Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 30.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1?

Explanation:

Dark Energy. Dark Energy is a hypothetical form of energy that exerts a negative, repulsive pressure, behaving like the opposite of gravity. It has been hypothesised to account for the observational properties of distant type Ia supernovae, which show the universe going through an accelerated period of expansion

A. When an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.

The average acceleration vector is defined as the rate at which the velocity changes with time.

When an object is slowing down, the acceleration of the object is in the opposite direction as the velocity.

Also, when an object is speeding up, the acceleration of the object is in the same direction as the velocity.

Thus, when an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.

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If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The image distance from the plane mirror is 5.1 m.

The object distance from the plane mirror, u = 5.1 m

a) We know that the magnification of a plane mirror is always unity. That means the magnification is always one.

The expression for magnification of a plane mirror is given by,

m = - u/v

Therefore, the image distance from the plane mirror,

v = u

v = 5.1 m

That means the image distance and object distance are the same in a plane mirror.

b) The object is positioned at 5.1 m distance in front of the plane mirror. so, the image will be formed at 5.1 m distance behind the plane mirror.

Therefore,

The distance between the image and the object = 5.1 + 5.1 = 10.2 m

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Answer:

yes

Explanation:

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This question involves the concepts of density, weight, and volume.

The change in weight of the cylinder will be "2.72 x 10⁻³ N".

The change in weight of the cylinder will be equal to the weight of the air inside the cylinder which is being removed from it:

\(\Delta W = W_a\)

where,

Therefore,

\(\Delta W = W_a = \rho Vg\\\\\Delta W = (1.225\ kg/m^3)(2.26\ x\ 10^{-4}\ m^3)(9.81\ m/s^2)\)

ΔW = 2.72 x 10⁻³ N

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Answer:

1) The force per egg caused by the weight of the block is 17.15 N

2) \(A= 0.686\ mm^2\)

Explanation:

Pressure

The pressure is computed as the force acting upon a surface divided by the area of the surface :

\(P=\frac{F}{A}\)

The weight of an object of mass m is:

W = mg

Where g is the gravitational acceleration of \(9.8\ m/s^2\)

The cement block has a mass of m=14 kg, thus its weight is:

W = 14*9.8

W = 137.2 N

1) This weight is evenly distributed over the 8 eggs, thus the force per egg is:

F = 137.2 N/8= 17.15 N

The force per egg caused by the weight of the block is 17.15 N

2) It's given the pressure on each egg as \(P= 25 \ N/mm^2\) and we know the force acting on each one is F=17.15 N. To find the contact area we solve the formula of the pressure for A:

\(\displaystyle A=\frac{F}{P}\)

\(\displaystyle A=\frac{17.15}{25}\)

\(\mathbf{A= 0.686\ mm^2}\)

As a result, each string is under about 71.3 N of tension.

The forces tugging on the rope from either end cause a certain strand of string or rope to be under strain. Recall that force equals mass times acceleration. Every change in acceleration or mass of the objects the rope is supporting will result in a change in tension in the rope, assuming the rope is stretched firmly.

The strain in the strings balances the block's weight in the vertical direction, giving us: 2T cos θ = mg

Therefore, we have: 2T sin θ = 0

since sin θ = 0 when θ = 26.3°.

Solving the first equation for T, we get:

T = mg / (2cos θ)

Substituting the given values, we get:

T = (14.7 kg)(9.81 m/s²) / (2cos 26.3°)

T ≈ 71.3 N

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Aproximately 1.09 m/s was the locust's first speed.

In engineering mechanics, vectors are used to express values with both a magnitude and a direction. For analysis, vector representations of a variety of engineering quantities—including forces, displacements, velocities, and accelerations—are required.

Δy = vsin(θ)t - 0.5gt²

0 = v*sin(55°)t - 0.5(-9.81 m/s²)*t²

t = 2vsin(55°)/g

Now, we can use the horizontal motion of the locust to find the initial velocity v. The horizontal distance traveled by the locust is given by:

Δx = v*cos(55°)*t

Substituting the expression for t that we just found:

0.750 m = vcos(55°)2vsin(55°)/g

Solving for v:

v = √(0.750 mg/(2sin(55°)*cos(55°)))

v ≈ 1.09 m/s

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Answer:

The induced emf  is  \(\epsilon = 0.1041 \ V\)  

Explanation:

From the question we are told that

   The  radius of the circular loop is  \(r = 9.50 \ cm = 0.095 \ m\)

     The  intensity of the wave is  \(I = 0.0215 \ W/m^2\)

