The capacitance of the antenna is 1.38 × 10⁻¹⁰ farads.
Here we have a tapering (old fashioned) car antenna made of steel (e = 2 × 10¹¹ [nm²]), measuring x as the distance from the attachment point on the car:
Radius = 10 mm at x = 0 mm
Radius = 5 mm at x = 100 mm
We can calculate the capacitance of the antenna using the following formula:
C = 2 × pi × e × ln (r₁ / r₂)
Where:
C is the capacitance in farads
e is the permittivity of the material in farads per meter
ln is the natural logarithm
r1 is the radius of the antenna at x = 0 mm in meters
r2 is the radius of the antenna at x = 100 mm in meters
Plugging in the values:
C = 2 × pi × 2 × 10¹¹ × ln (10 / 5)
C = 1.38 × 10⁻¹⁰ farads
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Which terms does velocity describe?
A. speed and momentum
B. gravity and direction
C. speed and direction
Answer:
c
Explanation:
El tren Lima la Orolla va a una velocidad de 10 km/h y de pronto aplica el freno por un derrumbe en la via. Si demora 18 segundos en detenerse ¿Qué distancia recorrerá hasta detenerse completamente?
Answer:
Distancia = 50.04 metros
Explanation:
Dados los siguientes datos;
Velocidad = 10 km/h
Tiempo = 18 segundos
Para encontrar la distancia;
Conversión:
10 km/h = 10 * 1000/3600 = 2.78 m/s
Distancia = velocidad * tiempo
Distancia = 2.78 * 18
Distancia = 50.04 metros
Por lo tanto, el tren viajaría 50.04 metros antes de detenerse por completo.
Answer:
yes
Explanation:
yes
A 3kW kettle boils water in 4 minutes. Does this use more electrical energy than a 150W fridge left on 1 hour?
Answer:
The kettle used more electrical energy
Explanation:
We need to find the appliance that used more electrical energy.
To solve this problem, we need to find the amount of electrical energy used by both appliances.
For the kettle;
Power consumed = 3kW
Time = 4minutes
Electrical energy = Power x time
Convert 4min to hr;
60min = 1hr
4min = \(\frac{4}{60}\) = \(\frac{1}{15}\)hr
Electrical energy = 3 x \(\frac{1}{15}\) = 0.2kwh
For the fridge;
Power consumed = 150W = 0.15kW
Time = 1hr
Electrical energy = 0.15kW x 1hr = 0.15kWh
A rightward force is applied to a 8.35 kg object
to accelerate it to the right at 10.6 m/s/s. The
coefficient of friction for the object and the
surface is 0.375. Determine the force of gravity.
the normal force, the force of friction, the
applied force, and the net force,
Force of gravity = mg = 8.35 * 9.8 = 81.83 N
normal force (N) = 81.83 N
force of friction = 30.69 N
Applied force = 119.2 N
net force = 88.51 N
given
mass = 8.35 kg
acceleration = 10.6 \(m/s^{2}\)
coefficient of friction (mu) = 0.375
force of gravity = mg = 8.35 * 9.8 = 81.83 N
normal force (N) = 81.83 N ( as mg = N )
force of friction = mu * normal = 0.375 * 81.83 = 30.69 N
F net = 0
applied force - force of friction = mass * acceleration
F - fr = ma
F = ma + fr
= 8.35 * 10.6 + 30.69
= 119.2 N
net force = F - fr = ma = 8.35 * 10.6
= 88.51 N
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we can only do ideal calculations when we are at standard temperature and pressure. (True or False)
It is true that we can only perform ideal calculations under normal pressure and temperature.
What is the usual temperature and pressure?The nominal air temperature at sea level are referred to as STP, or normal temperature and pressure. The conditions are 0 °C and 1 atmosphere of pressure, respectively.
Why do scientists utilize normal pressure and temperature?It is now simpler to compare various measures for gasses, such as the number of molecules of gas in a certain volume. For scientists to be able to compare different sets of data in a meaningful way, a global standard for temperature and pressure must be established.
