A thermometer has marks at every one degree increment and the alcohol level of the thermometer was perfectly half way between the 20 and 21 degree Celsius marks. The temperature should be reported as 20.5 degrees Celsius.
This is because the thermometer has marks at every one degree increment, and the alcohol level is exactly halfway between the 20 and 21 degree marks. Therefore, it makes sense to report the temperature as a decimal value of 0.5, indicating that it falls halfway between two integer values.
In this case, since the alcohol level is halfway between 20 and 21 degrees Celsius, the temperature should be reported as 20.5 degrees Celsius. This is because the midpoint of the two marks represents a 0.5-degree increment.
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A physics teacher assigns research to its students. The
objective is to change the size of the batteries in order to
investigate the effects on the luminosity of the light bulb.
Which quantity is the independent variable?
Which quantity is the dependent variable?
proof of conservation of energy
What’s the substance that is formed as the result of a chemical reaction?
A. Chemical reaction
B. Catalyst
C. Activation energy
D. Collision theory
E. Products
F. Reactants
G. Reaction rate
Answer:
d
Explanation:
a battery is connected to a resistor. as charge flows, the chemical energy of the battery is dissipated as _________.
As charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.
Electric power is defined as the rate at which electric energy is dissipated.
The power of the current flowing through the circuit is calculated as follows;
P = IV
P = I x IR
P = I²R
where;
P is the power dissipatedI is the current flowing in the circuitR is the resistance of the circuitThe electric energy is given as;
E = Pt
E = I²Rt
Thus, we can conclude that as charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.
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Cameras that use adaptive optics provide higher spatial resolution images primarily because
a. they operate above Earth's atmosphere.
b. they capture infrared light, which has a longer wavelength than visible light.
c. deformable mirrors are used to correct the blurring due to Earth's atmosphere.
d. composite lenses correct for chromatic aberration.
e. they simulate a much larger telescope.
Cameras that use adaptive optics provide higher spatial resolution images primarily because c. Deformable mirrors are used to correct the blurring due to Earth’s atmosphere.
Adaptive optics is a technique used in imaging systems to compensate for the distortion and blurring caused by Earth’s atmosphere. The atmosphere introduces turbulence and variations in the refractive index, which degrade the image quality of astronomical observations or even ground-based photography. To overcome this, adaptive optics systems use deformable mirrors that can rapidly adjust their shape to counteract the atmospheric turbulence. These mirrors have numerous actuators that change their surface shape in real-time, based on the feedback received from wavefront sensors.
By continuously measuring the distortion caused by the atmosphere and adjusting the deformable mirror accordingly, adaptive optics systems can effectively correct the blurring and improve the spatial resolution of the images. This allows for sharper and more detailed observations, enabling higher spatial resolution. Options a, b, d, and e are not the primary reasons why adaptive optics provides higher spatial resolution images. While operating above Earth’s atmosphere (a) can indeed improve image quality, it is not specific to adaptive optics. Infrared light (b) and correcting for chromatic aberration with composite lenses (d) are separate aspects of imaging technology. Simulating a larger telescope € is not the primary purpose of adaptive optics but rather achieving better image quality by compensating for atmospheric distortions.
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A motorist is speeding along at 33m/s when he sees a squirrel on the road 200 meters in
front of him. He tries to stop, but it takes 12 seconds for his car to stop
(a) What is the acceleration of the car? (assume acceleration was constant)
(b) Does the squirrel survive?
(c) How fast was the car moving at 100 meters?
a) the acceleration of the car = -2.75 m/s
b) d = 198 meters. Therefore, the squirrel would survive.
c) the car moving at 100 meters with a speed of 23.22m/s
What is acceleration ?
acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Use the kinematic equation to solve for the acceleration:
v = u +at
v = final velocity
u = initial velocity
a = acceleration
t = time
In this instance, the final velocity is 0 because he comes to a stop. We can solve for the acceleration by plugging in the given values:
0 = 33 + (12)a
0 = 33 + 12a
-33 = 12a
-33 / 12 = a --> a = -2.75 m/s²
b) Find the amount of distance necessary to stop. Use the formula:
v^2 = u^2 + 2ad
d = distance
Plug in the values:
0² = 33² + 2(-2.75 · d)
0 = 1089 - 5.5d
-1089 = -5.5d
d = 198 meters. Therefore, the squirrel would survive.