      The wavelength is  \(\lambda = 6.90\ m\)

Generally the intensity is mathematically represented as

         \(I = \frac{ c * B^2 }{ 2 * \mu_o }\)

Here  \(\mu_o\) is the permeability of free space with value  

         \(\mu_o = 4 \pi *10^{-7} N/A^2\)

B is the magnetic field which can be mathematically represented from the equation as

          \(B = \sqrt{ \frac{ 2 * \mu_o * I }{ c} }\)

substituting values

          \(B = \sqrt{ \frac{ 2 * 4\pi *10^{-7} * 0.0215 }{ 3.0*10^{8}} }\)

          \(B = 1.342 *10^{-8} \ T\)

The  area is mathematically represented as

       \(A = \pi r^2\)

substituting values

       \(A = 3.142 * (0.095)^2\)

       \(A = 0.0284\)

The angular velocity is mathematically represented as

        \(w = 2 * \pi * \frac{c}{\lambda }\)

substituting values          

       \(w = 2 * 3.142 * \frac{3.0*10^{8}}{ 6.90 }\)  

        \(w = 2.732 *10^{8} rad \ s^{-1}\)  

Generally the induced emf is mathematically represented as

        \(\epsilon = N * B * A * w * sin (wt )\)

At maximum induced emf  \(sin (wt) = 1\)

    So

         \(\epsilon = N * B * A * w\)

substituting values

         \(\epsilon = 1 * 1.342 *10^{-8} * 0.0284 *2.732 *10^{8}\)  

         \(\epsilon = 0.1041 \ V\)  

Answer:

When light traveling through air enters water at an angle, it moves in a curve in air and changes direction when it enters water. This bending of light is known as refraction. The angle at which the light bends depends on the difference in the refractive indices of the two media, which is why the light bends when it enters the denser medium of water.

Explanation:

It is given that,

The position of a particle is given by :

\(r(t)=(3t^2i+5j-6tk)\ m\)

(a) Velocity of a particle is given by :

\(v=\dfrac{dr(t)}{dt}\)

Putting values,

\(v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s\)

The acceleration of the particle is given by :

\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2\)

(b) At t = 0,

Velocity, v = 6k m/s

Acceleration, a = 6i m/s²

Answer:

So the force acting on the train during the time of constant acceleration is -35,217.75 N and the stopping distance is 985.76 m.

Explanation:

The force acting on the train during the time of constant acceleration can be calculated using the equation:

force = mass x acceleration

To calculate the acceleration, we can use the equation:

acceleration = (final velocity - initial velocity) / time

where the final velocity is 0 m/s (the train comes to rest), the initial velocity is 220 km/h (converted to m/s) and the time is 16s.

initial velocity = 220 x 1000/3600 = 61.11 m/s

acceleration = (0 - 61.11) / 16 = -3.819 m/s^2

force = mass x acceleration = 9.25 x 105 kg x -3.819 m/s^2 = -35,217.75 N

The negative sign indicates that the force is acting in the opposite direction of the velocity, which is in the opposite direction of the train's motion, which is braking.

To calculate the stopping distance, we can use the equation:

distance = (initial velocity x time) + (1/2 x acceleration x time^2)

stopping distance = (61.11 m/s x 16s) + (1/2 x -3.819 m/s^2 x 16s^2) = 985.76 m

So the force acting on the train during the time of constant acceleration is -35,217.75 N and the stopping distance is 985.76 m.

Answer:

The answer is "\(\bold{0, 12.8 \ \frac{m}{s^2}, and \ 6.4 \ \frac{m}{s^2}}\)"

Explanation:

For point a:

The average time interval acceleration for the box \(t = 0\ to\ t = 250 \ s:\)

\(\to \alpha_{0 \ to \ 2.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{0-0}{2.50-0}=0\)

For point b:

The average time interval acceleration for the box

\(t = 250 \ s\ to\ t = 750 \ s :\)  

\(\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{7.50-2.50}=12.8 \ \frac{m}{s^2}\)

For point c:

The average time interval acceleration for the box \(t = 0\ to \ t = 10 \ s :\)  

\(\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{10-0}=6.4 \ \frac{m}{s^2}\)

The translational speed of the bowling ball is 6.28 m/s.

Translational speed refers to the motion of an object in a straight line. It is the speed at which an object moves from one point to another in space. In the context of a ball rolling down an incline, translational speed would refer to the speed of the ball at any given moment as it moves in a straight line down the incline.

