(NH4)2S is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.550 M (NH4)2S solution.

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

\(\triangle G= -6.7 KJ/mol\)

Explanation:

From the question we are told that:

Chemical Reactions:

X=A⇌B,ΔG= 14.8 kJ/mol

Y=B⇌C,ΔG= -29.7 kJ/mol

Z=C⇌D,ΔG= 8.10 kJ/mol

Since

Hess Law

The law states that the total enthalpy change during the complete course of a chemical reaction is independent of the number of steps taken.

Therefore

Generally the equation for the Reaction is mathematically given by

\(T = +1 * X +1 * Y +1 *Z\)

Therefore the free energy, ΔG is

\(\triangle G=1 * \triangle G*X +1 * \triangle G*Y +1 * \triangle G *Z\)

\(\triangle G= +1 * (14.9) +1 * (-29.7) +1 * (8.10)\)

\(\triangle G= -6.7 KJ/mol\)

The equation MgO + 2HCl → MgCl₂ + H₂O is  a balanced equation.

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The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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Answer:

Beryllium

Explanation:

The boiling point of water is 100.0 °C, the boiling point of the solution will be : 101.49 °C.The correct answer is option (a) 100.00049 °C.

Ideal Solution : An ideal solution is a homogeneous mixture of two or more components that obeys Raoult's law, which states that each component's vapor pressure is proportional to its mole fraction.The boiling point of a solution depends on the solvent's properties and the solute's concentration. It's dependent on the mole fraction of the solvent and solute, as well as the total concentration of the solution. The change in boiling point of a solution is given byΔTb = Kb × m × i, whereKb = ebullioscopic constant, m molarity of the solution, and i = van't Hoff factor.Assuming that the solution's behavior is ideal, we may use the molality of the solution to compute the boiling point elevation of the solution.The molality of the solution is given by the following formula:m = (n₂ / m₂) ÷ (n₁ / m₁), where n is the number of moles, m is the mass, and the subscripts 1 and 2 refer to water and non-volatile solute sucrose, respectively.The molar mass of sucrose (C₁₂H₂₂O₁₁) is342.3 g/mol; therefore, the number of moles of sucrose is115.0 g ÷ 342.3 g/mol = 0.335 mol.m₁ = mass of water = 350.0 g, and m₂ = mass of sucrose = 115.0 g, as given in the problem.Therefore, the molality of the solution is given by:m = (0.335 mol / 0.115 kg) ÷ (1 mol / 1 kg) = 2.91 mol/kg.Substituting these values in the formula for ΔTb, we get:ΔTb = Kb × m = 0.512 °C m⁻¹ × 2.91 mol/kg = 1.49 °C.100.0 °C + 1.49 °C = 101.49 °C.

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Each kind of scientist is matched with an aspect of the hot spring he or she is most likely to study as follows:

A scientific observation can be defined as an active acquisition of knowledge (information) through one of the sense organs, while using scientific tools and instruments.

In Science, there are two main types of scientific observation and these include the following:

A hot spring can be defined as a natural or an artificially-induced phenomena in which very hot groundwater flows out from the Earth's crust due to the heat present in the geosphere.  

In this exercise, you're required to match each kind of scientist with an aspect of the hot spring he or she is most likely to study as follows:

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Complete Question:

Match each kind of scientist with an aspect of the hot spring she or he might study.

A. Geologist

B. Ecologist

C. Sociologist

D. Meteorologist

1. Relationships between organisms and the hot spring.

2. Human behavior around the hot spring.

3. Rocks around and under the hot spring.

4. Atmosphere and weather around the hot spring.

Answer:

The reaction rate increases in direct proportion to the concentration of the reactant in solution - second order reaction

The reaction rate is constant regardless of the amount of reactant in solution - zero order reaction

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order reaction

Explanation:

In a second order reaction, the rate of reaction is directly proportional to the concentration of reactants. This implies that, reaction rate varies as the concentration of the reactant in solution varies.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactants in solution. This means that reaction rate is constant regardless of the amount of reactant in solution.

For a first order reaction, the rate of reaction varies exponentially as the concentration of reactants. Hence, an increase or decrease in the concentration of the reactant in solution causes the reaction rate to increase or decrease exponentially.

Answer:

The chart is called the Periodic Table.

Hope this helps :)

Answer false:

Explanation:

According to the ideal gas law, when the temperature of a gas doubles, its volume doubles as well (Option B).

