in δcab, point e is the midpoint of segment ac and point d is the midpoint of segment bc. if the measure of segment ab is 8 units, what is the measure of segment segment ed?

Answer:

{x,y} = {67/16,-15/4}

Step-by-step explanation:

// Solve equation [2] for the variable  y

 [2]    2y = -8x + 26

 [2]    y = -4x + 13

// Plug this in for variable  y  in equation [1]

  [1]    4x + 5•(-4x+13) = -2

  [1]    -16x = -67

// Solve equation [1] for the variable  x

  [1]    16x = 67

  [1]    x = 67/16

// By now we know this much :

   x = 67/16

   y = -4x+13

// Use the  x  value to solve for  y

   y = -4(67/16)+13 = -15/4

Answer: A rhombus is a parallelogram but a parallelogram is not a rhombus.

Step-by-step explanation:

Answer nope

Step-by-step explanation:

Answers;

Larger angle = 62 degrees

Smaller angle = 28 degrees

Explanation:

Let the two complementary angles be x and y. Since the sum of complementary angles is 90degrees, hence;

x + y = 90 ....1

Let the larger angle be x and the smaller angle be y;

If the larger angle is 34° larger than the smaller angle,

x = 34 + y .....2

Substitute equation 2 into 1;

34+y+y = 90

34 + 2y = 90

2y = 90 - 34

2y = 56

Divide both sides by 2

2y/2 = 56/2

y = 28

Substitute y = 28 into equation 2;

x = 34 + 28

x = 62 degrees

Hence the measure of both anglea (x, y) is (62, 28)

Answer:

(1, 2.5 (or 3/2))

Step-by-step explanation:

It's the point the two lines meet

The precision of the protractor will determine the level of uncertainty in the measurement. A high-quality protractor will enable more precise measurements than a low-quality protractor with less accurate markings.

To determine the angle and its uncertainty, you'll need to provide the measured values and their uncertainties.  Using a protractor can provide a relatively precise measurement, but its precision may not be as high as specialized instruments or methods.

In order to determine an angle and its uncertainty, additional information is needed such as the degree of precision required, the size of the angle, and the measurement methodology. Without this information, it is impossible to determine the angle and its uncertainty.

Whether a protractor can be used to measure the angle with the required precision also depends on the quality of the protractor being used. A high-quality protractor with accurate markings and a clear scale will enable more precise measurements than a low-quality protractor with less accurate markings and a less clear scale.

Therefore, the precision of the protractor will determine the level of uncertainty in the measurement.

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4.1.2. the claim that the median price is R120,000 is not valid. 4.1.3. The mean price is the best suited for the data in dealer 2

4.1.1 To arrange the prices of car dealer 1 in descending order:

R178,200

R175,000

R155,700

R125,800

R115,000

R110,900

R108,500

R108,500

R99,900

R99,900

R95,000

4.1.2 To verify whether the claim that the median price of car dealer 1 is R120,000 is valid, we need to find the median of the data set:

Arranging the prices in ascending order:

R95,000

R99,900

R99,900

R108,500

R108,500

R110,900

R115,000

R125,800

R155,700

R175,000

R178,200

The median is the middle value, so we can see that the median price is R115,000. Therefore, the claim that the median price is R120,000 is not valid.

4.1.3 To determine the mean price of dealer 2, we sum up all the prices and divide by the total number of prices:

R138,600 + R140,000 + R165,000 + R180,000 + R192,000 + R235,000 + R238,000 + R400,000 + R450,000 + R650,000 + R700,000 = R3,378,600

To find the mean, we divide the sum by the number of prices:

Mean = R3,378,600 / 11 = R307,145.45

The mean price is the best suited for the data in dealer 2 because it takes into account all the prices and provides a measure of central tendency that is influenced by each data point. It gives an overall average price for the vehicles at dealer 2.

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The COUNTIF function is used to compute the number of times a particular condition is satisfied within a given range of cells.

It is an excel statistical function, which is used to count the number of cells that meet a criterion. To determine how many cells in the worksheet contain a number higher than or less than the one specified, the countif formula is used.

