What is the rate (in ft/s) at which the shadow changes when the person is 10 ft from the wall, if the person is walking away from the wall at a rate of 3 ft/s?

Answers

Answer 1

The rate at which the shadow changes when the person is 10 ft from the wall and walking away at a rate of 3 ft/s is -4.5 ft/s

To determine the rate at which the shadow changes when the person is 10 ft from the wall and walking away at a rate of 3 ft/s, we can consider similar triangles formed by the person, the length of the shadow, and the distance between the person and the wall.

Let's denote the length of the shadow as 's' and the distance between the person and the wall as 'd'. The rate at which the shadow changes (ds/dt) can be found using related rates:

(ds/dt) = (ds/dd) * (dd/dt)

Where (ds/dd) represents the rate at which the shadow changes with respect to the distance, and (dd/dt) represents the rate at which the distance changes.

In this case, we are given that (dd/dt) = -3 ft/s since the person is walking away from the wall. We need to determine (ds/dd) to find (ds/dt).

In similar triangles, the ratio of corresponding sides is constant. Therefore, we have:

s / d = k

where 'k' is the constant of proportionality. We can find 'k' by using the given information that when the person is 10 ft from the wall, the length of the shadow is 15 ft.

15 ft / 10 ft = k

k = 1.5

Now we can differentiate the equation with respect to 'd' to find (ds/dd):

(d/dt)(s/d) = (d/dt)(1.5)

(ds/dd) = (1.5)(dd/dt)

Substituting the given value:

(ds/dd) = (1.5)(-3 ft/s)

= -4.5 ft/s

Therefore, the rate at which the shadow changes when the person is 10 ft from the wall and walking away at a rate of 3 ft/s is -4.5 ft/s

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Answer 2

when the person is 10 ft from the wall and walking away at a rate of 3 ft/s, the rate at which the shadow changes is 0 ft/s.

The rate at which the shadow changes can be determined using similar triangles. Let's break down the problem step by step:
1. We are given that the person is walking away from the wall at a rate of 3 ft/s. This means that the distance between the person and the wall is increasing at a rate of 3 ft/s.

2. The person is initially 10 ft from the wall. We'll call this distance "x."

3. Let's assume that the length of the person's shadow is "y." We want to find the rate at which the shadow changes, which can be represented as dy/dt.

4. Since we have a similar triangle formed by the person, the wall, and the shadow, we can use the properties of similar triangles to find dy/dt.

5. The ratio of the lengths of corresponding sides of similar triangles is equal. In this case, we have:

  x/y = (x + 10)/(y + dy)

  where (x + 10) represents the new distance between the person and the wall, and (y + dy) represents the new length of the shadow.

6. We can solve for dy/dt by differentiating both sides of the equation with respect to time (t):

  d(x/y)/dt = d((x + 10)/(y + dy))/dt

  Simplifying the equation, we have:

  (1/y)*(dx/dt) = (1/(y + dy))*((dx/dt) + 0)

  Since dx/dt is given as 3 ft/s, we can substitute that value into the equation:

  (1/y)*3 = (1/(y + dy))*3

7. Now, we can solve for dy/dt. First, let's cross-multiply the equation:

  (1/y)*(y + dy) = 1

  Simplifying, we have:

  y + dy = y

  dy = 0

8. Since dy = 0,
we can conclude that the rate at which the shadow changes (dy/dt) is 0 ft/s. This means that the length of the shadow is not changing as the person walks away from the wall.


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Related Questions

Calculate the force on a wire of length 0.1 m carrying a current of 10A if it is
(a) perpendicular
(b) inclined at 300
(c) parallel to a magnetic field of 1 x 10-2 T

Answers

(a) The magnetic force experienced by the wire when it perpendicular is 0.01 N.

(b) The magnetic force experienced by the wire when the angle is  30⁰ is 5 x 10⁻³ N.

(c) The magnetic force experienced by the wire when it parallel is 0 N.

What is magnetic force?

