Steve races to the nearest taco stand at lunchtime and sees that his pedometer recorded his peak speed at 86.7 cm/s. What was Steve's peak speed in kilometers per hour

Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

Answer:

73.3333meters per second

Explanation:

average velocity= distance ÷ time

=(88×1000)/(20×60)

=73.3333m/s

Answer:

0.04 °C⁻¹

Explanation:

First, we need to calculate linear expansivity, then after finding that value, we can move on to finding the area expansivity.

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Finding Linear Expansivity :

⇒ α = Final length - Original length / (Original length × ΔT)

⇒ α = 9 - 4 / (4 × 70 - 20)

⇒ α = 5 / 5 × 50

⇒ α = 0.02

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Finding Area Expansivity :

⇒ Area Expansivity = 2 × Linear Expansivity

⇒ β = 2 × α

⇒ β = 2 × 0.02

⇒ β = 0.04 °C⁻¹

Calculate the value of the area expansion of a steel rod of lenght 4cm at 20°c after heating attains another length of 9cm at 70°c.

Area = 0.02

Area Expansity = \(0.0 {4}^{ - 1} \)

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \(\frac{distance }{time}\)

Insert the parameters and solve;

  Average speed  = \(\frac{50}{3}\)   = 16.66667m/s  = 20m/s

The correct option is D, a property of every heterogeneous mixture is the characteristics of the mixture change within a sample is a property of every heterogeneous mixture.

The correct option is C, The sand particles are visible and can be seen suspended in the water, the mixture is a suspension of sand in water.

The correct option is A, B, and C., Colloids are mixtures that contain particles that are larger than those found in a solution but smaller than those found in a suspension.

The correct option is A,  Two liquids can form only a homogeneous mixture when mixed together.

Suspension refers to a mixture of two or more substances, where one substance is finely dispersed in another substance but does not dissolve in it. The dispersed substance is called the solute, and the substance in which it is dispersed is called the solvent.

A common example of suspension is muddy water. The dirt particles are suspended in the water but do not dissolve in it. Another example is blood, where red blood cells are suspended in plasma. The properties of a suspension depending on the size, shape, and density of the suspended particles. Larger particles will settle more quickly than smaller particles, and denser particles will settle faster than less dense particles. This settling process is called sedimentation.

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Answer:

2.92 m

Explanation:

As we know, frequency × Wavelength = Speed of light

so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..

So Lambda (wavelength) = 3×10⁸/ 102.7 × 10⁶ which gives 2.92 metres or 2.92 × 10¹⁰ Å

Answer:

The pressure of the gas=4.002 atm

Explanation:

We are given that

R=0.0821

Number of moles, n=15

Temperature, T=299 K

Volume of gas, V=92 L

We have to find the pressure of the gas.

\(PV=nRT\)

Substitute the values

\(P\times 92=15\times 0.0821\times 299\)

\(P=\frac{15\times 0.0821\times 299}{92}\)

\(P=4.002 atm\)

Hence, the pressure of the gas=4.002 atm

Answer:

According to the ideal gas law equation,

PV = nRT               (here, P = 5.5 atm, V = 10L, T = 298K, R = 0.0821 atmL/mol K)

or, n = RT/PV = (0.0821 X 298)/(5.5 X 10) = 0.44 moles of He gas

Explanation:

Answer:

The work completed is 73.5 Joule

Explanation:

Mechanical Work

Mechanical work is the amount of energy transferred by a force that moves an object by a certain distance. It's a scalar quantity, with SI units of joules.

Being  the force and  the displacement the work is calculated as:

W=F.s

The box of m=5 kg is lifted by a distance of s=1.5 m. The force applied to lift the box is equal to the weight of the box, assuming it's lifted at a constant speed, thus:

F = mg = 5 * 9,8 = 49 N

The work is:

W = 49 N * 1.5 m

W = 73.5 J

The work completed is 73.5 Joule

The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

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The escape speed from the surface of the asteroid is 253.509 m/s.

Escape speed is the minimum speed that an object needs to reach in order to escape the gravitational pull of another object. In order for an object to escape the gravitational pull of a massive body, it must have enough kinetic energy to overcome the gravitational potential energy.

To calculate the escape speed from the surface of the asteroid, we need to use the following formula:

\(v = \sqrt{2GM/r}\)

where:

v = escape velocity

G = gravitational constant (6.67430 × 10⁻¹¹ m³/kg s²)

M = mass of the asteroid

r = radius of the asteroid

Substituting the given values into the formula, we get:

\(v = \sqrt{(2 \times 6.67430 \times 10^{-11} \times 1.915\times 10^{20}) / 397.5\times 10^3}\)

v = 253.5 m/s

Therefore, the escape speed from the surface of the asteroid is approximately 253.5 m/s.

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When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.

Answer:

they don't, if you get hit in the face then the brackets are gonna rub up against the inside of your mouth then you'll bleed

Explanation:

An object which starts from its resting place & accelerates at a speed of 4 rad/sec², the angular displacement is 8 rad.

An object's angular displacement is described in the following:

Angle displacement is equal to θ\(f\)-θ\(i\).

The following methodology must also be applied to determine angular displacement when the object's acceleration, starting velocity, and time are known:

θ=ωt+ 1/2αt²

[where θ= the angular displacement of an object,

ω= initial angular velocity,

α= angular acceleration,

t= time]

In this case, the object starts from the rest position.