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The strength of an electromagnet's magnetic field can be increased by which of the following? Multiple answers are correct. Select all that apply.
A. Increasing the amount of current flowing through the wire
B. Increasing the number of coils packed close together
C. The addition of a quartz core
D. Increasing the thickness of the coils
The strength of an electromagnet's magnetic field can be increased by the following below:
A. Increasing the amount of current flowing through the wire
B. Increasing the number of coils packed close together
D. Increasing the thickness of the coils.
What is a Magnetic field?This is referred to as a region around a magnetic material or a moving electric charge within which the force of magnetism acts.
Increasing the number of coils packed close together or the thickness will increase the strength of an electromagnet's magnetic field because each coil has its own magnetic field, so the more coils will increase it thereby making it the correct choices.
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How are waves reflected and refracted at boundaries between mediums?
The kinetic theory describes the __1__ of particles in matter and the forces of attraction between them. The theory assumes that the volume occupied by a gas is mostly __2__, that the particles of gas are relatively __3__, move __4__ of each other, and are in constant __5__ motion. The __6__ between particles are perfectly elastic so that the total __7__ remains constant. Gas pressure results from the simultaneous collisions of billions of particles with an object. Barometers are used to measure __8__ pressure. Standard conditions are defined as a temperature of __9__ and a pressure of __10__.
Answer:
1. Motion
2. Empty space
3. Far apart
4. Independently
5. Random or rapid
6. Collision
7. Kinetic energy
8. Atmospheric
9. 273 Kelvin or 0° Celsius
10. 1 atm, 101.3 kPa or 760 mmHg
Explanation:
In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.
Generally, matter exists in three (3) distinct or classical phases and these are;
I. Gas.
II. Solid.
III. Liquid.
Filling the missing words or texts in the question, we have;
The kinetic theory describes the motion of particles in matter and the forces of attraction between them. The theory assumes that the volume occupied by a gas is mostly empty space, that the particles of gas are relatively far apart, move independently of each other, and are in constant random or rapid motion. The collision between particles are perfectly elastic so that the total kinetic energy remains constant. Gas pressure results from the simultaneous collisions of billions of particles with an object. Barometers are used to measure atmospheric pressure. Standard conditions are defined as a temperature of 273 Kelvin or 0° Celsius and a pressure of 1 atm, 101.3 kPa or 760 mmHg.
Match the following vocabulary terms with their correct definition.
Respiratory System 1. Made up of your heart.
Cardiorespiratory Endurance 2. Used to describe good cardiorespiratory function.
Maximal Oxygen Uptake 3. Bad Cholesterol
LDL 4. The ability to exercise your entire body for a long period of time without stopping.
Cardiovascular System 5. Carries blood filled with waste products from the muscle cells back to the heart.
Cholesterol 6. Made up of your lungs.
Artery 7. Carries blood from your heart to another part of your body
Vein 8. Good Cholesterol
Aerobic Capacity 9. The best assessment to measure the fitness of the cardiovascular and respiratory systems.
HDL 10. A waxy, fat like substance found in meat, dairy, and egg yolks.
The correct matching of the terms is as follows:
Cardiovascular SystemMaximal Oxygen Uptake LDLCardiorespiratory EnduranceVein Respiratory SystemArteryHDLAerobic CapacityCholesterolWhat is the correct matching of the given terms?The correct matching to the given terms depends on the definition of the terms.
The correct matching of the terms is as follows:
Cardiovascular System - Made up of your heart.Maximal Oxygen Uptake - Used to describe good cardiorespiratory function.LDL - Bad CholesterolCardiorespiratory Endurance - The ability to exercise your entire body for a long period of time without stopping.Vein - Carries blood filled with waste products from the muscle cells back to the heart.Respiratory System - Made up of your lungs.Artery - Carries blood from your heart to another part of your bodyHDL - Good CholesterolAerobic Capacity - The best assessment to measure the fitness of the cardiovascular and respiratory systems.Cholesterol - A waxy, fat like substance found in meat, dairy, and egg yolks.In conclusion, respiratory function is measured by means of aerobic capacity.
