The estimated population in Houston, TX in 2010 was approximately 6.5 million.
What was the estimated population in Houston, TX in 2010?To estimate the population in 2010, we can assume a linear growth rate based on the given data points from 1970 to 1980.
Let's calculate the growth rate per year:
Growth rate = (Final population - Initial population) / Number of years
Growth rate = (3,200,000 - 2,100,000) / (1980 - 1970)
Growth rate = 1,100,000 / 10
Growth rate = 110,000
Now, let's calculate the estimated population in 2010 using the growth rate:
Population in 2010 = Population in 1980 + (Number of years * Growth rate)
Population in 2010 = 3,200,000 + (2010 - 1980) * 110,000
Population in 2010 = 3,200,000 + 30 * 110,000
Population in 2010 = 3,200,000 + 3,300,000
Population in 2010 = 6,500,000
Rounding to the nearest whole number, the estimated population in 2010 is 6,500,000.
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The seemingly __________ but very important goal of passing physics, and therefore maintaining a high gpa, motivated kelly to study extra long hours.
The seemingly invincible but very important goal of passing physics, and therefore maintaining a high GPA, motivated Kelly to study extra long hours.
The goal of the Physics primary is to provide the scholar with a broad understanding of the bodily standards of the universe, to help them develop critical thinking and quantitative reasoning skills, to empower them to suppose creatively and critically about medical troubles and experiments, and to provide schooling.
The key to passing a physics examination is to memorize critical equations and their applications. To do so, write down the equation on one facet of a observe card and what it's used for on the other side, then go through the cards and memorize every equation.
Physics allows us to prepare the universe. It deals with basics, and enables us to look the connections among seemly disparate phenomena. Physics gives us powerful gear to help us to explicit our creativity, to peer the sector in new approaches after which to alternate it. Physics is useful.
Invincible is an American adult animated superhero television series, based on the Image Comics series.
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What is thermodynamics?
A) The movement of energy
B) The classification of energy
C) the movement of heat
D) the way energy changes
Answer:
I think the answer should be C. I am not sure
Answer: c
Explanation: im pretty sure it’s C, because thermodynamics is the movement of heat. Kinda like an EMF Reader. (Electric Magnetic Feild reader). It’s complicated to explain how it works, but hey it works!
Certain radioactive material decays in such a way that the mass remaining after \( t \) years is given by the function \( m(t)=460 e^{-0.03 t} \) where \( m(t) \) is measured in grams. (a) Find the ma
(a) The mass at time t=0 is 460 grams. (b) Rounding to at least one decimal place, the mass last after 45 years is about 119.0 grams.
(a) To find the mass at time t=0, we alternative into the given characteristic:
m(0) = \(460e^(-0.03(0))\)
Since \(e^0\) is the same for at least one, we've got:
m(0) = 460(1) = 460 grams
Therefore, the mass at time t=0 is 460 grams.
(b) To locate the mass final after 45 years, we substitute t=45 into the given function:
m(45) = \(460e^(-0.03(45))\)
Using a calculator or software program, we will evaluate the expression:
m(45) ≈ \(460e^(-1.35\)) ≈ 460(0.2587) ≈ 118.96 grams
Rounding to at least one decimal location, the mass last after 45 years is about 119.0 grams.
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The correct question is:
"Certain radioactive material decays in such a way that the mass remaining after t years is given by the function m(t)=460e −0.03t where m(t) is measured in grams. (a) Find the mass at time t=0. Your answer is (b) How much of the mass remains after 45 years? Your answer is a Round answer to 1 decimal place."