The magnetic force experienced by the wire is calculated by applying the following;

F = BIL x sin(θ)

where;

B is the magnetic field strengthI is the current in the wireL is the length of the wireθ is the angle of inclination of the wire

When the angle of inclination is perpendicular,  

F = 1 x 10⁻² x 10 x 0.1 x sin(90)

F = 0.01 N

When the angle of inclination is 30⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(30)

F = 5 x 10⁻³ N

When the wire is parallel, the angle is 0⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(0)

F = 0 N

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A wave oscillates with a period of 4.25 X 10-10 s. How many waves will strike a signal detector in 3 seconds?

Answers

Answer:

\(n=7.05\times 10^9\) waves

Explanation:

Given that,

A wave oscillates with a period of \(4.25\times 10^{-10}\ s\)

We need to find the number of waves that will strike a signal detector in 3 seconds.

We know that,

Frequency = (no. of oscillations)/time

Time period = time/(no. of oscillations)

Let there are n waves that will strike

So,

\(n=\dfrac{3}{4.25\times 10^{-10}}\\\\=7.05\times 10^9\)

Hence, \(7.05\times 10^9\) waves will strike in 3 seconds.

Solve this code. Use the Periodic Table if necessary:

In Chicago, a group of spies is running a secret chemical plant which is disguised as a restaurant called the CHON SIP CaFe. However, by examining the name of the restaurant, you can tell what chemical elements are used there. What are they?


oxygen,
hydrogen,
sulfur,
sodium,
iodine,
fluorine,
iron,
cadmiun,
carbon,
potassium,
nitrogen,
phosphorus,
calcium,
silicon,

Answers

oxygen, hydrogen, sulfur, iodine, iron, carbon, nitrogen, phosphorus, calcium.

Un móvil viaja inicialmente con una velocidad de 55 m/s, al cabo de cierto tiempo, su velocidad es de 115 m/s, de repente frena bruscamente con una desaceleración de 14, 500 m/s2. ¿qué distancia recorrerá antes de frenar?

Answers

Answer:

Distancia, S = 2.84 metros

Explanation:

Dados los siguientes datos;

Velocidad inicial = 55 m/s

Velocidad final = 115 m/s

Deceleración = 14500 m/s²

Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;

V² = U² + 2aS

115² = 55² + 2*14500*S

13225 = 3025 + 29000S

29000S = 13225 - 3025

29000S = 10200

S = 29000/10200

Distancia, S = 2.84 metros

What happens to the voltage over the inductor due to Faraday’s law in the steady state?
For steady state, the equation for the voltage over the inductor is VL = i*RL = (V*RL)/(RL + R)

Answers

In steady state, the voltage over the inductor remains constant due to Faraday's law. Faraday's law states that a changing magnetic field induces an electromotive force (EMF) in a circuit. In the case of an inductor in steady state, the current flowing through the inductor is constant, so the magnetic field produced by the current is also constant. Therefore, there is no changing magnetic field to induce an EMF, and the voltage over the inductor remains constant.

The equation for the voltage over the inductor in steady state (VL = i*RL = (V*RL)/(RL + R)) shows that the voltage is determined by the current flowing through the inductor and the resistance of the circuit. Since the current is constant in steady state, the voltage over the inductor will also be constant. In the steady state, the voltage across the inductor drops to zero due to Faraday's law.

Faraday's law states that the voltage induced in a circuit is proportional to the rate of change of magnetic flux. In the steady state, the current through the inductor becomes constant, meaning the rate of change of magnetic flux is zero. Therefore, the induced voltage across the inductor is also zero. In the steady state, the equation for the voltage over the inductor is VL = i*RL = (V*RL)/(RL + R). However, since the rate of change of magnetic flux is zero, the voltage across the inductor becomes zero (VL = 0). This means that the voltage across the inductor is negligible in the steady state due to Faraday's law.

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A battery-powered set of five patio lanterns is connected in series. An ammeter measures the current through the battery as 0.75 A. The total resistance of the circuit is 52 0. (a) Calculate the voltage drop across the battery. (b) Calculate the voltage drop across each load.

Answers

Answer:

(a) 39 V

(b) 7.8 V

Explanation:

(a) Neglecting the internal resistance of the battery, the voltage drop (V) across the battery is found from Ohm's law as follows;

V = IR                -------------------------(i)

Where;

I = current through the battery

R = total resistance of the circuit.

