Lions obtain carbon they need by eating the animals that have carbon-based molecules stored in their bodies.
How do lions obtain the carbon they need?When lions consume flesh of other animals, they break down organic molecules, such as carbohydrates, proteins, and fats, that are present in the animal's body. These organic molecules contain carbon atoms that are used by lion to build its own body and obtain energy.
Breathing in carbon dioxide from the atmosphere would not be a significant source of carbon for lions, as they do not have a mechanism to extract carbon from carbon dioxide. Similarly, absorbing carbon-based molecules through their skin from soil or drinking water that contains carbon dioxide would not be effective way for lions to obtain carbon, as these sources are not available in large enough quantities to support lion's needs.
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Answer:
It is A.Explanation:
by eating animals that have carbon-based molecules stored in their bodies.
hope this helps good day
What is the speed of sound in air?
Answer:
Around 330 m/s
The speed of sound in air is 343 meters per second
a 66-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 826 n. what is the acceleration of the elevator?
The acceleration of the elevator in this scenario is: 12.5 m/s2
The acceleration of the elevator can be determined by using the equation a = F/m, where F is the force on the scale, and m is the mass of the man. In this case, the force on the scale is 826 N and the mass of the man is 66 kg. Therefore, the acceleration of the elevator is 826 N / 66 kg = 12.5 m/s2.
To further explain, an elevator is subject to two forces: the weight of the people and the weight of the elevator. As the elevator rises, the force of gravity increases and the force on the scale increases as well. This is why the man standing on the scale reads 826 N. Therefore, the acceleration of the elevator is equal to 12.5 m/s2.
It is important to note that the acceleration of an elevator can also be affected by its speed. If the elevator accelerates, the force on the scale increases, and the man's reading increases as well. Conversely, if the elevator decelerates, the force on the scale decreases, and the man's reading decreases.
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Imagine a planet moving in a perfectly circular orbit around the Sun and, because the orbit is circular, the planet is moving at a constant speed. Is this planet experiencing acceleration? Explain.
The centripetal force required for a planet to revolve in a circular motion around the sun is provided by the sun's gravitational pull on the planet. The round motion of the planet is caused by the centripetal force, which is always pointed in the direction of the sun's center at every point of its course.
What is the cause planet experiencing acceleration?The force of gravity accelerates items as they descend to the ground. Velocity is a measure of the speed and direction of motion, and acceleration is a change in velocity. The longer an object is in free fall, the faster it descends towards the ground due to gravity.
A planet needs to accelerate towards the circle's centre in order to travel in a curved route. Centripetal acceleration, which is provided by the gravitational attraction of the sun and the planet, is what causes this.
Therefore, yes, change in direction is acceleration.
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True or false? Only liquid refrigerant should enter the metering device.
Answer:
The given statement in this question is true. Only liquid refrigerant should enter the metering device.
. If an object travels at a constant velocity, how does its average velocity compare to its
instantaneous
velocity throughout the trip?
Answer:
The average velocity is equal to the instantaneous velocity
Explanation:
The average velocity, \(\overline v\), is given as follows;
\(\overline v = \dfrac{\Delta y}{\Delta t}\)
Where;
Δy = The change in displacement
Δt = The change in time
The instantaneous velocity is the derivative found of the position of the object's displacement with respect to time
Therefore, the instantaneous velocity, \(v_{inst}\) = The limit of the average velocity as the change in time becomes closer to zero
\(v_{inst} = \lim_{t \to 0} \left (\dfrac{\Delta y}{\Delta t} \right ) = \dfrac{dy}{dx}\)
When the velocity is constant, the displacement time graph is a straight line graph, and the slope of the displacement-time graph which is the same as the velocity is constant and therefore, we have;
\(Slope \ of \ straight \ line \ graph = \dfrac{y_2 - y_1}{t_2 - t_1} = \dfrac{\Delta y}{\Delta t}= \dfrac{dy}{dx}\)
Therefore, for constant velocity, we have, \(\overline v\) = \(v_{inst}\) the average velocity is equal to the instantaneous velocity.
Many animals use __?__to find prey.
2. A porpoise sends out an ultrasonic burst and hears the echo off his favorite food in 0.13 seconds. How far away is the food source? Assume that sound travels at 1,530 m/sec in water.
