Jake runs at 4 m/s along a train flatcar that moves at 10 m/s in the opposite direction. What is Jake's speed relative to the ground?

In this experiment, rubbing a plastic bag against wool allowed electrons to move back and forth between the two, creating a negative charge on the bag. When the negatively charged bag was brought close to the neutral PAN, the bag's negative charge attracted the PAN's electrons, separating the two charges and leaving the PAN with a positive charge. On touching the pan the surplus positive charge was neutralized, creating a spark.

When the pan was brought up to the nose a slight jolt was felt and a crackling sound was heard. This resulted in the excess charge in the pan being carried through the air to the nearest conductor, the person holding the pan.

The spark and shock were easy to see in a dark environment as there was no ambient light to obstruct the view. The blow was more pronounced and distinct, and the spark appeared as a bluish glow.

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Answer:

answer is an ASTEROID

Explanation:

Iridium is a material that forms at very high temperatures, which is why its presence shows that in the impact zone the temperature rose a lot, so we can imagine that the impact was by a body traveling at high speed, which is consistent with a body that comes from space.

An asteroid is a celestial body of some size that when entering the atmosphere heats up and collides with the Earth, leaving a crater that in general is much larger than the diameter of the object.

A meteorite is a small fraction of an asteroid that has been separated by the pressure of the sun, the attraction of the Earth, Moon or another massive body or a combination of these effects, in general, meteorites are small and when they enter the atmosphere They are consumed by heat and very few reach the surface of the Earth, those that do reach are very small.

Therefore due to the size of the crater and the existence of many dead animals around the body must have been very heavy, so the correct answer is an ASTEROID

Answer:

B) An asteroid impact

Explanation:

Answer:

No

Explanation:

Some objects gain momentum.

Answer:

B. False

Hope you could understand.

If you have any query, feel free to ask.

Answer:

its lost 91

Explanation:

Answer: Moisture and food (bread)

Explanation:

Mould grows best in humid, damp air/wet conditions.

Since the bread is moist it will provide humidity for the mould as well as food.

A container with a cover would not be a favoring condition as mould needs oxygen to grow and survive.

Answer:

A) At first, the water was a gas. Later, it was a liquid.

Explanation:

The molecules of a solid cant move at all, so therefore we can knock out B and C. Moleculaes move more freely in a gas form than in a water form, so therefore the firt form has to be a gas, so knock out the answer choice D, which keaves you with A. I hope this helps :)

Answer:

At first, the water was a gas. Later, it was a liquid.

Explanation:

\( \huge\longrightarrow{ \mathfrak{ \underline{ Answer }}}\)

The Sunlight is actually white in colour, but it's a mixture of seven different coloured lights of different wavelengths, and when sunlight is passed through a prism, it splits into its constituent units forming a spectrum when observed on a screen. And this shows that the Sunlight is composed of seven different coloured lights .

____________________________

They are :

____________________________

\(\mathrm{ \#TeeNForeveR}\)

The output response v(t) to a unit step input, we first express the transfer function H(s) in partial fraction form. After solving for constants A and B, we take the inverse Laplace transform of each term to get h(t). For the sinusoidal steady-state response to input vi(t) = 10 cos(40t + 60°) V, we multiply Vi(s) by H(s) and simplify V(s). Then, we use inverse Laplace transform properties to find the steady-state response v(t). The sinusoidal steady-state response to the input voltage vi(t) = 10 cos(40t + 60°) V is given by v(t) = (10 / ((s + 1)(s + 11))) * (s + 10) * (10 \(e^{(-20t)}\) + 200t \(e^{(-20t)}\)).