From the question;

I = 0.75A

R = 52.0Ω

Substitute the values of I and R into equation (i)

=> V = 0.75 x 52.0

=> V = 39Volts

Therefore, the voltage drop across the battery is 39 Volts

(b) Since the set of lanterns is connected in series, then the same current flows through each of the lanterns. Also, since the lanterns are identical, the resistance (\(R_{L}\)) of each of them is given by the total resistance (R = 52.0Ω) divided by the number of lanterns. i.e

\(R_{L}\) = \(\frac{52.0}{5}\)

\(R_{L}\) = 10.4Ω          [Each lantern has a resistance of 10.4Ω]

The current flowing through them is the same as the current (I = 0.75A) flowing the circuit.

Therefore, using Ohm's law, the voltage drop (\(V_L\))across each load (lantern) is

\(V_L\) = I x \(R_{L}\)

\(V_L\) = 0.75 x 10.4

\(V_L\) = 7.8Volts

Therefore, the voltage drop across each load is 7.8 Volts

Name HUAWEI P smart 2021 3. What is a rarefaction? Honors Physics: Sound Worksheet 1---Sound Basics 1. What type of wave are all sounds? 2. What is a compression? Date 4. In the diagram below, underneath each arrow, label the compressions with a C and the rarefactions with an R. Class Period 5. Many times in futuristic movies, an explosion occurs in space and loud 'boom' is created. Is this possible? Why or why not? 6. Sound travels approximately 340 m/s in air. Sound travels faster in steel. Explain why. Answer: 7. The pitch of any sound we hear is a result of what characteristic of the sound wave. 8. Humans are only able to hear sounds above 20Hz and below 20kHz. What is it called when: a. the frequency is above 20kHz? b. the frequency is below 20Hz? Answer: 9. The loudness of any sound is a result of what part of the sound wave? 10. Loudness of sound is measured in what unit?​

Name HUAWEI P smart 2021 3. What is a rarefaction? Honors Physics: Sound Worksheet 1---Sound Basics 1.

Answers

Rarefraction  is decrease of substance density .

What is the difference between Rarefraction and Compression?

1) Rarefraction is a space in a longitudinal wave  where particles are furthest apart and Compression is a place in a longitudinal waves and particles are in close vicinity.

2)The region where the substance in compressed is called Compression and the region where Medium spread out is Rarefraction . They are antagonist to each other.  

*All sounds are longitudinal waves and they also include compression and Rarefraction.

*Compression is decrease of Volume by applying stress on that substance.

* The force attraction between the Molecules of solid is more as compare to liquid and air . So ,that is steel has more sound as Compare to air ,it 17times faster than Air .

*Frequency is also known pitch in sound.

*If the frequency will be above than 20khz , it can lead to deafness or can make you uncomfortable for hearing.

*The loundness of any sound is a part of Amplitude .

*The loundness is measured in decibel.The normal person can hear only 50Decibels.

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1) With the aid of diagrams explain how two hollow cans be charged by induction using 5 units of positive charges.​

Answers

Answer:

plz mark as a pure substance abuse and function of the equation for sulphur dioxide

help ill give brainleist

Mechanical energy is lost:

when parts rub against each other
when heat radiates from the engine
whenever friction is present
all of the above

Answers

Transformation of Energy

Round the numbers that follow to three significant figures and express the result in standard exponential notation: (a) 143,700; (b) 0.09750; (c) 890,000; (d) 6,764E4; (e) 33,987.22; (f) - 6.5559.

Answers

Explanation:

Non-zero digits are always significant.

Zeros between significant digits are also significant.

Trailing zeros are significant only after a decimal point.

(a) 143,700

First, write in scientific notation.

1.437×10⁵

Now, round to 3 significant figures.