c)
Find the velocity at 100 meters by using the same formula as before:
v^2 = u^2 + 2ad
However, in this instance, we are solving for the final velocity. Plug in the given points to solve:
vf² = 33² + 2(-2.75 · 100)
vf² = 1089 + (-550)
vf² = 539
vf = √539
vf ≈ 23.22 m/s.
the car moving at 100 meters with a speed of 23.22m/s
a) the acceleration of the car = -2.75 m/s
b) d = 198 meters. Therefore, the squirrel would survive.
c) the car moving at 100 meters with a speed of 23.22m/s
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Comparing stuff from a battery to the rubbing stuff
While both the rubbing stuff and batteries involve the generation and use of electrical energy, they differ in their underlying mechanisms and practical applications.
When it comes to comparing the rubbing stuff to a battery, there are a few key differences to consider. Firstly, the rubbing stuff, which is often referred to as static electricity, is generated through friction between two different materials.
This process creates a build-up of electrical charges, which can then be discharged through a spark or shock. In contrast, a battery generates electricity through a chemical reaction between two different materials, typically a metal and an electrolyte.
Another key difference is that while the rubbing stuff is often a temporary phenomenon, as the charges will dissipate over time, a battery can provide a continuous source of power as long as it has sufficient charge.
Additionally, a battery can be recharged and reused, whereas the rubbing stuff is generally a one-time occurrence.
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Using what you know about the compressibility of different states of matter explain why
a) air is used to inflate tyres
b) steel is used to make railway lines
Answer:
Explanation:
a) Air is highly compressible. As it has pressure it can also handle atm (Atmosphere) pressure. It makes the drving smooth and gives the required friction for driving. Also it is very easily available.
b) Steel is free from rust and it has high tensile strength. It has the resistence to internal and external cracks.
If you decrease the length of the pendulum by 10%, how does the new period TN compare to the old period T ? TN/T = _____
The period of a pendulum is given by the equation: T = 2π√(L/g) where L is the length of the pendulum and g is the acceleration due to gravity.
If we decrease the length of the pendulum by 10%, the new length will be 0.9L. So, the new period TN can be calculated as follows:
TN = 2π√(0.9L/g) = 2π(0.9487)√(L/g)
Therefore, the ratio of the new period TN to the old period T is:
TN/T = [2π(0.9487)√(L/g)] / [2π√(L/g)]
TN/T = 0.9487
So, if you decrease the length of the pendulum by 10%, the new period TN will be approximately 95% (0.9487) of the old period T.
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In order to increase the pain of a common emitter amplifier, we have to reduce the output impedance Select one: True false . Ves V. The NMOS transtor certainly operates in saturation region Select one True False
In order to increase the gain of a common emitter amplifier, we have to reduce the output impedance. This statement is false.
To increase the gain of a common emitter amplifier, it is more common to focus on increasing the input impedance and/or the transconductance of the transistor, rather than specifically reducing the output impedance.
The NMOS transistor certainly operates in the saturation region.
False. The operating region of an NMOS transistor depends on the voltages applied to its terminals. The NMOS transistor can operate in different regions, including the cutoff, triode, and saturation regions. The specific region of operation depends on the voltages applied to the gate, source, and drain terminals of the transistor.
It's important to note that the answers provided above are based on the given options, but the questions could be more accurately answered with additional context or clarification.
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How do I write answers in standard form?
Answer:
Example
Write 81 900 000 000 000 in standard form: 81 900 000 000 000 = 8.19 × 1013
It’s 1013 because the decimal point has been moved 13 places to the left to get the number to be 8.19
Determine the gradient of the graph.
Answer:
There is no graph, I will edit once the graph is posted
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On what factors does critical velocity depend on
Explanation:
The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.
A diver has a mass of 90 kg. If he climbs ip a diving platform 12m high, how much potential energy does he have.
