Tiana has a new beaded necklace. The necklace has 3 blue beads and 17 white beads. What percentage of the beads on Tiana's necklace are blue?

The margin of error for this estimate is given as follows:

0.0505.

The margin of error of a confidence interval is calculated as half the difference between the bounds of the confidence interval.

The bounds of the confidence interval in this problem are given as follows:

0.6525 and 0.7535.

Hence the margin of error is calculated as follows:

(0.7535 - 0.6525)/2 = 0.0505.

(the two bounds are 0.6525 and 0.7535, we calculate the difference between them and then divide by 2 to obtain the margin of error).

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Answer:

24 cm²

Step-by-step explanation:

The area of a rhombus is half the product of its diagonals.

\(\boxed{\sf Area\;of\;a\;rhombus=\dfrac{diagonal\;1 \cdot diagonal\;2}{2}}\)

Therefore, to find the area of the rhombus, we need to find the lengths of the diagonals AC and BD.

The diagonals of a rhombus are perpendicular bisectors of each other.

The point of intersection of the diagonals of rhombus ABCD is point O.

We can use the given information to find the lengths of BO and OC, then  double these to find diagonals AC and BD.

The sides of a rhombus are equal in length. Therefore, if the perimeter of rhombus ABCD is 20 cm, each side length is 5 cm.

Therefore, the hypotenuse of right triangle BOC is BC = 5 cm.

If the ratio of AC : BD = 4 : 3, then the ratio of OC : BO = 2 : 1.5.

Let OC = 2x and BO = 1.5x.

Use Pythagoras Theorem to find the value of x.

\(\begin{aligned}BO^2+OC^2&=BC^2\\(1.5x)^2+(2x)^2&=5^2\\1.5^2x^2+2^2x^2&=25\\2.25x^2+4x^2&=25\\6.25x^2&=25\\x^2&=4\\\sqrt{x^2}&=\sqrt{4}\\x&=2\end{aligned}\)

Therefore, to find the lengths of OC and BO, substitute x = 2:

\(OC = 2x = 2(2) = 4\; \sf cm\)

\(BO = 1.5x = 1.5(2) = 3\; \sf cm\)

As the diagonals of a rhombus bisect each other:

\(AC = 2\cdot OC=2 \cdot 4 = 8\; \sf cm\)

\(BD = 2\cdot BO=2 \cdot 3 = 6\; \sf cm\)

Finally, substitute the lengths of the diagonals into the formula for the area of a rhombus:

\(\begin{aligned}\textsf{Area of rhombus $ABCD$}&=\sf \dfrac{diagonal\;1 \cdot diagonal\;2}{2}}\\\\&= \dfrac{AC \cdot BD}{2}\\\\&=\dfrac{8 \cdot 6}{2}\\\\&=\dfrac{48}{2}\\\\&=24\; \sf cm^2 \end{aligned}\)

Therefore, the area of rhombus ABCD is 24 cm².

By finding the surface area of the box, we can see that the cost to cover the box is $285

We assume that we need to cover the 6 faces of the box, then we need to find the total surface area.

The surface area is given as:

S = 2( B*H + H*W + B*W)

Where:

Then the surface area is:

S = 2*(7ft*9ft + 7ft*2ft + 9ft*2ft) = 190ft^2

Now we know that the paper costs $1.50 per square foot, then the cost to cover the box is:

cost =  190*$1.50 = $285

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Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

\(M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\)

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

D(-4,4), X(-2, 2)

The midpoint is

\(M = ( \frac{ - 4 - 2}{2} \: , \: \frac{4 + 2}{2} ) \\ = ( - \frac{ 6}{2} , \frac{6}{2} )\)

We have the final answer as

Hope this helps you

Answer:

.78q = 58

q = 74.4 = 74 questions

Answer:

Step-by-step explanation:

a. The range of G is the set of possible values that G can take. G represents the distribution over the number of girls chosen, so G can take any value between 0 and 2, inclusive. That is, the range of G is {0, 1, 2}.

b. To give the distribution over the random variable G, we need to determine the probability of each possible value of G.

Let's consider each possible value of G in turn:

If no girls are chosen (G=0), then both representatives must be boys. The probability of choosing a boy on the first draw is 3/10, and the probability of choosing another boy on the second draw is 2/9 (since there are only 2 boys left). Therefore, the probability of G=0 is (3/10) * (2/9) = 1/15.

