Answer:
A 40 Watt bulbtransfers energy to light and heat at a rate of 40 Joules per second.
Explanation:
What happens to the force of gravity between two masses if the mass of one of the objects decreases?
The force of gravity also increases
The force of gravity stays the same
The force of gravity decreases
none of these apply
It increases
Explanation:
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between object
Answer:
C: Gravity decreases
Explanation:
D 4.8
This is a harder question based on the Law of Conservation of Momentum. Take the time to work
your way through it. Start with a diagram.
A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the
east with a velocity of 150 m s². A 100 kg piece moves off with a velocity of 200 m s at a direction of
south 60° west. What is the velocity of the third piece?
It is possible
The velocity of the third piece is v₃ = -12500 kg·m/s / m₃
How do we calculate?The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.
velocity of the third piece = v₃.
The total initial momentum before the explosion = 0
The total final momentum after the explosion= 0
Initial momentum = 0 kg·m/s (since the bomb is at rest)
Final momentum = m₁v₁ + m₂v₂ + m₃v₃
m₁ = mass of the first piece = 150 kg
v₁ = velocity of the first piece = 150 m/s (to the east)
m₂ = mass of the second piece = 100 kg
v₂ = velocity of the second piece = 200 m/s (south 60° west)
m₃ = mass of the third piece = unknown
v₃ = velocity of the third piece = unknown
0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)
final momentum = 0 and hence v₃ is found as :
0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)
-12500 kg·m/s = (m₃)(v₃)
v₃ = -12500 kg·m/s / m₃
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A cockroach of mass m lies on the rim of a uniform disk of mass 5m that can rotate freely about its center like a merry-go-round. Initially the cockroach and disk rotate together with an angular speed of 0.26 rad/s. Then the cockroach walks half-way to the center of the disk.A. What is the angular speed of the cockroach-disk system after the cockroach walks to its final position? B. What is the ratio Kf/Ki of the new rotational kinetic energy of the system to its initial rotational kinetic energy?
Given data:
The mass of cockroch is m.
The mass of disk is 5m.
The initial speed of cockroch and disk is ω=0.26 rad/s.
Considering the radius of the disk is r, then the halfway radius of the disk will be r/2.
Part (a)
The final angular velocity can be calculated as,
\(\begin{gathered} (I+I)\omega=(I+I)_{final}\omega^{\prime} \\ (mr^2+\frac{1}{2}5mr^2)0.26=(m(\frac{r}{2})^2+\frac{1}{2}5m(\frac{r}{2})^2)\omega^{\prime} \\ 0.91=0.875\omega^{\prime} \\ \omega^{\prime}=1.04\text{ rad/s} \end{gathered}\)Thus, the final speed is 1.04 rad/s.
Part (b)
The ratio of kinetic energy can be calculated as,
\(\begin{gathered} \frac{K_f}{K_i}=\frac{\frac{1}{2}(I+I)_{final}\omega^2}{\frac{1}{2}(I+I)\omega^2} \\ \frac{K_f}{K_i}=\frac{\frac{1}{2}(m(\frac{r}{2})^2+\frac{1}{2}5m(\frac{r}{2})^2_{})(1.04)^2}{\frac{1}{2}(mr^2+\frac{1}{2}5mr^2)(0.26)^2} \\ \frac{K_f}{K_i}=7.42 \end{gathered}\)Thus, the ratio of kinetic energy is 7.42.
A pencil rolls across a table toward its edge. In one to two sentences, explain which direction the pencil will move once it leaves the table and why.
Answer:
it won't move unless it has momentum
Explanation:
An apple is thrown at an angle of 30° above the horizontal from the top of a building 20 m high. Its initial speed is 40 ms-1. Calculate
a)the time taken for the apple to strikes the ground
b) the distance from the foot of the building will it strikes the ground
c) the maximun height reached by the apple from the ground
Answer:
(a) 4.83 seconds
(b) 167.3m
(c) 40m
Explanation:
This is a two-dimensional motion. Therefore, the components of the initial velocity - \(u_X\) and \(u_Y\) - in the x and y directions are given as follows:
\(u_X\) = u cos θ --------------(*)
\(u_Y\) = u sin θ -------------(**)
Where
θ = angle of projection
(a) To calculate the time taken for the apple to strike the ground.