To find the output response v(t) to a unit step input, we need to take the inverse Laplace transform of the transfer function H(s) =\((s + 10) / (s^2 + 18s + 11).\)
Step 1: Write the transfer function in partial fraction form:
H(s) = A / (s + 1) + B / (s + 11)
Step 2: Multiply both sides of the equation by the denominator:
(s + 1)(s + 11) H(s) = A(s + 11) + B(s + 1)
Step 3: Set s = -1 and solve for A:
(-1 + 11) H(-1) = A(-1 + 11) + B(-1 + 1)
10 H(-1) = 10A
A = H(-1)
Step 4: Set s = -11 and solve for B:
(-11 + 1) H(-11) = A(-11 + 11) + B(-11 + 1)
-10 H(-11) = -10B
B = H(-11)
Step 5: Substitute the values of A and B back into the partial fraction form:
H(s) = H(-1) / (s + 1) + H(-11) / (s + 11)
Step 6: Take the inverse Laplace transform of each term:
h(t) = \(H(-1) e^{(-t)} + H{(-11)} e^{(-11t)}\)
Since we have a unit step input, the Laplace transform of a unit step function is 1/s. Therefore, the Laplace transform of the unit step input is U(s) = 1/s.
Step 7: Multiply the transfer function H(s) by the Laplace transform of the unit step input:
V(s) = H(s) U(s)
V(s) = (H(-1) / (s + 1) + H(-11) / (s + 11)) * (1/s)
Step 8: Take the inverse Laplace transform of V(s) to find the output response v(t):
h(t) = \(H(-1) e^{(-t)} + H{(-11)} e^{(-11t)}\)
Now, let's find the sinusoidal steady-state response to an input voltage vi(t) = 10 cos(40t + 60°) V.
Step 1: Write the input voltage in phasor form:
Vi(s) = 10 / (\(s^2\) + 40s + 1600)
Step 2: Multiply Vi(s) by the transfer function H(s):
V(s) = H(s) Vi(s)
V(s) = (s + 10) / (s^2 + 18s + 11) * (10 / (s^2 + 40s + 1600))
Step 3: Simplify V(s) by canceling out common factors and combining terms:
V(s) = (s + 10) / ((s + 1)(s + 11)) * (10 /\((s + 20)^2\))

Step 4: Take the inverse Laplace transform of V(s) to find the steady-state response v(t):
\(v(t) = (10 / ((s + 1)(s + 11))) * (s + 10) * (10 e^{(-20t)} + 200t e^{(-20t)})\)
Note: In this step, we use the inverse Laplace transform properties to simplify the expression.

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Answer:

A centripetal force

Explanation:

The type of force in the given scenario is tension. The correct option is c.

Tension is defined in physics as the pulling force conveyed axially by a string, cable, loop, or similar material, or by every end of a rod, truss member, or similar three-dimensional object.

Tension can also be defined as the action-reaction pair of forces acting at each end of said elements.

Newton's second law states that the tension in the rope must equal the weight of the backed mass.

Tension, the normal force, and friction are all examples of contact forces.

Since the weight is not moving, the acceleration is zero. Even if the acceleration is not zero, this equals zero.

Thus, the correct option is c.

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Your question seems incomplete, the missing options are:

Answer:

Nitrogen is de solvent while others are the solute

Answer:

The solar nebula became hot and dense because of that it pulling in more gas. This flattened into a rotating disk. It  spun  faster and faster, forming the Sun.

Explanation:

hope this helps

The solar nebula became hot and dense because of that it pulling in more gas. This flattened into a rotating disk. It  spun  faster and faster, forming the Sun. This order did the events forming our solar system occur.

In the so-called nebular hypothesis of the genesis of the solar system, the Sun and planets originated by condensation from a gaseous cloud. In 1734, Swedish philosopher Emanuel Swedenborg claimed that the planets arose from a nebular crust that enveloped the Sun before breaking apart. Immanuel Kant, a German philosopher, proposed in 1755 that the Sun and planets were created by a slow rotating nebula that was eventually pushed together by its own gravitational force and flattened into a spinning disc. In 1796, the French astronomer and mathematician Pierre-Simon Laplace presented a similar concept, but with the planets forming before the Sun. The Kant-Laplace theories were criticised by the British physicist James Clerk in the late nineteenth century.

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Answer:

Momentum is mass*velocity. Cheetah: 74*31 = 2294 kg-m/s.

