Answer:
2500
Step-by-step explanation:
25% of 10 000= 2500
Using the information given, select the statement that can deduce the line segments to be parallel. If there are none, then select none.
When m8 = m4
Using the information given, select the statement that can deduce the line segments to be parallel. If there are none, then select none.
When m8 = m4, the line segments are parallel.
When two line segments have the same slope (m8 = m4), then the line segments are parallel. Therefore, the statement that the line segments are parallel can be deduced if m8 and m4 are equal.
When two line segments have the same slope, then they will be parallel to each other. This can be deduced when the slopes of both line segments are equal, which is represented by m8 = m4. If the two line segments have the same slope, then they will be parallel to each other and will never meet or intersect. This is because parallel lines always have the same slope and never touch each other. In conclusion, the statement that two line segments are parallel can be deduced if m8 and m4 are equal.
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Kanye and his two friends are sharing the cost of lunch. the total cost of the bill is $15.27 . if Kanye has $20, how much will he have left after he pays his share?
Answer:$4.73
Step-by-step explanation:
Answer:
If Kayne is with his two friends, that means there are three people in total.
If there are three people sharing the price of this lunch, each person would have to pay 15.27/3 dollars.
Dividing, we get that each person must pay 5.09 dollars.
Subtracting 5.09 from 20, we have that Kayne will have $14.91 left after paying his share.
Hope this helps!
High School Advice Situation:
I am in Engineering 1 rn and I am a freshman and my semester 1 grade is a C and I am struggling, so I am thinking of withdrawing from my elective and go to a different elective which I know I can get an A+ in, but should I, because when I withdrawal I think it shows as an F. Help Please!
Step-by-step explanation:
Which do you enjoy the most?
I don’t get it or understand
Answer:
$1.30
Step-by-step explanation:
What you do is add the original 65 cents to the additional 65 cents that were shown to get 130. Since it's more than 100 you make it into dollars, so the final answer is $1.30.
Answer:
$1.30
Step-by-step explanation:
You need to know how coins look like. The middle one is a quarter and the other four are dimes. We know that quarters are worth 25 cents and dimes are worth 10 cents. Because there are 4 dimes, you do 4x10 which is equal to 40. We know that there is only one quarter so we do 40+25 which is equal to 65. Therefore, the tip is 65 cents Then, you add 65 cents to 65 cents again because Faaz had already put 65 cents there. 65+65 is equal to 130. 130 is equal to 1 dollar and 30 cents. Therefore, the tip is $1.30
x+4 if x <5
f(x)= 8
if 5
2x-1 if 7
For Ax), evaluate the following:
a. 10)
b. 46)
Answer:
f(0) = 4 , f(6) = 8
Step-by-step explanation:
Since
\(0 < 5\) then f(0) = 0+4 = 4
5 < 6 < 7 therefore f(6) = 8
What is the purpose of data? Answer below.
The purpose of data is to provide information and insights that can be used to make informed decisions, draw conclusions, and gain knowledge about a particular subject or phenomenon.
Data plays a crucial role in various fields, including science, business, research, healthcare, and everyday life.One primary purpose of data is to describe and understand the world around us.
By collecting and analyzing data, we can identify patterns, trends, and relationships that exist within a dataset. This helps us gain a deeper understanding of complex systems and phenomena.
For example, in scientific research, data is used to study the behavior of natural processes, investigate the effects of interventions, and formulate theories and models.
Data also serves as a foundation for making informed decisions. By examining relevant data, individuals and organizations can assess the potential outcomes of different choices and select the most optimal course of action.
Data-driven decision-making enables organizations to improve efficiency, identify opportunities, mitigate risks, and enhance overall performance. In fields like marketing and finance, data is extensively used for market research, customer segmentation, trend analysis, and financial forecasting.
Furthermore, data is crucial for monitoring and evaluating performance. By collecting data over time, organizations can track progress, measure outcomes, and identify areas for improvement. Data-driven monitoring allows for evidence-based assessments and adjustments to strategies or interventions.
Overall, the purpose of data is to provide reliable information that can be used to enhance understanding, support decision-making, and drive progress in various domains. It empowers individuals and organizations with the ability to derive insights, solve problems, and make meaningful contributions to society.