five moles of ideal gas located inside a cylinder with a movable piston are heated to 4 ° C. While the gas is being heated, it does the job by raising the piston up. Atmospheric pressure is not taken into account
Answer:
Explanation:
You didn't ask a question here, but I assume you want the pressure? You can use the ideal gas equation stating that:
PV = nRT
The 'P' is pressure, the 'V' is volume, the 'n is number of moles of gas, the 'R' is the ideal gas constant, and the 'T' is the temperature. First convert the Celsius degrees into Kelvin by using the following relation:
C + 273.15 = K
4 + 273.15 = 277.15K
Now, find the volume of a cylinder by using:
\(V=\pi r^2l\)
The 'l' is the length of the cylinder
Now just plug and chug everything into the ideal gas equation:
\(PV=nRT\)
\(P(\pi r^2l)=(5moles)(8.3145J/moles*K)(277.15K)P=\frac{11.52J}{\pi r^2l}\)
An object is sliding down an inclined plane at constant velocity. If the coefficient of kinetic friction between the object and the plane is , what is the angle of the plane?
The angle of the plane will be 26.57°.Angle of plane is the angle of elevaton at which the body exciute motion on the inclined plane.
What is kinetic friction?A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion.
Force on an object due to the gravitational force will be;
\(\rm F = mg\)
For the inclined plane the balance forces will be ;
\(\rm mgsin \theta = \mum g cos \theta \\\\ \rm\mu = tan \theta \\\\ \theta = tan^{-1}\mu \\\\ \theta = tan^{-1}0.5 \\\\ \theta = 26.57^0\)
Hence the angle of the plane will be 26.57°.
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A moon orbits a planet in a nearly circular orbit of radius R, as shown in the figure. Which of the following free-body diagrams could be used to analyze the forces exerted on the moon when it is at the position indicated in the figure?
I don't see any free body diagrams.
Free body diagram of a moon orbits a planet in a nearly circular orbit of radius R, as shown in the figure is attached in the answer. This could be used to analyze the forces exerted on the moon when it is at the position indicated in the figure.
What is free body diagram?Free-body diagrams are used to display the relative strength and direction of all forces that are being applied to an item in a certain scenario. A unique illustration of the vector diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout our study of physics. In a free-body diagram, the size of the arrow indicates the strength of the force.
The force is acting in the direction indicated by the arrow's direction. The exact type of force is labelled next to each force arrow in the diagram. In a free-body diagram, it is common practice to depict the item as a box and to draw the force arrow from the box's center outward in the direction that the force is acting.
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La velocidad de la luz es de 300 000 km/s, convertir a m/s.
ayudenme porfa
What are the forces like in a collision?
Answer:
The forces are a convergent
Explanation:
Without using afood flask, suggest another ways would you keep food warm a till to the hospital
Another way to keep food warm till you arrive at the hospital is by putting the food in a foil and wrapping it up with a towel to retain the heat.
What is Food preservation?Food preservation is defined as the process by which a cooked food or process food is kept in such a way that microorganisms cannot affect their taste and texture.
To prevent a cooked food from getting cold, you can put the food in an aluminium foil and wrap it with a towel to prevent heat loss.
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1. What type of VOM reading requires the meter to be placed in series with the circuit?
A. Resistance
B. Voltage
C. Current
O
D. Power
Answer:
C. Current.
Explanation:
In a series circuit the current is equal in all of its components, so to measure the current we put the meter in series with the circuit.
What will be the density of the air if the radius of the cylinder is halved while the length is unchanged?
If the radius of the cylinder is halved and length is kept unchanged then the density of air inside the cylinder will increase.
As it can be said that density is inversely proportion to the square of the radius.
Density of Cylinder
Density is the ratio of mass to volume.
The formula for density is: ρ= m/v.
The formula for the Mean Density of a cylinder is:
ρ= m/ (π•r²•h)
where:
ρ is the density of the cylinder
m is the mass of the cylinder
h is the height of the cylinder
So, with increase in radius the of the cylinder there is decrease in the density of cylinder.
And on decreasing the radius of the cylinder there is increase in the density of the cylinder.
As it can be said that density is inversely proportion to the square of the radius.
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What is the more common term for a quantitative
observation?
Answer:
Measurement
Explanation:
Scientific research require observation and there are two types of observations, quantitative and qualitative observation
Collecting quantifiable data that is possible to be expressed in a number format is said to be a quantitative observation
Quantitative observation can also be described as observations that are defined by both words and numbers and they are therefore more useful than qualitative observations that involve only words
Quantitative observations involve expressions of variables that are quantifiable, that is material hat can be expressed in numbers.
Answer:
Measurement
Explanation:
if you’re doing ck12 it’s the right answer
Hey Guys
(Read the paragraph and answer the questions follows) The maximum amount of solute that can be dissolved in a fix amount of solvent at a fix temperature is called solubility. On the basis of amount of solute dissolved in solution, there are three types of solutions- i. supersaturated, ii. saturated and iii. saturated solutions. Supersaturated solutions contains more amount of solute than solubility. Saturated solutions has amount of solute equal to the solubility but unsaturated solutions has less than solubility. Supersaturated solutions are unstable and convert into saturated solutions by precipitation. Unsaturated solutions can be converted into saturated by evaporation of solvent. A). If solubility of a solute 'X' in water is 29 g/Litre, 2.9 g/Litre solution of solute 'X' in water is called- * 2 points Saturated Supersaturated unsaturated semisaturated 8) B). If solubility of another solute 'Y' in water is 2.9 g/Litre, saturated solution of it should contain _____ g solute in ________ mL solution. * 2 points 29, 50,000 19, 1000 1.45, 500 2.9, 50,00 This is a required question 8) C). 20 g solute is dissolved in 50 g of solution. Calculate the mass % of solution. * 2 points 20% 50% 40% 25%
Ans It
(A) The solution X is unsaturated
(B) The solution Y should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is 40%
(A) The type of solution X is determined as follows;
The maximum amount of solute that can dissolve in solution X = 29 g/Liter
The amount of solute in solution X = 2.9 g/Liter
This solution is unsaturated because the amount of solute present is less than the maximum the solution can take.
(B) The amount solute and volume in the solution Y is calculated as follows;
The solubility = 2.9 g/Liter
\(solubility = \frac{2.9 \ g}{L} \times \frac{L}{ mL \times 1000} = \frac{2.9 \ g}{1000mL}\)
Thus, the solution should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is calculated as;
\(mass \ \% = \frac{20 \ g}{50 \ g} \times 100 \% = 40 \%\)
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Two people stand in place and pull on a rope in opposite directions. Which of the following correctly describes the movement of a flag tied in the middle of the rope
The rope's center flag remains stationary. Because the force being provided by your team to pull the flag is equal to the force being exerted by the opposing team but in the opposite direction, the flag does not move. The forces are acting in opposing ways.
It balances the forces acting on the rope. The flag in the middle of the rope won't move when the forces are balanced. One team must exert more force than the other in order to win the game.
Two forces are said to be balanced when their strengths are equal but their directions of action are opposing. Once more, tug-of-war is a prime illustration. The forces are balanced if the pullers are exerting equal force but going in the opposite direction on either side of the rope. There is hence no motion.
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If I have a series circuit with 3 resistors on it and each resistor has a resistance of 500
Ohms, what is my total resistance?
Answer:
1,500 ohms is the total resistance
!!!!Has anybody done the Lab report : Thermal Energy Transfer on edg? For physics
2 pages of data
Answer: the only thing I can't give you is the lab report because I haven't done it yet i dont want to lol.
Explanation:
i got a bunch of answers so if my answers are correct im putting them here
hi,please i need help with this one in physics.hurry and correct i need it.
Topic:Equilibrium.
The half-meter rule (easy math) is 0.5 meters or 50 centimeters since a meter is 1 meters long, which is equivalent to 100 centimeters. Therefore, we shall apply the 50 cm rule.
A 50 cm rule's center of mass is now 25 cm away.
Additionally, according to the data, the object is pivoted at 15 cm, while the 40 g object is hung at 2 cm from the rule's beginning. Using a straightforward formula, we can compare the two situations: the distance from the pivot to the center of the mass times the mass of the 40 g object divided by 2 cm must equal the distance from the pivot to the center of the mass times mass of the 10 x g object
The result of the straightforward computation must be 52g.
Most simplified version:
the center of mass of the rule is at the 25 cm mark
⇒ \(40 g * (15 cm - 2 cm)\)
⇒ \(= M * (25 cm - 15 cm)\)
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Which are examples of projectile motion? Check all that apply. A. A soccer ball rolling across the ground in the northeast direction. B. An arrow flying toward a target. C. A golf ball driven into
what is observed when a charged perspex rod is placed close to a suspended polystyrene sphere
When a charged body is placed near the conductor, the opposite charge is appeared on the one side of the uncharged conductor body near the charged body under the effect of induction.
The opposite charge on the another body is also known as the induced charge.
The perpex rod in the given question is charged.
let the charge on the perpex is positive as shown in the figure.
Then, the polystrene sphers (insulator uncharged sphere) will not have any charge induced as the charges are not free to move inside the insulator.
Thus, when a charged perspex rod is placed close to a suspended polystyrene sphere then the induced charge on the sphere is not observed under the phenomenon of induction process and sphere remain uncharged.
The gravitational interaction is caused by
Answer:
a weak interaction between particles the result from mass
A fish swimming at a rate of .6 m/s notices a huge shark. Three seconds later, the fish is swimming at a speed of 3 m/s. What is the fish's acceleration?
0.8 m/s/s
-0.8 m/s/s
12.5 m/s/s
-12.5 m/s/s
Answer:
C
Explanation:
???
i think
During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed v0 = 38 m/s at an angle θ = 34° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem.
Answer:
The horizontal distance is 136.6 m.
Explanation:
Given that,
Initial speed = 38 m/s
Angle = 34°
Suppose, Calculate the horizontal distance \(x_{max}\) in meters the ball has traveled when it returns to ground level.
We need to calculate the horizontal distance
Using formula of range
\(R=\dfrac{v_{0}^2\sin(2\theta)}{g}\)
Where, v= speed
g = acceleration due to gravity
Put the value into the formula
\(R=\dfrac{(38)^2\sin(2\times34)}{9.8}\)
\(R=136.6\ m\)
Hence, The horizontal distance is 136.6 m.
A 100 litre open-topped tank is filled to the brim with salt water. The salt concentration in the water is 80 g/L. Fresh water then pours into the tank at the rate of 10 L/sec. Assume the fresh water mixes completely with the salt water. The excess water runs out over the top (also at the rate of 10 L/sec). 10 L/s (fresh water) 100 L
a) Find an equation that gives the amount of salt remaining in the tank after t seconds.
b) How much salt is left in the tank after one minute?
c) How much salt is left in the tank after 100 L of brine has flowed out over the top of the tank?
d) When will half of the salt in the tank have flowed out over the top of the tank?
e) When will the tank contain salt water at a concentration of 5 g/L?
For the 100 litre open-topped tank:
a) rate of salt entering and leaving the tank: dS/dt = 0 - 80 = -80 g/secb) amount of salt left after 1 minute is 3200 gc) salt left in the tank after 100 L of brine has flowed out is 0d) half of the salt in the tank will have flowed out after 50 secondse) the tank will contain salt water after 250 seconds.How to solve for a 100 litre open-topped tank?a) To find an equation that gives the amount of salt remaining in the tank after t seconds, consider the rate at which salt enters and leaves the tank.
The initial amount of salt in the tank is 100 L × 80 g/L = 8000 g.
Rate of salt entering the tank:
The fresh water entering the tank at 10 L/sec has a salt concentration of 0 g/L. Therefore, the rate of salt entering the tank is 0 g/sec.
Rate of salt leaving the tank:
The excess water running out over the top at 10 L/sec carries away salt with a concentration of 80 g/L. Therefore, the rate of salt leaving the tank is 80 g/sec.
Rate of change of salt in the tank:
The rate of change of salt in the tank is given by the difference between the rate of salt entering and leaving the tank:
dS/dt = 0 - 80 = -80 g/sec
b) To find how much salt is left in the tank after one minute (60 seconds), integrate the rate equation from t = 0 to t = 60:
∫dS = ∫(-80) dt
ΔS = -80t + C
Since the initial amount of salt is 8000 g (at t = 0), solve for the constant C:
8000 = -80(0) + C
C = 8000
Therefore, the equation for the amount of salt remaining in the tank after t seconds is:
S(t) = -80t + 8000
Substituting t = 60 seconds:
S(60) = -80(60) + 8000
S(60) = 3200 g
c) After 100 L of brine has flowed out over the top of the tank, the remaining volume of salt water in the tank is 100 L (initial volume) - 100 L (flowed out) = 0 L. Therefore, there is no salt left in the tank.
d) To find when half of the salt in the tank has flowed out over the top, set S(t) = 0.5 × initial amount of salt:
0.5 × 8000 = -80t + 8000
-80t = 8000 - 4000
-80t = 4000
t = -4000 / -80
t = 50 seconds
Therefore, half of the salt in the tank will have flowed out over the top after 50 seconds.
e) To find when the tank contains salt water at a concentration of 5 g/L, set S(t) = V(t) × 5, where V(t) is the volume of water in the tank at time t:
V(t) × 5 = -80t + 8000
V(t) = (-80t + 8000) / 5
V(t) = 100 L (initial volume) - 10 L/sec × t (rate of water leaving the tank):
100 - 10t = (-80t + 8000) / 5
Multiplying both sides by 5:
500 - 50t = -80t + 8000
30t = 7500
t = 250 seconds
Therefore, the tank will contain salt water at a concentration of 5 g/L after 250 seconds.
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On a 100km track , a train travels the first 30km with a speed of 30km/h . How fast the train travel the next 70 km if the average speed for the entire journey is 40km/h?
Solution :-
Given :
Distance 1 = 30 km
Distance 2 = 70 km
We know that speed = distance/time
and, Average speed = total distance/total time taken
When the train acquired a speed of 30 km/hr, the time taken = 30/30 = 1 hour
Average speed = 9distance 1 + distance 2)/(time 1 + time 2)
AS time 2 or t2 is time taken for the second part of the journey of 70 km
⇒ 40 = 100/(1 + t2)
⇒ 40 + 40t2 = 100
⇒ 40t2 = 100 - 40
⇒ 40t2 = 60
⇒ t2 = 60/40
⇒ t2 = 1.5
So, t2 or time taken to travel the second part of the journey is 1.5 hours.
Speed of the second part of the journey = distance 2/time 2
⇒ 70/1.5
⇒ 46.666 km/hr or 46.7 km/hr.
Hence the answer is = 46.666 km/hr or 46.7 km/hr.
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a student is building a model of a solar eclipse. solar eclipses occur only during a new moon phase. which motion best demonstrates a solar eclipse?
The student's proper example demonstrates how the moon is in the right position to block the sun from Earth and so therefore cause a solar eclipse.
How frequently do solar eclipses start happening?Each year, there are anywhere from two to five celestial phenomena, lunar eclipse with a total occurring about every 18 months. Depending on what part of the world, you might be unable to see that eclipse.
How common are solar eclipses?Complete solar eclipses are exceptional occurrences. These are thought to happen about once 360 to 410 years in average at any given location, although happening someplace on Globe every two years on average.
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(d) A wire X of Resistance = 200, is replaced by wire Y of Resistance = 35 Q. Both wires are made of the
same material, Wire Y is double the area of wire X. Wire Y has a length of 2.5m.
i- Find the length of wire X.
ii- If wire X is connected to a battery of emf = 12V. Calculate the current in the wire.
pret
Length
iii-Clalculate the charge passing through the wire in 5 minutes
Current =
........... [3]
(2
(i) The length of wire X is determined as 7.14 m.
(ii) The current in the wire is determined as 0.06 A.
(iii) The charge passing through the wire in 5 minutes is 18 C.
What is the length of wire X?
The length of wire X is calculated by applying the following formula as shown below;
ρ = RA / L
where;
R is the resistance of the wireA is the area of the wireL is the length of the wireSince the wires are made of the same material, resistivity of wire X = resistivity of wire Y
let wire X = 1
let wire Y = 2
R₁A₁ / L₁ = R₂A₂ / L₂
L₁ = ( R₁A₁L₂ ) / ( R₂A₂ )
L₁ = ( 200Ω x A₁ x 2.5 m ) / ( 35Ω x 2A₁ )
L₁ = 7.14 m
The current flowing in wire X is calculated as follows;
V = IR
I = V / R
where;
V is the voltageR is the resistanceI = ( 12 V ) / ( 200Ω )
I = 0.06 A
The charge passing through the wire in 5 minutes is calculated as follows;
Q = It
Q = 0.06 A x ( 5 x 60 s )
Q = 18 C
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How is the mirror angle related to the angles of incidence and reflection?
Answer:
mirror angle is related to sngle of incident n reflection becuse they are ewaul to each other
A boat sailed 560 km in 8 hrs. It took three hours to travel the first 150 km. What was it’s average speed for the remaining journey?
Answer:
82 km/h
Explanation:
Given that A boat sailed 560 km in 8 hrs. It took three hours to travel the first 150 km. That is,
The remaining distance will be:
560 - 150 = 410 km
the remaining time will be:
8 - 3 = 5 hours
For the remaining Journey, average speed will be:
Speed = distance/time
Speed = 410/5
Speed = 82 km/h
Therefore, the average speed for the remaining journey will be 82 km/h
PLEASE HELP ME :( I've tried solving it many times but my teacher keeps saying its wrong i really need help
Answer:
The charge on each end of the wire produces what we call an electric field. The electric field makes negative electrons want to travel towards the positive end of the wire (the end with not enough electrons).
the answer is d because it's going to positive.
is am alright? let me know.
A 221-gram ball is thrown at a speed of 36.7 m/s from the top of a 39.8-m high cliff. Determine the impact speed of the ball when it strikes the ground. Assume negligible air resistance.
Given:
The mass of the ball is
\(\begin{gathered} m=221\text{ g} \\ =0.221\text{ kg} \end{gathered}\)The initial height of the ball is
\(h=39.8\text{ m}\)The initial speed of the ball is
\(v_i=36.7\text{ m/s}\)To find:
the impact speed of the ball when it strikes the ground
Explanation:
The initial potential energy of the ball is
\(\begin{gathered} (PE)_i=mgh \\ =0.221\times9.8\times39.8 \\ =86.2\text{ J} \end{gathered}\)The initial kinetic energy is
\(\begin{gathered} (KE)_i=\frac{1}{2}mv_i^2 \\ =\frac{1}{2}\times0.221\times(36.7)^2 \\ =148.8\text{ J} \end{gathered}\)The final energy of the ball is fully kinetic energy. Let the final impact speed of the ball is
\(v_f\)We can write, using the energy conservation principle that
\(\begin{gathered} (PE)_i+(KE)_i=\frac{1}{2}mv_f^2 \\ 86.2+148.8=\frac{1}{2}\times0.221\times v_f^2 \\ v_f^2=2\times\frac{86.2+148.8}{0.221} \\ v_f=46.1\text{ m/s} \end{gathered}\)Hence, the final impact speed of the ball is 46.1 m/s.