It is typed =COUNTIF

1. Select a cell

2. Type =COUNTIF

3. Double-click the COUNTIF command

4. Select a range

5. Type

,6. Select a cell (the criteria, the value that you want to count)7.

Hit enter Hence the answer is COUNTIF

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Equation shows  identity property of multiplication is (a + bi) × 1 = (a + bi)

What is Identity property of multiplication?

The identity property of multiplication says that the product of 1 and any number is that number.

We know, Identity property of multiplication states that

"the product of 1 and any number is that given number".

We know that every complex number have two parts one is real and other is imaginary.

If a is real number and b is imaginary  part then by definition

(a + bi) × 1 = (a + bi).

1. Uses Distributive Property of Multiplication.

2. Zero product property.

3. Commutative property of multiplication

4. Identity property of multiplication.

Hence, equation shows identity property of multiplication is (a + bi) × 1 = (a + bi)

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Answer:

48 meters

Step-by-step explanation:

3*4 = 12

5*4 = 20

4*4 = 16

These are the sizes when the triangle enlarges with a scale factor of 4.

To find perimeter, you add the sides together

12+20+16 = 48

The perimeter is 48 meters

The perimeter of larger triangle is 48m.

Given that,

According to the scenario, calculation of the given data are as follows,

Perimeter of larger triangle =  4m \(\times\) ( 3m + 5m + 4m)

= 4m \(\times\) 12m

= 48 m

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Answer:

44 yd^2

Step-by-step explanation:

Area of trapezium = ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides

= 1/2 (12 + 5.6) × 5

= 44yd^2

Answer:

C: 26

Step-by-step explanation:

The distance between A and B is 8 and the dstance between B and C is 5. Add 8+8+5+5=26

Answer:

Step-by-step explanation:

A) $51.5

B) two children tickets

Step-by-step explanation:

Given that the cost of admission for the Flemington Aquarium is $11.50 for each senior citizen, $14.75 for each adult and $7.25 for each child.

The cost of admission for the family of 3 adults and 1 child will be

(3 × 14.75) + (1 × 7.25)

44.25 + 7.25 = 51.5 dollars

What if two more tickets for admission are purchased for a total of $14.50?

Since there is no ticket of that amount, we can determine what type of tickets the family purchases by taking the amount of child tickets away from the amount. That is

14.5 - 7.25 = 7.25

The remaining money amount to child ticket again. We can therefore conclude that the two more tickets for admission purchased for a total of $14.50 are for 2 children tickets

hope this helped<3!!

Answer: 168

Step-by-step explanation:

Answer:

168

Step-by-step explanation:

34+8=42

42x4=168

Answer:

C, D, and G are 130 degrees. A, B, E, and F are all 50 degrees. H is 90 degrees.

A. 50°

B. 50°

C. 130°

D. 130°

E. 50°

F. 50°

G. 130°

H. 90°

Answer:

A. 150

Step-by-step explanation:

Calculate the probability of landing on an odd number: 1/2.

Multiply the probability by the number of trials: (1/2) * 300.

Simplify the expression: 150.

Therefore, a reasonable prediction is that the event of landing on an odd number will occur 150 times out of the 300 rolls of the fair 6-sided die.

5/98 is the probability he will choose one green marble and then one red marble.

Definition of probability

Three Types of Probability-

P(green) = ⇒ 5/14

P(red) = ⇒ 2/14

P(green and red) = ⇒ 5/98

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We will reject the H0 as there sufficient evidence is obtained that the percentage of people who believe that there is life on planets differs from 50%.

It is given that the sample size, (N) is 125

Probability (P)= 0.50 or 50%

P'= 50/120= 0.4166

Significance level (\(\alpha\))=0.10

If we consider the null and alternative hypotheses, they are:

H0= 0.50

H1≠ 0.50

For conducting the test statistics:

Z= \((P'-P)/\sqrt{P*(1-P)/N}\)

Z= \((0.41-0.50)/\sqrt{0.50*0.50/125}\)

Z= -2.01

The critical value of Z at \(\alpha\)=0.10 is 1.645 or -1.645

And the P- value at Z= 2.01 is 0.04

Decision Criteria: If the P-value is less than the significance level, we reject the H0. Also, if the Z is found to be greater than the critical value, we will reject H0.

