the product of 700 and 4000 expressed in scientific notation is

Answer:

y = 1/4x-1

Step-by-step explanation:

Ok first, you need to find the slope:

0+2 = 2=1

4+4 = 8=4

Slope: 1/4

y=1/4x+b

Now you need to find the y intercept which is b. For that you can take a coordinate pair and substitute it in the equation to find b.

I will use (4,0)

0=1/4 X 4 + b

0=x+b

minus x on both sides. x=1

-1=b

An equation of the line that passes through the pair of points

(- 4, - 2), (4, 0) is  y + 2 = (1/4)(x + 4).

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

Given, A  line that passes through the pair of points. (−4, −2), (4, 0).

We also know slope(m) = (y₂ - y₁)/(x₂ - x₁) = (0 + 2)/(4 + 4) = 1/4.

So, the equation of a line in point-slope form is y - y₁ = m(x - x₁).

∴ y + 2 = (1/4)(x + 4).

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Answer:

12

Step-by-step explanation: each side is 3, and there are 4 sides so 3*4=12

137

Step-by-step explanation:

43+ z=180

z=180-43

= 137

Answer:

137°

Step-by-step explanation:

Subtract 43 from 180

180 is the degree of a straight line

Angles y and 43 degree angle are equal so to find z you subtract the 43 from 180

180 - 43 = 137

Answer:

the price with the offer is going to be 1.59$

Step-by-step explanation:

\( \frac{x}{5.30} = \frac{70}{100} \)

\(100(x) = 70(5.30)\)

\(100(x) = 371\)

\( \frac{100(x)}{100} = \frac{371}{100} \)

\(x = 3.71\)

\(70\% \: \: \: of \: \: \: 5.30 \: \: \: is \: \: \: 3.71\)

\(5.30 - 3.71 = 1.59\)

Answer:

acute and obtuse and scalene are the answers

Answer: 17223

Step-by-step explanation:

You have to multiply your

Step-by-step explanation:

456×43-53(45)=

19608-53(45)

19608-2385

17223 Answer

A graph which shows the image of ABCD is: A. on a coordinate plane, parallelogram A'B'C'D' has points (-2, 5), (0, 3), (0, -1.2), (-2, 1).

A transformation refers to the movement of a point on a cartesian coordinate from its original (initial) position to a new location.

In Geometry, there are different types of transformation and these include the following:

Based on transformation of parallelogram ABCD, we can infer and logically deduce that a graph which shows the image of ABCD is that on a coordinate plane, with parallelogram A'B'C'D' having points (-2, 5), (0, 3), (0, -1.2), (-2, 1) as shown in the image attached below.

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The fraction computed shows that the number of his next 20 free-throw attempts that you expect Vijay to miss is 15.

From the information given, Vijay missed 12 out of his last 16 free throws. The fraction missed will be:

= 12/16

= 3/4

Therefore, the number of his next 20 free-throw attempts that you expect Vijay to miss will be:

= 3/4 × 20

= 15

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The probability that all 4 students will maintain or improve their average is 0.4096 (40.96%).

It is said that there are 80 percent chances that the student will maintain or raise the GPA score,

P = 1 - 0.8

P = 0.2.

The probability that all 4 students will maintain or improve their average can be calculated by multiplying the individual probabilities together since they are independent events.

P = 0.8 × 0.8 × 0.8 × 0.8

P = 0.4096

Therefore, the probability that all 4 students will maintain or improve their average is 0.4096 or 40.96%.

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Answer:

121 mocha cupcakes

Step-by-step explanation:

\( \frac{45}{100} \times 220 = 99 \\ 99of \: the \: cupcakes \: were \: chocolate \\ mocha \: cupcakes = 220 - 99 \\ = 121\)

To answer your question, I would need to know the sample size and the number of students who expressed satisfaction with the OPRE 3360 course. With this information, we could conduct a hypothesis test using a one-sample proportion test. We would use the null hypothesis that the proportion of satisfied students is equal to a hypothesized value (for example, 0.5 if we assume that half of all JSOM undergraduate students are satisfied with the course). The alternative hypothesis would be that the proportion of satisfied students is different from the hypothesized value.

Using the .05 level of significance, we would calculate the test statistic and compare it to the critical value from the standard normal distribution. If the test statistic falls within the rejection region (i.e. the absolute value of the test statistic is greater than the critical value), we would reject the null hypothesis and conclude that the proportion of all JSOM undergraduate students who are satisfied with OPRE 3360 course is statistically different from the hypothesized value.

Without the necessary information, it is not possible to provide a definitive answer to your question.
Hi! To answer your question about the proportion of all JSOM undergraduate students who are satisfied with the OPRE 3360 course at a 0.05 level of significance, please follow these steps:

1. Define the null hypothesis (H0): The proportion of satisfied students is equal to a certain value (e.g., 50% or 0.5).
2. Define the alternative hypothesis (H1): The proportion of satisfied students is different from the specified value (e.g., not equal to 50% or 0.5).
3. Collect a random sample of students and calculate the sample proportion of satisfied students (p-hat).
4. Determine the standard error of the proportion: SE = sqrt((p0 * (1 - p0)) / n), where p0 is the proportion from the null hypothesis, and n is the sample size.
5. Calculate the test statistic: Z = (p-hat - p0) / SE.
6. Determine the critical value for a two-tailed test at a 0.05 level of significance (Z-critical = ±1.96).
7. Compare the test statistic (Z) to the critical value (Z-critical). If |Z| > Z-critical, reject the null hypothesis and conclude that the proportion of all JSOM undergraduate students who are satisfied with the OPRE 3360 course is significantly different from the specified value at a 0.05 level of significance.

Please note that to complete the above steps, you need to provide the specified proportion value (e.g., 50% or 0.5) and the data from a random sample of students.

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The probability of event A and event B is 6.

Given that, P(A)=6, P(B)=20 and P(A∩B)=6.

P(A/B) Formula is given as, P(A/B) = P(A∩B) / P(B), where, P(A) is probability of event A happening, P(B) is the probability of event B.

P(A/B) = P(A∩B) / P(B) = 6/20 = 3/10

We know that, P(A and B)=P(A/B)×P(B)

= 3/10 × 20

= 3×2

= 6

Therefore, the probability of event A and event B is 6.

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Answer:

Slope intercept form : y=x-1

Point slope form : y+5=1(x+3)

Answer:

15

Step-by-step explanation:

The formula for Mean or Average = Sum of terms/Number of terms

We are given this number of points: 8,12,16,19,20

The average number of points per starting player is calculated as:

8+12+ 16+19+20/5

= 75/5

= 15

Therefore, the average number of points per starting player = 15

Answer:

8

Step-by-step explanation:

This is because the graph shows for 1 cup of pecans, there are 8 pralines.

Hope it helps!

Answer:

6.08333....

Step-by-step explanation:

.25 +w = 19/3

19/3=6.3333

6.3333-.25=6.08333....

Check:

.25+6.08333....=6.3333...

Answer:

3n + 2

Step-by-step explanation:

To find the exact length of the curve given by x = et − 9t, y = 12et/2, 0 ≤ t ≤ 3, we can use the arc length formula:
L = ∫(a to b) √[dx/dt]^2 + [dy/dt]^2 dt
Substituting the given values, we get:
L = ∫(0 to 3) √[e^t - 9]^2 + [6e^(t/2)]^2 dt
Simplifying the expression under the square root, we get:
L = ∫(0 to 3) √(e^(2t) - 18e^t + 81 + 36e^t) dt
L = ∫(0 to 3) √(e^(2t) + 18e^t + 81) dt
L = ∫(0 to 3) (e^t + 9) dt
L = [e^t + 9t] from 0 to 3
L = [e^3 + 9(3)] - [e^0 + 9(0)]
L = e^3 + 27 - 10.99
L ≈ 25.5
Therefore, the exact length of the curve is approximately 25.5 units.

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Answer:

6. 21.0°

7. 39.6°

8. 58.0°

9. 72.9°

Step-by-step explanation:

6. Reference angle (θ) = x°

Hypotenuse = 15

Adjacent = 14

Apply CAH:

\( Cos(\theta) = \frac{Adjacent}{Hypotenuse} \)

Plug in the values

\( Cos(x) = \frac{14}{15} \)

\( x = Cos^{-1}(\frac{14}{15}) \)

x ≈ 21.0° (nearest tenth)

7. Reference angle (θ) = x°

Opposite = 19

Adjacent = 23

Apply TOA:

\( Tan(\theta) = \frac{Opposite}{Adjacent} \)

Plug in the values

\( Tan(x) = \frac{19}{23} \)

\( x = Tan^{-1}(\frac{19}{23}) \)

x ≈ 39.6° (nearest tenth)

8. Reference angle (θ) = x°

Hypotenuse = 17

Adjacent = 9

Apply CAH:

\( Cos(\theta) = \frac{Adjacent}{Hypotenuse} \)

Plug in the values

\( Cos(x) = \frac{9}{17} \)

\( x = Cos^{-1}(\frac{9}{17}) \)

x ≈ 58.0° (nearest tenth)

9. Reference angle (θ) = x°

Opposite = 43

Hypotenuse = 45

Apply SOH:

\( Sin(\theta) = \frac{Opposite}{Hypotenuse} \)

Plug in the values

\( Sin(x) = \frac{43}{45} \)

\( x = Sin^{-1}(\frac{43}{45}) \)

x ≈ 72.9° (nearest tenth)

Answer:

Below

Step-by-step explanation:

Losing 27 % of value each year means it retains 73% each year

  we need to multiply 20 000 x  .73 x .73 x .73     ....  .73     (twelve times )

                  or   re-written as   20 000 * .73^12 = value =$ 458.04

As we have proved that the matrix u can be written as a linear combination of the column vectors of a, which implies that u lies in the plane in ℝ3 spanned by the columns of a.

Let us consider the given vectors u=−16 13 20 and the matrix a=5 −7 −2 4 2 2. To determine whether u lies in the plane in ℝ3 spanned by the columns of a, we need to check whether u can be written as a linear combination of the column vectors of a.

We can express the matrix a as a linear combination of its column vectors as follows:

a = 5 4 −2 ⋅ [1 0 0] + (-7) 2 4 ⋅ [0 1 0] + (-2) 2 2 ⋅ [0 0 1]

Therefore, the column vectors of a span a plane in ℝ3.

Now, let us try to express u as a linear combination of the column vectors of a:

u = α[5 4 −2] + β[-7 2 4] + γ[-2 2 2]

where α, β, and γ are constants to be determined.

Setting up a system of linear equations, we get:

5α − 7β − 2γ = −16

4α + 2β + 2γ = 13

−2α + 4β + 2γ = 20

Solving this system of equations, we get α = −4, β = −1, and γ = 3.

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Answer:

21 Remainder 16

Step-by-step explanation:

I used a calculator bcuz I'm  s t o o p i d :')

Answer:

x*5.5 + y* 7.25 = 45.5

x + y = 7

Step-by-step explanation:

every Espresso cost 5.5 => x*5.5

And the total cost is 45.5 so the sum should be 45.5

there are 7 coffees. means that the number of Espresso and latte is 7

Answer:

To find the perimeter of a polygon, we add up the lengths of all the sides. In this case, we have a quadrilateral with sides of length y+8, y+7, y+7, and y+8.

Perimeter = (y+8) + (y+7) + (y+7) + (y+8)

Simplifying by combining like terms, we get:

Perimeter = 4y + 30

Therefore, the perimeter of the quadrilateral is 4y + 30.

Answer:

4y + 30

Step-by-step explanation:

To find:-

Answer:-

Perimeter is simply the sum of all sides of any figure. Since here it is a quadrilateral, perimeter would be the sum of all four sides of it .

The four sides given to us are , y+7 , y+8 , y+7 and y+8. We can add them to find out the perimeter as ,

Perimeter = y+7 + y+8 + y+7 + y+8

Perimeter = 4y + 30

Hence the perimeter of the given figure is 4y+30 .

The simplified expression of g(x) = x² - 4x² + x + 6 is g(x) = -3x² + x + 6

From the question, we have the following parameters that can be used in our computation:

g(x) = x² - 4x²+x+6

Rewrite properly

So, we have the following representation

g(x) = x² - 4x² + x + 6

Evaluate the like terms

g(x) = -3x² + x + 6

The above expression cannot be further simplified

Hence, the solution is g(x) = -3x² + x + 6

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There were 60 jelly beans in the unopened bag of jelly beans.

Let's work through the problem step by step to find the original number of jelly beans in the bag.

John ate three-fourths of the jelly beans.

This means that he consumed 3/4 of the total number of jelly beans, leaving 1/4 of the original amount.

Mike then ate two-thirds of the remaining jelly beans.

Since 1/4 of the original amount was left after John, Mike ate 2/3 of this remaining 1/4.

To find out how much is left, we need to calculate \((\frac{1}{4} )\times (\frac{2}{3} )\).

\((\frac{1}{4} )\times(\frac{2}{3} )=\frac{2}{12} =\frac{1}{6}\)

Mike ate 1/6 of the original amount, leaving 1/6 of the original amount.

Finally, Fred ate the ten jelly beans that were left.

We know that these ten jelly beans represent 1/6 of the original amount.

Let's calculate how many jelly beans are equal to 1/6.

\(\frac{1}{6} = 10\) jelly beans

Now, we can determine how many jelly beans are equal to 6/6 (the whole).

\(\frac{1}{6} \times6=10\times6=60\) jelly beans

Therefore, there were 60 jelly beans in the unopened bag of jelly beans.

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As a simplified fraction, we have 107/33

Note that fractions are simply described as the part of a whole number or variable.

There are different types of fractions;

From the information given, we get;

3. 24 repeating can be expressed as the sum of 3 and 0. 24

Let x be 3.24

Then, we have;

Multiplying 100 by a certain number results in a repeating decimal of 324. 24

100x = 324.24

After taking the difference between the two equations, we have;

99x = 321.

Make 'x' the subject of formula, we have;

x = 321/99

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The values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.

The concept of the integral is a fundamental part of calculus and it is used to calculate the area under a curve or the volume of a 3-dimensional object. In this context, we will be exploring the integral of a two-dimensional set in the R^2 plane.

For every two-dimensional set C contained in R^2 for which the integral exists, the function Q(C) is defined as the double integral of the function (x^2 + y^2) over the set C. The double integral is a mathematical tool for finding the total volume under a surface.

Let's consider the three sets C1, C2, and C3 and find Q(C1), Q(C2), and Q(C3).

C1={(x,y) : −1 ≤ x ≤ 1, −1 ≤ y ≤ 1}

Q(C1) = ∬C1 (x^2 + y^2) dxdy = ∫^1_{-1}∫^1_{-1} (x^2 + y^2) dxdy = ∫^1_{-1} [(x^2 + y^2)/2]^1_{-1} dx = 4.

C2 ={(x,y):−1≤x≤1,−1≤y≤1}

Q(C2) = Q(C1) = 4.

C3 = {(x,y):x^2 + y^2 ≤1}

Q(C3) = ∬C3 (x^2 + y^2) dxdy = π.

In conclusion, the values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.

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