Answer:
10,584 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 90 × 9.8 × 12 = 10,584
We have the final answer as
10,584 JHope this helps you
Because the neutron has no charge, its mass must be found in some way other than by using a mass spectrometer. When a neutron and a proton meet (assume both to be almost stationary), they combine and form a deuteron, emitting a gamma ray whose energy is 2.2233 MeV. The masses of the proton and the deuteron are 1.007 276 467 u and 2.013 553 212 u, respectively. Based on this data, what is the mass of the neutron
Answer:
Explanation:
Energy of gamma ray = 2.2233 MeV
Let mass of neutron be n amu
mass defect of deuteron = 2.013553212 - ( 1.007 276 467 + n ) u .
in terms of energy this mass defect will be equal to energy of gamma ray
1 amu = 931 MeV
931 [ 2.013553212 - ( 1.007 276 467 + n ) ] = 2.2233
( 1.007 276 467 + n ) - 2.013553212 = .00238807733
n = 1.008664822 amu
so mass of neutron = 1.008664822 amu
calculate the speed of a bowling ball that travels 4 meters in 2 seconds
Answer:
2 m/s
Explanation:
Just divide the distance and time. 4/2= 2 m/s
What is the velocity of an object that has been in free fall for 2.5 s?
A. -3.9 m/s downward
B. 3.9 m/s downward
C. 250 m/s downward
O
D. 25 m/s downward
Answer: D. 25 m/s Downward
Explanation:
V = (g)(t)
V = (9.8 m/s²)(2.5)
V = 24.5 m/s
The least buoyant force on a rock is when it is submerged. A) near the surface. B) halfway to the bottom. C) near the bottom. D) none of the above
The least buoyant force on a rock is when it is submerged near the bottom. The correct answer is option C, near the bottom. Why is the least buoyant force on a rock when it is submerged near the bottom?
Explanation:
The buoyant force is the upward force that acts on an object when it is placed in a fluid, such as water. The amount of buoyant force is dependent on the weight of the fluid displaced by the object.
When an object is submerged in a fluid, the buoyant force acts upwards, opposing the force of gravity acting downwards on the object.
The buoyant force is the greatest when the object is submerged near the surface of the fluid. This is because the weight of fluid displaced is more at the surface than it is at the bottom of the fluid. As a result, the buoyant force is less when the object is submerged near the bottom of the fluid.
Therefore, the least buoyant force on a rock is when it is submerged near the bottom.
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Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car B at −10 m/s when they collide head–on. If the resulting velocity of Car B after the collision is 8 m/s, what is the velocity of Car A after the collision?
Answer:
The velocity of Car A after the collision is 10 [m/s] in opposite direction to its original movement
Explanation:
In order to solve this problem we must use the principle of conservation of linear momentum, which is defined as the product of mass by Velocity.
P = m*v
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity.
We have to study the moment before the collision and the moment after the collision, the moment before the collision will be taken to the left of the equal sign and the moment after the collision will be taken to the right of the equal sign.
ΣPbefore = ΣPafter
(m1*v1) + (m2*v2) = (m1*v3) + (m2*v4)
where:
m1 = m2 = 100 [kg]
V1 = velocity of car A = 8 [m/s]
V2 = velocity of car B = - 10 [m/s]
V4 = velocity of car B after the collision = 8 [m/s]
(100*8) - (100*10) = (100*V3) + (8*100)
V3 = -10 [m/s]
Answer:
Answer:
The velocity of Car A after the collision is 10 [m/s] in opposite direction to its original movement
Explanation:
In order to solve this problem we must use the principle of conservation of linear momentum, which is defined as the product of mass by Velocity.
P = m*v
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity.
We have to study the moment before the collision and the moment after the collision, the moment before the collision will be taken to the left of the equal sign and the moment after the collision will be taken to the right of the equal sign.
ΣPbefore = ΣPafter
(m1*v1) + (m2*v2) = (m1*v3) + (m2*v4)
where:
m1 = m2 = 100 [kg]
V1 = velocity of car A = 8 [m/s]
V2 = velocity of car B = - 10 [m/s]
V4 = velocity of car B after the collision = 8 [m/s]
(100*8) - (100*10) = (100*V3) + (8*100)
V3 = -10 [m/s]
Explanation:
height 5. An inclined plane is 100 m long and at an angle of 20° to the horizontal. The AMA of the slope is two. Calculate: a) the effort required to push a 7200 N block up the slope b) the ideal mechanical advantage c) the efficiency of the slope.
(a) The effort required to push the block up the slope is 3600 N.
(b) the ideal mechanical advantage of the slope is 2.92
(c) The efficiency of the slope is 68.5%.
What is the effort required?a) To calculate the effort required to push the block up the slope, we can use the formula:
Effort = Load / AMA
where;
Load is the weight of the block, and AMA is the actual mechanical advantage of the slope.Load = 7200 N
AMA = 2
Effort = 7200 N / 2
Effort = 3600 N
b) The ideal mechanical advantage (IMA) of an inclined plane is given by the formula:
IMA = Length of slope / Height of slope
Length of slope = 100 m
Angle of slope = 20°
We can use trigonometry to find the height of the slope:
Height of slope = Length of slope x sin(angle of slope)
Height of slope = 100 m x sin(20°)
Height of slope = 34.2 m (rounded to one decimal place)
Therefore, the ideal mechanical advantage of the slope is:
IMA = 100 m / 34.2 m
IMA = 2.92 (rounded to two decimal places)
c) The efficiency of the slope is given by the formula:
Efficiency = AMA / IMA x 100%
AMA = 2
IMA = 2.92
Efficiency = 2 / 2.92 x 100%
Efficiency = 68.5% (rounded to one decimal place)
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Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The P-waves have a speed of about 5 km/s. Estimate the average bulk modulus of Earth's crust given that the density of rock is about 2,900 kg/m3
The bulk modulus is a measure of the resistance of a material to compression and is an important parameter for understanding the behavior of seismic waves in the Earth's crust during earthquakes.
The speed of longitudinal waves (P-waves) in a solid is given by:
v = √(K/ρ)
where v is the velocity of the wave, K is the bulk modulus, and ρ is the density of the medium.
Rearranging the above equation, we get:
K = ρ * v^2
Substituting the given values, we get:
K = 2,900 kg/m^3 * (5,000 m/s)^2
K ≈ 7.25 x 10^10 N/m^2
Therefore, the average bulk modulus of Earth's crust is approximately 7.25 x 10^10 N/m^2. This value is consistent with the bulk moduli of various types of rocks that make up the Earth's crust, which typically range from 5 x 10^9 N/m^2 to 100 x 10^9 N/m^2.
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which statement best explains why a salt solution conducts electricity? responses the ions move freely in water but lose their charges. the ions move freely in water but lose their charges. the salt crystals dissolve and form bridges by which electric charges move. the salt crystals dissolve and form bridges by which electric charges move. the ions move freely in water and carry electric charges. the ions move freely in water and carry electric charges. the salt crystals remain intact and form bridges by which electric charges move.
Pure water is not so much conductive, and only a small piece of current can move during the water. When salt or sodium chloride (NaCl) is melted in it, Yet, the salt molecules divided into two pieces, a sodium ion and a chlorine ion.
The sodium ion is lost an electron, that gives it a positive charge. The chlorine ion has an more electron, giving it a negative charge.
An electric origin sending a current through water will have two terminals: one is negative that conducts electrons into the water, and another is positive one that removes them.
Opposite charges attract, so the sodium ions are engaged to the negative terminal, and the chlorine to the positive.
The ions form a bridge, the sodium ions fascinating electrons from the negative terminal, passing them to chlorine ions and then the positive terminal.
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Help me with this pls I will make brainlest
Answer:
Help with what??
Explanation:
Explanation:
there is no question to answer..
during a journey, a car travels at 40 km in 2.5 hours, next 62 km in 3 hours, then took a break for 30 minutes, again travelled the last 120 km in 3.2 hours. calculate the average speed of the car during the journey.
When you are playing pool and a moving ball hits a stationary ball and the moving ball stops what happens to the momentum of the moving ball?
When a moving pool ball hits a stationary ball, some kinetic energy from the moving pool ball is transferred to the stationary ball and it attains momentum.
Both in the case of elastic and inelastic collisions, momentum is preserved. That means the total momentum will always be the same.
Momentum (ρ) is defined as "mass in motion". There are two factors affecting the momentum. Mass(m) and velocity(v).
ρ = m×v
So for a stationary object momentum will be 0. When the moving ball hits the stationary ball, it starts moving, because it gets kinetic energy from the moving ball. The total momentum before and after the collision will always be equal.
mₐ₁× vₐ₁ = mₐ₂×vₐ₂ + m₂ v₂
mₐ₁× vₐ₁ is the momentum of ball A before the collision
mₐ₂×vₐ₂ is the momentum of ball A after collision
m₂ v₂ is the momentum of ball B after collision.
So the stationary ball begins to move after the collision due to increased kinetic energy and attains some momentum. The total momentum of the system remains the same.
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Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
A 1.35 kgkg block is attached to a spring with spring constant 15.0 N/mN/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 34.0 cm/scm/s . What are
Given :
Mass of block , m = 1.35 kg .
Speed constant , k = 15 N/m .
Speed at centre , v = 34 cm/s = 0.34 m/s .
To Find :
The amplitude of oscillation .
Solution :
Now , we know total energy is conserved in SHM .
So , K.E at zero displacement :
\(K.E=\dfrac{mv^2}{2}\\\\K.E=\dfrac{1.35\times 0.34^2}{2}\\\\K.E=7.8\times 10^{-2}\ J\)
Now , this K.E is equal to maximum P.E :
\(P.E=K.E=7.8\times 10^{-2}\ J\) .
\(P.E=\dfrac{kA^2}{2}\\\\7.8\times 10^{-2}=\dfrac{kA^2}{2}\\\\A=\sqrt{\dfrac{2\times 7.8 \times 10^{-2}}{15}}\ m\\\\A=0.1019 \ m\\\\A=10.2\ cm\)
Therefore , the amplitude is 10.2 cm .
Hence , this is the required solution .
he space shuttle is traveling at an altitude of 550 km around the earth, what would be the escape velocity (in km/s) at this altitude if the shuttle was to leave the gravitational field of the earth to travel to mars?
The escape velocity at a given altitude from the Earth's surface is the minimum velocity required to escape the Earth's gravitational field and travel to an infinite distance from the Earth.
To calculate the escape velocity at an altitude of 550 km from the Earth's surface, we can use the following formula:
v = sqrt(2GM/R)
where v is the escape velocity, G is the gravitational constant (6.6743 × 10^-11 m^3/kg s^2), M is the mass of the Earth (5.9722 × 10^24 kg), and R is the distance from the center of the Earth to the spacecraft's position (6378.1 km + 550 km = 6928.1 km).
Converting the formula to kilometers per second and plugging in the values, we get:
v = sqrt(2 × 6.6743 × 10^-11 × 5.9722 × 10^24 / 6928.1) km/s
v ≈ 10.9 km/s
Therefore, the escape velocity at an altitude of 550 km from the Earth's surface is approximately 10.9 km/s. This is the minimum speed that the space shuttle would need to attain to leave the Earth's gravitational field and travel to Mars.
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1. Two charged spheres are held a distance r apart, as shown in the figure below. Compare
the force of sphere A on sphere B with the force of sphere B on sphere A.
A.
B.
C.
D.
Sphere A
+3aC
FA on B-FB on A
3FA on B-9FB on A
9FA on B = -3FB on A
FA on B=-6FB on A
he
+9 MC
Sphere B
the two changes
horos
Answer:
F = K Qa Qb / R^2
The forces are equal - the same on each sphere
Suppose the force was repulsive, for simplicity, obviously a string holding them together would have the same tension in both directions
True or false? A well-oiled machine has no friction. Explain your answer.
Answer:
False
Explanation:
A well-oiled machine has oil because there is friction. The oil lessens the friction and also allows the machine to operate and function without wear parts heating up. Oil is a cooling lubricant that decreases friction but does not eliminate it.