problem 6: Consider two vectors A and B, expressed in unit vector notations as A = a1i + a2j and b = b1i + b2j.

Answer:

v = 31.89 m/s

Explanation:

p = m × v

1,850 = 58 × v

58v = 1,850

v = 1,850/58

v = 31.89 m/s

Answer:

both drivers experience the same force. just with different "results"

Explanation:

Answer:

You do

Explanation:

Momentum is mass*velocity. So Newton's 3rd law equal and opposite reaction. Because you weigh less you will have more force act on you than the driver who weighs more.

Answer:

its D

Explanation:

i just got it correct on a. p. e. x. :)

Answer:

Correct option is (a)

Explanation:

According to conservation of energy: Total energy of system remains conserved or we can say total energy = constant

(a) 400J of GPE is added and 250J of thermal energy is lost

⇒ Total energy = 400-250 J  = 150 J

hence, 150J energy is increased

(b) 100J of thermal energy is added and 450J of kinetic energy is lost

⇒ Total energy = 100-450 J  = -350 J

hence, 350J energy is decreased or lost by system

(c)200J of kinetic energy is added and 250J of thermal energy is lost

⇒ Total energy = 200-250 J  = -50 J

hence, 50J energy is decreased or lost by system

(d)300J of thermal energy is added and 450J of kinetic energy is lost

⇒ Total energy = 300-450 J  = -150 J

hence, 150J energy is decreased or lost by system

Therefore, correct option is (a)

Explanation:

According to conservation of energy: Total energy of system remains conserved or we can say total energy = constant

(a) 400J of GPE is added and 250J of thermal energy is lost

⇒ Total energy = 400-250 J  = 150 J

hence, 150J energy is increased

(b) 100J of thermal energy is added and 450J of kinetic energy is lost

⇒ Total energy = 100-450 J  = -350 J

hence, 350J energy is decreased or lost by system

(c)200J of kinetic energy is added and 250J of thermal energy is lost

⇒ Total energy = 200-250 J  = -50 J

hence, 50J energy is decreased or lost by system

(d)300J of thermal energy is added and 450J of kinetic energy is lost

⇒ Total energy = 300-450 J  = -150 J

hence, 150J energy is decreased or lost by system

Therefore, correct option is (a)

Answer:

Ask a question.

Explanation:

Your question is the basis of any theory.

Answer:

bad

Explanation:

One way to test this hypothesis would be to conduct an experiment in which water is subjected to light sources of varying intensity.

Photosynthesis is a process used by plants and some other organisms to convert light energy, typically from the sun, into chemical energy that can be used to fuel biological processes. During photosynthesis, light energy is absorbed by chlorophyll molecules in the plant's leaves and is then used to convert carbon dioxide and water into sugars and oxygen. This process provides the oxygen we breathe and the food we eat, making it one of the most important processes on Earth.

During the experiment, the rate of hydrolisis can be measured, and this data can then be compared to determine if the energy from the solar source is required for hydrolisis. Additionally, a control experiment can be conducted using light sources that do not contain solar energy, such as a light bulb, to compare to the solar energy experiment. This will allow scientists to determine the effect of the solar energy on the rate of hydrolisis, and confirm or refute the hypothesis.

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a) The value of the required velocity is v(t) = t²/2 - 4t + 4e⁻⁵

b) The value of the required distance is S(t) = t³/6 - 2t² + 4e⁻⁵t + 5

c) The value of the velocity when t = 9 is approximately -28.2 m/sec

(a)To find v(t), we need to integrate a(t) first

a(t) = 2∫

a(t) dt = ∫ 2

dt = 2t + C1

Here, C1 is the constant of integration

Next, we need to integrate v(t) by substituting the value of a(t) into it

v(t) = ∫ (2t + C1)

dt= t² + C1t + C2

Here, C2 is another constant of integration

v(0) = - 4⇒ C2 = - 4

Also, given: v(t) = Vt + 4e⁻⁵

Comparing the above two equations:

v(t) = Vt + 4e⁻⁵ = t² + C1t - 4

On differentiating with respect to t, we geta(t) = 2

Therefore, we get the differential equation as:

Vt + 4e⁻⁵ = t² + C1t - 4 - - - - - - (1)

