being applied to it. A 448 G force is calculated to be applied to its blade. Correct: 400 for Six!
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A density of solid 13g/cm³ at a temperature of 25°c was now heated to a temperature of 150°c find the new density of the solid ? Given linear expansivity to be 2 × 10⁻⁵ ?
Answer:
13.4225 g/cm³
Explanation:
Given that:
Linear expansivity α = 2 * 10^-5
Change in temperature dt = t2 - t1 = (150 - 25)°c = 125°c
Initial density (d1) = 13
New density d2 =?
Using the relation :
α = (d2 - d1) / d1 * dt
d2 - d1 = d1 * dt * α
d2 = d1 + d1*dt*α
d2 = d1(1 + d1*dt*α)
d2 = 13( 1 + (13*125*2*10^-5))
d2 = 13(1 + 0.0325)
d2 = 13(1.0325)
d2 = 13.4225
d2 = 13.4225 g/cm³
Help please
Identify three different alloys in your home. Describe how each alloy is used and why the properties of the alloy make it suitable for that application.
Three different alloys used in home are brass, bronze and copper. Brass and bronze are used for utensils and copper is used in the electrical circuits.
What are alloys?Alloys are the homogeneous mixture of metal mixed with metal or non metal. These alloys can't be separated by physical methods.
The alloy brass and bronze are used for utensils and copper is used in the electrical circuits.
The properties of the alloys make it suitable for that application is the electrical conductivity and their melting point.
Brass and Bronze are bad conductors of electricity. On the other side, copper is used in electrical circuits.
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Trong thí nghiệm giao thoa trên mặt nước, hai nguồn kết hợp A và B cách nhau 32 cm dao động cùng
pha với tần số f = 16 Hz. Biết tốc độ truyền sóng trên mặt nước là 48 cm/s. Một đường tròn có tâm tại trung
điểm O của AB, nằm trong mặt phẳng chứa các vân giao thoa, bán kính 20 cm. Số điểm dao động cực tiểu
thuộc đường tròn là
Answer:
48cm by the minus of difference of 32 CM length 20 CM because of the length of the building
Force=k((q1q1)/r^2)
The force that one electrically charged object exerts on other charged objects can be calculated using Coulomb's law.
You can see this law here written in equation form. The q's represent the two charges, and the r the distance between
the charges. The constant kis 9109
Using this information, calculate the electric force exerted by a +2 coulomb charge on another +2 coulomb charge,
when the charges are 25 meters apart
A)1.44*10^11
B)5.76*10^11
C)8 Newton’s
D)64 Newton’s
Answer:
transferred from one object to another. Charged objects can exert forces on other charged ... Electric charge can be measured using the law for the forces between charges
The electric force exerted by the +2 C on another +2 C when at a distance of 25 m is 5.76×10⁷ N
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the force Charge 1 (q₁) = 2 CCharge 2 (q₂) = 2 CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 25 mForce (F) =?F = Kq₁q₂ / r²
F = (9×10⁹ × 2 × 2) / (25)²
F = 36×10⁹ / 625
F = 5.76×10⁷ N
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Which is not a general adaptation?
OA. Camouflage.
OB. Legs for walking.
OC. Wings for flying.
D. Streamlined shape to reduce friction.
Camouflage is not a general adaptation.
What is adaptation?Adaptation refers to the evolutionary process through which organisms develop certain traits or characteristics that allow them to survive and reproduce in their environment. These traits can be physical, behavioral, or physiological and are shaped by natural selection.
Adaptations can be both structural, such as the long neck of a giraffe, or functional, such as the ability of some plants to tolerate drought conditions. They can also be behavioral, such as the way in which some birds build their nests, or physiological, such as the ability of some animals to regulate their body temperature in extreme environments.
Camouflage is a specific adaptation. It refers to an animal's ability to change the color or pattern of its body to blend in with its environment. It does not have the same universal application as other general adaptations, such as streamlined shapes to reduce friction or legs for walking.
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An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only force on each of the two particles is the force from the uniform electric field due to the capacitor. Each particle accelerates until striking one of the plates of the capacitor. (There is no gravity in this problem and we ignore the small force between the electron and the proton.) How do the final kinetic energies and final speeds (just before striking a plate) compare
Answer:
Explanation:
Let the potential difference between the middle point and one of the plate be ΔV .
electric potential energy will be lost and it will be converted into kinetic energy .
