hey beautiful. I will try to give brainliest to whoever can answer this CORRECTLY thanks in advanced.​

Answer:

40

Step-by-step explanation:

82 + 58 + ? = 180

140 + ? = 180

? = 40

Have an amazing day!

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Answer:

Step-by-step explanation:

From what I understand, you are trying to solve for a.

So,

d=g+2ac

d-g=2ac

(d-g)/2c=a

So,

a = (d-g) / 2c

The  growth rate of bacteria is about 26.8 hours to reach 500,000 cells, assuming there are no limiting factors.

The growth rate of bacteria is given as 20% per hour, which means that if there are N bacteria at the start of an hour, the number of bacteria at the end of the hour will be N + 0.2N = 1.2N. This assumes that there are no limiting factors such as space, nutrients, etc.

Let's assume that the time it takes to reach 500,000 cells is t hours. At the start, there is only one bacterium, so the number of bacteria after t hours can be written as:

N(t) = 1 x 1.2^t

We want to find the time t such that N(t) = 500,000. Therefore, we can write:

1.2^t = 500,000

Taking the natural logarithm of both sides, we get:

t ln(1.2) = ln(500,000)

t = ln(500,000) / ln(1.2)

t ≈ 26.8 hours

Therefore, it would take about 26.8 hours to reach 500,000 cells, but in absence of limiting factor.

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Answer:

x=3

Step-by-step explanation:

6x - 2 = x + 13

subtract 1x from both sides

5x - 2 = 13

isolate the 5x by adding 2 to both sides

5x = 15

finnaly devide both by 5

x = 3

Answer:

      -7

Step-by-step explanation:

     1.6x-2=x+13

   +1.6x      +1.6x

          -2=2.6x+13

          -13        -13

          -15=2.6x

(2.6 divided by 2.6)

(-15 divided by 2.6 is -7)

answer:-7

Sorryyyyy its hard to explain

To increase usability in a spreadsheet, you can use comments, descriptive labels, and data validation.

To increase usability in a spreadsheet, you can utilize the following techniques:

1. Comments: Comments allow you to add explanatory notes or instructions within cells. They can provide additional context or clarify the purpose of certain data or formulas. Users can view comments by hovering over the respective cell, making it helpful for collaboration and documentation.

2. Descriptive Labels: Instead of relying solely on cell references or generic labels, use descriptive labels that clearly indicate the purpose of each column, row, or range of cells. This approach enhances readability and makes it easier for users to understand the data and navigate through the spreadsheet.

3. Data Validation: Implement data validation rules to ensure the accuracy and integrity of the data entered into the spreadsheet. Data validation allows you to define constraints or conditions for input, such as numeric ranges, predefined lists, or specific text formats. It helps prevent errors and assists users in entering valid data.

4. Formatting: Properly formatting the cells, columns, and rows can greatly enhance usability. Use consistent formatting for similar types of data, apply color schemes or conditional formatting to highlight important information or trends, and adjust the column widths and row heights to optimize readability.

5. Sheet Organization: Organize the spreadsheet by using multiple sheets if needed. Group related information on separate sheets, and provide clear sheet names that reflect the content or purpose of each sheet. This helps users locate and navigate to specific sections or data within the spreadsheet.

6. Clear Instructions or Documentation: Provide clear instructions or documentation either within the spreadsheet or as separate documentation. Explain the purpose of the spreadsheet, any specific procedures or workflows, and how to interpret the data or use any embedded formulas or macros. This helps users understand the spreadsheet's functionality and ensures consistent usage.

7. Error Handling: Implement error handling mechanisms to provide informative error messages or alerts when users input incorrect or incompatible data. Clear error messages guide users in correcting their input and reduce frustration when dealing with potential errors.

By incorporating comments, descriptive labels, data validation, formatting, sheet organization, clear instructions/documentation, and error handling, you can significantly enhance the usability of your spreadsheet and make it more user-friendly for both yourself and others who interact with it.

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Step-by-step explanation:

40°+63°+e=180°

103°+e=180°

e=180°-103°

e=73°

The solution to the differential equation D²y(t) + 12 Dy(t) + 36y(t) = 2 \(e^{(-5t)}\), with initial conditions y(0) = 1 and Dy(0) = 0, is \(y(t) = (1 + 6t) e^{(-6t)}\).