To find v(t), we need to solve this differential equation

Substituting t = 0, in (1), we get

-4 + 4 = 0 + C1(0)⇒ C1 = 0

Therefore, the differential equation becomes:

Vt + 4e⁻⁵ = t² - 4

On differentiating the above equation w.r.t t, we get:

a(t) = 2

Therefore, we get

v(t) = t²/2 - 4t + 4e⁻⁵ - - - - - - (2)

Thus, the required velocity is given by:

v(t) = t²/2 - 4t + 4e⁻⁵

Part (b) To find s(t), we need to integrate v(t) first

v(t) = t²/2 - 4t + 4e⁻⁵∫ v(t)

dt = ∫ (t²/2 - 4t + 4e⁻⁵)

dt= t²/6 - 2t² + 4e⁻⁵t + C3

Here, C3 is the constant of integration

Also, given that S(0) = 5⇒ C3 = 5

Therefore, we get

S(t) = t³/6 - 2t² + 4e⁻⁵t + 5 - - - - - - (3)

Thus, the required distance is given by:

S(t) = t³/6 - 2t² + 4e⁻⁵t + 5

Part (c) To find the velocity when t = 9We can use the value of v(t) obtained in part (a)⇒ v(9) = (9)²/2 - 4(9) + 4e⁻⁵⇒ v(9) = - 28.2 (approx)

Thus, the velocity when t = 9 is -28.2 (approx)m/sec.

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Answer:

\(125\:\mathrm{minutes\: or\: }2.08\bar{3}\: \mathrm{hours}\)

Explanation:

Speed is given by \(s=\frac{d}{t}\), where \(d\) is distance travelled and \(t\) is time. Rearranging this equation, we have \(t=\frac{d}{s}\).

Plugging in our given information:

\(t=\frac{d}{s}=\frac{1500\:\mathrm{km}}{720\:\mathrm{km/h}}=2.08\bar{3}\: \mathrm{hours}\)

Thus, our answer is:

\(2.08\bar{3}\: \mathrm{hours}\cdot \frac{60\:\mathrm{minutes}}{1\:\mathrm{hour}}=\fbox{$125\:\mathrm{minutes}$}\)

Answer:

350Joules

Explanation:

According to law of Conservation of energy, the amount of energy at the used up at the start is equal to that at the end.

The initial energy used up is gravitational potential energy

Final energy at the lowest point is kinetic energy.

If the energy is conserved then it means energy is not used up during the process hence;

Initial Potential energy = Final kinetic energy

If the gravitational potential energy is 350Joules then her final kinetic energy at the lowest point will also be 350Joules

Answer:

18 V

Explanation:

According to Ohm's Law, current equals voltage divided by resistance. (I=V/R)

Using this, we can rearrange the equation to have it solved for voltage.

V=IR

Then, you plug in the values for the current and the resistance.

V=(3.6)x(5.0)

V=18

The distance d travelled by in object is 68.58 m

What is velocity ?

velocity is defined as rate of change of displacement d of the object with respect to rate of change in time t. In mathematics It is written as :

v = d/t

it should be noted that, velocity is nothing but speed in particular direction. That is velocity is vector quality having both magnitude and direction where as speed is just the magnitude of velocity.

1 feet = 0.3048 m

15 feet = 4.572 m

Now, calculating the distance d travelled by in object :

d = vt

d = 4.572 x 27

d = 68.58 m

Therefore, the distance d travelled by in object is 68.58 m

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Explanation:

think4

pleas! mark me s brainliest please please

Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

Answer:

the second process of using the the shovel to move the snow as it takes a longer time meaning more power is expended

The solar system shows the planets in their orbits around the sun in this order: Mercury, Venus, Earth with Moon, Mars, Jupiter, Saturn. Fixed stars are around the outside of the orbit of Saturn.

Explanation:

Aristarchus of Samos was an ancient Greek astronomer and mathematician who presented the first known heliocentric model that placed the Sun at the center. So I had to choose the choice that was most similar to that.

Explanation:

the correct answer is (true) if am not mistaking incase am wrong sorry

Answer:

F = 48 [N]

Explanation:

To solve this problem we must use Newton's third law, which tells us that the sum of forces on a body must be equal to zero, that is, the body is in static equilibrium or in equilibrium.

