How much work, in foot-pounds, is done when a 45-foot long cable with a weight-density of 7 pounds per foot is wound up 34 feet

The solution is a discrete value or values, not a range of solutions. The solution value(s) of x is/are -1, 1.

a. To find all integers x satisfying x is positive, we know that positive integers are greater than zero. Therefore, the correct choice is:

OC. All positive integers satisfy this condition.

b. To find all integers x satisfying x is negative, we know that negative integers are less than zero. Therefore, the correct choice is:

OC. All negative integers satisfy this condition.

c. To find all integers x satisfying x - 8 is positive, we need to consider that positive numbers are greater than zero. So we solve the inequality:

x - 8 > 0

Adding 8 to both sides:

x > 8

Therefore, all integers greater than 8 satisfy this condition. The correct choice is:

OB. All integers greater than 8 satisfy this condition.

d. To find all integers x satisfying |x| = 1, we need to consider that |x| represents the absolute value of x, which means it is the distance of x from zero. The only integers whose distance from zero is 1 are -1 and 1. Therefore, the correct choice is:

OB. The solution is a discrete value or values, not a range of solutions. The solution value(s) of x is/are -1, 1.

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Answer: d.

Step-by-step explanation:

each shirt costs 12.25

Total bit strings of length are 512.

What is bit ?

In each computing and digital communications, the bit is that the most elementary unit of information. The word could be a combination of 2 binary digits. A logical state with one amongst 2 potential values is portrayed by the bit.

Main body:

1 bit: 2 strings: 0, 1

2bit: 4 strings: 00, 01, 10, 11

3bit: 8 strings: 000, 001, 010, 011, 100, 101, 110, 111

4bit: 16 strings: 0000,0001,0010, 0011, 0100, 0101, 0110, 0111, 1000, 1001. 1010, 1011, 1100, 1101, 1110, 1111

5bit: 32 strings

6bit: 64 strings

7bit: 128 strings

8bit: 256 strings

9 bits: 512 strings

OR this can be done by

Each bit has 2 possible values, so a string of length 9 has 2⁹ = 512 possible values.

Hence total bit sting are 512.

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The value of x in the parallel lines is 11.2.

The value of x in the given parallel lines is calculated by applying the congruent method.

length of side 5 ≡ length of side 7

length of side 8 ≡ length of side x

5 / 7 = 8 / x

5x = 8 (7)

5x = 56

x = 56 / 5

x = 11.2

Thus, the value of x in the parallel lines is determined by applying congruent theorem.

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The distance between the given points a (5, 3) and b (7, -4) is `sqrt[53]` or approximately 7.28 units.

To find the distance between the given points a (5, 3) and b (7, -4),

we can use the distance formula.

Distance formula: The distance formula is used to find the distance between two points in a plane.

It is given by;`d = sqrt[(x2 - x1)² + (y2 - y1)²]`

where, (x1, y1) and (x2, y2) are the coordinates of two points on a plane,

and d is the distance between the two points.

So, for points a (5, 3) and b (7, -4), let's substitute the values in the formula;

d = sqrt[(7 - 5)² + (-4 - 3)²]d = sqrt[2² + (-7)²]d = sqrt[4 + 49]d = sqrt[53]

Hence, the distance between the given points a (5, 3) and b (7, -4) is `sqrt[53]` or approximately 7.28 units.

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Answer:

4

Step-by-step explanation:

2+2=4

The equivalent form   \([latex] {{8}^{\frac{1}{3}}}[/latex]\)can be determined where the origin of the numerator of 1.

When rewriting a radical with a fractional exponent, the numerator is the power to which the radicand is increased, and the denominator is the root or index.

The link between \([latex] \sqrt[n]{{{a}^{m}}}[/latex]and [latex] {{a}^{\frac{m}{n}}}[/latex]\)also applies to rational exponents with a numerator of 1. For instance, the radical \([latex] \sqrt[3]{8}[/latex]\)

can also be expressed as \([latex] \sqrt[3]{{{8}^{1}}}[/latex]\).

Since any number retains its value when raised to the first power, [/latex]. Now that you have the equivalent form of \([latex] {{8}^{\frac{1}{3}}}[/latex]\), you can determine where the origin of the numerator 1.

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Answer:

V(t) = 14,000(0.89)^t  

Step-by-step explanation:

Present value of the Dodge Challenger = $14,000

Present percentage value = 100%

Depreciation value = 11%

Number of years = t

Future value = V(t)

V(t) = Present value of the Dodge Challenger(Present percentage value - Depreciation value)^t

= 14,000(100% - 11%)^t

= 14,000(89%)^t

= 14,000(0.89)^t

V(t) = 14,000(0.89)^t

Respuesta:

176

Explicación paso a paso:

Dado :

La frecuencia máxima del pulso que se debe mantener durante las actividades aeróbicas viene dada por:

0,88 (220-A); donde A = edad

Para una persona de 20 años

Supongamos que la edad es de 20 años; A = 20

Poniendo A = 20 en la ecuación;

0,88 (220 - A); A = 20

Frecuencia de pulso máxima:

0,88 (220 - 20)

0,88 (200)

= 176

La frecuencia de pulso máxima es 176

The simplified form of the expression -6w + (–8.3) + 1.5+ (–7w) is -13w - 6.8.