To solve the given differential equation using the classical method, we can assume a solution of the form \(y(t) = e^{(rt)}\) and find the values of r that satisfy the equation. We then use these values of r to construct the general solution.

Using the classical method:

Substitute the assumed solution \(y(t) = e^{(rt)}\) into the differential equation:

D²y(t) + 12 Dy(t) + 36y(t) = \(2 e^{(-5t)}\)

This gives the characteristic equation r² + 12r + 36 = 0.

Solve the characteristic equation for r by factoring or using the quadratic formula:

r² + 12r + 36 = (r + 6)(r + 6)

= 0

The repeated root is r = -6.

Since we have a repeated root, the general solution is y(t) = (c₁ + c₂t) \(e^{(-6t)}\)

Taking the first derivative, we get Dy(t) = c₂ \(e^{(-6t)}\)- 6(c₁ + c₂t) e^(-6t).\(e^{(-6t)}\)

Using the initial conditions y(0) = 1 and Dy(0) = 0, we can solve for c₁ and c₂:

y(0) = c₁ = 1

Dy(0) = c₂ - 6c₁ = 0

c₂ - 6(1) = 0

c₂ = 6

The particular solution is y(t) = (1 + 6t) e^(-6t).

Using the Laplace transform method:

Take the Laplace transform of both sides of the differential equation:

L{D²y(t)} + 12L{Dy(t)} + 36L{y(t)} = 2L{e^(-5t)}

s²Y(s) - sy(0) - Dy(0) + 12sY(s) - y(0) + 36Y(s) = 2/(s + 5)

Substitute the initial conditions y(0) = 1 and Dy(0) = 0:

s²Y(s) - s - 0 + 12sY(s) - 1 + 36Y(s) = 2/(s + 5)

Rearrange the equation and solve for Y(s):

(s² + 12s + 36)Y(s) = s + 1 + 2/(s + 5)

Y(s) = (s + 1 + 2/(s + 5))/(s² + 12s + 36)

Perform partial fraction decomposition on Y(s) and find the inverse Laplace transform to obtain y(t):

\(y(t) = L^{(-1)}{Y(s)}\)

Simplifying further, the solution is:

\(y(t) = (1 + 6t) e^{(-6t)\)

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Answer:

The theoretical probability of landing on a star space on your first roll  

✔ decreases

The theoretical probability of not landing on a question mark on your first roll  

✔ increases

The theoretical probability of reaching the end space on your first roll  

✔ does not change

Answer:

1) Decreases

2) Increases

3) Does not change

Step-by-step explanation:

Answer:

Think its 275

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

6 inches

Step-by-step explanation:

1 inch = 2.54 cm.

 1 cm = 1/2.54 inches.

14 cm = 14/2.54

14 cm, when rounded to nearest inch, results in around 6 inches.

Answer:

Step-by-step explanation:

Answer:

hi do You have Instagram?

9514 1404 393

Answer:

Step-by-step explanation:

The downward-sloping line has a y-intercept of 1 and a slope of -2, so its equation is ...

  y = -2x +1

The graph is shaded on and above that line, so the inequality it represents is ...

  y ≥ -2x +1

__

The upward-sloping line has a y-intercept of +4 and a slope of +2, so its equation is ...

  y = 2x +4

The graph is shaded on and below that line, so the inequality it represents is ...

  y ≤ 2x +4

Then the system of inequalities is ...

  y ≥ -2x +1

  y ≤ 2x +4

Yes, The triangles are congruent by SSS i,e option(D)

When two corresponding sides and the angle included between them of one triangle match those of two corresponding sides and the angle included between them of another triangle, the two triangles are said to be congruent. Two triangles are said to be congruent if their three sides and three angles, in any orientation, are equal.

By applying the CPCTC (Corresponding Parts of Congruent Triangles are Congruent) theorem, the two sides of the triangle in issue are made equal, hence making the third sides equal.

