Is 1.0227 a rational number? Explain.

Answers

Answer 1

Answer:

A rational number

( it’s a terminating decimal, which means that the decimal has a definite ending point)

(I’m pretty sure...)


Related Questions

A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line. He must recalibrate his machines if the bolts are too long or too short. After sampling 121 randomly selected bolts off the assembly line, he calculates the sample mean to be 4.21 cm. He knows that the population standard deviation is 0.83 cm. Assuming a level of significance of 0.02, is there sufficient evidence to show that the manufacturer needs to recalibrate the machines? Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.​

Answers

The sample mean of 4.21 cm is significantly different from the specified target mean of 4.00 cm.

Step 1: State the hypotheses.

- Null Hypothesis (H₀): The mean length of the bolts is 4.00 cm (μ = 4.00).

- Alternative Hypothesis (H₁): The mean length of the bolts is not equal to 4.00 cm (μ ≠ 4.00).

Step 2: Compute the value of the test statistic.

To compute the test statistic, we will use the z-test since the population standard deviation (σ) is known, and the sample size (n) is large (n = 121).

The formula for the z-test statistic is:

z = (X- μ) / (σ / √n)

Where:

X is the sample mean (4.21 cm),

μ is the population mean (4.00 cm),

σ is the population standard deviation (0.83 cm), and

n is the sample size (121).

Plugging in the values, we get:

z = (4.21 - 4.00) / (0.83 / √121)

z = 0.21 / (0.83 / 11)

z = 0.21 / 0.0753

z ≈ 2.79 (rounded to two decimal places)

Step 3: Determine the critical value and make a decision.

With a level of significance of 0.02, we perform a two-tailed test. Since we want to determine if the mean length of the bolts is different from 4.00 cm, we will reject the null hypothesis if the test statistic falls in either tail beyond the critical values.

For a significance level of 0.02, the critical value is approximately ±2.58 (obtained from the z-table).

Since the calculated test statistic (2.79) is greater than the critical value (2.58), we reject the null hypothesis.

Conclusion:

Based on the computed test statistic, there is sufficient evidence to show that the manufacturer needs to recalibrate the machines. The sample mean of 4.21 cm is significantly different from the specified target mean of 4.00 cm, indicating that the machine's output is not meeting the desired length. The manufacturer should take action to recalibrate the machines to ensure the bolts meet the required length of 4.00 cm.

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What is the slope of a line parallel to the line whose equation is 6x + 5y = -5.
Fully simplify your answer.

Answers

                      ➢◇✳︎✧✥---------------------------------------------✥✧✳︎◇⤎

\(Hello\) \(There!\)

   We need to find the slope of the line that's parallel to 6x+5y=-5.

It's not hard, I promise! I'm going to take you through a few steps, and we'll find the answer.

Are you ready? Let's start. :)

\(Procedure:\)

➢ First, subtract 6x from both sides:

5y=-5-6x

✦ Switch the order of the terms:

5y=-6x-5

➢ Now, divide both sides by 5:

y=-6/5x-5/5

✦ Which is the same as

\(\bold{y=-\displaystyle\frac{6}{5} x-1}\)

➢ Part of the problem's already solved! :)

  Now, parallel lines have the same slope.

✦So the slope of the line parallel to 6x+5y=-5 is also:

◉ \(\bold{-\displaystyle\frac{6}{5}}\) ☑︎

Problem solved! :)

hope it's helpful!wishing you a great day!

\(Greetings !\)

     ◆     •     ❖ _____________________________________❖   •. ◆

Which of the following are disadvantages of the mode?
For many sets of data there are multiple modes.
The mode is affected by extremely large and small values.
For many sets of data there is no mode.
the mode can only be computed for interval-level data or higher

Answers

The disadvantages of the mode are: For many sets of data there is no mode.

The mode is a measure of central tendency that represents the most frequently occurring value in a dataset.

However, one of the disadvantages of the mode is that for many sets of data, there may not be a distinct mode. In such cases, the data may have a uniform distribution where all values occur with equal frequency, or it may have multiple modes with similar frequencies.

The mode is not affected by extremely large or small values. It only considers the frequency of values and not their magnitude. Therefore, extreme values do not influence the mode.