The ideal gas law relates the pressure, volume, number of moles and temperature of an ideal gas.

Let's consider the equation of the ideal gas law.

P . V = n . R .T

V = n . R . T / P

As we can see, there is a direct relationship between the volume and the temperature. Thus, if the temperature doubles, the volume will double as well.

According to the ideal gas law, when the temperature of a gas doubles, its volume doubles as well (Option B).

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Answer:

Test it with a blue light that is 45 cm away.

Explanation:

Answer:

D) 4.08

Explanation:

HC3H5O3, [HA]: 0.04L * 0.5M = 0.24L(M2)

M2 = 0.083M

C3H5O3-, [A-]: 1.0L * 0.2L = 0.24L (M2)

M2 = 0.83M

Use the Henderson-Hasselbalch equation:

log(0.83/0.083) = 1

Therefore pH = 3.08 + 1 = 4.08

Answer:

Tinatapon yong food

Explanation:

It's dangerous to eat

If a retail food establishment unknowingly contaminates food with dangerous bacteria, it can lead to foodborne illness outbreaks and pose a risk to public health.

If a retail food establishment, such as a restaurant or grocery store, unknowingly contaminates food with dangerous bacteria, several potential consequences can occur. Firstly, contaminated food can be distributed to customers, increasing the risk of foodborne illnesses. Consuming food contaminated with pathogens like Salmonella, E. coli, or Listeria can result in gastrointestinal symptoms, such as diarrhea, vomiting, and abdominal pain, and in severe cases, it can lead to hospitalization or even death, especially in vulnerable populations.

Secondly, if customers become sick due to consuming contaminated food, it can lead to negative publicity and damage the reputation of the establishment. This can result in a loss of customers, financial implications, and potential legal consequences if negligence is proven.

Additionally, if a foodborne illness outbreak occurs, it may trigger an investigation by local health authorities. The establishment may face inspections, potential closure, and the need for corrective actions to address the contamination issue. Public health agencies may also conduct trace-back investigations to identify the source of the contamination and prevent further spread.

Overall, the unknowing contamination of food with dangerous bacteria in a retail food establishment can have serious consequences, including the risk of foodborne illnesses, negative impact on the establishment's reputation, legal implications, and potential regulatory actions. It highlights the importance of proper food handling, hygiene practices, and regular monitoring to ensure the safety of the food served to the public.

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Answer:

2.29 g of N2

Explanation:

We have to start with the chemical reaction:

\(NaN_3~->~Na~+~N_2\)

The next step is to balance the reaction:

\(2NaN_3~->~2Na~+~3N_2\)

We can continue with the mol calculation using the molar mass of

\(NaN_3\) (65 g/mol), so:

\(3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3\)

Now, with the molar ratio between \(NaN_3\)  and \(N_2\)  we can calculate the moles of \(N_2\)  (2:3), so:

\(0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2\)

With the molar mass of \(N_2\) we can calculate the grams:

\(0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2\)

I hope it helps!

The mass of octane, C8H18 that must be injected to react with all of the oxygen in the cylinder to produce carbon dioxide and water is 0.14 g.

The balanced equation for the combustion of octane is:2C8H18 + 25O2 → 16CO2 + 18H2OFrom the above balanced chemical equation, we can see that 25 moles of O2 react with 2 moles of C8H18.

So, 12.5 moles of O2 will react with 1 mole of C8H18. We can use the ideal gas law PV = nRT to calculate the moles of oxygen present in the cylinder.

Here, we need to use the partial pressure of oxygen only since we are interested in the moles of oxygen only.

O2 = 21.00% × 101.0 kPa = 21.21 kPaV = 500.0 mL = 500.0/1000 = 0.5000 L (convert mL to L)R = 8.314 J/mol K (gas constant).

We have,PV = nRTn = PV/RTn = (21.21 × 10^3 Pa) × (0.5000 × 10^-3 m^3) / (8.314 J/mol K × 328.15 K) = 0.01578 moles of O2.

Since 12.5 moles of O2 react with 1 mole of C8H18,0.01578 moles of O2 will react with= (0.01578 moles × 1 mole C8H18)/12.5 moles = 0.001262 moles of C8H18

The molar mass of C8H18 is = 8 × 12.01 + 18 × 1.01 = 114.16 g/mol.