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are \(\dfrac{\lambda}{2}\)

Thus; for both speakers; the wavelength of the sound is:

\(\dfrac{\lambda}{2} = (10+30) cm\)

\(\dfrac{\lambda}{2} = (40) cm\)

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

\(\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o\)

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

\(\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o\)

\(\pi \ rad = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o\)

\(\pi \ rad = \dfrac{2 \pi}{8}+ \Delta \phi_o\)

\(\pi \ rad = \dfrac{ \pi}{4}+ \Delta \phi_o\)

\(\Delta \phi_o = \pi -\dfrac{ \pi}{4}\)

\(\Delta \phi_o = \dfrac{ 4\pi - \pi}{4}\)

\(\Delta \phi_o = \dfrac{ 3\pi}{4} \ rad\)

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

\(\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o\)

\(\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad\)

\(\Delta \phi = \dfrac{3 \pi}{4} \ rad\)

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

\(A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)\)

\(A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)\)

\(A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)\)

A = 0.765a

The expressions for sound interference allows to find the amplitude for the wave when the two speakers are together is:

Given parameters

To find

The interference phenomenon occurs when two coherent waves have paths of different lengths to reach a point, we have two extreme cases:

                        Δr = \(2n \ \frac{\lambda}{2}\)  

                        Δr = \((2n+1) \ \frac{\lambda}{2}\)  

Where Δr₁ and Δr₂ are the path difference, λ is the wavelength and n is an integer.

Let's start by looking for the wavelength that the speakers emit, see attached.

Destructive Interference       Δr₂ = (2n + 1) la / 2

Constructive interference    Δr₁ = 2n lam / s

Let's solve the system.

               Δr₂ - Δr₁ = \(\frac{\lambda}{2}\)  

Let's calculate

              30 - (-10) = \(\frac{\lambda}{2}\)  

              λ = 80 cm

Now we can use the general relation for the path change and the phase.

             \(\frac{\delta r}{\lambda } = \frac{\phi - \phi_o}{2\pi }\)

             \(\phi = \frac{\Delta r \ 2\pi }{\lambda } + \phi_o\)fi = Dr 2pi / lam + fio

Where \(\phi\) is the possible initial phase difference between the speakers.

Let's find the initial phase difference emitted by the two speakers, let's use destructive interference, for which the phase difference is:

             \(\phi = \pi \ rad\)  

Let's calculate

             \(\pi = \frac{2\pi }{80} \ 10 + \phi_o \\\phi_o = \pi - \frac{\pi}{4}\)

              \(\phi_o\)  = ¾ \(\pi\) rad

This value is kept constant, let's find the phase angle for when the speakers are together, so the path difference is zero Δr = 0      

            \(0= \frac{\phi - \phi_o}{2\pi }\\\phi = \phi_o\)

            \(\phi\) = ¾ pi

The amplitude of the sound wave is

            A = 2a cos \(\frac{\phi}{2}\)  

            A = 2a cos ⅜ π

           A = 0.765 a

In conclusion using the expression for sound interference we can find the amplitude for the wave when the two speakers are together is:

           A = 0.765a

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Answer:

60

Explanation:

(hint: speed = distance/time)

The average speed for this trip will be \(\rm 60 mile\ hr^{-1}\). The ratio of the total distance and time is average velocity.

The total distance traveled by an object divided by the total time taken is the average speed.

The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

The given data in the problem is;

t is the time taken = 5 hour

d is the distance tyravelled=300 miles

The average velocity is found as;

\(\rm v_{avg} = \frac{d_{total}}{t{total}} \\\\\ \rm v_{avg} = \frac{300}{5} \\\\ \rm v_{avg} = 60 mile\ hr^{-1}\)

Hence the average speed for this trip will be \(\rm 60 mile\ hr^{-1}\)

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The mass of the asteroid is \(2.1\times10^{5}\)Kg.

Mass is one of the fundamental quantities of physics and a fundamental property of matter. We can define mass as a measure of the amount of matter in a body. The SI unit of mass is the kilogram (kg).  The bit mass  does not change at any time. Only in certain extreme cases, when enormous amounts of energy are given or taken from the body. For example: in a nuclear reaction, a small amount of matter is converted into a huge amount of energy, which reduces the mass of the matter. The measurement system uses the following mass units: gram (g), kilogram (kg) and ton (t).