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Find the force necessary to pull a 6 kg object 3 m/s2
Answer:
18 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 6 × 3
We have the final answer as
18 NHope this helps you
34. Two students each carry a box up to the third floor of a building. The total mass of
each student and the box she is carrying is the same. Kyli makes the trip in 45 s
while Jaci takes 30 s. Which of the girls is doing the most work? Prove it by showing
how much work each of the girls do.
The work done by both students will be equal. Jaci has greater power than Kyli.
What is the work?Work can be explained as the energy needed when a force is exerted to move an object through a particular displacement. The work done depends upon the displacement and applied force of the object.
W= F × d
Where 'F' represents the exerted force and 'd' represents the displacement.
The power can be described as the rate of doing work and is the work done in unit time. The mathematical formula for power can be represented as mentioned below.
Power = Work/time = W/t
As the mass of the box is equal and both cover the same distance so the work done by both students will be equal. The time taken by both students is different. Therefore, the power will be different.
More the time is taken, the lesser the power. Therefore, Jaci has greater power than Kyli.
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The total momentum of a ______ remains constant through time,
regardless of changes within the system.
open system
closed system
generic system
all of the above
none of the above
#1)
A 500 Hz triangular wave with a peak amplitude of 50 V is applied to
the vertical deflecting plates of a CRO. A 1 kHz saw tooth wave with a
peak amplitude of 100 V is applied to the horizontal deflecting plates.
The CRO has a vertical deflection sensitivity of 0. 1 cm/V and a
horizontal deflection sensitivity of 0. 02 cm/V. Assuming that the two
inputs are synchronized, determine the waveform displayed on the
screen?
[2 Marks]
The CRO (Cathode Ray Oscilloscope) will display a triangular wave that is vertically stretched and horizontally compressed.
The vertical deflection plates will cause the triangular wave to be displayed with a peak-to-peak amplitude of\(100 cm (50 V * 0.1 cm/V)\), while the horizontal deflection plates will cause sawtooth wave to be displayed with a peak-to-peak amplitude of \(5000 cm (100 V * 0.02 cm/V).\) The synchronization of the two inputs will ensure that the triangular wave and the sawtooth wave are displayed in a coordinated manner, with each cycle of the sawtooth wave corresponding to five cycles of the triangular wave. The resulting display will show a pattern of diagonal lines that gradually rise and then quickly drop back to the starting position, with each line representing a cycle of the sawtooth wave.
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Is a fine for speeding based of the average speed or the instantaneous speed? Explain
Answer: Therefore, the instantaneous speed is only the answer, because, the detector can only detect the instantaneous speed but not the average speed.
Explanation:
How do you find average velocity during free fall?
In a 92 s interval, 562 hailstones strike a glasswindow of area 1.216 m² at an angle 64° to thewindow surface. Each hailstone has a mass of2 g and speed of 5.8 m/s.If the collisions are elastic, find the averageforce on the window.Answer in units of N.
Given that the number of hailstones is n = 562
The mass of hailstone is m = 2 g = 0.002 kg
The speed of hailstone is v = 5.8 m/s
The time taken will be t = 92 s
The angle is
\(\theta=64^{\circ}\)We have to calculate the force.
The force can be calculated by the formula
\(\begin{gathered} F=\text{ force due to one hailstone }\times numberofhailstones\text{ } \\ =m\frac{v}{t}\sin \theta\times n \end{gathered}\)Substituting the values, the force will be
\(\begin{gathered} F=\text{ }\frac{\text{0.002}\times5.8\times\sin 64^{\circ}\times562}{92} \\ =0.063\text{ N} \end{gathered}\)You are supplied with a metre rule, a 100 g weight, a knife edge, thread and an object of mass between 50 g and 200 g. Describe an experiment you would carry out, using the apparatus as supplied to find the mass of the object.
The description of the experiment needed for this is to make use of a string, suspend the weight, and then find the distance between the support and the center of mass of the knife-edge weight system
The Test I would carry outTo determine the weight of the item utilizing the provided equipment, my proposed method involves executing a straightforward test in a subsequent manner:
Fix one end of the string to the item and fasten the other end to the blade's tip.