The statement that the mode can only be computed for interval-level data or higher is incorrect. The mode can be computed for any type of data, including nominal, ordinal, interval, and ratio data. It is applicable to categorical as well as numerical data.

The main disadvantage of the mode is that for many datasets, there may not be a distinct mode.

The correct option is: For many sets of data there is no mode.

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Someone please help me asap.

Someone please help me asap.

Answers

The equation of the relationship is f(200) = 0.75 * 200

Writing the equation of the relationship

From the question, we have the following parameters that can be used in our computation:

Total number of drinks = 200

Cost of each drink = 0.75

Using the above as a guide, we have the following:

f(x) = Cost of each drink * Total number of drinks

Where

f(x) = Total cost

Substitute the known values in the above equation, so, we have the following representation

f(200) = 0.75 * 200

Hence, the equation is f(200) = 0.75 * 200

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-2(4n-8) helphelphelp

Answers

Answer:

-8n+16. You can also put 16-8n

-2(4n-8) helphelphelp
-8n+16 might be your answer :)

The histogram below shows information about the daily energy output of a
solar panel for a number of days.
Calculate an estimate for the mean daily energy output.
If your answer is a decimal, give it to 1 d.p.
Frequency density
Energy output (kWh)
Answer>

The histogram below shows information about the daily energy output of asolar panel for a number of days.Calculate

Answers

Answer:

  4.5 kWh

Step-by-step explanation:

You want an estimate of the mean of the solar panel output represented by the given histogram.

Mean

The mean of the output values can be estimated as the weighted average of the middle of each interval, weighted by the area of the histogram in that interval.

The computation looks like ...

  \(\dfrac{.5\times1+1.5\times1+2.5\times1+3.5\times4+4.5\times4+5.5\times3+6.5\times 2+7.5\times2}{1+1+1+4+4+3+2+2}\\\\\\=\dfrac{81}{18}=4.5\)

The mean daily energy output of the solar panel is about 4.5 kWh.

<95141404393>

The histogram below shows information about the daily energy output of asolar panel for a number of days.Calculate

help pls!! I'll mark brainlist for good answer!!!

help pls!! I'll mark brainlist for good answer!!!

Answers

Answer:

For number 1: 2 For number 2:for the y a-xis (up and down) 7 and for the second x-axis(left and right) 10

Step-by-step explanation:

If you look at the first parallelogram the first as the numbers 21 and 6, on the second 7 which tells you they divided by 3, so 6 divided by 3 is 2. For Problem 2: They provide the numbers 14,8, and 20 on the second triangular prism it says 4 telling you it is divided by 2, so you get the numbers 7 and 10 for your answer.

write a division story for 40 divided by 4. draw a bar diagram to represent your story. then solve.

Answers

Graphs are used to represent information in bar graphs. Students can solve problems and comprehend relationships between quantities by using bar graphs to show such relationships.

What is bar diagram example?To produce powerful problem-solvers, bar graphs were created!One unknown quantity that students must find is often included in problems that have two known quantities.Students can solve problems and comprehend relationships between quantities by using bar graphs to show such relationships.Graphs are used to represent information in bar graphs.To represent value, it uses bars that reach varying heights.Bar graphs can be produced using stacked, horizontal, grouped, or vertical bars to compare results in many categories (bars containing multiple types of information).Data with just one variable and classifications on a spatial, quantitative, or temporal basis are shown using a straightforward bar chart.

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Use calculus to find the area A of the triangle with the given vertices. (0, 6), (2, −3), (3, 4)

Answers

The area of the triangle with the given vertices is 11.5 square units.

Define the area of triangle by vertices?

The area of a triangle can be calculated using the coordinates of its vertices using the following formula.

To find the area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃), we can use the following formula:

A = (x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂))/2

Using this formula with the given vertices (0, 6), (2, −3), and (3, 4), we get:

A = (0(-3 − 4) + 2(4 − 6) + 3(6 − (-3)))/2

A = (0 - 4 + 27)/2

A = 23/2

A = 11.5

Therefore, the area of the triangle with the given vertices is 11.5 square units.