1.44×10⁵

(b) 0.09750

= 9.750×10⁻²

= 9.75×10⁻²

(c) 890,000

= 8.9×10⁵

= 8.90×10⁵

(d) 6,764×10⁴

= 6.764×10⁷

= 6.76×10⁷

(e) 33,987.22

= 3.398722×10⁴

= 3.40×10⁴

(f) -6.5559

= -6.5559×10⁰

= -6.56×10⁰

The scientific notation and round-off of the number are given below:-

(a) 143,700     = 1.44×10⁵

(b) 0.09750   = 9.75×10⁻²

(c) 890,000   = 8.90×10⁵

(d) 6,764×10⁴ = 6.76×10⁷

(e) 33,987.22 = 3.40×10⁴

(f) -6.5559     = -6.56×10⁰

What is a scientific notation?

Numbers that are either too large or too little to be conveniently stated in decimal form can be expressed using scientific notation. It may be called scientific form.

When a number is written using only the digits of the number, that is considered standard notation. Since words are not used in conventional number notation, this is the way that numbers are typically written.

Non-zero digits are always significant. Zeros between significant digits are also significant.

Trailing zeros are significant only after a decimal point.

(a) 143,700

First, write in scientific notation.

1.437×10⁵

Now, round to 3 significant figures.

1.44×10⁵

(b) 0.09750

= 9.750×10⁻²

= 9.75×10⁻²

(c) 890,000

= 8.9×10⁵

= 8.90×10⁵

(d) 6,764×10⁴

= 6.764×10⁷

= 6.76×10⁷

(e) 33,987.22

= 3.398722×10⁴

= 3.40×10⁴

(f) -6.5559

= -6.5559×10⁰

= -6.56×10⁰

Therefore, the numbers can be written in the scientific notations as above.

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The globe is divided into time zones, so that any given hour of the day in one time zone occurs at a different time in other time zones. For example, New York City is in one time zone and Los Angeles is in another time zone. When it is 8:00 a.m. in New York City, it is only 5:00 a.m. in Los Angeles. Explain how Earth’s motions cause this difference in times.

Answers

Answer:

The rotation of the earth on its tilted axis is the reason behind the difference in the length of the day and night time in different parts of the earth throughout the year. The annual motion of the Earth is called revolution. Since the path of the Earth is elliptical, the interval between the Earth and the Sun keeps shifting.

Explanation:

When sound waves superimpose they can interfere?

Answers

Answer:    

Explanation:

When two waves of similar frequency arrive at the same point and superimpose, they alternately constructively and destructively interfere. This alternating is known as a beat because it produces an unpleasant pulsing sound

why is clay soil chosen for earthenware? Explain it.

Answers

There are many reasons actually...

◇ Clayey soil is easy to mould than the other soils.

The other soils (like sandy soil & loamy soil) are grainy or dry in nature & cannot be moulded. In the ancient times, when technology & the know-hows were still not introduced, people used clayey soul to make earthern pots to store stuff. This practice still continues even today.

◇ It keeps water cool.

Ever wondered why water stored in the earthenware remains cool even on a sunny day? It's because the heat required for evaporation is taken from water inside the pot & thus it cools the water stored inside.

◇ Clayey soil is also moist, durable, more plastic like & easy to retain making it ideal for potters to make earthenware.

__________

Clay soil is used to make earthenwares because, clay can be easily molded to desired sizes and shapes. Clay absorbs water moiety and make the pot very cool inside.

What is clay?

Clay is a type of soil made by the sedimentation process near water resources.  They are rich in minerals. Clay is rich in silicates and intermolecular force in the soil is comparatively less and can be easily molded any shape and size.

When clay is fired to a high enough temperature, the glass-forming materials in the ceramic form a liquid glass. This glass bridges the gaps between the clay particles. As the pottery cools at the end of the firing process, the glass between the clay particles solidifies again.

Clay pots make the water cooler inside. Hence, clay is used to make earthen wares.

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Which object most likely has magnetic domains like those shown in the image? A. A piece of wood near a magnet
B. A steel paper clip near a magnet
C. A piece of wood, not near a magnet
D. A steel paper clip, not near a magnet​

Which object most likely has magnetic domains like those shown in the image? A. A piece of wood near

Answers

Answer:

b. A steel paper clip near a magnet

Explanation:

A steel paper clip near a magnet is an object that most likely has magnetic domains because of its inner composition.

What is magnetic domain?

A magnetic domain is a part or region within a magnetic substance in which the magnetization is present in a uniform direction.

