Drosophila yakuba and D. santomea are most closely related to each other. Therefore, they are considered _______ species. a. rooted b. sister c. homologous d. daughter e. paraphyletic

The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core

Nuclear fusion of hydrogen to form helium happens evidently in the solar and different stars. It takes area best at extremely high temperatures. Scientists are attempting to find methods to create controlled nuclear fusion reactions on earth.

Researchers at Lawrence Livermore countrywide Laboratory's country-wide Ignition Facility in California have spent over a decade perfecting their method and the feature now showed that the landmark test conducted on eight August 2021 did, in fact, produce the primary-ever successful ignition of a nuclear fusion reaction.

People had been capable of cause fusion, but in methods that might be uncontrolled, like in thermonuclear guns sometimes called hydrogen bombs. Fusion has additionally been proven in laboratories, but below conditions that eat a long way, extra strength than the reaction produces.

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The distance between crests of the sound wave is 0.114 meters, or 11.4 centimeters.

The distance between crests of a sound wave, or any wave, is called the wavelength (represented by the symbol λ). The wavelength can be calculated using the formula λ = v/f, where v is the speed of the wave and f is its frequency.

The speed of sound waves depends on the medium through which they are traveling. In air at room temperature and atmospheric pressure, the speed of sound is approximately 343 meters per second (m/s). Therefore, the wavelength of a sound wave with a frequency of 3000 Hz can be calculated as follows:

λ = v/f = 343 m/s / 3000 Hz = 0.114 m

So, the distance between crests of the sound wave is 0.114 meters, or 11.4 centimeters.

It is worth noting that sound waves are longitudinal waves, which means that the oscillations are parallel to the direction of wave propagation. This is in contrast to transverse waves, such as electromagnetic waves, in which the oscillations are perpendicular to the direction of wave propagation. In a longitudinal wave, the distance between successive compressions or rarefactions is equal to one wavelength.

In summary, the wavelength of a sound wave with a frequency of 3000 Hz is 0.114 meters, or 11.4 centimeters, assuming that the wave is traveling through air at room temperature and atmospheric pressure.

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When an electric current flows through a long straight wire from right to left and the wire is viewed end-on from the left end, the magnetic field goes in a counterclockwise direction. A magnetic field surrounds a conductor that carries an electric current.

Magnetic fields have both a direction and a magnitude, and they are always perpendicular to the direction of current flow in the conductor.

The magnetic field's orientation relative to the wire depends on the direction of current flow within the wire, according to the right-hand rule. The right-hand rule is a technique used to determine the direction of the magnetic field induced by a current-carrying conductor.

When an electric current flows through a long straight wire from right to left and the wire is viewed end-on from the left end, the magnetic field goes in a counterclockwise direction.

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Answer:

Linear

Explanation:

The slope is constant.

Answer:

A. Linear

Explanation:

hope I help you

Answer:

\(a=\dfrac{v-u}{t}\)

Explanation:

The acceleration of an object is the rate of change of velocity. The mathematical expression for the acceleration of an object is given by :

\(a=\dfrac{v-u}{t}\)

Where

v and u are final and initial velocities

t is time

or we can write acceleration as :

\(a=\dfrac{\Delta v}{\Delta t}\)

Hence, this is the required solution.

Answer:

I know that F=Gm1m2/r^2 or F=GMn/r^2 and G is like the universal gravitational constant so I hope this helps

Answer:

During a total lunar eclipse, the moon and sun are on the exact opposite sides of the Earth, leaving the moon entirely in the Earth's shadow. During a partial lunar eclipse, only part of the moon is in the Earth's shadow.

Explanation:

Answer:

the initial potential energy should be 20 kJ.

Explanation:

Based on law of conservation of energy, the kinetic energy delivered by the pile driver when it strikes the piles, should be equal to the initial potential energy.

Since the final kinetic delivered is given as 20 kJ, then the initial potential energy should be 20 kJ.

Therefore, the initial potential energy should be 20 kJ.

Answer: lots of them

Explanation:

The present value of the following single amounts are as follows;

PV for FV = $20,000, I =7%, N =10 years is $10,155.84

PV for FV = $14,000, I =8%, N =12 years is $4,489.92

PV for FV = $25,000, I =12%, N =20 years is $2,590.11

PV for FV = $40,000, I =10%, N =8 years is $18,520.89.

