QUUESTION Today, everything at a store is on sale! The store offers a 20% discount.
If the regular price of an item is `x` dollars, write an expression (not an equation so no equal sign) that can be used to find the discount price in dollars?

The probability that the first trial B, fails is given by 1-p. Hence, the correct answer is option C) 1-P.Let Y be a binomial random variable with parameters n and p.The probability that Y is zero is given by (1-p)^n. Hence, the correct answer is option A) (1-P)^n.

Bernoulli Distribution:In probability theory and statistics, the Bernoulli distribution is the discrete probability distribution of a random variable that takes the value 1 with probability p and the value 0 with probability q=1-p.

The Bernoulli distribution is the simplest distribution that has only two possible outcomes, 1 or 0.Binomial Distribution:The binomial distribution is a probability distribution that results from performing n independent Bernoulli trials, each with probability p of success.

A binomial random variable, Y, represents the number of successes in n Bernoulli trials with probability p.

The probability mass function of a binomial distribution is given byP(Y = k) = C(n, k) p^k q^(n-k)where C(n, k) = n!/[k! (n-k)!] is the binomial coefficient.P(Y = k) is the probability of getting k successes in n independent Bernoulli trials, where p is the probability of success in each trial and q = 1 - p is the probability of failure in each trial.

The question is formatted with HTML. Let B, and B, be Bernoulli trials with probability of success p.

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Critical values of the function f(θ) = 2cos(θ) +(sin(θ))² on the interval 0≤ θ < 2π is 0 and π.

Therefore, the answer is 0 and π.

f(θ) = 2cos(θ) +(sin(θ))²

f'(θ) = -2sin(θ) +2sin(θ)cos(θ)

Critical values of f are points at which f' is zero or not defined.

For all values of θ, we can find that f'(θ) is defined.

f'(θ) = 0

-2sin(θ) +2sin(θ)cos(θ) = 0

cos(θ) - 1 = 0 or sin(θ) = 0

cos(θ) = 1

θ = nπ, n = 0, 1, 2, ...

sin(θ) = 0

θ = nπ, n = 0, 1, 2, ...

Therefore in the interval 0 ≤ θ < 2π, critical values are 0 and π.

2π is not there as it is not included in the interval.

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Answer:

g(x) is shifted 5 units right and 2 units up from f(x).

Step-by-step explanation:

In this case, there are two unique factors: 2 and 3. The expression can be rewritten as (2^2) x 3, showing that the number 2 is raised to the power of 2 and then multiplied by 3. Since there are only two unique factors involved in this expression, the correct answer is: d. 2

The answer is d. 2. In a factorial combination, independent variables refer to the factors or variables that are being manipulated or varied. In the combination 2x2x3, there are two independent variables: the first variable has two levels or options, the second variable also has two levels or options, and the third variable has three levels or options. Therefore, the number of independent variables in this factorial combination is two.
 The given expression is 2x2x3, which is a product of three numbers. To determine the number of independent variables in this factorial combination, let's identify how many unique variables or factors are involved in the product.
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the binary representation of 63.25 as 111111.01.

To convert the decimal number 63.25 to binary, we need to convert the integer part (63) and the fractional part (0.25) separately.

1. Converting the integer part (63):

  Divide 63 by 2, and keep track of the remainders:

  63 ÷ 2 = 31 (remainder 1)

  31 ÷ 2 = 15 (remainder 1)

  15 ÷ 2 = 7 (remainder 1)

  7 ÷ 2 = 3 (remainder 1)

  3 ÷ 2 = 1 (remainder 1)

  1 ÷ 2 = 0 (remainder 1)

  The remainders in reverse order give us the binary representation of the integer part: 111111.

2. Converting the fractional part (0.25):

  Multiply 0.25 by 2 and record the whole number part:

  0.25 × 2 = 0.5 (0)

  0.5 × 2 = 1.0 (1)

  The whole number parts give us the binary representation of the fractional part: 01.

Putting the integer and fractional parts together, we have the binary representation of 63.25 as 111111.01.

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The binary representation of the decimal number 63.25 is 111111.01.

To convert the decimal number 63.25 to binary, we need to separate the whole number part and the fractional part.