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2.3.33
Find the zeros of the following quadratic function by completing the square. What are the x-intercepts of the graph of the function?
f(x) = x2 + 12x - 72
(a^-7 x b^-2)^-9 =?
Select the equivalent expression.
The equivalent expression to the expression (a⁻⁷ × b⁻²)⁻⁹ is (a⁷ × b²)⁹.
What are some rules of exponents?Some common rules of exponents are
xᵃ×xᵇ = xᵃ⁺ᵇ.
xᵃ/xᵇ = xᵃ⁻ᵇ.
Addition and subtraction of exponents are only possible for the same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.
The given expression is (a⁻⁷ × b⁻²)⁻⁹.
= a⁻⁷ˣ⁻⁹ × b⁻²ˣ⁻⁹.
= a⁶³ × b¹⁸.
= (a⁷ × b²)⁹.
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complete each proof using the properties of equality.Given -8(x-3)=-32 proof; x=7
y=2 x − 12 has how many real roots?
Answer: One root
Reason:
The term "root" refers to the x intercept.
We plug in y = 0 and solve for x to get the x intercept
y = 2x-12
0 = 2x-12
2x = 12
x = 12/2
x = 6
The root is 6.
The single x intercept is located at (6,0).
classify the following differential equation s given in both standard and differential form. Q5 only
Need help quick please
Answer:-1/6
Step-by-step explanation:
Draw a line out in the 2nd quadrant.
Your y=\(\sqrt{35}\) hypotenuse=6 use pythagorean theorem to solve for x
6² = 35 + x²
x=1
so
cosΘ = -1/6
In finance, one example of a derivative is a financial asset whose value is determined (derived) from a bundle of various assets, such as mortgages. Suppose a randomly selected mortgage in a certain bundle has a probability of 0.08 of default. (a) What is the probability that a randomly selected mortgage will not default? (b) What is the probability that nine randomly selected mortgages will not default assuming the likelihood any one mortgage being paid off is independent of the others? Note: A derivative might be an investment that only pays when all nine mortgages do not default. (c) What is the probability that the derivative from part (b) becomes worthless? That is, at least one of the mortgages defaults
Answer:
a) 92% probability that a randomly selected mortgage will not default
b) 47.22% probability that nine randomly selected mortgages will not default
c) 52.78% probability that the derivative from part (b) becomes worthless
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
In which \(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
And p is the probability of X happening
Suppose a randomly selected mortgage in a certain bundle has a probability of 0.08 of default.
This means that \(p = 0.08\)
(a) What is the probability that a randomly selected mortgage will not default?
Either it defaults, or it does not default. The sum of the probabilities of these outcomes is 1. So
0.08 + p = 1
p = 0.92
92% probability that a randomly selected mortgage will not default
(b) What is the probability that nine randomly selected mortgages will not default assuming the likelihood any one mortgage being paid off is independent of the others?
This is P(X = 0) when n = 9. So
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 0) = C_{9,0}.(0.08)^{0}.(0.92)^{9} = 0.4722\)
47.22% probability that nine randomly selected mortgages will not default.
(c) What is the probability that the derivative from part (b) becomes worthless? That is, at least one of the mortgages defaults
Either none defect, or at least one does. The sum of the probabilities of these events is 100%. So
p + 47.22 = 100
p = 52.78
52.78% probability that the derivative from part (b) becomes worthless
Select the best answer for the question.
1. Identify the binomial
O A. x² - 4x + 2
O B. 2x2 + 3x -1 + y
C.x²
O D. x² - 4
Mark for review (Will be highlighted on the review page)
The only option that is a Binomial is; D. x² - 4
What is the binomial?A binomial is defined as a polynomial with two terms.
Examples of binomials are; x − 2 and x − 6 are both binomials.
A) x² - 4x + 2; This is a quadratic function with 3 terms and is therefore a trinomial and not a binomial.
B) 2x² + 3x - 1y; This is a quadratic function with 3 terms and is therefore a trinomial and not a binomial.
C) x²; This has only one term and is therefore a monomial and not a binomial.
D) x² - 4; This is a polynomial with two terms and is therefore a binomial.