Horizontally position the knife edge onto a support to achieve balance.
Suspend the 100 g weight from the blade's tip using the string.
Using a meter rule, determine the distance between the support and the center of mass of the knife-edge weight system.
Remove the burden and substitute it with the item.
Rearrange the location of the item on the string until equilibrium is restored to the knife-edge weight mechanism.
Calculate the fresh extension between the support and the system's center of mass.
By applying the principle of moments, determine the weight of the object with respect to the known weight and the proportion of distances.
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A golfer imparts a speed of 29.0 m/s to a ball, and it travels the maximum possible distance before landing on the green. the tee and the green are at the same elevation. (a) how much time does the ball spend in the air? (b) what is the longest hole in one that the golfer can make, if the ball does not roll when it hits the green?
Explanation:
It is given that,
Initial speed of a golfer, u = 29 m/s
If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.
(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.
\(s=ut+\dfrac{1}{2}at^2\)
Here,
a = -g
s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).
So,
\(0=29\sin(45)t-\dfrac{1}{2}\times 9.8t^2\ (\text{Initial vertical component of velocity is taken})\\\\-4.9t^2+29\times \dfrac{1}{\sqrt2}t=0\\\\-4.9t^2+20.5t=0\\\\t=0,4.184\ s\)
So, it will take 4.184 seconds in the air.
(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :
\(x=vt\cos\theta\\\\x=29\times 4.184\times \cos(45)\\\\x=85.79\ m\)
Hence, this is the required solution.
A hungry bat finds the mother lode of flying insects between the headlights of two bicycles cruising towards each other through the Herrick lake forest preserve. The bikes are 100 meters apart at the start and one has a speed of 8 m/s and the other a speed of 10 m/s. The bat has a speed of 20 m/s. Assume that the bat flies from the front tire of one bike straight to the front tire of the other bike, then turns around with no delay and heads towards the other bike. This is repeated until both bikes and the bat are at the same place. Determine how far the bat flies during this flying feast.
Answer:
111.1 meters flown from bat
Explanation:
So one bike is going at 8m/s and the other bike is going at 10m/s in the direction towards the other bike. So we can make one bikes velocity =0 and the other we add the velocities together to get V of bike a = 18m/s while velocity of bike b =0m/s. Then we use the distance apart to find the time. so we take our average velocity formula and rearrange it to time = displacement/average velocity. This gives t = 100/18=5.55secs. We then take the bats velocity to find to the distance traveled. 5.55secs = x/20m/s. We just cross multiply to get 111.1 repeating which we just say is 111.1m traveled from the bat.
The distance traveled by the bat before the two bikes meet is 1,000 m.
Time taken for for the two bikes to be in the same place
The time taken for the bikes to meet or intersect each other is calculated as follows;
(Va - Vb)t = d
where;
t is the time taken for the bikes to meet each otherd is the distance between the bikesVa is the velocity of the first bikeVb is the velocity of the second bike(10 m/s - 8 m/s)t = 100 m
2 m/s (t) = 100 m
t = 100 m / 2 m/s
t = 50 seconds
Distance traveled by the bat within this periodDistance = average speed x time
Distance = 20 m/s x 50 s
Distance = 1,000 m
Thus, the distance traveled by the bat before the two bikes meet is 1,000 m.
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You've entered the Great Space Race. Your engines are hearty enough to keep you in second place. While racing, the person in front of you begins to have engine troubles and turns on his emergency lights that emit at a frequency of 5.820 1014 Hz. If the person in front of you is traveling 2694 km/s faster than you when he turns on his lights, what is the frequency of the emergency lights that you observe when it reaches you in your spaceship
The frequency of the emergency lights that you observe will be slightly higher at 5.821 1014 Hz due to the Doppler effect caused by the relative motion between the source and the observer.
In the Great Space Race, if the person in front of you turns on emergency lights that emit at a frequency of 5.820 1014 Hz and is traveling 2694 km/s faster than you, the frequency of the lights that you observe will be slightly different due to the Doppler effect. This effect causes the frequency of a wave to change when there is relative motion between the observer and the source of the wave.