Therefore,

r = 1 250 m

m1 = 2.50 kg

Fg =  0.225 n

by using Newton's law of universal gravitation

\(F_{g} =G \frac{m_{1 }m_{2} }{r_{2} }\)

\(m_{2} = \frac{F_{g}r_{2} }{Gm_{1} }\)

\(m_{2} =\frac{0.225\times1250}{6.6743\times 10^{11 }\times 2.50 }\)

\(m_{2} = 2.1\times10^{5} Kg.\)

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Answer:

Thermosphere A,B

Mesosphere B,C,D

Stratosphere D,E,F

Troposphere G

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Answer:

\(\boxed {\boxed {\sf v_i= 4 \ m/s}}\)

Explanation:

We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.

\(v_f= v_i + at\)

The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.

Substitute the values into the formula.

\(16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)\)

Multiply.

\(16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)\)

\(16 \ m/s = v_i + 12 \ m/s\)

We are solving for the initial velocity, so we must isolate the variable \(v_i\). Subtract 12 meters per second from both sides of the equation.

\(16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s\)

\(4 \ m/s = v_i\)

The cyclist's initial velocity is 4 meters per second.

Given:

R1 = 56Ω

R2 = 8 Ω

Give that the resistors are i

A graduated cylinder is used to measure volume in a laboratory setting.

A graduated cylinder is a cylindrical container with volume markings along its length. It is made from glass or plastic and is designed to accurately measure the volume of liquids. To use a graduated cylinder, the liquid is poured into the cylinder, and the volume is read by aligning the bottom of the meniscus (the curved surface of the liquid) with the appropriate marking on the cylinder. The graduated markings on the cylinder allow for precise volume measurements, making it a common tool in chemistry, biology, and other scientific disciplines where accurate volume measurements are required.

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The Direction of the Velocity Vector

Objects moving in uniform circular motion will have a constant speed. Velocity, being a vector, has both a magnitude and a direction. The magnitude of the velocity vector is the instantaneous speed of the object.

Six examples in which Physics has been used in daily life include:

Physics plays a major role in transportation, from the design of cars and airplanes to the operation of trains and buses. Physics is also used in communications, from the design of telephone networks to the operation of the internet.

Physics is used to generate energy from various sources, such as fossil fuels, nuclear power, hydroelectric power, and wind power. Physics is used in medical imaging, such as X-rays, CT scans, and MRI.

Physics plays a major role in construction, from the design of buildings and bridges to the materials used in construction.  Physics is also used in entertainment, from the design of amusement park rides to the operation of video games.

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Abiotic variables are particularly essential since they have a direct impact on organisms' ability to live.

The correct options are a. There are about 6.25 x 10^18 excess electrons on the object and c. There are about 1.6 x 10^19 excess electrons on the object.

If an object has a positive charge of +1 Coulomb, it means that it has an excess of positive charge. This implies that there is a deficiency of negatively charged electrons. Therefore, option a is true, stating that there are about 6.25 x 10^18 excess electrons on the object. Option c is also true, indicating that there are about 1.6 x 10^19 excess electrons on the object.

When an object has a positive charge, it means that it has lost electrons. The charge of one electron is approximately -1.6 x 10^-19 Coulombs. So, to obtain a charge of +1 Coulomb, a large number of electrons need to be removed from the object. Option a is true because it suggests that there are approximately 6.25 x 10^18 excess electrons on the object.

Option c is also true because it states that there are about 1.6 x 10^19 excess electrons, which is a possible scenario given the magnitude of the positive charge. Options b and d are incorrect because they suggest that electrons have been removed from the object, which contradicts the fact that the object has a positive charge.

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Answer: a balloon, of negligible mass, is submerged in a container of water and tied to a dynamometer as in Figure 3.53. What is the volume of the balloon if the dynamometer scale is in newtons?​

Explanation:

Answer:C car

Explanation:

The age of the cloth material is obtained from the calculation as  1843 years .

We know that the half life of a radioactive isotope refers to the time that is taken for only half of the number of the original radioactive isotopes that are present to remain in the sample.