For simplicity, let's first calculate the maximum height H reached by the apple.
Using one of the equations of motion as follows, we can find H:
v² = u² + 2as ---------------(i)
Where;
v = velocity at maximum height = 0 [at maximum height, velocity is 0]
u = initial vertical velocity of the apple = \(u_Y\)
=> u = \(u_Y\) = u sin θ
=> \(u_Y\) = 40 sin 30°
=> \(u_Y\) = 40 x 0.5
=> \(u_Y\) = 20 m/s
a = acceleration due to gravity = -g [apple moves upwards against gravity]
a = -10m/s²
s = H = maximum height reached from the top of the building
Substitute these values into equation (i) above to have;
0² = \(u_Y\)² + 2aH
0² = (20)² + 2(-10)H
0 = 400 - 20H
20H = 400
H = 20m
The total time taken to strike the ground is the sum of the time taken to reach maximum height and the time taken to strike the ground from maximum height.
=>Calculate time t₁ to reach maximum height.
Using one of the equations of motion, we can calculate t₁ as follows;
v = \(u_Y\) + at ---------------(ii)
Where;
v = velocity at maximum height = 0
u = initial vertical velocity of the apple = \(u_Y\)
a = -g = -10m/s² [acceleration due to gravity is negative since the apple is thrown upwards to reach maximum height]
t = t₁ = time taken to reach maximum height.
Equation (ii) then becomes;
0 = 20 + (-10)t₁
10t₁ = 20
t₁ = 2 seconds
=>Calculate time t₂ to strike the ground from maximum height.
Now, using one of the equations of motion, we can calculate the time taken as follows;
Δy = \(u_Y\) t + \(\frac{1}{2}\)at ---------------(iii)
Where;
Δy = displacement from maximum height to the ground = maximum height from top of building + height of building = 20 + 20 = 40m
a = g = 10m/s² [acceleration due to gravity is positive since the apple is now coming downwards from maximum height]
t = t₂ [time taken to strike the ground from maximum height]
\(u_Y\) = initial vertical velocity from maximum height = 0
\(u_Y\) = 0
Equation (iii) then becomes
40 = 0t + \(\frac{1}{2}\)(10)t₂²
40 = 5t₂² [divide through by 5]
8 = t₂²
t₂ = ±\(\sqrt{8}\)
t₂ = ±\(2\sqrt{2}\)
t₂ = +2\(\sqrt{2}\) or -2\(\sqrt{2}\)
since time cannot be negative,
t₂ = 2\(\sqrt{2}\) = 2.83 seconds
Therefore, the time taken for the apple to strike the ground is;
t₁ + t₂ = 2 + 2.83 = 4.83 seconds
(b) The distance from the foot of the building where the apple will strike the ground
Since this is the horizontal distance, we use the horizontal version of equation (iii) as follows;
Δx = \(u_X\) t + \(\frac{1}{2}\)at -----------(v)
Where
Δx = distance from the foot of the building to where the apple strikes the ground.
\(u_X\) = initial horizontal velocity of the apple as expressed in equation (*)
\(u_X\) = 40 cos 30
\(u_X\) = 34.64 m/s
t = time taken for the motion of the apple = 4.83 seconds [calculated above]
a = acceleration due to gravity in the horizontal direction = 0. [For a projectile, there is no acceleration in the horizontal direction since velocity is constant]
Substitute these values into equation (v) as follows;
Δx = \(u_X\) t + \(\frac{1}{2}\)(0)t
Δx = 34.64 x 4.83
Δx = 167.3 m
Therefore, the distance from the foot of the building is 167.3m
(c) The maximum height reached by the apple from the ground
This is the sum of the height reached from the top of the building (20m which has been calculated in (a) above) and the height of the building.
