need help knowing if I got it right

Answer:

they want to know all the angles that are the same (congruent) s angle 8

Step-by-step explanation:

by inspection we can tell which are the same at angel 8

2,3,5 are all the same as angle 8

Answer:

A. 2000 square inches

B. 53.1 square inches

The perimeter of DEFG will be 2(√10+√17).

The cοοrdinate system that is mοst frequently emplοyed in three-dimensiοnal systems is called spherical cοοrdinates οf the system, represented as (r,Ф,∅ ).

The surface area in three dimensiοns is calculated using the spherical cοοrdinate system. Radial distance, pοlar angles, and azimuthal angle are the three numbers that these cοοrdinates indicate. Additiοnally knοwn as spherical pοlar cοοrdinates.

A 2-dimensiοnal graph with an x-axis and a y-axis is given.

A parallelοgram DEFG is drawn οn it with cο-οrdinates (2,1), (3,4), (7, 5) and (6,2) respectively.

Sο the perimeter will be DE = √10

DG=√17

EF = √17

FG=√10

Sο the perimeter will be 2(√10+√17).

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Answer:

158

Step-by-step explanation:

did you want an explanation?

Answer:

see below

Step-by-step explanation:

(x) = 7 - 2x

Let t(x) =0

0 = 7-2x

Subtract 7 from each side

-7 = -2x

Divide by -2

-7/-2 =-2x/-2

7/2 =x

h(x) = 4x + 2

Replace x with x+3

h(x+3) = 4(x+3) + 2

Distribute

            = 4x+12 +2

            =4x+14

Answer:

19) \(x=\frac{7}{2}\)

20) \(h(x+3)=4x+14\)

Step-by-step explanation:

19)

We have the function:

\(t(x)=7-2x\)

And we want to find x such that t(x)=0.

So, substitute 0 for t(x):

\(0=7-2x\)

Solve for x. Subtract 7 from both sides:

\(-7=-2x\)

Divide both sides by -2:

\(\frac{7}{2}=x\)

Flip:

\(x=\frac{7}{2}\)

20)

We have:

\(h(x)=4x+2\)

To find h(x+3), substitute (x+3) for x. This yields:

\(h(x+3)=4(x+3)+2\)

Multiply:

\(h(x+3)=4x+12+2\)

Add:

\(h(x+3)=4x+14\)

And we're done!

The volume of the parallelepiped is 55 cubic units.

In the question, we are asked to find the volume of the parallelepiped with adjacent edges PQ, PR, and PS, given P(−2, 1, 0), Q(5, 3, 5), R(1, 4, −1), S(3, 6, 2).

We first find the vectors:

PQ = Q - P

= < 5 - (-2), 3 - 1, 5 - 0 >

= < 7, 2, 5 >.

PR = R - P

= < 1 - (-2), 4 - 1, -1 - 0 >

= < 3, 3, -1 >.

PS = S - P

= < 3 - (-2), 6 - 1, 2 - 0 >

= < 5 , 5, 2 >.

The volume of the parallelepiped can be found using the triple product of these vectors, PS.( PQ * PR )

\(= \begin{vmatrix}5 & 5 & 2 \\ 7 & 2 & 5 \\ 3 & 3 & -1\end{vmatrix}\)

We solve this determinant to get the value of the volume of the parallelepiped.

\(= \begin{vmatrix}5 & 5 & 2 \\ 7 & 2 & 5 \\ 3 & 3 & -1\end{vmatrix}\\= 5\begin{vmatrix}2 & 5\\ 3 & -1\end{vmatrix} - 5\begin{vmatrix}7 & 5\\ 3 & -1\end{vmatrix} + 2\begin{vmatrix}7 & 2\\ 3 & 3\end{vmatrix}\\\)

= 5(2*(-1)-5*3)-5(7*(-1)-5*3)+2(7*3-2*3)

= 5(-17) - 5(-22) + 2(15)

= -85 + 110 + 30

= 55.

Thus, the volume of the parallelepiped is 55 cubic units.

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The length of the sides of the triangle QRT are;

QR = 3√5

RT = 9√2

TQ = 3√5

The formula for distance between two coordinates is;

D = √[(x₂ - x₁)² + (y₂ - y₁)²]

We are given the coordinates of the triangle QRT as;

Q = ( - 2 , - 1 )

R = ( 1 , 5 )

T = ( - 8 , - 4 )

Thus;

QR = √[(5 - (-1))² + (1 - (-2))²]

QR = √(3² + 6²)

QR = √45

QR = 3√5

Similarly;

RT = √[(-8 - 1)² + (-4 - 5)²]

RT = √(81 + 81)

RT = 9√2

Similarly, TQ is;

TQ = √[(-1 - (-4))² + (-2 - (-8))²]

TQ = √(9 + 36

TQ = √45

TQ = 3√5

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Let's begin by listing out the information given to us:

Number of flowers = 100

He wants to put the same number of flowers in each vase. To obtain this, we must find out the factor pairs of 100. We have:

For equation 1;

For equation 2;

For equation 3;

The probability at least 7 of the puppies will be male is approximately 0.0805 or 8.05%.