Whole Number Part:

Divide the whole number part (63) by 2:

Divide the quotient (31) by 2:

Divide the quotient (15) by 2:

Divide the quotient (7) by 2:

Divide the quotient (3) by 2:

Divide the quotient (1) by 2:

Reading the remainders in reverse order, the binary representation of the whole number part is 111111.

Fractional Part:

To convert the fractional part (0.25) to binary, we multiply the fractional part by 2 and note the whole number part of the result. Repeat this process until the fractional part becomes 0 or until the desired precision is achieved.

Multiply the fractional part (0.25) by 2:

Multiply the fractional part (0.5) by 2:

Since the fractional part becomes 0, we stop the process.

Reading the whole number parts in order, the binary representation of the fractional part is 01.

Combining the binary representation of the whole number part and the fractional part, the binary representation of the decimal number 63.25 is 111111.01.

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The supervisor calculates the mean number of miles that the employees in a department live from work and obtains the value  (x-bar).

The mean, denoted by x - bar (x-bar), is a statistical measure that represents the average value of a set of data. In this case, the supervisor is interested in determining the average distance in miles that the employees in a department live from their workplace.

By calculating x-bar, the supervisor obtains a single value that summarizes the central tendency of the data set.

The mean is computed by summing all the distances and dividing the sum by the total number of employees in the department.

It provides valuable insight into the typical commute distance of the employees and can be used for various purposes, such as evaluating transportation needs or planning employee benefits.

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Answer:

0.635

Step-by-step explanation:

This is half way between 0.63 and 0.64.

Hope this helps!

Answer:

0, 1/18, and 1/36

Step-by-step explanation:

For i = 2, the probability it lands on 6 is 0, because you cannot sum to 2 with a 6. The same applies to i = 3 thru i = 6.

For the probability that at least one of a pair of fair dice lands on 6 for i = 7, there are only two possible ways, the first roll is a 6 and the second roll is a 7, and the first roll is a 1 and the second roll is a 6. The total amount of ways is 6 * 6 = 36, so the total probability is 1/18. This also applies to i = 8 thru i = 11.

For i = 12, there is only one way to get 12, the first dice lands on 6 and the second dice lands on 6. Assuming the dice are indistinguishable, the probability is 1/36.

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

We have,

The complementary probability of "at least one die lands on 6" is "neither of the dice lands on 6."

Therefore, you need to find the probability that neither of the dice lands on 6 for each possible sum i, and then subtract that probability from 1 to get the desired probability.

Let's go through the cases:

i = 2 (only possible sum with two dice):

In this case, both dice must show a 1.

The probability of this happening on a fair 6-sided die is

(1/6) * (1/6) = 1/36.

i = 3: The combinations are (1, 2) and (2, 1).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 4:

The combinations are (1, 3), (2, 2), and (3, 1).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 5:

The combinations are (1, 4), (2, 3), (3, 2), and (4, 1).

The probability of any of these happening is 4 * (1/6) * (1/6) = 1/9.

i = 6:

The combinations are (1, 5), (2, 4), (3, 3), (4, 2), and (5, 1).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 7:

The combinations are (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

The probability of any of these happening is 6 * (1/6) * (1/6) = 1/6.

i = 8:

The combinations are (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 9:

The combinations are (3, 6), (4, 5), and (5, 4).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 10:

The combinations are (4, 6) and (6, 4).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 11:

The combinations are (5, 6) and (6, 5).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 12:

The combination is (6, 6).

The probability of this happening is (1/6) * (1/6) = 1/36.

Now, sum up the probabilities for each case:

(1/36) + (1/18) + (1/12) + (1/9) + (5/36) + (1/6) + (5/36) + (1/12) + (1/18) + (1/18) + (1/36)

This simplifies to:

69/36 = 23/12

Thus,

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

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Answer:

Option 2. That is the best option for this problem

Exponential growth model represents the population growth of a species over a period of time under ideal conditions, where the resources are unlimited.

The formula for exponential growth is given as;

P(t) = P0ert

Where;

P(t) = population at a specific time 't'

P0 = the initial population

r = the rate of growth t = time elapsed In this problem,

the initial population P0 is 217, and after 4 months, the population has increased to 434.