= 20m + 20m = 40m
Which statement correctly identifies the scientific question and describes why the question is scientific?
Answer:
i had this question as well!
Explanation:
Answer:
1. to the Mystic 2. A Theme or social value 3. Something that can be valued 4. Can’t be observed/ Noticed.
Explanation:
What does g stand for
Group of answer choices
gravity
The acceleration of gravity
The force of gravity
Answer:
the acceleration of gravity.
Answer:
g stand for the acceleration of gravity .
Explanation:
As the distance between the sun and earth decreases, the gravity force between them
a
Increases
b
decreases
c
stays the same
Answer:
a increases
Explanation:
as distance between two objects increases the gravitational force decreases so when distance decreases the gravitational force increases
The question is in the screenshot
Answer:
40.0
Explanation:
\(\int^{10}_{2} f(x) \text{ } dx \approx 2f(2)+3f(4)+2f(7)+f(9) \\ \\ =2(0)+3(3)+2(8)+15 \\ \\ =0+9+16+15 \\ \\ =40\)
PLEASE HELP! THIS IS TO BE TURNED IN IN ABOUT 3 MINUTES!!!!!!!
How must the net force be acting on an object in order for the object to have a circular motion? What is this type of force called?
the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. what is the radius of the moon? please show work.
Answer:
1737 kilometers
In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00 102 m distance in 9.5 s. Assuming that he ran with a constant speed equal to his average speed, and his kinetic energy was 3.40 103 J, what was Burrell’s mass?
Answer:
61.33 Kg
Explanation:
From the question given above, the following data were obtained:
Distance = 1×10² m
Time = 9.5 s
Kinetic energy (KE) = 3.40×10³ J
Mass (m) =?
Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:
Distance = 1×10² m
Time = 9.5 s
Velocity =?
Velocity = Distance / time
Velocity = 1×10² / 9.5
Velocity = 10.53 m/s
Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:
Kinetic energy (KE) = 3.40×10³ J
Velocity (v) = 10.53 m/s
Mass (m) =?
KE = ½mv²
3.40×10³ = ½ × m × 10.53²
3.40×10³ = ½ × m × 110.8809
3.40×10³ = m × 55.44045
Divide both side by 55.44045
m = 3.40×10³ / 55.44045
m = 61.33 Kg
Thus, the mass of Leroy Burrell is 61.33 Kg
What is activated by the sympathetic system?
1. The digestive system
2. The "rest and digest" response
3. O The "fight or flight" response
4. The "breed and feed" response
Answer:
1 the digestive system thats all
the distance that a body in free fall falls each second is
a. is about 9.8m
b. is about 19.6m
c. increases as time passes
d. none of the above are correct
The distance that a body in free fall falls each second is (A). is about 9.8m is correct option.
The distance that a body in free fall falls each second is about 9.8 meters, which is equivalent to the acceleration due to gravity on the Earth's surface.
This means that in the absence of air resistance, an object dropped from a certain height will fall 9.8 meters during the first second, 19.6 meters during the second second, 29.4 meters during the third second, and so on. The distance increases as time passes, but not at a constant rate, as it is being affected by the acceleration due to gravity.
Therefore, the correct option is (a) .
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what is an emergent curriculum
Answer:
Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.
The Short Answer:
Earth's tilted axis causes the seasons. Throughout the year, different
parts of Earth receive the Sun's most direct rays. So, when the North
Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And
when the South Pole tilts toward the Sun, it's qvinter in the Northern
Hemisphere.
1. What direction is the Earth tilted in the summer here in
Buffalo?
a) towards the Sun
b) away from the Sun
23.5
Answer:
I cannot fully see the picture, but I'm going to have to tell you to go with towards the sun because it says summer.