If one girl is chosen (G=1), then one representative must be a girl and the other must be a boy. There are two ways this can happen: either the girl is chosen first and then the boy, or the boy is chosen first and then the girl. The probability of choosing a girl on the first draw is 7/10, and the probability of choosing a boy on the second draw is 3/9 (since there are 3 boys left). The probability of choosing a boy on the first draw is 3/10, and the probability of choosing a girl on the second draw is 7/9 (since there are 7 girls left). Therefore, the probability of G=1 is (7/10) * (3/9) + (3/10) * (7/9) = 14/45.

If two girls are chosen (G=2), then both representatives must be girls. The probability of choosing a girl on the first draw is 7/10, and the probability of choosing another girl on the second draw is 6/9 (since there are 6 girls left). Therefore, the probability of G=2 is (7/10) * (6/9) = 7/15.

Therefore, the distribution over the random variable G is:

G=0 with probability 1/15

G=1 with probability 14/45

G=2 with probability 7/15

Answer:

STEP 1: See attached drawing  on graph paper

STEP 2:

Length of segment 1 - 2 = 100 feet

Length of segment 2 - 3 = 89.44 ft.

Length of segment 3 - 4 = 186.82 ft.

Length of segment 4 - 5 = 120.83 ft.

Length of segment 5 - 1 = 136.01 ft.

STEP 3:

The perimeter of the property is 633.103 ft.

STEP 4:

The cost of fencing by Company 1 is $7597.24

The cost of fencing by Company 2 is $8246.55

Therefore, the company that provides the cheapest quote for fencing the property is Company 1

Step-by-step explanation:

STEP 1: See attached drawing  on graph paper

STEP 2:

Therefore, we have

Length of segment 1 - 2 = √(8² + 6²) = 10 × 10 = 100 feet

Length of segment 2 - 3 = √(4² + 8²) = 4·√5× 10 = 40·√5 feet = 89.44 ft.

Length of segment 3 - 4 = √(5² + 18²) = √349 = 10·√349 feet = 186.82 ft.

Length of segment 4 - 5 = √(11² + 5²) = √146 = 10·√146 feet = 120.83 ft.

Length of segment 5 - 1 = √(11² + 8²) = √185 = 10·√185 feet = 136.01 ft.

STEP 3:

Therefore, the perimeter of the property = 100 + 89.44  + 186.82 + 120.83  + 136.01  = 633.103 ft.

STEP 4:

Hence the cost of fencing the property by Company 1 = $12 × 633.103 = $7597.24

The cost of fencing the property by Company 2 = $250 + $15 × 533.103 = $8246.55.

The area of the logo is given as 139 cm

In order to get the area of the shape, i would have to get the area of the triangles first

area of a triangle = 1/2 b * h

base = 9 / 2 = 4.5

h = 6

area = 1/2 * 9 * 6

= 27

Area of 2 triangle = 2 x 27

= 58

The are aof the square = a * a

= 9 * 9

= 81

The total area of the logo is given as 81 + 58

= 139 cm

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As an inequality, the number that is less than 0.4 is 0.09

The number is given as:

0.4

Let the number be represented as x.

So, we have:

x < 0.4

From the list of given options, the possible value of x is 0.09.

This means that 0.09 is less than 0.4

i.e 0.09 < 0.4

Hence, the number that is less than 0.4 is 0.09

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Given:

The given value is \(-a\).

To find:

The multiplicative inverse of \(-a\).

Solution:

We know that \(y\) is the multiplicative interval of \(x\) if \(xy=1\).

Let \(x\) be the multiplicative inverse of the given value \(-a\). Then,

\((-a)\times x=1\)

Divide both sides by \(-a\).

\(x=\dfrac{1}{-a}\)

\(x=-\dfrac{1}{a}\)

Therefore, the multiplicative inverse of \(-a\) is \(-\dfrac{1}{a}\). Hence the correct option is A.

Step-by-step explanation:

the solution is in the picture

Answer:

probabilty is the chance for you to get something

Answer:

This is the likelihood of getting 3 heads

Answer:

Continuous

A continuous random variable has infinitely many values, and those values can be associated with measurements on a continuous scale in such a way that there are no gaps or interruptions.

The GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2) is a^(2)b^(2), and the factored form of the polynomial is a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1).

The GCF, or greatest common factor, is the largest factor that all terms in a polynomial have in common. In this case, we need to find the GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2).

First, we need to look at the exponents of each term to determine the GCF. The smallest exponent for a is 2, and the smallest exponent for b is 2. Therefore, the GCF for this polynomial is a^(2)b^(2).