Thus, in this case, we see that, the P-value, 0.04 is less than the significance level, i.e., 0.10, we will reject the H0.

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According to the question, the average score for the variable x1 is 1.88.

To find the average score for the variable x1, we need to assign numerical values to the categories S, M, and L. Let's assign S = 1, M = 2, and L = 3, as instructed.

Suppose we have a dataset with n observations of x1. Let's denote the values of x1 as \(x1_1, x1_2, ..., x1_n\). To find the average score, we need to calculate the sum of all the scores and divide it by the total number of observations.

The average score for x1 can be calculated as:

\(\[ \text{Average score} = \frac{\text{Score of } x1_1 + \text{Score of } x1_2 + \ldots + \text{Score of } x1_n}{n} \]\)

Let's assume we have the following values for x1: S, L, M, S, M, M, L, S. The corresponding scores are 1, 3, 2, 1, 2, 2, 3, 1.

Now we can calculate the average score:

\(\[ \text{Average score} = \frac{1 + 3 + 2 + 1 + 2 + 2 + 3 + 1}{8} \]\)

            = \(\frac{15}{8}\)

            = 1.875

Rounding the answer to two decimal places, the average score for the variable x1 is 1.88.

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If a function f is differentiable at a point a and f(a) is not equal to zero, then the absolute value function |f| is also differentiable at that point.

The proof involves considering two cases based on the sign of f(a) and showing that the limit of the difference quotient exists for |f| at point a in both cases. However, it is important to note that |f| is not differentiable at the point where f(a) equals zero.

To prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a) ≠ 0, we need to show that the limit of the difference quotient exists for |f| at point a.

Let's consider the function g(x) = |x|. The absolute value function is defined as follows:

g(x) = {

x if x ≥ 0,

-x if x < 0.

Since f(a) ≠ 0, we can conclude that f(a) is either positive or negative. Let's consider two cases:

Case 1: f(a) > 0

In this case, we have g(f(a)) = f(a). Since f is differentiable at a, the limit of the difference quotient exists for f at point a:

lim (x→a) [(f(x) - f(a)) / (x - a)] = f'(a).

Taking the absolute value of both sides, we have:

lim (x→a) |(f(x) - f(a)) / (x - a)| = |f'(a)|.

Since |g(f(x)) - g(f(a))| / |x - a| = |(f(x) - f(a)) / (x - a)| for f(a) > 0, the limit on the left-hand side is equal to the limit on the right-hand side, which means |f| is differentiable at a when f(a) > 0.

Case 2: f(a) < 0

In this case, we have g(f(a)) = -f(a). Similarly, we can use the same reasoning as in Case 1 and conclude that |f| is differentiable at a when f(a) < 0.

Since we have covered both cases, we can conclude that if f is differentiable at a and f(a) ≠ 0, then |f| is also differentiable at a.

Note: It's worth mentioning that at the point where f(a) = 0, |f| is not differentiable. The proof above is valid when f(a) ≠ 0.

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Given the test statistic and p-value for the alternative hypothesis μx # 45 are 1.78 and 0.08 respectively, if the alternative hypothesis were µx > 45 The correct answer is: b. The p-value would equal 0.04.

The p-value represents the probability of obtaining a test statistic as extreme as the observed one, assuming the null hypothesis is true. In this case, if the alternative hypothesis were changed to µx > 45 (one-sided alternative), the p-value would be different.

Since the original p-value was given as 0.08 for the alternative hypothesis µx ≠ 45 (two-sided alternative), we need to consider the area in the tail of the distribution corresponding to the new alternative hypothesis. In a one-sided test, we are only interested in one tail of the distribution.

If the original p-value was 0.08 for both tails, in the case of a one-sided test, the p-value would be half of that value since we are considering only one tail. Therefore, the new p-value would be 0.08 / 2 = 0.04.

So, the correct answer is:

b. The p-value would equal 0.04.