Given the expression in the question;

-6w + (–8.3) + 1.5+ (–7w)

To simplify, first remove the parenthesis

Note that;

-6w + × - 8.3 + 1.5 + × - 7w

-6w - 8.3 + 1.5 - 7w

Next collect and add like terms

-6w - 7w - 8.3 + 1.5

Add -6w and -7w

-13w - 8.3 + 1.5

Add -8.3 and 1.5

-13w - 6.8

Therefore, -13w - 6.8 is the simplified form.

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Answer:

30

Step-by-step explanation:

use calculator LOL

360 divided by 12 is 30.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Given;

Dividend=360

Divisor=12

Now

=360/12

=30

Therefore, by algebra answer will be 30.

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Answer:

       \(\frac{2}{7}\)

Step-by-step explanation:

3.5 = \(\frac{7}{2}\)

swap the numerator and denominator (flip the fraction):

reciprocal of \(\frac{7}{2}\) is \(\frac{2}{7}\)

The probability that one team wins in exactly five games assuming each team has an equal likelihood of winning each game is 0.29.

Algorithm World Series(n, p)

//Computes the odds of winning a series of n games

//Input: A number of wins n needed to win the series and probability p of one particular team winning a game

//Output: The probability of this team winning the series

q ← 1 − p

for j ← 1 to n do

P[0, j] ← 1.0

for i ← 1 to n do

P[i, 0] ← 0.0

for j ← 1 to n do

P[i, j] ← p ∗ P[i − 1, j] + q ∗ P[i, j − 1]

return P[n, n]

Both the time efficiency and the space efficiency are in Θ(n2) because each entry of the n + 1-by-n + 1 table (except P[0, 0], which is not computed) is computed in Θ(1) time

a. Let P(i, j) be the probability of A winning the series if A needs i more games to win the series and B needs j more games to win the series. If team A wins the game, which happens with probability p, A will need i − 1 more wins to win the series while B will still need j wins. If team A looses the game, which happens with probability q = 1 − p, A will still need i wins while B will need j − 1 wins to win the series.

This leads to the recurrence

P(i, j) = pP(i − 1, j) + qP(i, j − 1) for i, j > 0

The initial conditions follow immediately from the definition of P(i, j):

P(0, j)=1 for j > 0, P(i, 0) = 0 for i > 0

b. Here is the dynamic programming table in question, with its entries rounded-off to two decimal places. (It can be filled either row-by-row, or column-by-column, or diagonal-by-diagonal.)

i/jj 0  1      2     3     4

0       1      1     1     1

1    0  0.40  0.64  0.78  0.87

2    0  0.16  0.35  0.52  0.66

3    0  0.06  0.18  0.32  0.46

4    0  0.03  0.09  0.18  0.29

Thus, P[4, 4] ≈ 0.29.

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Complete question:

World Series Odds. [20 marks total] Consider two teams, A and B, playing a series of games until one of the teams wins n games. Assume that the probability of A winning a game is the same for each game and equal to p and the probability of A losing a game is q = 1 − p. (Hence, there are no ties.) Let P(i, j) be the probability of A winning the series if A needs i more games to win the series and B needs j more games to win the series.

(a) Set up a recurrence relation for P(i, j) that can be used by a dynamic programming algorithm. Hint: In the situation where teams A and B need i and j games, respectively, to win the series, consider the result of team A winning the game and the result of team A losing the game.

(b) Find the probability of team A winning a seven-game series if the probability of it winning a game is 0.4. Hint: Set up a table with five rows (0 ≤ i ≤ 4) and five columns (0 ≤ j ≤ 4) and fill it by using the recurrence derived in part (a).

(c) Write C/C++ pseudocode for a dynamic programming algorithm to solve this problem and determine its time and space efficiencies. Hint: Your pseudocode should be guided by the recurrence you set up in part (a).

Bonnie bought approximately 4 bags of chips and 14 cans of pop for a total cost of $17.50.

Let's assume the number of bags of chips Bonnie bought is x.

According to the given information, Bonnie bought ten more cans of pop than bags of chips. Therefore, the number of cans of pop Bonnie bought is x + 10.

We are also given that Bonnie spent $17.50 on these purchases.