Therefore, we can say the triangles are congruent by SSS i,e option(D)

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Answer:

1/5 or 0.2

Step-by-step explanation:

Answer:

Step-by-step explanation:

I = prt

I = 800 × 1.8% x 15

I = $216

Remember the percent sign for the rate or write it as a decimal (multiplier)! In this case the multiplier would be 0.018!

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The length of the rectangular prism is 20 meters.

1. We know that the volume of a rectangular prism is given by the formula V = lwh, where l represents the length, w represents the width, and h represents the height.

2. In this case, we are given that the width (w) is 16 meters and the height (h) is 19 meters. The volume (V) is given as 6,049.6 cubic meters.

3. Plugging the given values into the volume formula, we have 6,049.6 = l * 16 * 19.

4. To find the length (l), we need to isolate it on one side of the equation. Dividing both sides of the equation by (16 * 19), we get l = 6,049.6 / (16 * 19).

5. Evaluating the expression on the right-hand side, we have l = 6,049.6 / 304.

6. Simplifying the division, we find l = 20 meters.

Therefore, the length of the rectangular prism is 20 meters.

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The nation of Border Kingdom can produce 300 bottles of high-quality wine per hour if it forgoes producing 8k televisions, while it can produce 60 8k televisions per hour if it forgoes producing wine.

The neighboring country of Coastal Realm, on the other hand, can produce 150 bottles of high-quality wine per hour if it forgoes producing 8k televisions, or it can produce 50 8k televisions per hour if it forgoes producing wine. The opportunity costs of producing the two goods are constant in both nations.

Opportunity cost is the value of the best alternative forgone when an economic choice is made. In this scenario, the opportunity cost of producing one bottle of high-quality wine in Border Kingdom is equal to 1/60 8k television, while the opportunity cost of producing one bottle of high-quality wine in Coastal Realm is equal to 1/50 8k television. Therefore, the Border Kingdom has a comparative advantage in producing wine as its opportunity cost of producing wine is lower compared to Coastal Realm. Similarly, Coastal Realm has a comparative advantage in producing 8k televisions as its opportunity cost of producing 8k televisions is lower compared to Border Kingdom.

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The table layout and relationship structure of a relational database is called its schema.

A schema in a relational database refers to the overall structure and organization of tables, their attributes (columns), and the relationships between them. It defines the blueprint for how the data is organized and stored in the database.

The schema includes information such as the table names, column names, data types, constraints, and the relationships established through keys (such as primary keys and foreign keys). It provides a logical representation of the database structure and helps ensure data integrity and consistency.

The schema serves as a guide for creating, modifying, and querying the database tables. It defines the structure that enforces rules and relationships between tables, facilitating data manipulation and retrieval.

By designing a well-defined schema, database administrators and developers can establish the foundation for efficient data storage, retrieval, and management within a relational database system.

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Answer:

If you're a freshman then you're required to attend the orientation

Step-by-step explanation:

Given

Statement: All freshman are required to attend orientation.

Required

Write as an if-then form

First, we need to split the given statement

1: All freshman

2: Attend orientation.

Next, is to convert to if-then:

If you're a freshman then you're required to attend the orientation

Answer:

the answer is 1100

Step-by-step explanation:

you will do... 5500*20/100

The value of the fourth term f(4) in the sequence is 0

From the question, we have the following parameters that can be used in our computation:

If f(1) = 2, f(2) = 4

f(n)=2f (n - 1) - 2f (n - 2)

Using the given recursive formula, we can find the value of f(3) and f(4) by working backwards:

f(3) = 2f(2) - 2f(1) = 2(4) - 2(2) = 8 - 4 = 4

f(4) = 2f(3) - 2f(2) = 2(4) - 2(4) = 8 - 8 = 0

Therefore, f(4) = 0.

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Answer:

42.85%

Step-by-step explanation:

Given that,

The polar exhibit at the zoo has only penguins and seals. There are 14 penguins for every 6 seals.

The percentage is given by :

\(\%=\dfrac{6}{14}\times 100\\\\=42.85\%\)

So, 42.85 % of exhibit are seals.

Answer:

C And D!

Step-by-step explanation:

Answer: I think it’s A (x + 4 = 14) I’m not sure though

The statement, When two events are disjoint, they are also independent is false.