To find the rate of growth r, we can substitute the given values in the formula and solve for r.

434 = 217e4r

Dividing both sides by 217;

2 = e4r

Taking the natural logarithm of both sides;

ln(2) = 4rln(e)ln(2) = 4r

∴ r = ln(2)/4

The population will reach 4640 when;

P(t) = P0ert

4640 = 217e(ln(2)/4)t

Dividing both sides by 217;

21.42201835 = e(ln(2)/4)t

Taking the natural logarithm of both sides;

ln(21.42201835) = ln(e(ln(2)/4)t)ln(21.42201835)

= (ln(2)/4)tln(2.6528)

= (ln(2)/4)t

Dividing both sides by

ln(2)/4;t = ln(2.6528) / ln(2)/4t

= 25.44 ≈ 25 months (rounded to the nearest whole number)Therefore, after 25 months, the catfish population will reach 4640. Answer: 25 months.

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Answer:

A. c = 15.9 + 12(y - 2014)

B. c = 15.9 + 12(2025 - 2014)

C. 147.9 gigabytes

D. Unsure what you meant

Step-by-step explanation:

A. In this equation, 'c' represents the flash storage capacity in year 'y' and '15.9' is the flash storage capacity in year 2014. '12' represents the yearly increase in storage and '(y-2014)' represents how many years have passed from 2014.

B.To find the average flash storage capacity of smartphones in 2025, we can use the equation:

c = 15.9 + 12(y - 2014)

We can substitute 'y' with 2025 in the above equation to find the average flash storage capacity of smartphones in 2025

C.

c = 15.9 + 12(2025 - 2014)

c = 15.9 + 12(11)

c = 15.9 + 132

c = 147.9 gigabytes

Answer:

120$

Step-by-step explanation:

as we know the formula to calculate i is (ptr)/100

so i =(1000×6×2)/100

=(12000)/100

=120$

Answer: 100,000

Step-by-step explanation: 1,000,000 divided by 10.

Answer:

i think seventy two......72

The semimajor axis of Halley's Comet's orbit is approximately 17.91 AU. To find the semimajor axis of Halley's Comet's orbit, we can use Kepler's third law, which relates the orbital period (T) and the semimajor axis (a) of an object in an elliptical orbit:

T^2 = 4π^2a^3/GM,

where T is the orbital period, G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2), and M is the mass of the central body (in this case, the Sun).

First, we need to convert the orbital period from years to seconds:

T = 76 years = 76 × 365.25 days × 24 hours × 60 minutes × 60 seconds = 2.399 × 10^9 seconds.

Next, we can rearrange the equation to solve for the semimajor axis (a):

a = (T^2 * GM / (4π^2))^(1/3).

The mass of the Sun, M, is approximately 1.989 × 10^30 kg.

Plugging in the values, we have:

a = (2.399 × 10^9 seconds)^2 * (6.67430 × 10^-11 m^3 kg^-1 s^-2) * (1.989 × 10^30 kg) / (4π^2)^(1/3).

Calculating this expression, we find:

a ≈ 17.91 astronomical units (AU).

Therefore, the semimajor axis of Halley's Comet's orbit is approximately 17.91 AU.

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The length of each side of the triangle is 8 cm, 19 cm and 25 cm when perimeter of triangle is 52 cm.

According to the question,

We have the following information:

We have a triangle whose sides are x, 2x+3 and 3x+1.

Perimeter of triangle = 52 cm

We know that perimeter of a triangle is the sum of all three sides of a triangle.

x+2x+3+3x+1 = 52

We know that the terms with the same variables can only be added or subtracted from each other.

So, we have the following expression:

6x+4 = 52

6x = 52-4

6x = 48

x = 8 cm

Now, putting the value of x in all three sides of the triangle:

x = 8 cm

2x+3 = 2*8+3

16+3 = 19 cm

3x+1 = 3*8+1

24+1 = 25 cm

Hence, the length of each side of the triangle is 8 cm, 19 cm and 25 cm when its perimeter is 52 cm.

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she need 240 number of participant .