Electrical potential energy lost = Vq , where q is charge on charge particle .
For proton
ΔV× q = 1/2 M V² ( kinetic energy of proton )
where M is mass and V be final velocity of proton .
For electron
ΔV× q = 1/2 m v² ( kinetic energy of electron )
where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .
As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same
1/2 M V² = 1/2 m v²
(V / v )² = ( m / M )
(V / v ) = √ ( m / M )
In other words , their velocities are inversely proportional to square root of their masses .
Two people push on a shopping cart from opposite sides. In which situation
will the motion of the shopping cart stay the same?
A. The two people push with different amounts of force.
B. One of the people stops applying a force.
C. One of the people applies twice as much force.
D. The two people push with a balanced
face
Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.
In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.
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write down one use of diffuse reflection
Answer:
The ability of humans to see clothing's and other objects depends on diffuse reflection.
Explanation:
Hoped that helped
A stunt bicycle rider goes 39m in 3.0s. How fast is the cyclist riding?
Answer:
Speed of stunt bike rider = 13 meter/ Second
Explanation:
Given:
Distance cover by stunt bike rider = 39 meter
Time taken by stunt bike rider = 3 seconds
Find:
Speed of stunt bike rider
Computation:
Speed = Distance / Time
Speed of stunt bike rider = Distance cover by stunt bike rider / Time taken by stunt bike rider
Speed of stunt bike rider = 39 / 3
Speed of stunt bike rider = 13 meter/ Second
members of the phylum_______ are adapted to live in harsh environments
The wavelength of a ray of blue light is 475 nm. If its frequency is x×10^14Hz
what is the value of x?
The value of the variable in the frequency will be 3.316.
What is the wavelength and frequency of light?
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), millimeters (mm), or nanometers (nm).
The formula of the frequency is given as,
f = c / λ
Where 'f' is the frequency, c is the speed of light, and 'λ' is the wavelength.
The wavelength of a ray of blue light is 475 nm. If its frequency is x · 10¹⁴ Hz. Then the value of the variable 'x' is given as,
x · 10¹⁴ = (3 · 10⁸) / (475 · 10⁻⁹)
Simplify the equation, then we have
x · 10¹⁴ = (3 · 10⁸) / (475 · 10⁻⁹)
x = (3 · 10⁸) / (475 · 10⁻⁹ · 10¹⁴)
x = (3 · 10⁸) / (475 · 10⁵)
x = 6.316
The value of 'x' is 6.316.
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the table lists the heights and weights of six wide receivers who played for the atlanta falcons during the 2010 football season. a. make a scatter plot for the data. be sure to label your axes.
Unfortunately, as an AI text-based model, I am unable to directly create visual content like scatter plots. However, I can guide you on how to create a scatter plot based on the given data.
To make a scatter plot for the heights and weights of the wide receivers, follow these steps:
1. Prepare your data: Organize the heights and weights of the six wide receivers in a table, with one column for heights and another for weights.
2. Choose a scale: Determine the appropriate scale for each axis based on the range of values in the data. Ensure that the plot will adequately represent the variations in both height and weight.
3. Assign axes: Label the vertical axis (y-axis) for the heights and the horizontal axis (x-axis) for the weights. Include the units of measurement (e.g., inches for height and pounds for weight).
4. Plot the data points: For each wide receiver, locate the corresponding height and weight values on the axes and mark a point. Repeat this for all six wide receivers.
5. Add labels and title: Label each data point with the respective player's identifier (name, jersey number, or any other identifier you prefer). Additionally, provide a title for the scatter plot, such as "Height and Weight of Atlanta Falcons Wide Receivers (2010 Season)."
Remember to maintain clear and readable labels, and use appropriate symbols or markers for the data points.
By following these steps, you can create a scatter plot representing the heights and weights of the Atlanta Falcons wide receivers during the 2010 football season.
Learn more about creating scatter plots and data visualization techniques using graphing software or tools available online for your specific needs.
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how can you grow taller in a small amount of time?
Answer:
.
