The volume of a sphere is increasing at the rate of 8cm3/s. Find the rate at which its surface area is increasing when the radius of the sphere is 12cm.

The speed of the car is 10.10 meters per second.

The rate at which an object's position changes in any direction is referred to as speed.

The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

The speed of the car = total distance travelled/ time interval

= 200 km/5.5 hour

= 200 × 1000 meter/ 5.5 × 3600 second

= 10.10 meter/second

Hence, the speed of the car is 10.10 meters per second.

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Answer:

Acceleration is a vector, is measured in m/s, and A.

Explanation: SO BASICALLY, the answer to this question is A, B, and C. The last one would not fit the description of acceleration because it is describing Velocity.

The integral of the force over the distance can be used to calculate the amount of work needed to draw up a certain section of the cable.

Let's use the symbol w to represent the cable's weight per unit length. The cable's overall weight can thus be expressed as wL, where L is the cable's length. In this issue, L = 40 ft and w = 60 lb/40 ft = 1.5 lb/ft are given.

The work necessary to lift a section of the cable with length x is:

W = F(x')dx' 0x F(x')

Given that the cable's weight is uniformly distributed, we have:

F(x') = w(x - x')

When we insert this into the integral, we obtain:

W = ∫0x w(x - x')

dx'\s= wx^2/2

When we enter the values, we obtain:

75 ft-lb = W = (1.5 lb/ft)(10 ft)2/2

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The pulley is initially at rest are:

a) The angular acceleration is 0 rad/s^2.

b) The angular speed is 0 rad/s.

Initially, the acceleration of the pulley is zero. As the pulley starts to move, the acceleration increases until it reaches its maximum value, which is determined by the magnitude of the force applied to it. As the pulley continues to move, the acceleration gradually decreases until it reaches zero again as the pulley comes to rest.

Angular acceleration is the rate at which the angular velocity of an object changes over time. It is usually expressed in terms of radians per second squared (rad/s2). Angular acceleration is caused by a torque being applied to an object and can be used to predict the angular velocity of a spinning object. Angular acceleration is a vector quantity, meaning it has both magnitude and direction.

Angular speed is the rate at which an object rotates or revolves around an axis. It is measured in terms of angle per unit of time and is usually expressed in radians per second (rad/s) or revolutions per second (rpm). Angular speed is related to linear speed, which is the distance traveled per unit of time. The angular speed can be calculated by taking the ratio of the linear speed and the radius of the circular path.

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So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.

Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.

Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.

Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).

If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.

Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.

Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.

Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]

Electrical tape

Rubber bands

Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)

The shift or change in a wave's frequency or wavelength brought on by the proximity of an emitting or reflecting sound source to the receiver. Therefore, the wavelength of the sound wave is 1.10 meters.

You may have noticed that the pitch of a fast-moving siren suddenly decreases as it passes past you. Because the pitch is higher, the siren initially appears to be approaching you. The siren's pitch drops as it moves away from you after passing you. The Doppler effect is being displayed here.

wavelength = speed / frequency

where wavelength is in units of meters, speed is in units of meters per second (m/s), and frequency is in units of Hertz (Hz).

For a sound wave with a speed of 680 m/s and a frequency of 220 Hz:

wavelength = speed / frequency

wavelength = 680 m/s / 220 Hz

wavelength = 3.09 m

Therefore, the wavelength of the sound wave is 3.09 meters.

For a sound wave with a speed of 960 m/s and a frequency of 875 Hz:

wavelength = speed / frequency

wavelength = 960 m/s / 875 Hz

wavelength = 1.10 m

Therefore, the wavelength of the sound wave is 1.10 meters.

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Answer:

The force formula is defined by Newton's second law of motion: Force exerted by an object equals mass times acceleration of that object: F = m×a( force = mass×area)

The graph of the relationship between amplitude and decibel level of sound is not a linear graph but a logarithmic graph.

It is known as the Sound Intensity Level graph, where the amplitude of the sound is plotted on the x-axis, and the decibel level of sound is plotted on the y-axis.

As the amplitude of the sound increases, the decibel level increases as well. The relationship is not directly proportional, as a small change in amplitude can result in a significant change in decibel level. For example, a sound with an amplitude of 1 Pa has a decibel level of 0 dB, whereas a sound with an amplitude of 10 Pa has a decibel level of 20 dB. This indicates that the decibel level is increasing exponentially with the increase in amplitude.