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Suppose the test statistic and p-value for the alternative hypothesis μx # 45 are 1.78 and 0.08, respectively. How would this p- value change if the alternative hypothesis were µx > 45 instead?

a. The p-value would not change.

b. The p-value would equal 0.04.

c. The p-value would equal 0.16.

d. The p-value would equal -0.08

Answer:

100/x/100

Step-by-step explanation:

Step-by-step explanation:

=========================================================

Explanation:

Focus solely on triangle ABD.

Let x be the length of AD. This is the unknown horizontal leg of the triangle. The vertical leg is known, so we'll say b = 16.

The hypotenuse is 20, so c = 20.

Use the pythagorean theorem to find x

a^2 + b^2 = c^2

x^2 + 16^2 = 20^2

x^2 + 256 = 400

x^2 = 400 - 256

x^2 = 144

x = sqrt(144)

x = 12

Segment AD is 12 cm long.

Answer:

See below (I hope this helps!)

Step-by-step explanation:

When dividing exponential terms of the same base, we can simply subtract the exponents, therefore:

\(\frac{x^{6} }{x^{8} } = x^{(6-8)} = x^{-2}\)

The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.

To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:

% Replace '12345678' with your actual student number

studentNumber = '12345678';

% Extract the first 4 digits as the first number

firstNumber = str2double(studentNumber(1:4));

% Extract the last 3 digits as the second number

secondNumber = str2double(studentNumber(end-2:end));

% Find the GCD using the Euclidean algorithm

gcdValue = gcd(firstNumber, secondNumber);

% Display the result

disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);

Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.

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Answer:

4/11, 3, 17/5, 3.421, 3.48

Step-by-step explanation:

4/11 = 0.36363636(repeating)

17/5 = 3.4

4/11 is the smallest given that is is not even 1

3 is smaller than 17/5, an easy way to know that is to simply 17/5 where it equals 3.4

17.5 or 3.4 is slightly smaller than 3.421, it is exactly 0.021 smaller than 3.421

3.421 is smaller than 3.48

least is 4/11 and greatest is 3.48, the in between numbers are all placed correctly in the answer section

Answer:

The answers from least to greatest are 3.36, 3.4, 3.421, 3.48

Step-by-step explanation:

17/5= 3 2/5, 3 2/5 = 3.4

3 4/11 = 3.36

3.421 stays the same

3.48 stays the same

I hope this helps and have a wonderful day!

Answer:

x=10

5x=50

2x=20

Step-by-step explanation:

110+5x+2x = 180  combine like terms and move the constants to the same side

7x=70

x = 10

5(10) = 50

2(10) = 20

Answer:

Number 3 is 8(2x−3)8(2−3)

Step-by-step explanation:

Answer:

12 soccer practices

Step-by-step explanation:

1 Soccer practice = 2 / 3 hour

We have 8 hours

8 / 2/3

multiply the top and bottom by 3 to get rid of the 3

8 * 3 = 24

2/3 * 3 = 2

24 / 2 = 12

Answer:

One way to answer your problem is by using proportions, and the following method can be done:

Step-by-step explanation:

\(\frac{1}{\frac{2}{3}}=\frac{x}{8}\)

Then that reduces to the following:

\(\frac{8}{\frac{2}{3}}=x=12\)

So the answer would be 12 practices.

For the exponential function:

g(x) = 14*(2)^x

We can see that:

a = 14, and b = 2.

A general exponential function is written as:

y = a*(b)^x

Where a is the inital value of the exponential function and b is the base.

Here we have the exponential function:

g(x) = 14*(2)^x

Comparing that to the general one, we can see that the initial value is 14 and the base is 2.

Then:

a = 14

b = 2

The correct option is the second one.

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In a simple linear regression model , if we change the input variable by 1 unit , output variable will change by its slope.

What is linear regression?

According on the value of another variable, a variable's value can be predicted using a linear regression analysis. The dependent variable is the one you're trying to forecast. The term "independent variable" refers to the variable you are using to forecast the value of the other variable.

Main Body:

For linear regression

Y=a + bx + error

If we neglect error

then Y=a + bx.

If x increases by 1

then Y = a +b(x+1) which implies

Y=a + bx + b.

So Y increases by its slope.

Hence their is an increase in the slope in y.

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