To calculate the observed frequency of the lights, we can use the following equation:
f' = f × (c ± v) / (c ± vs)
Where f is the frequency of the lights as emitted by the source, v is the velocity of the source relative to the observer, c is the speed of light, and vs is the velocity of the observer.
Plugging in the given values, we get:
f' = 5.820 1014 Hz × (c + 2694 km/s) / (c - v)
Assuming that the observer (you) is not moving, we can simplify this equation to:
f' = 5.820 1014 Hz × (c + 2694 km/s) / c
Solving for f', we get:
f' = 5.820 1014 Hz × (299792458 + 2694000) / 299792458
f' = 5.821 1014 Hz (rounded to three significant figures)
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A 37 kg child jumps in the air. At the maximum height of the jump, the GPE is 500J. If the mass of the boy is tripled, how much Potential Energy does the child have at the top of his jump? If the same boy's mass is doubled, but his height is quadupled, how much Potential Energy does the child have at it's maximum and in what position in the jump will he be?
Answer:
*Answers are in their respective order with the questions.
\(1500\:\mathrm{J},\\4500\:\mathrm{J},\\5.52\:\mathrm{m}\)
Explanation:
The [gravitational] potential energy of an object is given by \(PE=mgh\), where \(m\) is the mass of the child, \(g\) is acceleration due to gravity, and \(h\) is the height of the object (relative to the ground).
"If the mass of the boy is tripled, how much potential energy does the child have at the top of his jump?"
Without actually plugging and chugging, notice the formula in which gravitational potential energy is given. Potential energy is directly proportional to mass. Therefore, if the mass of the boy is tripled, his potential energy will also be tripled, yielding an answer of \(500\cdot 3=\boxed{1500\:\mathrm{J}}\)
"If the same boy's mass is doubled, but his height is quadrupled, how much potential energy does the child have at its maximum and in what position in the jump will he be?"
In similar fashion to the first question, we can note that the potential energy of an object is directly proportional to its mass and height. Therefore, if the boy's mass is doubled and his height is quadrupled, his potential energy will be \(2\cdot 4=8\) times as large at maximum height. Thus, he will have \(500\cdot 8 =4,000\:\mathrm{J}\) of potential energy at the maximum height. I'm assuming that "in what position in the jump will he be?" is asking for the height at the maximum height of the jump.
The original height can be solved using:
\(PE=mgh,\\500=37\cdot 9.8\cdot h,\\h=\frac{500}{37\cdot 9.8}=1.37892995036\:\mathrm{m}\)
Quadrupled implies being multiplied by four. Therefore, we have:
\(h'=1.37892995036\cdot 4=5.51571980143\approx \boxed{5.52\:\mathrm{m}}\)
Water has a ph of 7. ph is defined as the negative log of the hydrogen ion concentration [h ]. explain why water is assigned a ph of 7.
Answer: Concentration of H+ =10^-7; log of 10^-7=7 so pH=7
Explanation:
what is the initial velocity of an object thrown straight up that takes 5 seconds to reach its highest point?
Answer:
50 [m/s].
Explanation:
1) formula is: V-V₀=g*t, where V₀ - final velocity (it is 0), V - required initial velocity, g≈10 [m/s²] and t - elapsed time.
2) according to the formula above:
V=g*t; ⇒ V=5*10=50 [m/s].
The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz
A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.
B) Using the MATLAB function trapz, the work done is approximately 7750 J.
Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.
A) Force (F) = 200 N (constant for all t)
Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)
Step size (h) = 0.25
To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.
Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.
Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].
For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²
Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).
Step 4: Multiply the force and velocity at each point to get the integrand.
For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]
Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].
The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]
Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).
Step 6: Multiply the result by the step size h to get the work done.
Work done: 1250 J
B) % Define the time intervals and step size
t = 0:0.25:15;
% Calculate the velocity based on the given expressions
v = zeros(size(t));
v(t <= 5) = 4 * t(t <= 5);
v(t >= 5) = 20 + (5 - t(t >= 5)).^2;
% Define the force value
F = 200;
% Calculate the work done using MATLAB's trapz function
\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;
% Display the result
disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);
The final answer for the work done using MATLAB's trapz function with the given force and velocity is:
Work done using MATLAB's trapz function: 7750 J
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mol Assume that oxygen approximates an ideal gas. The molar mass of O2 is 329 Determine the temperature at which the root-mean-square speed (thermal speed) of oxygen molecules would be 393" ( in °C) wered Answer - 74.8694 margin of error +/- 1%
The temperature at which the root-mean-square speed of oxygen molecules would be 393 m/s is approximately 74.87 °C with a margin of error of +/- 0.75 °C.
T = mv(rms)^2 / (3k)
Substituting the given values, we get:
T = (0.329 kg/mol) * (393 m/s)^2 / (3 * 1.38 x 10^-23 J/K)
T = 3196.23 K
Converting to Celsius:
T = 3196.23 K - 273.15 = 2923.08 °C
Rounding to the nearest hundredth and applying the margin of error of +/- 1%, we get:
T = 74.87 ± 0.75 °C
Temperature is a measure of the average kinetic energy of the particles in a system. Kinetic energy is the energy of motion, and the more motion there is, the higher the temperature. Temperature is usually measured in degrees Celsius (°C) or Fahrenheit (°F), or in the SI unit of Kelvin (K).
At the microscopic level, the temperature is related to the random motion of atoms and molecules in a substance. When two objects are in contact, heat energy can flow from the hotter object to the cooler object until they reach thermal equilibrium, where their temperatures are equal. The amount of heat energy transferred depends on the temperature difference between the objects and their thermal conductivities.
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what are the magnifications of the objective lenses
Answer:
Objective Lenses: Usually you find 3 or 4 objective lenses on a microscope. They almost always consist of 4x, 10x, 40x and 100x powers, when coupled with a 10x (most common) eyepiece lens, total magnification is 40x (4x times 10x) 100x, 400x and 1000x
Explanation:
Objective lenses come in various magnification powers, with the most common being 4x, 10x, 40x, and 100x, also known as scanning, low power, high power and typically oil immersion objectives, respectively
One acre is equal to 43560ft².How much is it in m²?
1 ft²= 0.09290304m²
so:
43560ft²= 0.09290304m²×43560
= 4,046.8564224 m²
Answer: 4046.9m² (approx.)
Explanation:
An acre is 43560 ft², but the US has two feet, the International foot, and the (old) Survey foot. Since 1983, the answer varies by state according to which foot the State has adopted for surveying. (Previously, it was always the Survey foot).
International: 43560 ft² x (0.3048 m/ft)² = 4046.856 422 m²
Survey: 43560 ft² x (1200/3937 m)² = 4046.872 610 m²
Both round to 4046.9 m² if that’s good enough, but there is a tiny difference.
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This graph shows the energy of a reaction over time. Which statement is
true?
A. H represents the energy of the products.
B. G represents the activation energy.
C. G represents the energy of the products.
D. F represents the activation energy
Answer: D.
Explanation: Just took the quiz.
Answer:
D. F represents the activation energy
Explanation:
T/F Vectors can be added together using the rules of algebra
The given statement "vectors can be added together using the rules of algebra" is true.
A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are a few examples of vectors in nature.
When performing vector addition, you simply add the corresponding components of each vector together.
For example, if you have two vectors A = (a₁, a₂) and B = (b₁, b₂),
their sum C = A + B would be:
C = (a₁ + b₁, a₂ + b₂)
Any two vectors are not subject to the vector addition rule. Only when two vectors of the same kind and nature are they added.
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Identify one simple machine used at your home and explain how it makes your work easier
Answer:
they are,
1. scissor = they are very useful for cutting papers, clothes, etc. if there wouldn't be sicssor than we would not be able to cut various things . it has made easier to cut tgings.
2. nailcutter= it is also one type of simple machine. it is used to trim our nails. if there would be no nailcutter then our nail would be so dirty and long.
hope it helps..