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The volume of 2 rectangular pyramids are 5632 in3 and 11000 in3. What is there scale factor
Answer:
Denote the scale factor is k.
=> The ratio between the volume of two rectangular pyramids: k^3
=> k^3 = 11000/5632
=> k^3 = 1.95
=> k = ~1.25
Hope this helps!
:)
Henry went clothes shopping and bought 3 pairs of shorts for $22.99 each, 2
shirts for $32.99 each and one pair of shoes for $54.99. What is the most
reasonable estimate of the total amount he spent on all the clothing?
A. $135
O B. $184
C. $190
D. $223
Answer:
$190
Step-by-step explanation:
22.99 times 3 = 66.97
32.99 times 2 = 65.98
one pair of shoes is 54.99.
66.97 + 65.98 + 54.99 = 187.94
187.94 is closer to 190
Can somebody help me with this problem
Answer:
42/6=7
Step-by-step explanation:
You are dividing 42 by 6, since only 6 can sit at a table
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Give the domain and range. On a coordinate plane, points are at (negative 2, negative 1), (0, 1), (2, 3). a. domain: {2, 0, 2}, range: {1, 1, 3} b. domain: {–1, 1, 3}, range: {–2, 0, 2} c. domain: {–2, 0, 2}, range: {–1, 1, 3} d. domain: {1, 1, 3}, range: {2, 0, 2} Please select the best answer from the choices provided A B C D
Answer:
c. domain: {-2, 0, 2}, range: {-1, 1, 3}
Step-by-step explanation:
From the given points (negative 2, negative 1), (0, 1), (2, 3), we can determine the domain and range.
The domain represents the set of all possible x-values of the points, and the range represents the set of all possible y-values of the points.
In this case, we can see that the x-values are -2, 0, and 2, and the corresponding y-values are -1, 1, and 3.
Therefore, the correct answer is:
c. domain: {-2, 0, 2}, range: {-1, 1, 3}
6 -9x = 5x -10x + 2 solve for x
12. A jet stream can move a particle of air
11 miles in 5 minutes. At this rate, how far
will the particle move in 1 hour?
(5 minutes = 1 hour) (Example 1)
Answer:
132 particles
Step-by-step explanation:
5 minutes = 11 miles
1 hour (60 minutes)
11*x = 11 x 60 = 660
11x = 660/5=132
The distance of a jet stream can move a particle of air 132 miles in 1 hour.
Here,
A jet stream can move a particle of air 11 miles in 5 minutes.
We have to find, The distance of particles move in 1 hour.
What is distance?
The length along a line or line segment between two points on the line or line segment.
Now,
A jet stream can move a particle of air 11 miles in 5 minutes.
5 minutes = 11 miles
Then, for 1 minute a jet stream can move a particle of air = 11 / 5 miles
Hence, In 1 hour ( 60 minutes) a jet stream can move a particle of air;
⇒ \(\frac{11}{5} * 60 = 132\)
So, The distance of a jet stream can move a particle of air 132 miles in 1 hour.
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A one-way data table summarizes
A. a single input's impact on the output of interest
B. values of the input cells that will cause the single output value to equal zero
C. multiple input's impact on a single output of interest
D. values of cells when not all of the model is observable on the screen
Answer:
A
Step-by-step explanation:
hope this helps! :) Hope you have. a great day
Identify the proof to show that △ABD≅△CBD
, where ∠BDA≅∠BDC
are right angles, D
is the midpoint of AC¯¯¯¯¯
, AB¯¯¯¯¯≅BC¯¯¯¯¯
, and BD¯¯¯¯¯
bisects ∠B
.
The figure shows two triangles A B D and C B D with a common side B D. Points A, D, C lie on one line.
We have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.
To prove that △ABD ≅ △CBD, we can use the SAS (Side-Angle-Side) congruence criterion.
Given:
∠BDA ≅ ∠BDC (Both are right angles)
D is the midpoint of AC¯¯¯¯¯
AB¯¯¯¯¯ ≅ BC¯¯¯¯¯
BD¯¯¯¯¯ bisects ∠B
Proof:
Since D is the midpoint of AC¯¯¯¯¯, we have AD ≅ CD by the definition of a midpoint.