So we can conclude that a steel paper clip near a magnet is an object that most likely has magnetic domains because of its inner composition.

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PLEASE HELP!!

A fisherman pulls a boat towards land,
The forces acting on the boat are shown in Diagram 1
The fisherman exerts a force of 300 N on the boat
The sea exerts a resistive force of 250 N on the boat.
Diagram 1
250N
300N

Describe the motion of the boat.​

PLEASE HELP!!A fisherman pulls a boat towards land,The forces acting on the boat are shown in Diagram

Answers

Answer:

The boat will move in the direction of the force exerted.

Explanation:

To describe the motion of the boat, we shall first obtain the net force acting on the boat. This can be obtained as illustrated below:

From the question given above, the following data were obtained:

Force exerted (Fₑ) = 300 N

Resistive force (Fᵣ) = 250 N

Net force (Fₙ) =?

Fₙ = Fₑ – Fᵣ

Fₙ = 300 – 250

Fₙ = 50 N

Thus, the net force acting on the boat is 50 N in the direction of the force exerted.

Since the net force is in the direction of the force exerted, the boat will move in the direction of the force exerted..!

Assertion:The voltage- current graph will always be a straight line moving away from both the axes.

Reason:The current in a circuit is directly proportional to its voltage.

Select the correct answer to these questions from the codes (i), (ii), (iii) and (iv) as given below.

(i) Both A and R are true and R is the correct explanation of the Assertion.

(ii) Both A and R are true but R is not the correct explanation of the Assertion.

(iii) A is true but R is false.

(iv) A is false but R is true

Answers

Answer:

the answer is (i)

Explanation:

Because it is true that the current in a circuit is directly proportional to its current

And that's according to ma views

the density of sand is more than the density of wood why?​

Answers

Compared to wood, which tends to have looser particles, sand has smaller, more sinkable granules that can occupy more space.

Last summer, Jose left early in the morning at 5 a.m. and drove to Ensenada 100 miles away. He stopped to get gas and drove an extra 300 miles. He finally stopped in Cabo San Lucas at 1p.m. What was the average speed that Jose was traveling?

Answers

Answer:50 miles per hour

a mass weighing 54 pounds stretches a spring 3.84 inches. determine the amplitude and period of motion if the mass is initially released from a point 8 inches above the equilibrium position with an upward velocity of 5 ft/s

Answers

The restoring force F of a spring is proportional to its displacement x from its equilibrium position. This law is called Hooke's law, and it can be written mathematically as follows:

F = − kx

where k is the spring constant

The period of motion can be determined by the following formula:

T=2π\(\sqrt{\frac{m}{k} }\)

where, m = the mask = spring constant

Let the amplitude of motion be A. The total energy of a mass attached to a spring is given by:

E=\(\frac{1}{2}\)k\(A^2\)

The maximum kinetic energy of the mass is given by

K = \(\frac{1}{2}\)m\(v^2\)

The maximum potential energy is given by

U = \(\frac{1}{2}\)k\((A + x_0)^2\)

where \(x_0\) is the displacement of the mass from the equilibrium position when it is released from a point 8 inches above the equilibrium position with an upward velocity of 5 ft/s. The maximum potential energy is equal to the maximum kinetic energy.

Equating the two, we have:

\(\frac{1}{2}\)m\(v^2\) = \(\frac{1}{2}\)k\((A + x_0)^2\) ⇒ A + \(x_0\) = \(\sqrt{\frac{mv^2}{k} }\)

Using this value of A + \(x_0\), we can determine the amplitude of motion as follows:

A = \(\sqrt{\frac{mv^2}{k} }\) − \(x_0\)

The mass in pounds can be converted to slugs as follows: \(m = \frac{54}{32.2} = 1.68\) slugs.

The displacement x of the spring from its equilibrium position can be determined as follows: \(x = \frac{3.84}{12} = 0.32\) ft.

The spring constant k can be determined using the formula:

\(k=\frac{k}{x}\)

where F is the force exerted on the spring when it is stretched by the mass.

The force F can be determined using the formula: F = m * g where g is the acceleration due to gravity.