ΣF = 0

24 + 24 - F = 0

F = 24 + 24

F = 48 [N]

Note: Jeff's force should be equal to the sum of Sally and Misha's forces, but in the opposite direction.

The coefficient of kinetic friction between Makiko and her sister is approximately 0.226.

μ = (F_friction) / (F_normal)

where:

μ is the coefficient of kinetic friction,

F_friction is the force of friction,

F_normal is the normal force.

First, we need to find the normal force acting on Keko. Since they are on a horizontal surface and moving at a constant speed, the normal force is equal in magnitude and opposite in direction to the gravitational force:

F_normal = m * g

where:

m is the mass of Keko, and

g is the acceleration due to gravity (approximately 9.8 m/s^2).

Given:

mass of Keko (m) = 18 kg

F_normal = 18 kg * 9.8 m/s^2

F_normal = 176.4 N

Next, we can calculate the force of friction (F_friction) using the force applied by Makiko. The force of friction can be determined by resolving the applied force into horizontal and vertical components.

F_friction = F_applied * sin(θ)

where:

F_applied is the applied force, and

θ is the angle above the horizontal (27°).

Given:

applied force (F_applied) = 0.91 x 10^2 N

angle above the horizontal (θ) = 27°

F_friction = (0.91 x 10^2 N) * sin(27°)

F_friction ≈ 39.97 N

Now we can calculate the coefficient of kinetic friction (μ):

μ = F_friction / F_normal

μ = 39.97 N / 176.4 N

μ ≈ 0.226

Therefore, the coefficient of kinetic friction between Makiko and her sister is approximately 0.226.

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Answer:

41.57.

Explanation:

Sometimes if you type in google "area of a regular hexagon, it will give you a calculator you can use to solve your math questions.

They will be instructed to park their cars in a cool dry environment in order to prevent rusting of the vehicle parts.

This is defined as a chemical change in which Iron reacts with Oxygen to form a new substance called Iron oxide.

Iron oxide is usually brownish in color and further corrodes the metal parts. It is also referred to as a Chemical change in chemistry due to new substance being formed.

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Answer:

Gas Solid Liquid Plasma

Explanation:

Answer:

plasma

Explanation:

plasma has charged particles and ions and electrons floating around

To solve the given problems, I will assume you are referring to a Cartesian coordinate system, where the x-axis is horizontal and the y-axis is vertical. To find the x-component of the electric field (Ex) at point P, we can use the formula:

Ex(P) = (k * λ1 * a) / (2πε₀ * (a² + y²)^(3/2))

Where:

k is the Coulomb's constant (approximately 8.99 × 10^9 N m²/C²)

λ1 is the charge density of the line of charge

a is the x-coordinate of point P

ε₀ is the permittivity of free space (approximately 8.85 × 10^12 C²/N m²)

y is the y-coordinate of point P, which is 0 in this case

Plugging in the given values, we get: Ex(P) = (8.99 × 10^9 N m²/C² * 1.8 × 10^(-6) C/cm * 8.6 cm) / (2π * 8.85 × 10^(-12) C²/N m² * (8.6 cm)²). Calculate the expression to find the value of Ex(P). Since the line of charge is aligned with the y-axis and point P is located on the x-axis (y = 0), the y-component of the electric field (Ey) at point P is zero.

Ey(P) = 0. To calculate the total flux (Φ) passing through the cylindrical surface, we can use Gauss's Law. Since the cylinder is symmetric, the electric field is constant and perpendicular to the surface at all points. The flux passing through the surface is given by:

Φ = E * A

Where:

E is the magnitude of the electric field

A is the area of the cylindrical surface

Calculate the expression to find the value of Φ. When the second line of charge with charge density λ2 is added, the electric field at point P will change. To find the new values of Ex(P) and Ey(P), we need to calculate the electric field contribution from both line charges and add them together. Follow the same approach as in problem 3 to calculate the new total flux Φ passing through the cylindrical surface. When the initial line of charge is moved parallel to the y-axis at x = -4.3 cm, the x-component of the electric field at point P (Ex(P)) will change. Use the same formula as in problem 1 with the new position of the line of charge to calculate the new value of Ex(P).

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