Answer:
Below
Explanation:
"echo location"
The sound travels the distance, d , to the food and back for a total distance of 2d
2d = 1530 m/s * .13 s
d = ~ 99 m away
Mrs. Byers is swinging a mass on a string above her head with a radius of 7 m. If she decreases the radius by a factor of 7, by what factor does the centripetal acceleration change?
Answer:
Explanation:
Given:
V₁ = V₂ = V
R₁ = 7 m
n = 7
R₂ = R₁ / n = 7 / 7 = 1 m
____________
aₙ₂ / aₙ₁ - ?
aₙ₁ = V₁² / R₁ = V² / 7
aₙ₂ = V₂² / R₂ = V² / 1 = V²
aₙ₂ / aₙ₁- = V² / (V²/7) = 7
Centripetal acceleration increased by 7 times
If the potential energy of a roller coaster is 60,000 J at the highest point, what is its kinetic energy at the lowest point?
Answer:
60 000 J
Explanation:
The PE will be converted to KE entirely (if the lowest point is ground level)
2. Use Evidence Based on your results in this activity, describe the characteristics of a circuit
that would carry the maximum amount of electric current. Include characteristics such as
voltage, wire diameter, wire length, wire temperature, and wire material.
A circuit that minimizes resistance will be able to carry the maximum amount of current.
What is Current?
It is defined as the amount of electric charge passing through a given point in a circuit in unit time. The SI unit of electric current is the ampere (A), which is defined as one coulomb of electric charge per second. Electric current can be either direct current (DC), which flows in one direction only, or alternating current (AC), which changes direction periodically.
Based on the results of this activity, a circuit that would carry the maximum amount of electric current should have:
High voltage: A higher voltage will cause a greater potential difference and push more electrons through the circuit.
Thicker wire diameter: A thicker wire diameter will have lower resistance, allowing more current to flow through the wire.
Shorter wire length: A shorter wire length will have lower resistance, allowing more current to flow through the wire.
Lower wire temperature: A lower wire temperature will have lower resistance, allowing more current to flow through the wire.
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If I release a golf ball at a height of 31 cm and a length of 31 cm the mass is equal to 45.93 g what is theKinetic energy
When a ball is at a particular height it possess potential energy which is given as,
\(U=\text{mgh}\)The potential energy is converted into kinetic energy of the ball. According to conservation of energy,
\(K=U\)which can be further given as,
\(K=\text{mgh}\)Substitute the known values,
\(\begin{gathered} K=(45.93\text{ g)(}\frac{1\text{ kg}}{1000\text{ g}})(9.8m/s^2)(31\text{ cm)(}\frac{1\text{ m}}{100\text{ cm}})(\frac{1\text{ J}}{1kgm^2s^{-2}^{}}) \\ =0.140\text{ J} \end{gathered}\)Thus, the kinetic energy of the ball is 0.140 J.
2. The velocity of a moving body increases from 10 m/s to 15 m/s in 5 seconds. Calculate its acceleration. 1m/s²]
Answer:
a=1m/s²
Explanation:
note that the moving body is accelerating from 10m/s to 15m/s, so in this case the initial velocity is 10mls, and the final velocity is 15m/s, and the body makes this increase in just 5seconds. so looking at what we've been given in the question, we can now calculate acceleration.
so our Data is;
V= 15m/s
U= 10m/s
t= 5m/s
a=?
we can find acceleration by using these two formulas;
1) V= U + at
15= 10+ a(5)
15=10+5a
make 5a the subject of the formula, and to make it the subject of the formula, we need to transpose 10m/s, and when we transpose it, it will
become a negative number because of crossing the equal sign
15-10=5a
5=5a
divide throughout by 5 to remain with a
5/5=5a/5
1=a
:. a=1m/s²
then the second formula is;
a= (V-U)/t
a=(15-10)/5
a=5/5
a=1m/s²
What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?
Answer:
Explanation:
The centripetal acceleration:
aₙ = F /m = 125 /19 ≈ 6.6 m/s²
Which of the following is an example of a fixed resistor?
A. Thermistor
B. Rheostat
C. Photoresistor
D. None of these
Answer:
None of these
Explanation:
Just took the test.
Find the x-component of this
vector:
70.8°
Remember, angles are measured from
the +x axis.
x-component (m)
Enter
45.6 m
C
Help Resources
ALL
It i
Fine
Re
Examp
PPT Tr
side
Compet
The x-component of this vector inclined from the horizontal axis is 15m.
What is vector?A vector is the representation of a physical quantity in magnitude and direction.