Explanation:
Answer:
do sports eg skipping rope, playing basketball, badminton etc. in other words, activities that involve jumping
Find the phase and the missing properties of p, t, v, u, and x for water at1. 500 kpa, 100°c2. 5000 kpa, h = 1800 kj/kg3. 5000 kpa, u = 2950 kj/kg4. −6°c, v = 1 m3/kg.
1) The missing properties are \(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\) and \(h = 640.59\,\frac{kJ}{kg}\). (Subcooled liquid)
2) The missing properties are \(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\) and \(x = 0.394\). (Liquid-gas mix)
3) The missing properties are \(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\) and \(u = 3251.7\,\frac{kJ}{kg}\). (Superheated steam)
4) The missing properties are \(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\) and \(x = 2.988\times 10^{-3}\). (Solid-gas mix)
How to determine the phase of water based on information from steam tablesIn this question we must determine the phase associated to the given pressure (\(p\)), in kilopascals, temperature (\(T\)), in degrees Celsius, specific volume (\(\nu\)), in cubic meters per kilogram, internal energy (\(u\)), in kilojoules per kilogram, enthalpy (\(h\)), in kilojoules per kilogram, or quality (\(x\)), no unit.
1) Pressure - 500 kPa, Temperature - 100 °CBy steam tables we know that saturation temperature associated with pressure is 151.83 °C, which means that water is a subcooled liquid and quality does not apply herein.
The missing properties are summarized below:
\(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\), \(h = 640.59\,\frac{kJ}{kg}\)
The missing properties are \(\nu = 0.001093\,\frac{m^{3}}{kg}\), \(u = 639.54\,\frac{kJ}{kg}\) and \(h = 640.59\,\frac{kJ}{kg}\). (Subcooled liquid) \(\blacksquare\)
2) Pressure - 5000 kPa, Specific enthalpy - 1800 kJ/kgBy steam tables we know that water is a mix of gaseous and liquid phases. Hence, the missing properties are summarized below:
\(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\), \(x = 0.394\)
The missing properties are \(T = 263.94\,^{\circ}C\), \(\nu = 0.0163\,\frac{m^{3}}{kg}\), \(u = 1719\,\frac{kJ}{kg}\) and \(x = 0.394\). (Liquid-gas mix) \(\blacksquare\)
3) Pressure - 5000 kPa, Internal energy - 2950 kJ/kgBy steam tables we know that water is a superheated steam. Hence, missing properties are summarized below:
\(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\), \(u = 3251.7\,\frac{kJ}{kg}\)
The missing properties are \(T = 422.825\,^{\circ}C\), \(\nu =0.0603\,\frac{m^{3}}{kg}\) and \(u = 3251.7\,\frac{kJ}{kg}\). (Superheated steam) \(\blacksquare\)
4) Temperature - -6°C, Specific volume: 1 m3/kgBy ice tables we know that properties correspond to a mix of solid and gaseous phases. Thus, missing properties are summarized below:
\(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\), \(x = 2.988\times 10^{-3}\)
The missing properties are \(P = 0.36873\,kPa\), \(u = -337.836\,\frac{kJ}{kg}\), \(h = -337.458\,\frac{kJ}{kg}\) and \(x = 2.988\times 10^{-3}\). (Solid-gas mix) \(\blacksquare\)
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if it takes a ball dropped from rest 2.714 s to fall to the ground, from what height h was it released?
The required height from which the ball is released is calculated to be 36.09 m.
The ball is said to be at rest u = 0 m/s.
Time taken to fall to the ground, t = 2.714 s.
Let H is the height from which ball is released. It is given using the formula,
H = u t + 1/2 a t²
where,
u is initial velocity
t is time
a is acceleration
Here, a = g
So, H = 1/2 a t² = 1/2(9.8)(2.714)² = 36.09 m.
Thus, required height from which the ball is released is calculated to be 36.09 m.
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Volume of 10 coin is 25ml what is the volume of 1 coin
Answer: 2.5 ML
Explanation:
10 ÷ 10 = 1
25 ÷ 10 = 2.5
The volume of 1 coin is 2.5 ML
pls help i’ll give brainliest if you give a correct answer!!
Answer:
South ....................
Answer:
South ;)
Explanation:
I just did it .