A dielectric block such as shown in Fig. P5.1 is uniformly polarized. The polarization is P. Find the polarization charge density , on the faces 1, 2, and 3. (Find both magnitude and sign of the charge.) P Fig. P5.1
The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
Thus, A dielectric is considered to be polarized when its molecules acquire an electric dipole moment when exposed to an external electric field.
Electric polarization of the dielectric is the term used to describe the electric dipole moment induced per unit volume of the dielectric material.
The forces that emerge from these interactions can be calculated using the polarization density, which also defines how a material reacts to an applied electric field and how it modifies the electric field. It is comparable to magnetization, which measures a material's equivalent response.
Thus, The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
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these 14 PLEse thanks
The spaces labeled 1 through 14 in the diagram using the following terms are:
mantlelithospheric platerift valleyocean floormidocean ridgemountain rangepartially molten rock becomes new ocean floortrenchocean floorlithospheric platecontinentold ocean floor becomes partially molten rocklithospheric plate "conveyer belts"What are plate tectonics?Plate tectonics is the scientific theory that explains the large-scale motions of Earth's lithosphere (the outermost layer of the Earth) and the processes that cause these motions. The lithosphere is divided into a number of large plates that move relative to each other over the asthenosphere, the more plastic, ductile, and weaker layer below the lithosphere.
Plate tectonics explains a variety of geologic phenomena, including the formation of mountains, earthquakes, volcanoes, and the distribution of continents and oceans. According to this theory, the lithospheric plates move due to the motions of convection cells in the Earth's mantle, which is the layer below the asthenosphere.
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If a bus is traveling at 12m/s and a passenger on the bus is walking to the back of the bus at a velocity of 5m/s, what is the relative velocity of the passenger relative to the ground?
The relative velocity is 17m/s.
The relative velocity of the passenger relative to the ground can be found by applying the concept of relative motion.
speed of bus (vb)=12m/s
speed of passenger inside the bus(vp)= 5m/s opposite to the speed of bus
speed of passenger relative to the ground = v
v= vb+vp
v= 12+(-5), since passenger is traveling in opposite direction
v=7m/
Therefore, the velocity of passenger relative to the ground is 7m/s.
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Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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10. Jane puts the north pole of a bar magnet near an object on her desk. As the magnet gets
closer to the object; the object is repelled and moves away from the magnet. Which of the
following statements about the object on Jane's desk is true?
a. The object is not made of metal.
b. The object has randomly-arranged domains.
c. The object has a north pole but no south pole.
d. The object is a magnet or has been magnetized.
Answer: D
Explanation: because
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Brainlist!! Help!! The nucleus contains protons and neutrons. Being positively charged, the protons repel each other. The nucleus should fly apart due to the repulsive force. Yet, the nuclei of most atoms are stable - explain.
Answer:
The reason that the nucleus of most atoms does not fall apart despite the oppositely charged protons exerting a repulsive force on each other is the strong nuclear force.
What is the strong nuclear force?The strong nuclear force is one of the fundamental forces in nature that acts between protons and neutrons in the atomic nucleus. It is a short-range force that is much stronger than the electromagnetic force (which produces the repulsion between protons).
The strong nuclear force is responsible for holding the nucleus together.
Additionally, the ratio of protons to neutrons in a nucleus also affects its stability. Therefore, if there is an imbalance in this ratio, the repulsive force between the protons can become too strong, causing the nucleus to become unstable and undergo radioactive decay.
Overall, the nucleus remains stable due to the balance between the strong nuclear force and the repulsive force between the protons.
A 0.21 kg apple falls from a tree to the ground 4.0m below. Ignoring air resistance, determine the apple's kinetic energy, the gravitational potential energy, and the total mechanical energy of the system when the apple’s height above the ground is 3.0m.
Given :
Mass of the apple (m): 0.21 kgHeight of the apple above the ground at the start (initial height) (h1): 4.0 mHeight of the apple above the ground at the end (final height) (h2): 3.0 mAcceleration due to gravity (g): 9.81 m/s^2To Find :
The falling apple's kinetic energy, gravitational potential energy, and total mechanical energy.