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PLEASE HELP ILL GIVE BRAINLIAST
CD is the perpendicular bisector of AB.
AD = 6x – 2 and DB = 2x + 18.
Determine the value of x.
x = [ ? ]
A.
D
B.
Enter

PLEASE HELP ILL GIVE BRAINLIAST CD is the perpendicular bisector of AB.AD = 6x 2 and DB = 2x + 18.Determine

Answers

Answer:

Step-by-step explanation:

48-5+ 2x -7 -54 ABE 39. - x=2. 66 - 12 = 54. BC, 15. AB=5 =BC. 6x = 66. - They are. XH. Not. 2) Find the coordinates of the midpoint of the segment with the given endpoints. ... j) Concurrency of Perpendicular Bisectors of a Triangle Theorem: ... Find AE. 40. Find AD. 76. 76. Sy + 20. Find BC. 54. Find AC. 80. Find CD. 76.

A long-sleeve shirt has 8 front buttons and 2 cuff buttons; a short-sleeve shirt has 6 front buttons and no cuff buttons. The factory which makes ‘Slimboy Shirts’ uses 10 times as many front buttons as cuff buttons. What is the ratio of long-sleeve shirts to short-sleeve shirts produced by the factory?

Leave your ratio in its simplest form.

Answers

Answer:

ratio of long-sleeved shirts to short-sleeved shirts is 1:2 this is my answer that I thought of if you don't feel comfortable believing me just wait for another person to answer and see what they say.

Step-by-step explanation:

The ______ is a measure of the error in using the estimated regression equation to predict the values of the dependent variable in a sample.
A. sum of squares due to regression (SSR)
B. sum of squares due to error (SSE)
C. erorr term
D. residual

Answers

B. squares due to error (SSE) is the correct option.

What is squares due to error (SSE)?

Sum Squared Error (SSE) is an accuracy metric that squares the mistakes before adding them. When the data points are of equal magnitude, it's utilised to assess the forecasting model's accuracy. The forecast is more precise the lower the SSE. Choosing the forecasting model that best suits your data will be made easier for you if you are aware of this accuracy statistic.

The sum of squares due to error (SSE) is a measure of the error in using the estimated regression equation to predict the values of the dependent variable in a sample.

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Which equation represents the graphed function? 5 O y = 4x - 2 O y=-4x-2 O y = x=2 5 4 3 2 1 23 (4, -1) O y=-x-2 0,-2) 097​

Which equation represents the graphed function? 5 O y = 4x - 2 O y=-4x-2 O y = x=2 5 4 3 2 1 23 (4, -1)

Answers

Answer :The correct equation is the third option : y = (1/4)x - 2

\( \rm\frac{d}{dx} \left ( \bigg( \int_{1}^{ {x}^{2} {}{} } \frac{2t}{1 + { t}^{2} } dt\bigg) \bigg( \int_{ 1 }^{ lnx} \frac{1}{(1 + {t)}^{2} }dt \bigg)\right) \\ \)​

Answers

Applying the product rule gives

\(\displaystyle \frac{d}{dx}\int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \frac{d}{dx}\int_1^{\ln(x)}\frac{dt}{(1+t)^2}\)

Use the fundamental theorem of calculus to compute the remaining derivatives.

\(\displaystyle \frac{4x^3}{1+x^4} \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \frac{1}{x(1+\ln(x))^2}\int_1^{x^2}\frac{2t}{1+t^2}\,dt\)

The remaining integrals are

\(\displaystyle \int_1^{\ln(x)}\frac{dt}{(1+t)^2} = -\frac1{1+t}\bigg|_1^{\ln(x)} = \frac12-\frac1{1+\ln(x)}\)

\(\displaystyle \int_1^{x^2}\frac{2t}{1+t^2}\,dt=\int_1^{x^2}\frac{d(1+t^2)}{1+t^2}=\ln|1+t^2|\bigg|_1^{x^2}=\ln(1+x^4)-\ln(2) = \ln\left(\frac{1+x^4}2\right)\)

and so the overall derivative is

\(\displaystyle \frac{4x^3}{1+x^4} \left(\frac12-\frac1{1+\ln(x)}\right) + \frac{1}{x(1+\ln(x))^2} \ln\left(\frac{1+x^4}2\right)\)

which could be simplified further.