Next, we need to factor out the GCF from each term in the polynomial. This is done by dividing each term by the GCF and then multiplying the GCF by the resulting polynomial.

So, the factored form of the polynomial is:

a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1)

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Answer:

216

Step-by-step explanation:

15^2=225

3^2=9

225-9=216

a) 2.7% of mayflies live at least 26.8 hours.

b) 85% of the mayflies die after approximately 26.2 hours.

a) We can begin by standardizing the value of 26.8 hours:

\(z = \frac{26.8 - 23.7}{1.6} = 1.9375\)

Using a standard normal table or a calculator, we can find that the probability of a standard normal random variable being greater than 1.9375 is approximately 0.027, or 2.7%. Therefore, about 2.7% of mayflies live at least 26.8 hours.

b) We want to find the value of x such that 85% of the mayflies have a lifespan less than x. To do this, we need to find the z-score corresponding to the 85th percentile of the standard normal distribution:

\(z = \text{invNorm}(0.85) \approx 1.04\)

Then we can solve for x:

\(x = \mu + z\sigma = 23.7 + 1.04(1.6) \approx 26.2\)

Therefore, 85% of the mayflies die after approximately 26.2 hours.

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The upper bound for the 98% confidence interval for the difference in true averages number of flowers visited a day between anna's and allen's hummingbirds is 28.77.

To find the upper bound for the 98% confidence interval for the difference in true average numbers of flowers visited a day between Anna's and Allen's hummingbirds, we need to use the following formula:

Upper bound = (x1 - x2) + zα/2 * √(s1^2/n1 + s2^2/n2)

where x1 and x2 are the sample means, s1^2 and s2^2 are the sample variances, n1 and n2 are the sample sizes, and zα/2 is the critical value from the standard normal distribution for a 98% confidence interval (which is 2.33).

Plugging in the given values, we get:

Upper bound = (220 - 196) + 2.33 * √(47.2/30 + 40.6/30)

Upper bound = 24 + 2.33 * √(2.84 + 1.35)

Upper bound = 24 + 2.33 * √4.19

Upper bound = 24 + 2.33 * 2.046

Upper bound = 28.77

Therefore, the upper bound for the 98% confidence interval for the difference in true average numbers of flowers visited a day between Anna's and Allen's hummingbirds is 28.77 (rounded to 2 decimal places).

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The best approximation for the area of this circle is approximately 50.2 m².Option (c) is the correct answer.

To determine the best approximation for the area of this circle, we need to use the formula for the area of a circle, which is given by A = πr².

Here, we are given the value of π to be approximately equal to 3.14.

Now, we need to determine the radius of the circle.

From the diagram, we can see that the diameter of the circle is 8 meters.

Therefore, the radius is half of this, which is 4 meters.

Substituting the values of π and r into the formula, we get: A = πr²= 3.14 × 4²= 3.14 × 16= 50.24 (to two decimal places)

Therefore, the best approximation for the area of this circle is approximately 50.2 m².Option (c) is the correct answer.

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(a) The power series solution for the Associated Laguerre Equation must terminate because the equation satisfies the necessary termination condition for a polynomial solution.

(b) The general expression for the power series coefficients in terms of the first coefficient can be obtained by using recurrence relations derived from the differential equation.

(a) The power series solution for the Associated Laguerre Equation, when expanded as a polynomial, must terminate because the differential equation is a second-order linear homogeneous differential equation with polynomial coefficients. Such equations have polynomial solutions that terminate after a finite number of terms.

(b) To find the general expression for the power series coefficients in terms of the first coefficient, one can use recurrence relations derived from the differential equation. These recurrence relations relate each coefficient to the preceding coefficients and the first coefficient. By solving these recurrence relations, one can express the coefficients in terms of the first coefficient and obtain a general expression.

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Answer:

\(y = 2 \: cos \: (\frac{1}{3} x)\)

option C is the right option.

Explanation:

General expression of a cosine function is:

y=A cos k X

where A is amplitude and 2 pi/k is its period.

In our case,

\( - y = 2 \: cos \: (\frac{1}{3} x) \:\)

has :

\(amplitude = 2 \\ period = 2\pi \times 3 = 6\pi\)

hence, the right answer is of option C

hope this helps...

Good luck on your assignment..

A beverage company has decided to manufacture a new juice with mixed flavors, which is prepared from orange and pineapple. The vitamin contents are 5% of vitamin A and 2% of vitamin C in the orange flavor, while pineapple flavor contains 8% of vitamin C.