Solution :
We can use the conservation of energy principle to find the apple's kinetic energy, gravitational potential energy, and total mechanical energy at the height of 3.0m above the ground.
First, we need to find the gravitational potential energy (GPE) of the apple when it is at the height of 4.0m above the ground:
GPE = mgh
where m is the mass of the apple, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground.
So, GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) = 8.2266 J
Next, we find the apple's kinetic energy (KE) just before it hits the ground. We can use the conservation of energy principle, "which states that a system's total mechanical energy is conserved (i.e., it remains constant) if no external forces are acting on it." In this case, gravity is the only force acting on the apple, an internal force within the system (i.e., the apple and the Earth).
So, at the height of 3.0m above the ground, the total mechanical energy (TME) of the system is:
TME = GPE + KE
Since the apple is falling freely, we can assume that all of its potential energy at the height of 4.0m has been converted into kinetic energy just before it hits the ground. Therefore, at the height of 3.0m above the ground, the GPE is:
GPE = (0.21 kg) x (9.81 m/s^2) x (3.0 m) = 6.1359 J
Using the conservation of energy principle, we can find the kinetic energy just before the apple hits the ground:
TME = GPE + KE
KE = TME - GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) - 6.1359 J = 2.0907 J
Therefore, the kinetic energy of the apple just before it hits the ground is 2.0907 J.
To summarize:
Gravitational potential energy (GPE) of the apple at a height of 4.0m above the ground: 8.2266 J
Gravitational potential energy (GPE) of the apple at a height of 3.0m above the ground: 6.1359 J
Kinetic energy (KE) of the apple just before it hits the ground: 2.0907 J
The system's total mechanical energy (TME) is conserved throughout the fall.
It's a physics question about resistance
Pls help
The picture of the question is down below
A. We deduce here that the resistance of the copper wire at 20°C is 7.58 Ω.
B. The new temperature = 20.833°C.
How we arrived at the solution?The resistance of a wire is:
R = ρL/A
where:
R is the resistance in ohms
ρ is the resistivity of the material in ohm-meters = 1.72 x 10-8 Ωm
L is the length of the wire in meters = 200 m
A is the cross-sectional area of the wire in square meters = πr² = π(0.25 mm)² = 4.909 x 10^-7 m²
Thus,
R = 1.72 x 10-8 Ωm x 200 m / 4.909 x 10^-7 m² = 7.58 Ω
B. The new temperature:
The temperature coefficient of resistance (α) is a measure of how much the resistance of a material changes with temperature.
For aluminum, α = 0.0039/°C. This means that for every 1°C increase in temperature, the resistance of aluminum increases by 0.0039 Ω.
T = 20°C + (900 Ω - 600 Ω) / 600 Ω α
T = 20°C + (300 Ω) / (600 Ω) (0.0039/°C)
T = 20°C + 0.0065°C
T = 20.833°C
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A sample from a meteorite that landed on Earth has been analyzed, and the result shows that out of every 1,000 nuclei of potassium-40 originally in the meteorite, only 250 are still present, meaning they have not yet decayed. How old is the meteorite (in yr)?
PLEASE ANSWER WITH ACTUAL ANSWER AND I WILL MARK BRAINLIEST (IF YOU GIVE ME A SCAMMY ANSWER I WILL REPORT YOU!!!)
A student wants to determine the local value of the gravitational field strength, g , in their classroom. Which of the following experimental set-ups would allow a student to calculate the magnitude of the gravitational field strength using only the quantities measured?
Select TWO answers.
A: Run a lab cart down an inclined plane; measure the length of the ramp and the time it takes the cart to reach the bottom.
B: Hang a known mass from a spring scale; measure the spring scale reading when the mass is at rest.
C: Accelerate a lab cart horizontally; measure the mass of the cart and its acceleration.