Substituting the values, we get: F = 1.68 * 32.2 = 54.1 lbf

Substituting these values into the formula for k, we get \(k =\frac{54.1}{0.32} = 169.0\) lbf/ft.

The period of motion can be determined using the formula: T = 2π\(\sqrt{\frac{m}{k} }\).

Substituting the values, we get: T = 2π\(\sqrt \frac{1.68}{169.0}\) = 0.504 s.

Using the value of \(x_0\), we can determine the amplitude of motion as follows: A = \(\sqrt{\frac{mv^2}{k} }\)  − \(x_0\).

Substituting the values, we get: A = \(\sqrt{ \frac{1.68*\frac{25}{9} }{169.0}} - 0.67A\)= 0.062 ft or 0.74 .

When a mass is hung on a spring, it extends from its original length to a new length. This change in length is known as the displacement. The point where the mass hangs without moving up or down is known as the equilibrium position. The restoring force, which is proportional to the displacement from the equilibrium position, acts on the mass when it is displaced from its equilibrium position. This law is known as Hooke's law. The constant of proportionality is known as the spring constant. The period of motion of the mass attached to the spring can be determined using the formula T = 2π\(\sqrt{\frac{m}{k} }\), where m is the mass and k is the spring constant. The amplitude of motion is the maximum displacement of the mass from its equilibrium position.

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With -6.0 D corrective lenses, Juliana's distant vision is quite sharp. She has a pair of -4.0 D computer glasses that puts her computer screen right at her far point. How far away is her computer?

Answers

Answer:

If Juliana's far point is at infinity with her -6.0 D corrective lenses, then her near point is at:

1/f = 1/do + 1/di

where f is the focal length of the computer glasses, do is the distance of the object (which is infinity), and di is the distance of the image (which is the near point).

Solving for di, we get:

di = 1 / ((1/f) - (1/do))

Since do is infinity, the equation simplifies to:

di = f

So the distance of the image (the near point) is equal to the focal length of the computer glasses.

Since Juliana's computer glasses have a power of -4.0 D, the focal length of the glasses is:

f = 1 / (-4.0 D) = -0.25 m

Therefore, the distance of Juliana's computer screen is 0.25 m or 25 cm away from her computer glasses.

Explanation:

List three ways light can be grouped based on how much light shines through or passes through them

Answers

Answer:

Materials can be classified based on the amount of light they transmit. Materials, which allow complete transmission of light, are called transparent. Any object can be seen through a transparent material. One example of transparent material is pure glass.

Explanation:

Does this help ?

Answer:

light, materials, and shadows

Explanation:

hope this helps have a good rest of your day :) sorry if incorrect

Which change increases the electric forcWhich change increases the electric force between objects?e between objects?

Answers

The electric force increases because the amount of charge has a direct relationship to the force. ... Electrons are added to two negatively charged objects. Hope it helps

Answer:

b

Explanation:


1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)

Answers

1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.

1b) The height of the tank is 2 m.

2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.

3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.

3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.

3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

1a) To calculate the amount of energy stored in the three weights, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

For the 4.5 kg weight:

E = 4.5 x 10 x 0.7 = 31.5 J

For each of the 3.5 kg weight:

E = 3.5 x 10 x 0.7 = 24.5 J

Thus, the total energy stored when all three weights are raised by 70 cm is:

31.5 J + 24.5 J + 24.5 J = 80.5 J

1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:

E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)

To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:

Mass = 200 kg

The height of the tank is 2 m.

Therefore, the gravitational potential energy stored in the water in the tank is:

E = mgh = 200 x 10 x 2 = 4000 J

Assumptions made in the answer:

We have assumed that the tank is full.

2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:

PE = KEPE = mghKE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:

PE = mgh = 200 x 10 x 2 = 4000 J

The potential energy is converted into kinetic energy when the water flows out of the taps.

Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)

3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:

Mass = Volume x Density

Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg

3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:

E = mgh

Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J

3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:

PE = KEP

E = mgh

KE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,

PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:

Power = Energy / Time

Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)

The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

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The moon's mass is 7.4×1022kg and it orbits 3.8×108m from the earth with a period of 27.3 days.
What is the angular momentum of the moon around the earth?
Express your answer using two significant figures.