To determine the probability that at least 7 of the puppies will be male, we will have to use the binomial probability formula.

P(X ≥ k) = 1 - P(X < k)

where X is the number of male puppies, P is the probability of a puppy being male and k is the minimum number of male puppies required.

We can solve this problem by finding the probability that 0, 1, 2, 3, 4, 5, or 6 of the puppies are male, and then subtracting that probability from 1. We use the binomial distribution formula to find each of these individual probabilities.

P(X=k) = nCk * pk * (1-p)n-k

where n is the total number of puppies, p is the probability of a puppy being male (0.5), k is the number of male puppies, and nCk is the number of ways to choose k puppies out of n puppies. We'll use a calculator to compute each probability:

P(X < 7) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6)

P(X = 0) = 11C0 * 0.5⁰ * (1-0.5)¹¹ = 0.00048828125

P(X = 1) = 11C1 * 0.5¹ * (1-0.5)¹⁰ = 0.00537109375

P(X = 2) = 11C2 * 0.5² * (1-0.5)⁹ = 0.03295898438

P(X = 3) = 11C3 * 0.5³ * (1-0.5)⁸ = 0.1171875

P(X = 4) = 11C4 * 0.5⁴ * (1-0.5)⁷ = 0.24609375

P(X = 5) = 11C5 * 0.5⁵ * (1-0.5)⁶ = 0.35595703125

P(X = 6) = 11C6 * 0.5⁶ * (1-0.5)⁵ = 0.32421875

P(X < 7) = 0.00048828125 + 0.00537109375 + 0.03295898438 + 0.1171875 + 0.24609375 + 0.35595703125 + 0.32421875 = 1 - P(X < 7) = 1 - 1.08184814453 = -0.08184814453 ≈ 0.0805

Therefore, the probability that at least 7 of the puppies will be male is approximately 0.0805 or 8.05%.

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The angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\),\) which is approximately 1.107 radians or 63.43 degrees.

To determine the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\),\) we can follow these steps:

1. Express \(\(z_0\)\) in polar form: To find the polar form of \(\(z_0\)\), we need to calculate its magnitude \((\(r_0\))\) and argument \((\(\theta_0\))\). The magnitude can be obtained using the formula \(\(r_0 = |z_0| = \sqrt{\text{Re}(z_0)^2 + \text{Im}(z_0)^2}\)\):

\(\[r_0 = |2i + 1| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}\]\)

  The argument \(\(\theta_0\)\) can be found using the formula \(\(\theta_0 = \text{arg}(z_0) = \arctan\left(\frac{\text{Im}(z_0)}{\text{Re}(z_0)}\right)\)\):

\(\[\theta_0 = \text{arg}(2i + 1) = \arctan\left(\frac{2}{1}\right) = \arctan(2)\]\)

2. Find the polar form of \(\(w\)\): The polar form of \(w\) can be expressed as \(\(w = |w|e^{i\theta}\)\), where \(\(|w|\)\) is the magnitude of \(\(|w|\)\) and \(\(\theta\)\) is its argument. Since \((w = z^2\)\), we can substitute z with \(\(z_0\)\) and calculate the polar form of \(\(w_0\)\)using the values we obtained earlier for \(\(z_0\)\):

 \(\[w_0 = |z_0|^2e^{2i\theta_0} = \sqrt{5}^2e^{2i\arctan(2)} = 5e^{2i\arctan(2)}\]\)

3. Determine the argument of \(\(w_0\):\) To find the argument \(\(\theta_w\)\) of \(\(w_0\)\), we can simply multiply the exponent of \(e\) by 2:

  \(\[\theta_w = 2\theta_0 = 2\arctan(2)\]\)= 1.107 radians

Therefore, the angle of rotation at the point \(\(z_0 = 2i + 1\)\) when \(\(w = z^2\)\) is \(\(2\arctan(2)\).\)

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The complete question is:

"Determine the angle of rotation, in radians and degrees, at the point z0 = 2i + 1 when w = z^2."

9. H is a subspace of R3 as it contains a 2s vector [0, 2s, 0].

10. H is a subspace of R3 as it consists of the zero vector [0, 0, 0].

11. W is a subspace of R3 as it is spanned by the vectors [1,0,0] and [1,1,0].

12.W is a subspace of R4 as it is spanned by the vectors [1,2,0,0] and [0,-1,4,0].