A vector incline at an angle in has two components. On in x direction and other is in y direction.
For the given length of vector = 45.6 m and the angle of inclination from the +x axis θ = 70.8°
The x component of the given vector is
= 45.6cos 70.8°
= 14.99 m
Thus, the x- component of this vector is 15m.
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Answer: -14.99
Explanation: I had the same question and here's what I got:
Values:
A = -45.6
θ = -70.8
Ax = A cos(θ)
= 45.6cos(70.8)
Ax = -14.99 (The - signs because the vector is left)
Bonus:
How to solve the y-component of the same problem:
A = 45.6
θ = 70.8
Ax = A sin(θ)
= 45.6sin(70.8)
Ax = 43 (I am unsure why it's not negative but trust me, this is correct.)
Always use significant figure rules. Remember that these rules apply to all numbers that are measurements.
Calculate the potential drop across R2
The potential drop across \(R_2\) is 7.455 V.
The potential drop across \(R_2\), we need to know the voltage drop across \(V_2\) and the current flowing through \(R_2\).
The voltage drop across \(R_1\) can be calculated using Ohm's law:
\(V_1\) = I * \(R_1\)
here \(V_1\) is the voltage drop across \(R_1\), I is the current flowing through \(R_1\), and \(V_2\) is voltage and the resistance of \(R_1\).
The current flowing through \(R_1\) is given, so we can calculate the voltage drop as follows:
\(V_1\) = (11.38 A) * (0.02899 m)
= 3.125 V
The current flowing through \(R_2\) can be calculated using Ohm's law:
I * \(R_2\) = \(V_2\) / \(R_2\)
here \(V_2\) is the voltage across \(R_2\), \(R_2\) is the resistance of \(R_2\), and I is the current flowing through \(R_2\).
We know that the potential difference between the ends of \(R_2\) is 2.70 V, so we can calculate the current flowing through \(R_2\) using the equation:
I = \(V_2\) / \(R_2\)
I = 2.70 V / 0.02899 m
= 92.28 A
Therefore, the potential drop across \(R_2\) is:
\(V_2\) = I *\(R_2\) * \(R_2\)
= (2.70 V) * (0.02899 m)
= 7.455 V
Therefore, the potential drop across \(R_2\) is 7.455 V.
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What is the probability of rolling a 6 on a number cube?
I was researching something for some teaching resources when I came across the phrase "six-sided number cube" on the AP Statistics website, which is a sort of Martian-like description of what we call a die in English.
With six numbers, there are 63 potential combinations. In general, the formula shown below can be used to determine how many combinations are possible given a set of n elements: 2n – 1 is the number of combinations with n elements. The equation then reads as follows for 6 elements. 6 elements could be combined in 720 different ways using the formula 6*5*4*3*2. If you have the option, you can alter the order of the components in a way that uses less of each.
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Melanie ran the 100 meters race in 12 seconds what was her avarage speed?
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
A spring with a spring constant of 40 N/m is compressed 0.15 m. How much energy is stored in the spring?
Answer: Energy is conserved.
Explanation: Energy stored in spring = Potential energy gained by object at maximum height
Jacob and Sydney went to Amazon forest to test the resistive forces offered by the sandal wood. They picked a huge tree that matched their requirement. They fired a bullet from their gun at the tree trunk. The bullet from the gun moving at 575 m/s penetrates the tree trunk to a depth of 5.50 cm. The mass of the bullet is 7.80 g. a) Find the average frictional force from the tree trunk that stops the bullet. b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.
a) The average frictional force from the tree trunk that stops the bullet is given by the formula F = (0.0078 kg * 575 m/s) / Δt, where Δt is the time it takes for the bullet to come to a stop.
b) The time elapsed between the moment the bullet enters the tree and the moment it stops moving is given by the formula Δt = (0.0078 kg * 575 m/s) / F, where F is the average frictional force.
a) To find the average frictional force from the tree trunk that stops the bullet, we can use the concept of impulse. The impulse is defined as the change in momentum of an object and is equal to the force applied multiplied by the time it acts.
The initial momentum of the bullet can be calculated using the formula:
p_initial = m * v_initial
where p_initial is the initial momentum, m is the mass of the bullet, and v_initial is the initial velocity of the bullet.
Mass of the bullet, m = 7.80 g
= 0.0078 kg
Initial velocity of the bullet, v_initial = 575 m/s
Substituting the values, we have:
p_initial = 0.0078 kg * 575 m/s
The final momentum of the bullet is zero since it comes to a stop.