Answers

The angular momentum of the moon around the earth is 2.84 × 10³⁴ kgm²/sec, if the mass of the moon is 7.4 × 10²² kg.

Mass of the moon, M = 7.4 × 10²² kg

Radius of the orbital path, R = 3.8 × 10⁸ m

Time period of of one rotation, T = (27.3×86400) = 2.36 × 10⁶ seconds

Angular velocity, ω = 2π/T

ω = (2×3.14)/(2.36 × 10⁶) =  2.66 × 10⁻⁶ rad/sec

Moment of inertia of the moon around the earth, I = M×r²

I = 7.4 × 10²² × (3.8 × 10⁸)²

I = 1.068 × 10⁴⁰ kg-m²

Angular momentum of the moon, U = I × ω

= 1.068 × 10⁴⁰ × (2.66 × 10⁻⁶)

= 2.84 × 10³⁴ kg-m²/sec

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The image shows a type of fault.

What stress causes this type of fault to form?
A. Compression
B. Gravity
C. Tension
D. Shearing​

The image shows a type of fault. What stress causes this type of fault to form? A. CompressionB. GravityC.

Answers

Answer:

D. Shearing​

Explanation:

D. Shearing​

The Answer is: Shearing

The image shows a type of fault. What stress causes this type of fault to form? A. CompressionB. GravityC.

Whispering Gallery: A hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the center, how high will the ceiling be at the center?

Answers

The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.

Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.

The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.

Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.

To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:

b = √(a² - c²)

where c represents the distance from the center to each focus. In this case, c = 25 feet.

Substituting the values into the formula:

b = √(50² - 25²)

b = √(2500 - 625)

b = √(1875)

b = 43.3 feet

Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

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if a machine produces electric power directly from sunlight, then it is _____.

Answers

If a machine produces electric power directly from sunlight, then it is Photovoltaic (PV).

Explanation: Photovoltaic (PV) refers to the process of converting sunlight into electricity. PV technology uses silicon cells to absorb photons (particles of light) to release electrons. It is also known as solar cells. Solar cells, also known as photovoltaic cells, are usually made of silicon and convert the light energy of the sun directly into electrical energy. A group of solar cells forms a solar panel, which can be used to generate electricity from the sun's energy, while a group of solar panels forms a solar array.

Thus, photovoltaic cells are the best answer for the given question.

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how much does a change in mass affect the kinetic energy of two balls of comparable diameter?​

Answers

Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

Can the motion of gestures and arm movement be considered part of the Kinesthetic learning style. Explain with reasoning if it can be part of that learning style or not Your answer 3 points

Answers

The motion of gestures and arm movement can be considered part of the kinesthetic learning style. Kinesthetic learners prefer to learn through physical activity, movement, and tactile experiences. Gestures and arm movements engage the body and provide a physical connection to the learning process.

1. Physical Engagement: Kinesthetic learners rely on physical movement to enhance their learning experience. Gestures and arm movements allow them to physically interact with information and reinforce their understanding. For example, while learning a new concept or solving a problem, kinesthetic learners may use hand gestures to represent different elements or manipulate objects to better comprehend the subject matter.

2. Tactile Connection: Kinesthetic learners often benefit from tactile experiences as it helps them internalize information. By incorporating gestures and arm movements, they create a physical connection to the learning material. These physical actions provide sensory feedback and reinforce the learning process, allowing kinesthetic learners to better retain and recall information.

3. Whole-Body Learning: Kinesthetic learners thrive when they can engage their entire body in the learning process. Gestures and arm movements involve the larger muscles and promote a more holistic learning experience. The physicality of these movements can enhance their understanding and enable them to grasp concepts in a way that complements their learning style.

In conclusion, gestures and arm movements can be considered part of the kinesthetic learning style as they facilitate physical engagement, provide a tactile connection, and support whole-body learning. Incorporating these movements can be an effective strategy for kinesthetic learners to enhance their comprehension and retention of information.

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If an object is moving at 5m/s north and an balanced force is acting on it, it will continue to move at that same velocity.

Answers

Answer:An object having balanced forces definitely cannot be accelerating.

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