Future value (FV) =$20,000,

Interest rate (I) =7%,Time (n) = 10 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 20000 / (1 + 0.07)10PV = 20000 / 1.96715PV = $10,155.84

Future value (FV) =$14,000,

Interest rate (I) =8%,

Time (n) = 12 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 14000 / (1 + 0.08)12PV = 14000 / 3.12159PV = $4,489.92

Future value (FV) =$25,000,

Interest rate (I) =12%,Time (n) = 20 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 25000 / (1 + 0.12)20PV = 25000 / 9.64632PV = $2,590.11

Future value (FV) =$40,000,Interest rate (I) =10%,Time (n) = 8 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 40000 / (1 + 0.1)8PV = 40000 / 2.15893PV = $18,520.89

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Answer:

A

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

A 710 kg k g car drives at a constant speed of 23 m/s and is subject to a drag force of 500 N. The required power to drive the car on the ground is 11.5 kW

Power is defined as the amount of work done per unit time.

P = W/Δt

Where:

W = work done

Δt = time period

Since W = F . s  

Hence,

P = F . s/Δt = F . v

Where:

F = force acted on the object

s = distance

v = velocity

Parameters given in the problem:

F = 500 N

v = 23 m/s

Hence, the required power is:

P = (500) (23 ) = 11,500 Watt = 11.5 kW

Your question is incomplete, but most probably your question was:

A 710kg car drives at a constant speed of 23m/s . It is subject to a drag force of 500 N. What power is required from the car's engine to drive the car on level ground?

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answers

81.6 pounds rounded or just 81.571 if it needs to be exact

Answer:

B

Explanation:

Amplitude, in simple terms, is height of the peak. This is done by measuring the peak point to the middle line.

That is B.

The equation of the force between the two masses separated by distance r, is determined as Gmm/r².

The equation of the force between the two masses is determined from Newton's law of universal gravitation as shown below.

f = Gmm/r²

where;

Thus, the equation of the force between the two masses separated by distance r, is determined as Gmm/r².

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Answer:

-0.056 is the deceleration

If the direction of the applied force is reversed on a block sliding on a horizontal surface, the force of kinetic friction between the block and the surface will also be reversed.

The force of kinetic friction will now act in the opposite direction of the applied force, and its magnitude will remain the same (0.5 N). As a result, the net force acting on the block will be the difference between the applied force and the force of kinetic friction, which will determine the block's acceleration. The block will slow down and eventually stop moving, as the force of kinetic friction will be greater than the applied force in this case.

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Your question is incomplete, but most probably, the complete question is:

A horizontal force acts on a block sliding on a horizontal surface. The force of kinetic friction between the block and the surface is 0.5F. If the direction of the applied force is reversed, which is true?

The magnitude of the net force on the block increases.

The magnitude of the acceleration of the block remains the same.

The kinetic energy of the block increases.

The velocity of the block remains the same.

The first sign of carburetor ice would probably be a decrease in rpm if an aircraft had a fixed-pitch propeller and a float-type carburetor.

The temperature decrease in the carburetor as a result of gasoline evaporation and the temperature loss related to the pressure drop in the venturi is what lead to carburetor ice.

The temperature decrease in the carburetor is what leads to carburetor icing. The throttle valve will get frozen with water vapor if the temperature falls below freezing.

While initially increasing the Venturi effect, this ultimately inhibits airflow. When the outside air temperature is below 70 degrees F, carb icing most frequently happens (21 degrees C).

Engine sluggishness, loss of RPM, and loss of manifold pressure are signs of carb ice. In general, if you suspect carb ice, immediately administer carb heat or alternative air.

Hence, the first sign of carburetor ice would probably be a decrease in rpm.

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a. 4.80 C is the charge on each plate of a 3.00-F capacitor linked to a 16.0-V battery.

b. The charge stored is 0.75 C if the identical capacitor is linked to a 2.50-V battery.

Capacitors store electrical energy on their plates by building an electric charge. The quantity of charge held on each plate is determined by the capacitance and voltage of the battery to which it is attached.

(a) To calculate the charge on each capacitor plate, use the formula Q = CV, where C is the capacitance (3.00 F) and V is the voltage (16.0 V).

Q = CV = (3.00 x \(10^{-6}\))(16.0) = 48 x \(10^{-6}\) C = 48 µC

(b) If the same capacitor is connected to a 2.50-V battery, the charge stored can be calculated using the same formula:

Q = CV = (3.00 x \(10^{-6}\))(2.50) = 7.5 x \(10^{-6}\) C = 7.5 µC

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The length of the rubber band that the boy must use is 0.024 m or 24 mm.

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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The Hertzsprung-Russell (HR) diagram is a plot of luminosity versus temperature. HR diagrams are used to determine the age, distance, and relative size of stars. A typical HR diagram shows main sequence stars on the left side of the diagram, giant stars in the middle, and supergiant stars on the right side.