I need help solving this

I need help solving this

Answers

56.5 cm²

Given

Radius : 6 cm

To find

Area of the semicircle

we know that

Area of a semicircle = πr²/2

Inserting the value of radius

Area of the given semicircle = (3.14 x 6cm x 6cm)/2 Area of the given semicircle = 113.04cm²/2 Area of the given semicircle = 56.5 cm²

I NEED HELP ASAP choose one of the multiple choice

I NEED HELP ASAP choose one of the multiple choice

Answers

Answer:

B. Square both sides of the equation.

Step-by-step explanation:

You cannot do anything to the equation unless you square both sides to eliminate the square root on the left (squaring each individual term of the equation does not help; you need to square the entire square root to eliminate it).

Hope this helps!

What is the length of the segment joining the points at (−4, 1) and (3, 7)? Round to the nearest tenth if necessary. Enter your answer in the box. units: __

Answers

Answer:

Image result for length of the segment

The length of this line segment is the distance between its endpoints A and B.

Step-by-step explanation:

Answer: 9.2

√7-1^2 +  3-(-4)^2

√6^2 +  7^2

√36 + 49

√85 or 9.2

What is the length of the segment joining the points at (4, 1) and (3, 7)? Round to the nearest tenth

Please please please help me
I really need to pass this I will give brainliest and a lot of points please just help me solve this correctly

Please please please help me I really need to pass this I will give brainliest and a lot of points please

Answers

The length of side AB is about 5.87 units.

How to find the side of a right triangle?

The triangle ABC is a right angle triangle. A right angle triangle is a triangle that has one of its angles as 90 degrees.

Therefore, let's find the length AB in the right triangle.

Using trigonometric ratios,

cos 33 = adjacent / hypotenuse

Therefore,

Adjacent side = AB

hypotenuse side = 7 units

cos 33° = AB / 7

cross multiply

AB = 7 cos 33

AB = 7 × 0.83867056794

AB = 5.87069397562

AB = 5.87 units

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From a collection of 52 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possible?

Answers

Answer:

132,600 possibilities

Step-by-step explanation:

The first one chosen can be 1 of 52

The 2nd one chosen is 1 out 51

And the 3rd chosen is 1 out 50

So...

52 x 51 x 50 = 132,600

There are 22,100 groups of 3 customers that are possible from the given collection of 52 store customers.

What is a combination?

It is an arrangement of a set of numbers from a total set where the order of the set is not relevant.

We have,

The number of groups of 3 customers that can be chosen from a collection of 52 store customers can be calculated using the combination formula:

nCr = n! / r!(n - r)!

where n is the total number of customers (52) and r is the number of customers chosen (3).

Substituting the values, we get:

52C3 = 52! / 3!(52 - 3)!

52C3 = 52! / 3!49!

52C3 = (52 × 51 × 50) / (3 × 2 × 1)

52C3 = 22,100

Therefore,

There are 22,100 groups of 3 customers that are possible from the given collection of 52 store customers.

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During a single day at the radio station WMZH, the probability that a particular song is played is 1/6. What is the probability that this song will be played on exactly 6 days out of 7 days? Round your answer to the nearest thousandth.

Answers

Around 0.000125 or 0.0125% of the time, the song will be played exactly six out of seven days.

Every day represents a trial in this binomial probability issue, and there are only two potential results:

either the music is played (a success), or it is not (failure). We're looking for the likelihood that exactly 6 out of 7 trials will be successful.

The likelihood of success (performing the song) is 1/6, while the likelihood of failure (not playing the song) is 1 - 1/6 = 5/6, on any given day.

We can use the binomial probability formula to find the probability of exactly 6 successes in 7 trials:

P(6 successes) = (7 choose 6) * (1/6)⁶ * (5/6)¹

where (7 choose 6) is the number of ways to choose 6 days out of 7 to play the song, and is calculated as:

(7 choose 6) = 7! / (6! * 1!) = 7

Plugging in the values, we get:

P(6 successes) = 7 * (1/6)⁶ * (5/6)¹

P(6 successes) ≈0.00012502

Therefore, the probability that the song will be played on exactly 6 days out of 7 is approximately 0.000125 or 0.0125%.

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find the missing probability. P(A)=1/5, P(A u B)=12/25, P(A n B)=7/100, P(B)=?