In a sample space, we can use probability laws to determine the probabilities of these events and how they relate to each other. Disjoint Events: Two events are non-overlapping or mutually exclusive if they have no common outcome. Mathematically, this can be written as, P(B ∩ A) = 0 --(1)

Independent Events: Events are independent when they do not "affect" the probability of another event occurring. Mathematically written as:

P(B/A) = P(B) P(A and B)

=> P(B ∩ A) = P(B) × P(A) --(2)

(1) ) and (2) events cannot be independent unless they overlap. That is, if events do not overlap, they are also dependent. Hence, disjoint events are not independent that means the above statement is false.

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Answer:

Step-by-step explanation:

2x+15+x+10+3x+5=180 degree(sum of interior angles of a triangle)

6x+30=180

6x=180-30

x=150/6

x=25

therefore the value of x is 25 degree.

Answer: 80 + 65x ≤ 425

Step-by-step explanation: I took the test and got it right

also make sure it is the same problem.

I promise it is right! Good luck!!! ;)

Answer:c

Step-by-step explanation:did the test

Given, There are 4 boxes in total. A book is to be selected from one of the boxes. The probability of selecting a book from a box can be represented as P(Maths) = 3xP(Chem)P(Chem) = 2xP(Bio)P(Bio) = P(Phy)

Required:  Probability of being taken out for each subject: Let the total probability be equal to 1. Thus, P(Maths) + P(Chem) + P(Bio) + P(Phy) = 1We know, P(Chem) = 2xP(Bio) [Given]and, P(Bio) = P(Phy) [Given]Putting the values, P(Maths) + 2P(Bio) + P(Bio) + P(Bio) = 1 => P(Maths) + 4P(Bio) = 1. We need to find P(Maths), P(Chem), P(Bio) and P(Phy). Therefore, we need one more equation to solve for all the variables. Let's consider a common multiple of all the probabilities such as 12. So, P(Maths) = 9/12P(Chem) = 3/12P(Bio) = 1/12P(Phy) = 1/12. The probability that Mathematics or Biology is taken out by the student: P(Maths or Bio) = P(Maths) + P(Bio) = 9/12 + 1/12 = 10/12 = 5/6 = 0.83 or 83%2.

Given, Events A and B are mutually exclusive. So, P(A ∩ B) = 0.P(A) = 0.4P(B) = 0.5 (i) P(A U B) = P(A) + P(B) - P(A ∩ B) = 0.4 + 0.5 - 0 = 0.9 (ii) P(AC) = 1 - P(A) = 1 - 0.4 = 0.6 and (iii) P(AC ∩ B) = P(B) - P(A ∩ B) [As A and B are mutually exclusive] = 0.5 - 0 = 0.5 Therefore, P(AC ∩ B) = 0.5

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1. (i)The probability of being taken out for each subject is 1/7

(ii). The probability of math or biology taken out by the student is 4/7

2. (i)The probability of the event P(AUB) is 0.9

(ii) The probability of the event P(AC) is 0.6

(iii) The probability of the event P(AC n B) is 0

1. i. To find the probability of each subject being taken out, we can assign probabilities to each subject category based on the given information.

Let's denote the probabilities as follows:

P(M) = Probability of taking out a math book

P(C) = Probability of taking out a chemistry book

P(B) = Probability of taking out a biology book

P(P) = Probability of taking out a physics book

From the given information, we have:

P(M) = 3P(C)  (Math book is three times more likely than a chemistry book)

P(C) = 2P(B)  (Chemistry book is twice as likely as biology)

P(B) = P(P)  (Biology and physics are equally likely)

We can assign a common factor to the probability of taking out a biology book, say k. Therefore:

P(M) = 3k

P(C) = 2k

P(B) = k

P(P) = k

Next, we can find the value of k by summing up the probabilities of all subjects, which should equal 1:

P(M) + P(C) + P(B) + P(P) = 3k + 2k + k + k = 7k = 1

k = 1/7

Now, we can calculate the probabilities for each subject:

P(M) = 3k = 3/7

P(C) = 2k = 2/7

P(B) = k = 1/7

P(P) = k = 1/7

ii. To calculate the probabilities that Mathematics or Biology is taken out, we can simply sum up their individual probabilities:

P(Mathematics or Biology) = P(M) + P(B) = 3/7 + 1/7 = 4/7

2. i. Since events A and B are mutually exclusive, their union (A U B) means either event A or event B occurs, but not both. In this case, P(A U B) is simply the sum of their individual probabilities:

P(A U B) = P(A) + P(B) = 0.4 + 0.5 = 0.9

ii. The complement of event A (AC) represents the event "not A" or "the complement of A." It includes all outcomes that are not in event A. The probability of the complement can be found by subtracting the probability of A from 1:

P(AC) = 1 - P(A) = 1 - 0.4 = 0.6

iii. Since events A and B are mutually exclusive, their intersection (AC n B) means both event A and event B cannot occur simultaneously. In this case, the probability of their intersection is 0, because if event A occurs, event B cannot occur, and vice versa:

P(AC n B) = 0

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The storm rainfall flux is 0.00127 m2/hr, 1.27 kg liquid water/m2hr, 2.8 lb liquid water/m2hr, 1.27 liters liquid water/m2hr, and 0.335 gallons liquid water/m2hr. The amount of liquid water fell on the garden is 80.6 L, 21.3 gallons.

Dimensions of outdoor vegetable garden = 2 m × 2 m

Storm rainfall = 0.8 inches of rain

Time of storm = 1 hr(

a) The rainfall flux is the amount of rainfall per unit area and unit time. It is given as:

Rainfall flux = (Amount of rainfall) / (Area × Time)

Given the area of the garden is 2 m × 2 m, and the time is 1 hr, the rainfall flux is:

Rainfall flux = (0.8 inches of rain) / (2 m × 2 m × 1 hr)

Converting inches to meters, we get:

1 inch = 0.0254 m

Therefore,

Rainfall flux = (0.8 × 0.0254 m) / (2 m × 2 m × 1 hr) = 0.00127 m/hr

Converting the rainfall flux to other units:

In kg/hr:

1 kg of water = 1000 g of water

Density of water = 1000 kg/m3

So, 1 m3 of water = 1000 kg of water

So, 1 m2 of water of depth 1 m = 1000 kg of water

Therefore, 1 m2 of water of depth 1 mm = 1 kg of water

Therefore, the rainfall flux in kg/hr = (0.00127 m/hr) × (1000 kg/m3) = 1.27 kg/m2hr

In lbs/hr:

1 lb of water = 453.592 g of water

So, the rainfall flux in lbs/hr = (0.00127 m/hr) × (1000 kg/m3) × (2.20462 lb/kg) = 2.8 lbs/m2hr

In liters/hr:

1 m3 of water = 1000 L of water

So, 1 m2 of water of depth 1 mm = 1 L of water

Therefore, the rainfall flux in L/hr = (0.00127 m/hr) × (1000 L/m3) = 1.27 L/m2hr

In gallons/hr:

1 gallon = 3.78541 L

So, the rainfall flux in gallons/hr = (0.00127 m/hr) × (1000 L/m3) × (1 gallon/3.78541 L) = 0.335 gallons/m2hr

(b) To calculate the amount of water that fell on the garden, we need to calculate the volume of water.

Volume = Area × Depth.

The area of the garden is 2 m × 2 m.

We need to convert the rainfall amount to meters.

1 inch = 0.0254 m

Therefore, 0.8 inches of rain = 0.8 × 0.0254 m = 0.02032 m

Volume of water = Area × Depth = (2 m × 2 m) × 0.02032 m = 0.0806 m3

Converting the volume to other units:

In liters:

1 m3 of water = 1000 L of water

Therefore, the volume of water in liters = 0.0806 m3 × 1000 L/m3 = 80.6 L

In gallons:

1 gallon = 3.78541 L

Therefore, the volume of water in gallons = 80.6 L / 3.78541 L/gallon = 21.3 gallons.

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Step-by-step explanation:

x = ??

y = 72 + 40 = 112

x =112 - 180

x = 180-112

x = 68

or = 180 - 72 = 108

180 - 40 = 140

140 - 108 = 32