Moreover, the graph shows that the human ear has a limited range of hearing, which is between 0 dB and 140 dB. Beyond this range, sounds become too loud to hear or can cause damage to the ear. Therefore, it is important to monitor the decibel level of sound to protect our hearing.

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The acceleration on side b (ab) is 0.80 times the acceleration on side a (aa).

For side b:

The normal force is equal to the weight of the box, which is mg, where m is the mass of the box (10 kg) and g is the acceleration due to gravity. Thus, N = mg.

The force of friction on side b can be written as:

\(Fb = \mu b * mg\).

Since  \(\mu b = 0.80 * \mu a\),

we have \(Fb = 0.80 * \mu a * mg\).

Using Newton's second law, Fb = ma. Substituting the force of friction expression, we get:

\(0.80 * \mu a * mg = ma.a = 0.80 * \mu a * g.\)

For side a:

The force of friction on side a (Fa) is given by\(Fa = \mu a * mg\).

Using Newton's second law, Fa = ma. Substituting the force of friction expression, we get:

\(\mu a * mg = ma.\)

Simplifying the equation, we find:

\(a = \mu a * g.\)

Comparing the accelerations on side b (ab) and side a (aa), we have:

\(ab = 0.80 * \mu a * g, \\aa = \mu a * g.\)

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--The complete Question is, A box of mass 10 kg is placed on a ramp inclined at an angle of 30 degrees to the horizontal. The terrain on the upper side of the ramp, denoted as side b, is smoother than the lower side, denoted as side a. The friction coefficient on side b is 0.80 times the friction coefficient on side a. If the box starts sliding down from rest, what is the acceleration of the box on side b compared to side a? --

Answer:

The Answer To This Question Is B

Explanation: Please Mark Brainliest!

The point where the potential is zero is at a distance of 2 cm from the origin on the x-axis between the two charges.

There are two charges and we need to find a point on the x-axis between the two charges where the electric potential is zero. The charges are

q₁ = -2.00 nC and q₂ = 3.00 nC.

The electric potential at a point on the x-axis is given as:

\(V=kq₁/(r₁) + kq₂/(r₂)\)

By using the principle of superposition, the potential can be written as:

\(V = k(q₁/r₁ + q₂/r₂)\)

We need to identify the point on the x-axis where V=0. Now, the distance of the point from both the charges is equal. Hence, r1 = r2 = r

Distance of each charge from the origin = 0.02 m

Now, we have

\(V = k(q₁/r + q₂/r)0 \\\)

\(= k(-2 × 10⁻⁹ / r + 3 × 10⁻⁹ / r)0\)

\(= k(1 × 10⁻⁹ / r)\)

\(r = 3/2 × 10⁻⁹ / (9 × 10⁹ × 8.99 × 10¹)\)

\(r = 2 cm\)

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The wavelength of the light produced by lasers in CD drives is 780 nm.

The wavelength of the light produced by lasers in CD drives are given below.

A laser is a light source that emits light through a process known as stimulated emission. The term "laser" stands for Light Amplification by Stimulated Emission of Radiation. Lasers emit light coherently, which means that the waves of light they emit are in phase with one another.

Wavelength of Laser Light Lasers are used to read and write data from and to CDs and DVDs. In a CD or DVD player, the laser emits light of a specific wavelength onto the disk.

As a result, the reflection of the laser light is altered. The alterations reflect the 1s and 0s that make up the data stored on the disc, allowing the laser to read the data.

Wavelength of the Light Produced by Lasers in CD Drives. The wavelength of the light produced by lasers in CD drives is around 780 nm (nanometers).

The wavelength of the light produced by lasers in CD drives is 780 nm.

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The type of asteroid that would appear darkest and reflect the least light is type option E) S.

Among the given options, type E) S asteroids would appear darkest and reflect the least amount of light. Asteroids are classified into different types based on their composition, and type S asteroids belong to the silicate group. They are made up of rocky materials, such as silicates and metals, and they tend to have a relatively low albedo.

Albedo refers to the amount of light an object reflects, and a low albedo means that the object absorbs more light than it reflects. As a result, type S asteroids appear darker because they absorb a significant portion of the incident light rather than reflecting it. Their dark appearance is due to their composition and surface properties.

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Answer:

b

Explanation:

imagine urself on an elevator dont you feel lighter

A wheelchair ramp length is 20 ft; the ramp height is 5 ft;  and the effort to push the chair is 40 lbs. Using the mechanical advantage formula, is the person’s weight is 160 lbs.