Answers

Answer:  7/20

Work Shown:

P(A u B) = P(A)+P(B)-P(A n B)

12/25 = 1/5+P(B)-7/100

12/25 = 20/100+P(B)-7/100

12/25 = P(B)+13/100

12/25-13/100 = P(B)

48/100-13/100 = P(B)

35/100 = P(B)

7/20 = P(B)

P(B) = 7/20

To send a telegram,the first 18 words cost 35kobo and each additional word cost 2 1/2. how much will it cost to send a telegram of 48 words?​

Answers

Answer:

110 kobo

Step-by-step explanation:

first 18 = 35 kobo

48-18 = 30 words left

30x2.5  = 75 kobo

35 + 75 = 110 kobo

Rewrite the following equation in slope-intercept form.

y + 8 = –3(x + 7)


Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answers

Answer: y = -3x - 21

Step-by-step explanation:

Slope intercept form: y = mx + b

m is the slope, and b is the y-intercept.

y + 8 = -3(x + 7)

Start by distributing -3 into the parenthesis.

y + 8 = -3x - 21

subtract 8 from both sides to get the final answer.

y = -3x - 29

Answer:

Slope-intercept form,

y = -3x - 29

Step-by-step explanation:

Now we have to,

→ Rewrite the given equation in the slope-intercept form.

The slope-intercept form is,

→ y = mx + b

The equation is,

→ y + 8 = -3(x + 7)

Then the value of y will be,

→ y + 8 = -3(x + 7)

→ y + 8 = -3x - 21

→ y = -3x - 21 - 8

→ [ y = -3x - 29 ]

Hence, answer is y = -3x - 29.

What is the exact value of sin pi/3?

Answers

The exact value of sin(pi/3) is √3. By definition, the sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse. Therefore, sin(pi/3) = √3/1 = √3.

The exact value of sin(pi/3) can be determined using trigonometric properties and identities.

First, we know that pi/3 is equivalent to 60 degrees. In a unit circle, the point corresponding to 60 degrees forms an equilateral triangle with the origin and the x-axis. This triangle has side lengths of 1, 1, and √3.

To find the sine of pi/3, we consider the side opposite the angle (pi/3) in the triangle. In this case, the opposite side has a length of √3. The hypotenuse of the triangle is 1, as it is the radius of the unit circle.

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Can y’all help me on question 35?!

Can yall help me on question 35?!

Answers

Answer:

c

Step-by-step explanation:

C becasue 1 week = 15 mulitipication facts memorized

It’s D because w is number of weeks so c is wrong

what is the radius of a circle whose equation is x2y28x6y210 2 units 3 units 4 units 5 units

Answers

The radius of the given circle is 2 units.

Here, we are given an equation of a circle as follows-

\(x^{2}+ y^{2} + 8x - 6y + 21 = 0\)

The general form of the equation of a circles is -

\((x- h)^{2}+ (y-k)^{2} = r^{2}\)

where (h, k) are the coordinates of the center of the circle and r is the radius of the circle.

Let us convert the given equation into the general form by completing the squares as follows -

\(x^{2}+ y^{2} + 8x - 6y + 21 = 0\)

\(x^{2}+ (2*4)x+ y^{2} - (2*3)y + 21 = 0\)

\(x^{2}+ (2*4)x+ 16 -16+ y^{2} - (2*3)y + 9 - 9+ 21 = 0\)

\([x^{2}+ (2*4)x+ 16] -16+ [y^{2} - (2*3)y + 9] - 9+ 21 = 0\)

\((x+4)^{2} -16+ (y - 3)^{2} - 9+ 21 = 0\)

\((x+4)^{2} + (y - 3)^{2} = 16 + 9 - 21\)

\((x+4)^{2} + (y - 3)^{2} = 4\)

\((x+4)^{2} + (y - 3)^{2} = 2^{2}\)

Thus, we have obtained the equation of the circle in the general form. From this, we can observe that the center coordinates will be (-4, 3) and the radius of the circle will be 2 units.

Therefore, the radius of the given circle is 2 units.

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Two puppies, Ruth and Scoonsie, are playing together. Scoonsie weighs
11
1111 kilograms, and Ruth is lighter than Scoonsie.
Write an inequality that describes

rr, Ruth's weight in kilograms.

Answers

Given inequality statement solution is :-  Ruth's weight, denoted by 'rr,' is less than 11,111 kilograms.

The state of not being equal, especially in status, rights, and opportunities1—is a concept very much at the heart of social justice theories. However, it is prone to confusion in public debate as it tends to mean different things to different people.

There are five systems or types of social inequality: wealth inequality, treatment and responsibility inequality, political inequality, life inequality, and membership inequality. Political inequality is the difference brought about by the ability to access governmental resources which therefore have no civic equality.

Let's denote Ruth's weight as 'rr' in kilograms. Since Ruth is lighter than Scoonsie, we can write the following inequality:

rr < 11,111 kilograms

This inequality states that Ruth's weight, denoted by 'rr,' is less than 11,111 kilograms.

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En un triatlón, Jenny nadó durante 1 hora, anduvo en bicicleta durante 1,75 horas y corrió durante 1 hora. Su velocidad promedio en bicicleta fue 2 veces su velocidad promedio para correr, y su velocidad promedio para correr fue 8 veces su velocidad promedio para nadar. La distancia total del triatlón fue de 55,5 kilómetros. Escribe una ecuación y resuélvela para encontrar la velocidad de nado promedio de Jenny en kilómetros por hora. Explique su ruta de solución y el razonamiento detrás de su trabajo.

Answers

Jenny's Average swimming speed is 1.5 km/h.

Jenny's average swimming speed as S (in km/h). We can then use the given information to set up equations and solve for S.

We know that Jenny swam for 1 hour, so the distance she swam is given by the formula: Distance = Speed * Time.

Thus, the distance she swam is S * 1 = S km.

Next, we know that her average running speed is 8 times her average swimming speed. Therefore, her average running speed is 8S km/h.

Since she ran for 1 hour, the distance she ran is 8S * 1 = 8S km.

Furthermore, we are given that her average bicycling speed is 2 times her average running speed. Therefore, her average bicycling speed is 2 * 8S = 16S km/h.

She biked for 1.75 hours, so the distance she biked is 16S * 1.75 = 28S km.

The total distance of the triathlon is the sum of the distances for each segment: Distance(swimming) + Distance(running) + Distance(biking) = 55.5 km.

Therefore, we can write the equation:

S + 8S + 28S = 55.5.

Simplifying the equation, we get:

37S = 55.5.

To solve for S, we divide both sides of the equation by 37:

S = 55.5 / 37 = 1.5.

Thus, Jenny's average swimming speed is 1.5 km/h.

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the Jones family received 19 pieces of mail on November 3. The mail consisted of letters, bills,magazines,and ads. How many letters did they receive if they received five more ads than bills, the same number of letters as magazines, and three more bills than magazines?​

Answers

Answer:

2 letters.

Step-by-step explanation:

Consider the number of bills as x.

Since they recieve "5 more ads than bills" ads is x+5.

And since they recieved "three more bills than magazines," magazines is x-3.

And since they recieved the same number of magazines and letters, letters is also x-3.

bills=x

ads=x+5

magazines=x-3

letters=x-3.

19 pieces of mail = bills +ads + magazines + letters

plug in the information: 19 = x + (x+5) + (x-3) + (x-3)

group the x's and add the numbers: 19 = 4x -1

solve for x:  x=5

We are still not done since x is the number of bills, not letters.

Plug the value of x into "letters = bills-3."

so...

Letters = 5 - 3

Letters = 2.

The Jones family received 19 pieces of mail on November 3 includes 2 number of letters, 5 number of bills, 2 number of magazines, 10 number of ads .

Let's break down the information given in the problem:

The Jones family received a total of 19 pieces of mail.

They received more ads than bills (specifically, 5 more ads than bills).

They received the same number of letters as magazines.

They received 3 more bills than magazines.

Let's use variables to represent the quantities:

Let A represent the number of ads.

Let B represent the number of bills.

Let L represent the number of letters.

Let M represent the number of magazines.