Graphing cell means to picture primary impacts and connections. The numbers in the secret elements address bunch implies in a 2 x 2 x 3 plan. The negligible means for factors An and B are likewise shown. The cell implies are plotted as line diagrams and as reference charts.

Now, According to the question:

We have Dr. Green is interested in conducting a 2 x 2 x 3 within-group factorial design.

There are 12 cells in factorial, and each cell 20 participant.

Then, number of participant = 20(12) = 240 participant.

Thus, she need 240 number of participant .

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Answer:

x - 1

Step-by-step explanation:

3(3x + 3) - 2(5 + 4x)

9x + 9 -10 - 8x

x - 1

hope this helps!

Answer:

13 x 9 x 5

Step-by-step explanation:

because there is 13 steps in one flight and there fore we need to multiply 13 x 9

then we have to multiply the product by 5 because it is asked how many steps does she climb in five days

The required answer is he equilibrium price will be $8, and the equilibrium quantity will be 320 units.

After the introduction of the new desalination technology, the market supply curve will shift to the right, since firms will be able to produce more water at a lower cost. The new supply curve will be given by:

! = 5P + (8 * quantity) - 5

This is because the cost of producing each unit of water has now increased by $8, but the supply function remains the same.  specifically general equilibrium theory, a perfect market, also known as an atomistic market, is defined by several idealizing conditions, collectively called perfect competition, or atomistic competition. In theoretical models where conditions of perfect competition hold, it has been demonstrated that a market will reach an equilibrium in which the quantity supplied for every product or service, including labor, equals the quantity demanded at the current price

To find the equilibrium price and quantity, we need to set the new supply curve equal to the demand curve:

400 - 10P = 5P + (8 * quantity) - 5

Simplifying and solving for P:

15P = 405 + 8Q

P = 27 + (8/15)Q

Next, we substitute this expression for P into either the demand or supply curve and solve for Q. Let's use the demand curve:

400 - 10(27 + (8/15)Q) = Q + 5

Simplifying:

Q = 60

Therefore, the equilibrium quantity is 60 units of water, and the equilibrium price can be found by plugging this quantity into the expression for P:

P = 27 + (8/15)(60) = $43.20
So the equilibrium price is $43.20 per unit of water.

To find the market supply curve after the introduction of the new desalination technology and the equilibrium price and quantity, follow these steps:

Step 1: Determine the new supply curve.
Since the desalination technology allows for unlimited water production at a cost of $8, the new supply curve will be a horizontal line at P = $8. This is because suppliers will be willing to supply any quantity of water at that price.
Step 2: Find the new equilibrium price and quantity.

To find the new equilibrium, we need to determine where the new supply curve intersects the demand curve. The demand curve is given by Qd = 400 - 10P. To find the intersection, set the price P equal to $8 in the demand equation:

Qd = 400 - 10(8)
Qd = 400 - 80
Qd = 320

So, at the equilibrium price of $8, the quantity demanded is 320 units.

In conclusion, the market supply curve after the introduction of the new desalination technology will be a horizontal line at P = $8. The equilibrium price will be $8, and the equilibrium quantity will be 320 units.

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Answer:

2

a=-3 , b=-7 , c=2

a=quadratic term

b=linear term

c=constant term

Answer:

2z:2x

Step-by-step explanation:

you can write z/x as z:x. Then just multiply both sides by the same number to get an equivalent ratio. Let's multiply by 2.

The percentage of games which Jay won is 44 percent.

This is referred to as a number or ratio expressed as a fraction of 100 and is usually denoted as %.

Percentage is calculated by : parts/whole × 100.

In this scenario we can deduce that the part is 154 while the whole is 350. Therefore: 154/350 × 100 = 44 percent.

Hence the most appropriate choice is 44 percent.

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The unit of slope for a graph of capacity (nF) on the y-axis and the inverse of distance (mm^-1) on the x-axis depends on the specific units used for capacitance and distance.

Recall that the slope of a linear graph is given by:

slope = (change in y) / (change in x)

In this case, the change in y is given in units of capacitance (nF), and the change in x is given in units of the inverse of distance (mm^-1). Therefore, the unit of slope is:

(nF) / (mm^-1)

This can also be written as:

nF * mm

So, the unit of slope for this graph is "nanofarads times millimeters" (nF * mm).