We can be able to obtain the age of the cloth by looking at the amount of the radioactive carbon -14 that is still left in the sample. How do we do that? We have to turn to a formula that says;

0.693/\(t_{\frac{1}{2} }\) = 2.303/tlog (Ao/A)

\(t_{\frac{1}{2} }\) = half life of the material

t = age of the material

Ao = amount initially present

A = Amount present at time t

Then we have;

0.693/5730 = 2.303/tlog (Ao/0.8Ao)

1.21 * 10^-4 = 0.223/t

t = 0.223/1.21 * 10^-4

t = 1843 years

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The total work done by dissipative forces on the pendulum system between its initial and final states is 165 J.

Kinetic energy is the energy possessed by a moving object due to its motion. It is defined as one-half the mass of an object multiplied by the square of its velocity.

The kinetic energy of the wrecking ball at the final state is given by (1/2)mv², where v is its speed.

under which m is the object's mass and v is its velocity. The unit of kinetic energy is joules (J).

Assuming that the system is conservative (i.e., no external forces are acting on the system), the total work done by dissipative forces on the pendulum system between its initial and final states is equal to the total mechanical energy lost by the system due to dissipative forces. The mechanical energy of the system is given by the sum of its kinetic energy and potential energy:

E = K + U

At the initial state, the wrecking ball has only potential energy, which is equal to its gravitational potential energy:

U_i = mgh_i

where m is the mass of the ball, g is the acceleration due to gravity (9.8 m/s²), and h_i is the initial height of the ball (3.5 m). Therefore, the initial mechanical energy of the system is:

E_i = U_i = mgh_i

At the final state, the wrecking ball has both kinetic energy and potential energy. Its kinetic energy is given by:

K_f = (1/2)mv²

where v is the speed of the ball (5.0 m/s). Its potential energy is given by:

U_f = mgh_f

where h_f is the final height of the ball (2.0 m). Therefore, the final mechanical energy of the system is:

E_f = K_f + U_f = (1/2)mv² + mgh_f

Since the system is conservative, the total mechanical energy is conserved, i.e., E_i = E_f. Therefore, the total work done by dissipative forces on the pendulum system is:

W = E_i - E_f = mgh_i - (1/2)mv² - mgh_f

Plugging in the given values, we get:

W = (75 kg)(9.8 m/s²)(3.5 m) - (1/2)(75 kg)(5.0 m/s)² - (75 kg)(9.8 m/s²)(2.0 m)

W = 165 J

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Answer:

\(\vec{A} + \vec{B} = \vec{A} - \vec{B}\) if and only if \(\vec{B}\) is a zero vector.

Explanation:

An equation is true if and only if adding the same value to both sides of the equation (the value needs to be compatible) gives an equation that is also true.

Start with the \(\vec{A} + \vec{B} = \vec{A} - \vec{B}\).

This equation is true if and only if \(\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}\) (\(\vec{B}\) is added to both sides of the original equation.)

Vector addition and subtraction are associative. Therefore, \(\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}\) if and only if \(\vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right)\), which is equivalent to \(\vec{A} + 2\, \vec{B} = \vec{A}\).

\(\vec{A} + 2\, \vec{B} = \vec{A}\) if and only if \(\left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A}\) (\(\left(-\vec{A}\right)\)is added to both sides of this equation,) which is equivalent to \(2\, \vec{B} = \vec{0}\).

\(2\, \vec{B} = \vec{0}\) if and only \(\displaystyle \frac{1}{2} \cdot \left(2\, \vec{B}\right) = \frac{1}{2} \cdot \vec{0}\), which is equivalent to \(\vec{B} = \vec{0}\). That is: \(\vec{B}\) is the zero vector.

In other words:

\(\begin{aligned}& \vec{A} + \vec{B} = \vec{A} - \vec{B}\\ &\iff \left( \vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B} \\ &\iff \vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right) \\ & \iff \vec{A} + 2\, \vec{B} = \vec{A} \\ & \iff \left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A} \\ &\iff 2\, \vec{B} = \vec{0} \\ &\iff \frac{1}{2} \cdot 2\,\vec{B} = \frac{1}{2} \cdot \vec{0} \\ &\iff \vec{B} = \vec{0}\end{aligned}\).

Hence, \(\vec{A} + \vec{B} = \vec{A} - \vec{B}\) if and only if \(\vec{B}\) is the zero vector.