From the information given, we can set up the following equations:

A + B + L + M = 19 (total pieces of mail)

A = B + 5 (more ads than bills)

L = M (same number of letters as magazines)

B = M + 3 (3 more bills than magazines)

Now, let's solve this system of equations step by step:

From equation (4), we know that B = M + 3. We can substitute this into equation (2):

A = B + 5

A = (M + 3) + 5

A = M + 8

Now we have expressions for A, B, and L in terms of M:

A = M + 8

B = M + 3

L = M

Substitute these expressions into the total mail equation (equation 1):

A + B + L + M = 19

(M + 8) + (M + 3) + M + M = 19

4M + 11 = 19

4M = 8

M = 2

Now that we know M (number of magazines), we can find the other quantities:

L = M = 2

B = M + 3 = 5

A = M + 8 = 10

So, the Jones family received:

2 letters

5 bills

2 magazines

10 ads

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Let Y1,Y2,....,Y5 be a random sample of size 5 from a normal population with mean 0 and variance 1 and let Y bar=(1/5)sumation from i=1 to 5 Yi. Let Y6 be another independent observation from the same population. What is the distribution ofa) W= sumation from i=1 to 5 of Yi^2 ? Why ?b) U= sumation from i=1 to 5 of ( Yi- Y bar)^2? Why?c) sumation from i=1 to 5 of ( Yi- Y bar)^2 + Y6^2 ? Why?

Answers

a) From the given information, \(Y_{1}, Y_{2},...........Y_{5}\)

be a random sample of size 5 from a normal population with mean 0 and variance 1. Hence,

\(W=(\sum_{i=1}^5 Y_{i}^2)\sim X_{5}^2\)

b) From the given information, the random variable is   \(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

and  \(Y_{1}, Y_{2},...........Y_{5}\)

representing the standard normal variables. Hence,

.\(U=(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2) \sim X_{5}^2\)

c) From the given information,\(Y_{1}, Y_{2},...........Y_{5}\)

representing the standard normal variables and moreover, \(Y_{6}\)

is independent standard normal variable. Hence,  \(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\sim X_{5}^2\)

and

.\(Y_{6}^2\sim X_{1}^2\)

What is Chi-square distribution?

Chi-square distribution with k degrees of freedom is defined as the sum of the k standard normal variables. This is also defined as the square of the deviations taken from the mean. Chi-square distribution is used for testing goodness of fit and independence in contingency tables.

• If  \(z_{1}, z_{2},...........z_{k}\)

are independent standard normal variables, then

\(\sum_{i=1}^k z_{i}^2\sim X_{k}^2\)

• If   \(X\sim X_{m}^2\)

and   \(Y\sim X_{n}^2\)

, then

\((X+Y)\sim X_{m+n}^2\)

Step: 1

(a)

The distribution of    \(\sum_{i=1}^5 Y_{i}^2\)

is obtained below:

From the given information, \(Y_{1}, Y_{2},...........Y_{5}\)

be a random sample of size 5 from a normal population with mean 0 and variance 1. Hence,

\(W=(\sum_{i=1}^5 Y_{i}^2)\sim X_{5}^2\)

The random variable,  \(W=\sum_{i=1}^5 Y_{i}^2\)

representing the sum of squares of standard normal variables and hence, the distribution of   \(W=\sum_{i=1}^5 Y_{i}^2\)

is identified as chi-square distribution.

Hint:

Use chi-square distribution to find the distribution of

.\(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

Step: 2

(b)

From the given information, the random variable is   \(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

and  \(Y_{1}, Y_{2},...........Y_{5}\)

representing the standard normal variables. Hence,

.\(U=(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2) \sim X_{5}^2\)

The random variable    \(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

representing the sum of squares of deviations taken from the mean for 5 standard normal variables and hence, the distribution of
\(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

is chi-square distribution with 5 degrees of freedom.

Hint:

Use       \((X+Y)\sim X_{m+n}^2\)  

to find the distribution of

\(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2+Y_{6}^2\)

Step: 3

(c)

From the given information,\(Y_{1}, Y_{2},...........Y_{5}\)

representing the standard normal variables and moreover, \(Y_{6}\)

is independent standard normal variable. Hence,  \(U=\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\sim X_{5}^2\)

and

.\(Y_{6}^2\sim X_{1}^2\)

Therefore,

\(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2+Y_{6}^2\sim X_{5+1}^2\)

\(\sim X_{6}^2\)

The distribution of    \(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2+Y_{6}^2\)

is identified as chi-square distribution with degrees of freedom is obtained by adding the degrees of freedom of\(\sum_{i=1}^5 (Y_{i} - \bar{Y})^2\)

and the degrees of freedom of   \(Y_{6}^2\).

The distribution of   \(W=\sum_{i=1}^5 Y_{i}^2\)

is chi-square distribution with 5 degrees of freedom.

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