9. To find a 2s vector v in R3 such that H is a subspace of R3, we can choose v = [0, 2s, 0]. This vector satisfies the condition of H being a subspace since it is of the form 2s, and any scalar multiple of v will also be of the form 2s, which is within H. Therefore, H is a subspace of R3.

0. Let H be the set of all vectors of the form [0, 0, 0]. To show that H is a subspace of R3, we can use the method from Exercise 9. By choosing v = [0, 0, 0],

we can see that H is closed under scalar multiplication and addition, as any scalar multiple or sum of the zero vector will still result in the zero vector. Therefore, H is a subspace of R3.

11. Let W be the set of all vectors of the form [b, c, 0], where b and c are arbitrary. To show that W is a subspace of R3, we need to find vectors u and v such that W is spanned by (u, v).

We can choose u = [1, 0, 0] and v = [0, 1, 0]. Any vector in W can be expressed as a linear combination of u and v, and therefore W is spanned by (u, v). This shows that W is a subspace of R3.

12. Let W be the set of all vectors of the form [s, 2s - t, 4t] in R4. To show that W is a subspace of R4, we can use the method from Exercise 11. By choosing u = [1, 2, 0, 0] and v = [0, -1, 4, 0],

we can observe that any vector in W can be expressed as a linear combination of u and v. Hence, W is spanned by (u, v), indicating that W is a subspace of R4.

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Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

8 - 24k + 1 = -25 - 7k

-24k + 9 = -25 -7k

-17k + 9 = -25

-17k = -34

k = 2

answer is D

Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{k = 2}}}}}\)

Option D is the correct option.

Step-by-step explanation:

\( \sf{8(1 - 3k) + 1 = - 25 - 7k}\)

Distribute 8 through the parentheses

\( \longrightarrow{ \sf{8 - 24k + 1 = - 25 - 7k}}\)

Add the numbers : 8 and 1

\( \longrightarrow{ \sf{9 - 24k = - 25 - 7k}}\)

Move 7k to left hand side and change it's sign

Similarly, move 9 to right hand side and change it's sign

\( \longrightarrow{ \sf{ - 24k + 7k = - 25 - 9}}\)

Collect like terms

\( \longrightarrow{ \sf{ - 17k = - 25 - 9}}\)

Calculate

\( \longrightarrow{ \sf{ - 17k = - 34}}\)

Divide both sides by -17

\( \longrightarrow{ \sf{ \frac{ - 17k}{ - 17} = \frac{ - 34}{ - 17} }}\)

Calculate

\( \longrightarrow{ \sf{k = 2}}\)

Hope I helped!

Best regards! :D

Based on the degrees of freedom (df) of 2, it can be concluded that there are 3 total categories or levels for the two variables being tested.

In a chi-square test for independence, the degrees of freedom are calculated by subtracting 1 from the number of categories in each variable and multiplying those values together. So, in this case, df = (number of categories in variable 1 - 1) x (number of categories in variable 2 - 1). Since df = 2, there must be 3 total categories or levels for the two variables being tested.

A chi-square test for independence is a statistical test used to determine whether there is a relationship between two categorical variables. The test compares the observed frequency of responses in each category for the two variables to the expected frequency of responses if there was no relationship between the variables. If the observed and expected frequencies are significantly different, the test concludes that there is a relationship between the variables. One of the outputs of the chi-square test is the degrees of freedom (df), which is a measure of the number of categories or levels in the two variables being tested. In general, the more categories or levels there are, the more information the test has to determine whether there is a relationship between the variables.

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The time it will take to cover another distance of 145 miles is; 2.5 hours

We are given;

First distance driven = 348 miles

Time taken for first distance = 6 hours

Formula for speed is;

Speed = Distance/Time taken

Thus;

Speed for fist distance = 348/6

Speed = 58 mph

Now, at the same speed she wants to cover another distance 0f 145 miles. Thus;

Time taken = distance/speed

Time taken = 145/58

Time taken = 2.5 hours

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Answer:

£0.75

Step-by-step explanation:

Add 2.10

Do 2.90 * 2

add 2.10 and 5.80

subtract the sum from 9.4

divide by 2

Answer:

12,17,22,27,32

Step-by-step explanation:

Answer:

This weekend I played basketball

Step-by-step explanation:

I practiced my jumpshot

layups

etc

Answer:

D/0

Step-by-step explanation:

the domain of (g o f )(x) is "all x > 0".

Answer: x=0

Step-by-step explanation:

Answer:

47

Step-by-step explanation:

20 + 27 = 47

The value of the expression is 295.