D: Drop a heavy metal ball; measure the drop height and the time it takes the ball to hit the ground.
Answer:
Most likely (B)
Explanation:
B in the passage is the most representative out of all your choices and it has evidence from the passage
Hope dis helps Jit!
Sorry i forgot to type C
B and C both measure mass while the others are calculations and are bias
The following experimental set-ups would allow a student to calculate the magnitude of the gravitational field strength using only the quantities measured:
Hang a known mass from a spring scale; measure the spring scale reading when the mass is at rest.Drop a heavy metal ball; measure the drop height and the time it takes the ball to hit the ground.What is gravitational field?A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies.
When a known mass from a spring scale is hung; by e; measuring the spring scale reading when the mass is at rest, the magnitude of the gravitational field strength ( reading/mass) can be calculated.
When a heavy metal ball is dropped, by measuring e the drop height and the time it takes the ball to hit the ground, the magnitude of the gravitational field strength ( h = gt²/2) can be calculated. Hence, option (B) and option (D) is correct.
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A 20-Kg child is on a swing attached to 3.0 m-long chains. The child swings back and forth, swinging out to a 60-degree angle. (This is the angle that the chains make with the vertical.) What is the childs maximum speed on the swing
Answer:
v = 29.4 m / s
Explanation:
For this exercise we can use the conservation of mechanical energy
Lowest starting point.
Em₀ = K = ½ m v²
final point. Higher
\(Em_{f}\) = U = m g h
Let's use trigonometry to lock her up
cos 60 = y / L
y = L cos 60
Height is the initial length minus the length at the maximum angle
h = L - L cos 60
h = L (1- cos 60)
energy is conserved
Em₀ = Em_{f}
½ m v² = mgL (1 - cos 60)
v = 2g L (1- cos 60)
let's calculate
v² = 2 9.8 3.0 (1- cos 60)
v = 29.4 m / s
A moon orbits an isolated planet in deep space. Which of the following forces that the planet exerts on the moon can be considered as negligible?
A. The electric force
B. The force due to gravity
C. Both the electric force and the force due to gravity
D. Neither the electric force nor the force due to gravity
Answer:
A
Explanation:
electric force
The electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.
The given problem is based on the comparison between the gravitational force and electrostatic force. Consider the two bodies as moon and a planet such that the force exerted between the moon and the planet is given as,
\(F_{g}=\dfrac{G\times M \times m}{r^{2}}\) ..................................................(1)
Here, G is the gravitational constant, M is the mass of moon, m is the mass of planet and r is the distance between the moon and the planet.
And the electrostatic force is the force between the two charged entities on moon and the planet. So, it is given as,
\(F_{e}=\dfrac{k \times Q \times q}{r^{2}}\) ....................................................(2)
Here, k is the Coulomb's constant, Q is the charge entity at moon and q is the charged entity on planet.
The forces obtained in equation (1) and (2) depends on the masses and charges, which clearly signifies that the masses have more numerical value than charges, hence the electrostatic force will leave much lesser influence than gravitational force. So, it can be neglected.
Thus, we conclude that the electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.
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the temperature at which the velocity of sound in air is twice its velocity at 15°C
With the use of below formula, at 879 °C, velocity will be double the velocity at 15 °C.
What is the relationship between Velocity and sound ?The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K\(\sqrt{T}\)
Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;
(v2/v1) = √(T2 / T1)
Where
v2 = final velocityv1 = initial velocityT2 = final absolute temperatureT1 = initial temperature.Recall that absolute temperature = °C + 273.
If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,
Temperature in Kelvin K = 15 + 273 = 288
Substitute all the parameters into the formula
(2 × v1)/v1 = √(T2/288)
2 = √ (T2 /288)
Square both sides
4 = (T2/288)
T2 = 4 × 288
T2 = 1152K
Temperature in degrees Celsius = 1152 - 273 = 879 °C.
Therefore, at 879 °C, velocity will be double the velocity at 15 °C.
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