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Answer:

240000

Step-by-step explanation:

Answer:

240,000

Step-by-step explanation:

Pretend it is only 4 ten thousands. It would be 40,000. Since it is 24, there are 2.4 times more digits, so it would be 240,000 since it is at least 10 times more than a thousand which would be the 40,000 .

In case anyone needs 24 ten thousandths in the future:

0.0024

0.00024 is equal to 24 hundred-thousandths and there are tenths (0.1), hundredths (0.01), and thousandths (0.001). Then ten thousandths would just be a step lower (0.0001) but since there are 24, it would go into the thousandths place but have the four in the ten thousandths. So it would be 0.0024.

is (g o f)(2) = 4. This means that when we plug the value of 2 into the composite function (g o f), the result is 4.

To explain further, we first evaluate f(2) and find that it equals -2. Then, we substitute -2 into g(x) and calculate g(-2) by squaring it. The result is 4, which is the final value of the composite function (g o f)(2).

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X is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

a. To calculate the sample median of x, we can use the median function in R. So, the code would be:
median(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the sample median of x.
b. To find the .34 quantile of x, we can use the quantile function in R. The code would be:
quantile(x, 0.34)
where x is the variable that we have assigned the agriculture column of swiss to, and 0.34 represents the desired quantile. Running this code would give us the value of the .34 quantile of x.
c. To calculate the interquartile range of x, we can use the IQR function in R. The code would be:
IQR(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

The "fertility", "Switzerland", and "x <- swiss $ agriculture" terms.
a. To calculate the sample median of x (the agriculture column in the Swiss dataset), use the following R command:
median_x <- median(swiss$agriculture)
b. To find the 34th percentile (0.34 quantile) of x using the R quantile function, use the following R command:
quantile_x <- quantile(swiss$agriculture, probs = 0.34)

c. To calculate the interquartile range of x (the agriculture column in the Swiss dataset) using R, use the following R commands:
Q1 <- quantile(swiss$agriculture, probs = 0.25)
Q3 <- quantile(swiss$agriculture, probs = 0.75)
IQR_x <- Q3 - Q1
This will give you the interquartile range (IQR) of the agriculture column in the Swiss dataset.

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There are nC2 different votes possible, where n is the number of bands on the list and nC2 represents the number of ways to choose 2 bands out of n.

To calculate nC2, we can use the formula for combinations, which is given by n! / (2! * (n-2)!), where ! represents factorial.

Let's say there are m bands on the list. The number of ways to choose 2 bands out of m can be calculated as m! / (2! * (m-2)!). Simplifying this expression further, we get m * (m-1) / 2.

Therefore, the number of different votes possible is m * (m-1) / 2.

In the given scenario, we don't have the specific number of bands on the list, so we cannot provide an exact number of different votes. However, you can calculate it by substituting the appropriate value of m into the formula m * (m-1) / 2.

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The reason this method works is that the LCM is the smallest multiple that all the numbers have in common. When we break each number down into its prime factors, we are essentially finding all the factors that each number shares with the others.

The factor tree method is a useful technique for finding the least common multiple (LCM) of two or more numbers.

The method works by breaking each number down into its prime factors, and then finding the product of all the unique factors raised to their maximum powers.

By taking the product of all the unique factors raised to their maximum powers, we are essentially finding the smallest multiple that includes all these shared factors.

For example, let's find the LCM of 12 and 18 using the factor tree method:

We start by breaking down 12 and 18 into their prime factors:  \(12 = 2^2 \times 3\) and \(18 = 2 \times 3^2.\)

We then identify the unique factors and their maximum powers: \(2^2 \times 3^2.\)

Finally, we multiply the unique factors raised to their maximum powers: \(2^2 x 3^2 = 36.\)

So the LCM of 12 and   \(18\) is \(36\)  . This method works because 36 is the smallest multiple that includes all the shared factors of 12 and 18 (which are 2, 2, and 3).

Therefore, The reason this method works is because the LCM is the smallest multiple that all the numbers have in common. When we break each number down into its prime factors, we are essentially finding all the factors that each number shares with the others.

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