Now, let's calculate the total cost of the bags of chips and cans of pop:

Cost of x bags of chips = x dollars

Cost of (x + 10) cans of pop = (x + 10) dollars

The total cost is the sum of the cost of bags of chips and cans of pop:

Total cost = x + (x + 10) = 2x + 10

According to the given information, the total cost is $17.50:

2x + 10 = 17.50

Subtracting 10 from both sides of the equation:

2x = 17.50 - 10

2x = 7.50

Dividing both sides by 2:

x = 7.50 / 2

x = 3.75

Therefore, Bonnie bought 3.75 bags of chips (which we'll assume is 4 bags since we can't have a fraction of a bag) and (3.75 + 10) = 13.75 (which we'll assume is 14 cans since we can't have a fraction of a can) cans of pop.

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A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).

Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.

As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt

Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.

For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:

E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.

Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:

dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt

where M is a martingale with M(0) = 0.

Thus, X(t) can be represented as an Itô process on [0,T] of the form:

X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds

Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.

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Answer:

Step-by-step explanation:

Multiply by x^2 on both sides

9x^2+27x+8=0

Factor.

The answers are -1/3, -8/3

Answer:

r,myp5\6t[

Step-by-step explanation:

Answer:

(y-6)/(4+r)=x

Step-by-step explanation:

y=4x+rx+6

y-6=4x+rx

y-6=x(4+r)

divide both sides by (4+r)

(y-6)/(4+r)=x

Answer:

1.25

Step-by-step explanation:

original price + markup = retail

The markup = original * markup percentage

original  + original * markup percent= retail

Factor out the original

original( 1+ markup percent) = retail

original ( 1 + 60%) = 2

Change to decimal form

original ( 1+ .60) = 2

original ( 1.60) = 2

Divide each side by 1.6

original = 2/1.6

original =1.25

Answer:

1.25

Step-by-step explanation:

Sue’s Corner Market has a markup of 60% on bottled water.So therefore an equation to represent this is original price + markup price = price after markup.Then divide both side by 1.6.(LMK if this help hopefully it does)

Answer:

3n+5

Step-by-step explanation:

3n + 5

There are no other like terms for 3n because no other value contains n.

Therefore 7 and -2 are like terms due to them both being constant whole number.

So subtract 2 from 7 and you will get five

Hence the answer is 3n + 5

Answer:

t = 10.5 minutes

Step-by-step explanation:

Curves on the graph show the distance covered by two runners during the first 21 minutes of a race.

These curves intersect each other at a point which shows a common location of both the runners on the graph.

This common point is at the mid of t = 9 and 12 seconds

Therefore, time at which both the runners passes the other will be,

t = \(9+\frac{12-9}{2}\)

 = 9 + 1.5

 = 10.5 minutes

Answer:

It's either 10.5 or 11

Step-by-step explanation:

The 90th percentile of the thermometer readings is approximately 1.282 degrees Celsius.

To find the 90th percentile of the thermometer readings, which are normally distributed with a mean of 0 degrees and a standard deviation of 1 degree Celsius, follow these steps:

1. Look up the z-score corresponding to the 90th percentile in a standard normal distribution table or use a calculator. The z-score for the 90th percentile is approximately 1.282.

2. Since the mean (µ) is 0 and the standard deviation (σ) is 1, use the z-score formula to find the temperature reading at the 90th percentile:

X = µ + z × σ.

3. Substitute the values:

X = 0 + 1.282 × 1.

4. Calculate the result:

X ≈ 1.282 degrees Celsius.

Thus, the 90th percentile of the thermometer readings is approximately 1.282 degrees Celsius.

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The required, there is no highest common factor between 4454 and 121j²k. None of the options are correct.

The highest common factor (HCF) of two or more numbers is the largest number that divides all of the numbers exactly.

Here,
To find the greatest common factor (GCF) of 4454 and 121j²k, we need to factor both numbers into their prime factors and then identify the common factors.

Since 4454 is an even number and 121 is an odd number so there is no prime highest common factor between the given number.

Thus, none of the options are correct.

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Step-by-step explanation:

four million seven hundred thousand can be written by

4,700,000

Answer:

x=0.7x+24

We move all terms to the left:

x-(0.7x+24)=0

We get rid of parentheses

x-0.7x-24=0

We add all the numbers together, and all the variables

0.3x-24=0

We move all terms containing x to the left, all other terms to the right

0.3x=24

x=24/0.3

x=80

And that's how you get 80

Step-by-step explanation:

i hope this helps.    :)

Answer: x = 80

Step-by-step explanation:

80 - 24 = 56

56 divided by 0.7 = 80

answer:

x^2 - 2 x + 4

explanation: you want to factor the expression using a^3 + b^3= (a+b) (a^2 - ab+b^2)

then

(x,2) x (x^2 - 2x+4)

_________________

           x+2

then reduce so,

(x+2) x (x^2- 2x +4)

_________________

            x+2

then cross out  repeating which is x+2

then you get your answer!

Answer:

0

Step-by-step explanation:

The slope is always 0 on a horizontal line.