The location of stars on the HR diagram reveals a lot about the conditions of the star. For example, main sequence stars are stars that have reached a state of equilibrium between their inward pull of gravity and their outward radiation pressure. They are characterized by a stable core temperature and a stable rate of energy generation.

On the other hand, giant stars are stars that have exhausted the fuel in their core, causing the core to contract and heat up, while the outer layers expand and cool. This causes the star to move to the right on the HR diagram.

Supergiant stars are even larger than giant stars and have even cooler and more luminous outer layers. They are found on the upper right-hand corner of the HR diagram.

White dwarfs are stars that have exhausted all of their nuclear fuel and have contracted to a very small size. They are located on the lower left-hand side of the HR diagram.

Overall, the location of a star on the HR diagram provides a lot of information about the conditions of the star, including its size, temperature, and luminosity.

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Answer: Polish creates a thin layer of wax on the surface of the leather which protects the leather from getting wet and undergoing wear and tear. It also has a lubricating effect on the leather keeping it supple and preventing the leather from drying out and cracking

Answer:

the time comes eventually.

Explanation:

ur body just be giving up

Answer:

28.8kg

Explanation:

h1=8m

h2=2m

h2-h1=6m

k=48 N/m

g=10m/(s^2)

w=F

10m=6*48

m=28.8kg

The weight of a peanut butter will be same as it is on earth, which means weight will be 12 N.

Weight is nothing but a force of gravity applied on the object.

The amount of force is = mg = W .

where, m = mass of the object and g is the acceleration due to gravity.

In this expression of weight, g depends on mass and radius of planet.

So, g' is the acceleration on another planet

g' = \(\frac{G M}{R^{2} }\)

putting the values, we get

g' = \(\frac{G 4Me}{(2Re)^{2} }\)   =  \(\frac{G 4Me}{4Re^{2} }\)  =  \(\frac{G Me}{Re^{2} }\)  = g (acceleration due to gravity)

Here we see that g' on another planet is same as g which is the acceleration due to gravity.

So weight will be as "mg" , same as on earth.

Hence the weight of a jar of peanut buffer will be 12 n.

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Answer:

This plasma mostly consists of electrons

Answer:

i don't know this answer

Answer:

Finley, Xander and Max

Explanation:

v = Final velocity

t = Time

u = Initial velocity = 0

a = Acceleration

From kinematic equations we get

\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}=\dfrac{v-0}{t}\\\Rightarrow a=\dfrac{v}{t}\)

Xander

v = 4.5 m/s, t = 3.5 s

\(a=\dfrac{4.5}{3.5}\\\Rightarrow a=1.29\ \text{m/s}^2\)

Finley

v = 3.6 m/s, t = 4.2 s

\(a=\dfrac{3.6}{4.2}\\\Rightarrow a=0.86\ \text{m/s}^2\)

Max

v = 7.3 m/s, t = 1.2 s

\(a=\dfrac{7.3}{1.2}\\\Rightarrow a=6.083\ \text{m/s}^2\)

The required list is Finley, Xander and Max.

Answer:

Finley, Xander and Max

Explanation:

Given,

The temperature in Fahrenheit, F=57.39 °F

The temperature can be converted from degree Fahrenheit to degree celcius using the formula,

On substituting the known values,

Thus 57.39 °F in degree celcius is 14.11 °C

Most deserts are associated with the subtropical high.

A subtropical high is a semi-permanent high-pressure system located near the Tropics of Cancer and Capricorn. This high-pressure system creates stable atmospheric conditions that inhibit the formation of clouds and precipitation. As a result, regions located under the subtropical high, known as subtropical deserts, tend to be dry and arid.

Deserts cover about one-third of the Earth's land surface, and many of them are located in subtropical regions such as the Sahara, the Arabian Desert, and the Mojave Desert. Other deserts, such as those found in polar regions, are associated with different atmospheric systems.

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Most deserts are associated with the subtropical high.

These are areas of high atmospheric pressure located around the 30th parallel north and south of the equator, where the trade winds converge and create stable, dry conditions.

The descending air masses from the subtropical high-pressure zones prevent the formation of clouds and cause the hot, dry climate associated with deserts.

However, there are also other factors that contribute to the formation of deserts, such as the rain shadow effect, which occurs when moist air is forced to rise over a mountain range and then cools and releases its moisture on the windward side, leaving the leeward side dry.

Polar deserts are also formed due to the cold temperatures and low humidity of the polar regions.

Overall, while there are different factors that can lead to the formation of deserts, the subtropical high-pressure zones are the most commonly associated with desert regions due to the stable, dry conditions created by the descending air masses.

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