The change in momentum is given by:
Δp = p_final - p_initial
Δp = 0 - (0.0078 kg * 575 m/s)
The average frictional force (F) can be calculated using the formula:
F = Δp / Δt
where Δt is the time it takes for the bullet to come to a stop.
Now we can calculate the average frictional force:
F = (0.0078 kg * 575 m/s) / Δt
b) To determine the time elapsed between the moment the bullet enters the tree and the moment it stops moving, we can rearrange the formula for average frictional force and solve for Δt:
Δt = (0.0078 kg * 575 m/s) / F
a) The average frictional force from the tree trunk that stops the bullet is given by the formula F = (0.0078 kg * 575 m/s) / Δt, where Δt is the time it takes for the bullet to come to a stop.
b) The time elapsed between the moment the bullet enters the tree and the moment it stops moving is given by the formula Δt = (0.0078 kg * 575 m/s) / F, where F is the average frictional force.
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An 0. 80-kg block is held in place against the spring by a 67-n horizontal external force (see the figure. The external force is removed, and the block is projected with a velocityv1 = 1. 2 m/s upon separation from the spring. The block descends a ramp and has a velocity v2 = 1. 9 m/s at the bottom. The track is frictionless between points a andb. The block enters a rough section atb, extending toe. The coefficient of kinetic friction over this section is 0. 39. The velocity of the block isv3 = 1. 4 m/s atc. The block moves on tod, where it stops. The spring constant of the spring is closest to
The spring constant of the spring is closest to 210 N/m.
First, let's calculate the potential energy stored in the spring:
PE = 1/2 k x^2
Therefore:
x = F_ext / k = 67 N / k
and:
\(PE = 1/2 k (67 N / k)^2 = 2244.5 J/k\)
Next, let's calculate the kinetic energy of the block at point b:
\(KE\_b = 1/2 m v2^2 = 0.5 * 0.8 kg * (1.9 m/s)^2 = 1.216 J\)
The work done by friction over the rough section is given by:
\(W\_f = f\_k * d\)
The frictional force is:
f_k = μ_k * m * g
Substituting the given values, we get:
\(f\_k = 0.39 * 0.8 kg * 9.81 m/s^2 = 3.06 N\)
The distance traveled over the rough section is:
\(d = h\_b - h\_c = 0.3 m - 0.1 m = 0.2 m\)
Therefore:
\(W\_f = 3.06 N * 0.2 m = 0.612 J\)
Finally, let's calculate the kinetic energy of the block at point c:
\(KE\_c = 1/2 m v3^2 = 0.5 * 0.8 kg * (1.4 m/s)^2 = 0.392 J\)
Using the principle of conservation of mechanical energy:
\(PE = KE\_b + KE\_c + W_f\)
Solving for k, we get:
\(k = 2 * (KE\_b + KE\_c + W_f) / (67 N / k)^2\)
Substituting the given values, we get:
\(k = 2 * (1.216 J + 0.392 J + 0.612 J) / (67 N / k)^2 = 210 N/m\)
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how much work is done when a 125 g tomato is lifted 13.6 m ? express your answer with the appropriate units.
Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .
What do you understand by work done?The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.
Work can be calculated by multiplying force with distance in the direction of force , and can be written as :
W = F × d
Given m= 125g = 0.125 kg
h= 13.6 m
W= P E
= m *g *h
= 0.125 * 9.8 * 13.6
Work done = 16.66 J
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What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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Shortest to longest wavelength
When isaac newton theorized that gravity caused objects to fall to the ground, he had also discovered the force that causes:.
Answer:
He did not find out any other force
Explanation:
Maybe the answer is that newton found out that the same force causes the earth rotating around the sun.
Can someone Please help me ?
What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s2?
Answer:
60m/s
Explanation:
We are given that
Speed of car after 5 sec, v=40m/s
Acceleration ,a=\(-4m/s^2\)
We have to find the initial speed of car.
We know that
Acceleration, a=\(\frac{v-u}{t}\)
Where v=Final speed
u=Initial speed
Using the formula
\(-4=\frac{40-u}{5}\)
\(-4\times 5=40-u\)
\(-20=40-u\)
\(u=40+20\)
\(u=60\)
Hence, initial speed of car=60m/s
Using the same criteria as in Question 1 for the percentage differences, describe your results for the determination of mass of the meter stick in Part 3 of the experiment
The percentage difference between Kₒw and Cᵢcw for the first two parts of the laboratory falls within acceptable ranges. The difference is 0.59 or less, which is excellent.