So, the mass of C8H18 required is = 0.001262 × 114.16 = 0.1445 g or 0.14 g (approx.)

Therefore, the mass of octane, C8H18 that must be injected to react with all of the oxygen in the cylinder to produce carbon dioxide and water is 0.14 g.

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Answer:

D. Ultraviolet light should have a short wavelength, not a long wavelength.

Explanation:

just took the quiz on Ed

The mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

Electromagnetic spectrum is the arrangement of electromagnetic radiations in the order of increasing frequency or decreasing wavelength.

Examples electromagnetic radiations based on increasing wavelength  include;

Thus, the mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

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Answer:

1.75 moles

Explanation:

According to CaC₂(s) + 2 H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)

2 moles of H20 will produce 1 mole of Ca(OH)2

therefore 3.5 moles of H2O will produce 3.5 x (1/2) = 1.75 moles of Ca(OH)2

Answer:

Two positive aspects of using methane recapture systems are able to generate significant electricity. Another benefit is that the process of anaerobic digestion creates heat that can be used to warm buildings where animals are kept

Answer:  The correct answer is;

Two positive aspects of using methane recapture systems include lowering the impact on greenhouse gasses and the production of energy. Methane is a very potent greenhouse gas that is contributing to global warming. As a result, the recapturing process reduces the methane impacts of global warming by reclaiming and reusing the gas for other purposes. Recaptured methane can be stored and used to generate electricity or used as fuel to power updated vehicles and other engines on the farm. The overall benefits from this combination are reducing impacts causing global warming and lower the cost of electricity or fuel on the farm.

Explanation:  This answer has been confirmed correct.

The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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Answer: 1 M \(BeCl_2\) > 1 M KCl = 2 M \(CH_3CH_2CH_2OH\) > 1 M \(C_12H_{22}O_{11}\)

Explanation:

\(\pi =iCRT\)

\(\pi\) = osmotic pressure = ?

i = vant hoff factor

C= concentration in Molarity  

R= solution constant

T= temperature

a) 1 M \(BeCl_2\)

i = 3

\(BeCl_2\rightarrow Be^{2+}+2Cl^-\)

Thus Concentration of ions = \(3\times 1M=3M\)

b) 1 M KCl

i = 2

\(KCl\rightarrow K^{+}+Cl^-\)

Thus Concentration of ions = \(2\times 1M=2M\)

c) 2 M \(CH_3CH_2CH_2OH\)

i = 1 ( as it doesnot dissociate)

Thus Concentration of ions = \(1\times 2M=2M\)

d) 1 M \(C_12H_{22}O_{11}\)

i = 1  ( as it doesnot dissociate)

Thus Concentration of ions = \(1\times 1M=1M\)

Thus order from highest to lowest osmotic pressure is:

1 M \(BeCl_2\) > 1 M KCl = 2 M \(CH_3CH_2CH_2OH\) > 1 M \(C_12H_{22}O_{11}\)

Answer:

[Ne] 3s² 3p¹

Explanation:

The relative atomic mass of oxygen would be 15.88.

The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. So, we can use the following formula to find the relative atomic mass of oxygen:

( Molar mass of oxygen / Molar mass of noble gas ) = ( Rate of diffusion of noble gas / Rate of diffusion of oxygen )^2

We can plug in the given values:

( Molar mass of oxygen / Molar mass of noble gas ) = (141.1 cm / 500 cm)^2

Solving for the molar mass of oxygen:

Molar mass of oxygen = ( Molar mass of noble gas ) * (141.1 cm / 500 cm)^2

We know that the molar mass of noble gas is equal to its atomic mass, so we can rewrite this as:

Relative atomic mass of oxygen = ( Atomic mass of noble gas ) * (141.1 cm / 500 cm)^2

We do not know which noble gas is being referred to, so we cannot look up its atomic mass. However, we can use the fact that the relative atomic mass of oxygen is approximately 16, since oxygen is the most common isotope of oxygen and its relative atomic mass is defined as 16. Therefore:

Relative atomic mass of noble gas = 16 / (141.1 cm / 500 cm)^2

Relative atomic mass of noble gas = 16 / (0.0796)^2

Relative atomic mass of noble gas = 316.2

Therefore, the relative atomic mass of oxygen is approximately:

Relative atomic mass of oxygen = 316.2 * (141.1 cm / 500 cm)^2 = 15.88

So the relative atomic mass of oxygen is approximately 15.88.

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