To find the translational speed of the bowling ball after it has rolled to the bottom of the incline, we need to use the equation of motion:

\(v = sqrt(v0^2 + 2ax)\)

where v is the final velocity, v0 is the initial velocity (0 in this case), a is the acceleration (9.81 m/s^2), and x is the distance traveled (2 m).

So,

\(v = sqrt(0 + 2 * 9.81 * 2)\\v = sqrt(39.24)\\v = 6.28 m/s\)

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Making progress by conducting studies for research, project or article and presenting this progress to scientists represent a category that belongs to Science (Option A).

Sciences can be defined as a body of empirical knowledge whose development is based on the presentation of results from experiments in peer-reviewed publications and the generation of projects to investigate different issues of the real world.

Therefore, we can conclude that Science is a body of info based on the transference of knowledge which involves developing projects or writing scientific articles (Option A).

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According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.

1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.

E = (1/4πϵ0) (Q/r^2)

where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.

The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:

Φ = ∫E⋅dA = E ∫dA = E(2πR)L

Substituting the expression for the electric field, we have:

Φ = (Q/2ϵ0r^2)(2πRL)

Therefore, the outward electric flux through the rounded "side" of the cylinder is:

Φ = (Q/ϵ0)(R/Lr^2)

2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:

E = (1/4πϵ0) (Q/R^2)

The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:

Φ = ∫E⋅dA = E ∫dA = EπR^2

Substituting the expression for the electric field, we have:

Φ = (Q/ϵ0)(R/r^2)

3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:

Φ = (Q/ϵ0)(R/r^2)

4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:

Φ_total = Φ_side + Φ_top + Φ_bottom

= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)

Simplifying this expression, we have:

Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]

5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:

Φ_total = Q/

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ANSWER

EXPLANATION

To find the thickness of the bubble at that point, apply the condition for constructive interference:

where d = thickness

n = refractive index

m = 0, 1, 2...

For the second longest wavelength, m = 1, and for normal incidence:

Therefore, substituting the given values into the equation and solving for d:

That is the thickness of the bubble.

Answer:

If Earth hadn't been hit by Orpheus, it would be covered by ocean, with perhaps a few mountaintops emerging through the water. There would be no humans, but there could be other forms of life. Earth would rotate rapidly, as the moon would not be present to produce the tidal friction that slows Earth's rotation today

The following is not a source of outdoor air pollution : D) Household cleaning products.

Presence of one or more substances in air at concentration or for a duration above the natural level is called air pollution.

Outdoor air pollution refers to pollutants that are released into the atmosphere by sources outside of buildings or structures. The sources of outdoor air pollution can be natural or human-made. Some examples of sources of outdoor air pollution are:

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Solid fuel burning

E) Forest fires

Therefore, the correct option is D) Household cleaning products.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Household cleaning products.

Answer: 10,500 kg m/s

Explanation: (1,000 + 50)(10)

Answer:

Explanation:

When the elevator is accelerating downwards, the apparent weight of the person is reduced, and when the elevator is accelerating upwards, the apparent weight is increased.

First, we need to determine the actual weight of the person. We can do this by using the formula:

Weight = mass x gravity

where mass is the mass of the person and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.

Weight = (598.900 N) / (9.81 m/s^2) = 61.048 kg

Now, when the elevator is not moving, the person is only experiencing the force due to gravity, which is:

Weight = mass x gravity = (61.048 kg) x (9.81 m/s^2) = 598.78 N

Therefore, the scale would read approximately 598.78 Newtons when the elevator is not moving.

Answer:I need the answer pls

Explanation:

I don't have one

Answer:

The answer is D, what the cell parts are.

Explanation:

The energy that is required by the space probe is 2.94 * 10^14 J.

Let us recall that the gravitational potential energy is the energy that is possessed by a body by virtue of the position of the body in space. We know that the energy that is possessed by the space probe is the gravitational potential energy and we have to obtain the energy required.

Recall that energy required = Work done = mgh

m = mass of the object

g = acceleration due to gravity

h = distance covered

Then;

100-kg * 9.8 m/s^2 *  3 × 10^11 m

= 2.94 * 10^14 J

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Answer:

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Answer:

The correct answer is c) allow you to use less force to do the same amount of work.

Answer:

Explanation:

a ) magnitude of force = centripetal force = m v² / R , m is mass , v is velocity of skater , R is radius of circular path .

= 54 x 3.94² / .9

= 931.41 N

= .93141 kN.

b ) Her weight = mg = 54 x 9.8 = 529.2 N

= .5292 kN .

Ratio = .93141 / .5292 = 1.76