We can simplify the expression by grouping the terms that have the same value:

26 + (25 + 25) + (24 + 24) - (23 + 23) - (22 + 22) - (21 + 21) - (20 + 20) + (19 + 19) + (18 + 18) + 17 - (16 + 16) + (15 + 15) + (14)

= 26 + 50 + 48 - 46 - 44 - 42 - 40 + 38 + 36 + 17 - 32 + 30 + 14

= 295

The given expression involves a series of numbers where some of them are added and some of them are subtracted. To simplify this expression, we need to group the terms that have the same value. We can see that the expression has pairs of numbers that add up to the same value, such as (25 + 25), (24 + 24), and so on. We can combine these pairs and simplify the expression further.

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The relation "r" on the set of all integers, where x = y^2, is not reflexive.

A relation is reflexive if every element in the set is related to itself. In this case, for the relation x = y^2 to be reflexive, every integer "x" should be related to itself, meaning that x = x^2. However, this is not true for all integers.

For example, if we consider x = 2, it is not equal to 2^2 = 4. Similarly, if we consider x = -3, it is not equal to (-3)^2 = 9.

Since there are integers that do not satisfy the condition x = x^2, the relation x = y^2 is not reflexive on the set of all integers.

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The

speed

indicated in kilometers per hour is 85 km/h, as shown on the circular scale of the automobile

speedometer

.

The automobile

speedometer

is an instrument that measures the speed of a vehicle. It has a circular

scale

that reads both miles per hour (mph) and kilometers per hour (km/h). To determine the

speed

in kilometers per hour, the user must first locate the needle on the scale. The needle should be pointing to a specific number that corresponds to both mph and km/h. For example, if the needle is pointing to 85, then the speed indicated in kilometers per hour is 85 km/h. It is important to note that if the needle is located between two

numbers

, the user should determine the approximate speed by interpolating the two numbers. To find the speed in miles per hour, the user can simply look at the number that corresponds to the needle on the scale. In this case, the speed indicated in miles per hour is 53 mph.

The complete question: An automobile speedometer with circular scales reading both miles per hour and kilometers por hour is shown. What speed is indicated in miles per hour? 100 120 140 80 160 *60 180 200 40 20 220 Own 240 Express your answer in miles per hour v.2 mph

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Answer:

376.81

Step-by-step explanation: 376.81

The rejection region for a hypothesis test can be found, we need to specify the significance level (α) and the test statistic distribution.

Given that the question mentions "t" and asks us to round to three decimal places, we can infer that we are dealing with a t-test and should use the t-distribution.

The rejection region for a t-test is located in the tails of the t-distribution. The specific critical values depend on the degrees of freedom and the significance level (α).

Since the question does not provide the degrees of freedom or the significance level, we cannot provide a specific answer. However, I can explain the general procedure:

1. Determine the degrees of freedom based on the sample size and test conditions.
2. Determine the critical value(s) for the desired significance level (α) from the t-distribution table or a statistical software.
3. If the calculated test statistic (t) falls within the rejection region (tails of the t-distribution), we reject the null hypothesis (H0). Otherwise, we fail to reject the null hypothesis.

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It has been shown that if A is a symmetric matrix with eigenvalues λ1, λ2, . . . , λn, then the singular values of A are |λ1|, |λ2|, . . . ,|λn|.

To show that the singular values of a symmetric matrix A are |λ1|, |λ2|, . . . ,|λn|, we first need to recall that the singular values of A are the positive square roots of the eigenvalues of \(A^T A\) (where \(A^T\) denotes the transpose of A).

Now, since A is symmetric, we know that \(A^T = A\), which means that \(A^T A = A^2\).

So the eigenvalues of \(A^T A\) are the squares of the eigenvalues of A.

That is, if λ1, λ2, . . . , λn are the eigenvalues of A, then λ1², λ2², . . . , λn² are the eigenvalues of \(A^T A\).

But we also know that the eigenvalues of a symmetric matrix are real, so λ1, λ2, . . . , λn are real numbers.

And since the singular values of A are the positive square roots of the eigenvalues of \(A^T A\), it follows that the singular values of A are |λ1|, |λ2|, . . . ,|λn|. This completes the proof.

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Answer: 5%

Step-by-step explanation:

First and foremost, we need to know that 60 minutes = 1 hour. Therefore,

7 hours = 60 × 7 = 420 minutes.

Number of minutes awake = 21 minutes

Number of minutes supposed to be asleep = 7 hours = 420 minutes

The percentage of the seven hours that Frank was awake during the night will be:

= 21/420 × 100

= 1/20 × 100.

= 5%