AB¯¯¯¯¯ ≅ BC¯¯¯¯¯ (Given)
BD¯¯¯¯¯ is a common side for both triangles.
∠BDA ≅ ∠BDC (Given)
To apply the SAS congruence criterion, we need to show that one pair of corresponding sides and the included angle are congruent in both triangles.
AD ≅ CD (Side) - This is true as D is the midpoint of AC¯¯¯¯¯.
∠BDA ≅ ∠BDC (Included Angle) - Both are right angles.
By the SAS congruence criterion, we can conclude that △ABD ≅ △CBD.
Therefore, we have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.
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Find the value of x that makes m|n.143°(5x + 13)°AEmnLines m and n are parallel when x =
Since both angles are in matching corners, they are corresponding angles.
Corresponding angles are equal.
So:
143 = 5x + 13
Solve for x
143 - 13 = 5x
130 = 5x
130/5 = x
x= 26
Answer:
x=26
40% is NOT equivalent to....?
A. 0.4
B.2/5
C.40/100
D. 0.04
E. None correct
Answer:
d
Step-by-step explanation:
d is .04 percent plz mark branliest
what is the factterd form for the eqaution 3x^2+8x+4
Answer:
(3x+2)(x+2)
Step-by-step explanation:
1 Split the second term in 3{x}^{2}+8x+43x
2
+8x+4 into two terms.
3{x}^{2}+6x+2x+43x
2
+6x+2x+4
2 Factor out common terms in the first two terms, then in the last two terms.
3x(x+2)+2(x+2)3x(x+2)+2(x+2)
3 Factor out the common term x+2x+2.
Evaluate the expression for q = -2. 8q=
Answer:
-16
Step-by-step explanation:
8q
Let q = -2
8*-2
-16
Stephen is combining all juice shown to make fruit punch. Does the expression (64+28+76)/6 make sense’s
Yes, the expression (64+28+76)/6 makes sense as it represents the average quantity of juice per unit when combining all the shown juices.
To determine whether the expression (64+28+76)/6 makes sense, we need to evaluate the components of the expression and consider whether the mathematical operations are valid.
The expression (64+28+76)/6 represents the sum of three numbers (64, 28, and 76), divided by 6. Let's break it down step by step:
Addition: We have three numbers being added together: 64, 28, and 76. The sum of these numbers is 168 (64 + 28 + 76 = 168).
Division: The sum of the three numbers, 168, is then divided by 6. Division is a valid mathematical operation.
Now, let's analyze whether the expression makes sense in the context of Stephen combining all the juice to make fruit punch. The numbers 64, 28, and 76 may represent quantities of juice (in some units) that Stephen is combining. However, without further information or context, we cannot determine if the expression accurately represents the combination of these juices.
If the numbers 64, 28, and 76 represent quantities of juice in the same units (such as milliliters or liters), then the expression (64+28+76)/6 would represent the average quantity of juice per unit. The result, 168/6, would be 28. This would imply that each unit (e.g., glass or serving) of the fruit punch contains an average of 28 units of juice.
In summary, mathematically, the expression (64+28+76)/6 is valid. However, without additional context regarding the units or quantities being represented, it is not possible to determine whether the expression accurately describes the process of combining the juices to make fruit punch.
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When is a repeating decimal acceptable to use during calculations? When should you convert a repeating decimal to a fraction for calculations?
A repeating decimal is acceptable to use during calculations when you require a certain level of precision
When is a repeating decimal acceptable to use during calculations?A repeating decimal is acceptable to use during calculations when you require a certain level of precision, but it's important to keep in mind that the result will be an approximation rather than an exact value.
It is commonly used in situations where a rounded value is sufficient and the level of precision doesn't significantly impact the final result.
On the other hand, you should convert a repeating decimal to a fraction for calculations when you need an exact value or when further mathematical operations or comparisons are required.
Converting a repeating decimal to a fraction allows for precise calculations and eliminates any potential rounding errors associated with working with decimal approximations.
Converting a repeating decimal to a fraction involves identifying the repeating pattern and expressing it as a fraction. This allows for exact calculations and maintains the mathematical properties of fractions.
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find the missing number in this proportion.
\( \frac{48}{80} = \frac{6}{?} \)