Calculation

The equation for the mechanical advantage,

Is the effort multiplied by the ramp length should equal the weight of the person multiplied by the height of the ramp

(effort x ramp length= persons weight x ramp height).

For this scenario,

the equation would be effort (40 lbs) x ramp length (20 ft) = persons weight (x) x ramp height (5ft).

               40 x 20 = (x) x 5

Solving for x,

the persons weight is 160 lbs.

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Answer:

The weak nuclear force perhaps?

Explanation:

the weak nuclear force is the fundamental force responsible for the radioactive decay of particles

We will have that the direction of centripetal force is pointed directly towards the point of revolution/rotation; this in a circular movement is pointing directly to the center of the circular motion.

Complete Question:

A student has been assigned to measure the density of an irregularly shaped piece of metal.

Which apparatus would be most appropriate to carry out this task?

Group of answer choices

A. ruler, balance

B. beaker, crucible

C. flask, Bunsen burner

D. graduated cylinder, balance

Answer:

D. graduated cylinder, balance

Explanation:

In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.

The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.

A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.

Answer:

B

Explanation:

Answer:

 v = 344.1 m / s    

 d = 1720.5 m

Explanation:

For this problem we must calculate the speed of sound in air at 22ºC

           v = 331 RA (1+ T / 273)

we calculate

           v = 331 RA (1 + 22/273)

           v = 344.1 m / s

the speed of the wave is constant,

           v = d / t

           d = v t

we calculate

           d = 344.1   5

           d = 1720.5 m

|E| = 16.67 N/C and the direction of this Electric field is in the downward direction.

We have a Charge particle present inside a Electric field.

We have to determine the magnitude (in n/c) and direction of an electric field that exerts a 2 x \(10^{-5}\) Newton.

The electric field intensity at a point R meters away from a charge Q is the amount of force experienced by the test charge (\($q_{o}\)) of unit magnitude at a distance R meters away the Charge Q. Mathematically -

E = \($\frac{F}{q}\)

According to the question, we have -

F = 2 x \(10^{-5}\) Newton

|Q| = - 1.2 \(\mu\)C = - 1.2 x \(10^{-6}\)  \(\mu\)C = 1.2 x \(10^{-6}\) \(\mu\)C

Therefore -

E = \($\frac{2\times 10^{-5} }{1.2\times 10^{-6} }= \frac{100}{6} = 16.67\;N/C\)

Therefore -

|E| = 16.67 N/C and the direction of this Electric field is in the downward direction.

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Answer:

Tt can be calculated by copy

Answer:

vhijko and eye rudiieidjdjddjjd

Explanation:

jdjdjdjdjfjofkd ruudoeksowkosksd and nkdeondjvndkxnfuvjfk

When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.

Answer:

/////////////////////////////////////////////////

Explanation:

Answer:

c 0.10

Explanation:

V=IR

12.0V=I x 120.12ohms

I=0.099

I= 0.10

Answer:

f=ma

therefore we have f=36N

                               m=9kg

a=f/m

36/9

=4m/s^2

Explanation:

The acceleration of 9 kg rock and being acted upon by a 36 N force would be 4 m/s2

Recall Newton's law of motion which says that the magnitude of a force (F) needed to accelerate (a) a body with mass (m) is the product of the acceleration and the mass of the body.

In other words; F = ma

Thus, a = F/m

In this case, F = 36 N and m = 9 kg

acceleration (a) = 36/9

                            = 4 m/s2

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Motor vehicle crashes account for more than 90% of all transportation-related fatalities.Motor vehicle crashes are a significant contributor to fatalities in transportation-related incidents worldwide.

They encompass accidents involving cars, trucks, motorcycles, and other vehicles on roads. The high percentage indicates that the majority of fatalities in transportation are directly linked to motor vehicle accidents. This highlights the urgent need for improving road safety measures, promoting responsible driving behaviors, and implementing effective traffic regulations to reduce the number of accidents and ultimately save lives. Efforts such as enforcing seatbelt usage, discouraging distracted driving, and educating the public on the dangers of impaired driving can contribute to decreasing this alarming statistic.

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Answer:

477.75cm^2

Explanation:

Area formula is L x W

27.3cm x 17.5cm = 477.75cm^2

Answer:

477.75

Explanation:

multiply one side by the other