So, the initial angular speed, ω= 0 rad/sec

Provided angular acceleration ,α = 4 rad/sec²

Time ,t= 4 sec

So, θ= \(0*4+ (1/2)*4*4\)

⇒θ= 0+ 8

⇒θ= 8 rad

Therefore, it is concluded that the angular displacement is 8 rad.

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Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

The flow velocity and the gauge pressure in such a pipe on the top floor is \(P2 = 4.8547 × 10^5 Pa + (1\)

To solve this problem, we can use the principle of conservation of mass and conservation of energy for an incompressible fluid. We assume that the fluid is incompressible, so its density remains constant throughout the pipe.

First, we can calculate the flow velocity at street level using the equation of continuity:

A1V1 = A2V2

where A1 and A2 are the cross-sectional areas of the pipe at street level and the top floor, respectively, and V1 and V2 are the corresponding flow velocities.

We can calculate the cross-sectional areas using the formula for the area of a circle:

\(A = πr^2\)

where r is the radius of the pipe. Thus,

\(A1 = π(0.025 m)^2 = 0.00196 m^2A2 = π(0.013 m)^2 = 0.0005309 m^2\)

Now, we can solve for V1:

\(V1 = (A2/A1) * V2 = (0.0005309 m^2 / 0.00196 m^2) * 0.06 m/s = 0.0162 m/s\)

Next, we can use the principle of conservation of energy to relate the pressure and velocity at street level to the pressure and velocity at the top floor. We assume that there is no frictional losses or energy transfer to the surroundings, so the total mechanical energy of the fluid is conserved. This gives us the Bernoulli equation:

\(P1 + (1/2)ρV1^2 + ρgh1 = P2 + (1/2)ρV2^2 + ρgh2\)

where P1 and P2 are the pressures at street level and the top floor, respectively, ρ is the density of the fluid, g is the acceleration due to gravity, h1 is the height of the pipe at street level, and h2 is the height of the pipe at the top floor.

We can assume that the height difference between the two floors is the only difference in potential energy. Also, we can assume that the density of water is constant at 1000 kg/m^3. Thus, we can simplify the equation to:

\(P1 + (1/2)(1000 kg/m^3)(0.0162 m/s)^2 + (1000 kg/m^3)(9.81 m/s^2)(0 m) = P2 + (1/2)(1000 kg/m^3)V2^2 + (1000 kg/m^3)(9.81 m/s^2)(20 m)\)

Simplifying and solving for P2, we get:

\(P2 = P1 + (1/2)(1000 kg/m^3)(V1^2 - V2^2) + (1000 kg/m^3)(9.81 m/s^2)(h2 - h1)P2 = 3.8 atm + (1/2)(1000 kg/m^3)(0.0162 m/s)^2 - (1/2)(1000 kg/m^3)(V2^2) + (1000 kg/m^3)(9.81 m/s^2)(20 m)\)

We can convert the gauge pressure at street level to absolute pressure by adding atmospheric pressure (1 atm) and converting to Pascals (Pa):

\(P1 = (3.8 atm + 1 atm) * 1.01325 × 10^5 Pa/atm = 4.8547 × 10^5 Pa\)

Now we can solve for P2:

\(P2 = 4.8547 × 10^5 Pa + (1\)

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For the given information regarding the slab, (a) the roll force is 20062.83 lb, (b) the roll torque is 300.94 kip·in, and (c) power required to accomplish this operation is 2.63 kW.

It is given that:

(a) From the formula of roll force,

F = (0.5 × K × n × (h1 - h2) × w) / (ln (h1 / h2))

Put the given values,

F = (0.5 × 25000 × 0.16 × (3.0 - 2.5) × 9) / (ln (3.0 / 2.5))

F = 20062.83 lb

Therefore, the roll force is 20062.83 lb.

(b) From the formula of roll torque,

T = (F × R) / 1000

Put the given values,

T = (20062.83 × 15) / 1000

T = 300.94 kip·in

Therefore, roll torque is 300.94 kip·in.

(c) From the formula of power,

P = (T × 2π × N) / 33000

where N is the speed of roll in rpm

Put the given values,

N = (v × 12) / (2π × R) = (30 × 12) / (2π × 15) = 45.68 rpm

P = (300.94 × 2π × 45.68) / 33000P = 2.63 kW

Therefore, the power required is 2.63 kW.

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A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?

Zero. It is sitting on the ground.   This would almost always “assume” a friction-less environment where the only force acting on the bullet is gravity.  In this case, it would be 100 m/s immediately before hitting the ground. (zero once it comes to rest)

The gravitational potential energy of a 9.2 kg mass on the surface of the Earth is equal to zero.

Gravitational potential energy can be defined as the energy exhibited by an object because of a change in its position in a gravitational field.

The gravitational potential energy of two interacting masses is given by

\(U=-G\frac{mM}{R}\)

where m & M are the masses, R is the distance between the masses, and G is the gravitational constant.

The gravitational potential energy of a body at height h can be given by:

\(U = mgh,\)            where m is the mass of the object.

Given, the mass of the object, m= 9.2 Kg

The height from the surface = 0

The gravitational potential energy, U = mgh = 0

Therefore,  the gravitational potential energy of a mass on the surface of the Earth is zero.

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Answer:

B. raising the temperature of the air

Answer:

19500kg

Explanation:

If you divide 195000N by 10