Determine the percentage difference?In the first two parts of the laboratory, the percentage difference between Kₒw (known forces balanced) and Cᵢcw is calculated.
A difference of 0.59 or less is considered excellent, indicating a high level of accuracy and precision in the measurements. This suggests that the experimental values closely match the expected values.
By meeting the criteria, it can be concluded that the experimental results for the first two parts of the laboratory are reliable and consistent.
The small percentage differences indicate that the measurements are within the acceptable range of uncertainty, providing confidence in the experimental procedure and data analysis.
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Complete question here:
Consider the percentage difference between the _ Kow and the C icw for the first two parts of the laboratory when known forces are balanced. A difference of 0.59 or less is excellent; difference of 1.0% or less is good, and difference of 2% or less is acceptable. Based on these criteria, describe your results for the first two parts of the laboratory and defend your statement Using the same criteria as in Question for the percentage differences_ describe your results for the determination of mass of the meter stick in Part 3 of the laboratory and fr the determination of the lever arm of the mass M4 in Part of the laboratory
Which of the following Resistors A, B, C or D, would use the least power? Make
your claim, give evidence and explain your reasoning. You may use math to support
your claim.
Please Help.
i think the answer is D 10.0
M 25 m in the distance traveled and an uncertainty of 1 s in the elapsed time. (a) calculate the percent uncertainty in the distance. (b) calculate the uncertainty in the elapsed time. (c) what is the average speed in meters per second? (d) what is the uncertainty in the average speed?
The answer for sub question A) calculate the percent uncertainty in the distance is 0.059%.
The answer for sub question B) calculate the uncertainty in the elapsed time is 9,012 s
The answer for sub question C) what is the average speed in meters per second is 4.681 m/s
The answer for sub question D) what is the uncertainty in the average speed is 0.0032 m/s
How are the answers calculated?To calculate the percentage of uncertainty of distance we have uncertainty = 25 m and distance = 42.188 km which is 42188 m.
Now \(\frac{25}{42188}\) x 100% = 0.059%
To calculate time elapsed, we have the following data:
2hr which is 7200 s, 30 min which is 1800 s and 12 s
Adding these all up, we get 9012 s.
The average speed in m/s is calculated by 42188 m/ 9012 s = 4.681 m/s
The uncertainty in average speed is calculated by 4.681 m/s x \(\frac{0.059 + 0.01}{100}\)
= 0.0032 m/s
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The complete question is A marathon runner completes a 42.188 km course in 2 h , 30 min, and 12 s . There is an uncertainty of 25 m in the distance traveled and an uncertainty of 1 s in the elapsed time. (a) Calculate the percent uncertainty in the distance. (b) Calculate the uncertainty in the elapsed time. (c) What is the average speed in meters per second? (d) What is the uncertainty in the average speed?
rotational kinematics with constant angular acceleration: a 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a rate of 20.0 revolutions per second. when the power to the grinder is turned off, the grinding wheel slows with constant angular acceleration and takes 50.0 s to come to a rest. (a) what was the angular acceleration (in rad/s2) of the grinding wheel as it came to rest if we take a counterclockwise rotation as positive? (b) how many revolutions did the wheel make during the time it was coming to rest?
(a) The angular acceleration of the grinding wheel as it came to rest is approximately -0.008 rad/s² (clockwise).
(b) The wheel made approximately 1000 revolutions during the time it was coming to rest.
(a) We can use the formula of rotational kinematics:
ω = ω₀ + αt
where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.
Given:
ω = 0 rad/s (final angular velocity)
ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)
t = 50.0 s
Substituting the values into the formula, we have:
0 = 20.0 * 2π + α * 50.0
Solving for α, we get:
α ≈ -0.008 rad/s² (clockwise)
(b) To find the number of revolutions the wheel made during the time it was coming to rest, we can use the formula:
θ = ω₀t + 0.5αt²
where θ is the angular displacement.
Given:
ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)
t = 50.0 s
α ≈ -0.008 rad/s² (clockwise)
Substituting the values into the formula, we have:
θ = (20.0 * 2π) * 50.0 + 0.5 * (-0.008) * (50.0)²
Simplifying the equation, we find:
θ ≈ 1000 revolutions
Therefore, the wheel made approximately 1000 revolutions during the time it was coming to rest.
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