The company's policies are to add at least 20 L of orange flavor to the new juice and limit the vitamin C content to no more than 5%. The cost of orange flavor is $1000 per liter, while the cost of pineapple flavor is $400 per liter.To satisfy a minimum demand of 100 L of juice, we must determine the optimal amount of each flavor to use.A) A linear programming model is needed for the company to solve this problem (Minimize production cost of the new juice)B) Use a graphic solution for this problem.The objective function of the optimization problem can be given as:min C = 1000x + 400yThe constraints that the company has are,20x + 0y ≥ 100x + y ≤ 5x ≥ 0 and y ≥ 0The feasible region can be identified by graphing the inequality constraints on a graph paper. Using a graphical method, we can find the feasible region, and by finding the intersection points, we can determine the optimal solution.The graph is shown below; The optimal solution is achieved by 20L of orange flavor and 80L of pineapple flavor, as indicated by the intersection point of the lines. The optimal cost of producing 100 L of juice would be; C = 1000(20) + 400(80) = $36,000.C) If the company decides that the juice should have a vitamin C content of no more than 7%, it would alter the problem's constraints. The new constraint would be:x + y ≤ 7Dividing the equation by 100, we obtain;x/100 + y/100 ≤ 0.07The objective function and the additional constraint are combined to create a new linear programming model, which is solved graphically as follows: The feasible region changes as a result of the addition of the new constraint, and the optimal solution is now achieved by 20L of orange flavor and 60L of pineapple flavor. The optimal cost of producing 100 L of juice is $28,000.

In conclusion, the optimal amount of each flavor that should be used to satisfy a minimum demand of 100 L of juice is 20L of orange flavor and 80L of pineapple flavor with a cost of $36,000. If the company decides that the juice should have a vitamin C content of no more than 7%, the optimal amount of each flavor is 20L of orange flavor and 60L of pineapple flavor, with a cost of $28,000.

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Colin has lived by the biblical ideal of avoiding debt, purchasing the lowest item, repaying a loan, and being financially honest.

With an auto loan, you may borrow money from a bank and use it to purchase a vehicle. The loan must be repaid with interest over a defined period of time in fixed instalments from you.

Lenders will aim for a credit score of at least 750 when you apply for a vehicle loan.

The additional costs won't dramatically raise the price of the automobile because of the low interest rate. The periodic payments won't put undue strain on your current or next finances.

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Answer:

I believe it it (-1.5,1.5)

(Fixed)

The area of the larger figure that is similar to the smaller one is: 28.2 m².

Where A and B represent the areas of two similar figures, and a and b are their corresponding side lengths, respectively, the formula that relates their areas and side lengths is:

Area of figure A / Area of figure B = a²/b².

Given that the two figures are similar as shown in the image above, find each of their respective side lengths if we are given the following:

Perimeter of smaller figure = 20 m

Area of smaller figure = 19.6 m²

Perimeter of larger figure = 34m

Area of larger figure = x

Therefore:

20/34 = a/b

Simplify:

10/17 = a/b.

Find the area (x) of the larger figure using the formula given above:

10²/12² = 19.6/x

100/144 = 19.6/x

100x = 2,822.4

x = 2,822.4/100

x ≈ 28.2 m²

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Answer:

72

Step-by-step explanation:

9 = 3^2

18 = 2 * 3^2

72 = 2^3 * 3^2

For LCM use common and not common factors with greater exponent.

Use 2^3 and 3^2.

LCM = 2^3 * 3^2 = 8 * 9 = 72

Answer: 72

C. 0.432 is the probability of selecting 2 females using binomial approximation.

The given problem can be solved by using the binomial distribution formula, which is given by:

p(x) = C(n, x) * p^x * q^(n-x)

Where:

p(x) = probability of x successes in n trials

C(n, x) = combination of n things taken x at a time

p = probability of success

q = probability of failure

q = 1 – p

In this case, the probability of selecting 2 females is to be determined. Therefore, x = 2.

Let us substitute the given values in the formula:

p(x = 2) = C(n, x) * p^x * q^(n-x) = C(3, 2) * (6/10)^2 * (4/10)^1 = 0.432

Therefore, the probability of selecting 2 females using binomial approximation is 0.432, which is option c.

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Answer:

Yes

Step-by-step explanation:

Answer:

m∠A = 24° , a ≈ 26 ft , b ≈ 51 ft

Step-by-step explanation: