When two forces are the same strength but act in opposite direction , they are called

Two things that keep windows from shattering are the strength of the glass and the ability of the window frame to dampen vibrations.

The strength of the glass is important because it determines how much force the glass can withstand before it breaks. Modern windows are typically made of tempered glass, which is treated with heat to make it stronger and more resistant to shattering.

The ability of the window frame to dampen vibrations is also crucial because glass is prone to resonance, which is a phenomenon that occurs when an object is subjected to vibration at its natural frequency.

If the frequency of the vibration matches the natural frequency of the glass, the glass can begin to vibrate and eventually shatter. To prevent this, window frames are designed to be sturdy and to dampen vibrations, which helps to prevent the glass from vibrating and shattering.

In summary, both the strength of the glass and the ability of the window frame to dampen vibrations are important factors that help to prevent windows from shattering.

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Making progress by conducting studies for research, project or article and presenting this progress to scientists represent a category that belongs to Science (Option A).

Sciences can be defined as a body of empirical knowledge whose development is based on the presentation of results from experiments in peer-reviewed publications and the generation of projects to investigate different issues of the real world.

Therefore, we can conclude that Science is a body of info based on the transference of knowledge which involves developing projects or writing scientific articles (Option A).

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The total amount of energy transferred as heat is equal to 288 Joules.

Given the following data:

To calculate the total amount of energy transferred as heat, we would apply the first law of thermodynamics.​

Mathematically, the first law of thermodynamics is given by the formula:

\(\Delta E = Q - W\)

Where;

Substituting the given parameters into the formula, we have;

\(123 = Q - 165\\\\Q=123+165\)

Q = 288 Joules.

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Answer:

well i tough it was infinte but its not an the layer is a d         i       c               k  

Explanation:

Answer:

The best answer is b. Institutional review board.

Psychologists are required to adhere to ethical guidelines when conducting research involving human participants. Before beginning their research study, they must have their study design reviewed and approved by an Institutional Review Board (IRB) to ensure that the study meets ethical standards and that the rights and welfare of the participants are protected. The IRB is an independent committee of experts that reviews and monitors research involving human participants.

Explanation:

Answer: B is correct

Explanation:

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

v_wind = 101.46 km / h   ,  θ = 61.8

Explanation:

This is a velocity composition exercise.

Let's do the problem in parts. Let's start by knowing the speed of the plane without air.

           v = d / t

           v = 750 / 3.14

           v = 238.85 km / h

This is the speed of the plane relative to the Earth and it does not change.

In the second part, when there is wind, the travel time is greater than when there is no wind, therefore the wind delays the plane. To be more general, suppose that the wind has two components vₓ and \(v_{y}\)

Let's use trigonometry to find the components of the plane's speed

          cos θ = v_N / v

          sin θ  = v_W / v

          v_N = v cos θ

          v_W = v sin θ

let's calculate

          V _N = 238.85 cos 22 = 221.46 km / h

           v_W = -238.85 sin 22 = -89.47

the negative sign is because the plane is going west and the positive sign is the east direction.

As it indicates that the destination of the avine is towards the north, the x component of the wind must be

              vₓ - v_W = 0

              vₓ = v-w

              vₓ = 89.47 km / h

in the direction to the East.

Now let's analyze the component of the wind in the Nort-South direction,

Indicate the travel time, let's calculate the speed that the component must have the speed of the plane

             v_total = d / t

             v_total = 750 / 4.32

             v_total = 173.61 km / h

This is the final speed of the plane, which can be written

              v_total = v_n - vy

               vy = v_n - v_total

               vy = 221.46 - 173.61

               vy = 47.85 km

this component is directed towards the south

Let's use the Pythagorean Theorem, to find the magnitude

             v_wind² = vₓ² + vy²

             v_wind = √ (89.47² + 47.85²)

             v_wind = 101.46 km / h

the address will then be found using trigonometry

             θ = Vy / vx

             θ = tan⁻¹ (vy / vx)

             θ = tan⁻¹1 (47.85 / 89.47)

             θ = 28.14

Therefore, the magnitude of the wind speed is 101.5 km / h and its direction is 28º south of the East, to give this value

                  90- θtea = 90- 28.2

                  θ = 61.8

East of South

Answer: Positive Talk

Explanation:

Answer:

when the angle between the displacement and direction of force is zero

Answer:

Only when the force is applied in the same direction as the displacement of the object on which it acts, it does maximum work. This is because the work done by a force is given by the dot product of the force and displacement vectors. The dot product of two vectors is maximum when they are parallel to each other. Therefore, when a force is applied in the direction of displacement, it does maximum work.

When a force is applied perpendicular to the displacement, it does no work at all. This is because the dot product of two perpendicular vectors is zero. When a force is applied at an angle to the displacement, it does some work but not maximum.

It's important to note that the amount of work done by a force also depends on its magnitude and the distance over which it acts. The greater the magnitude of the force and the longer the distance over which it acts, the more work it will do.

In summary, a force does maximum work only when it is applied in the same direction as the displacement of the object on which it acts.

Answer:

e% = 2.2%

Explanation:

In the measurements it is very important the precision of the readings and the knowledge of how the uncertainty or errors in each measurement propagates when carrying out the different calculations

In this case the area of ​​the body is its length l = 5.9 mm, for its width a = 4.1 mm

           S = l a

The error can be calculated using derivatives and considered the worst of all cases

         Δs = ds /dl  Δl + dS /da  Δa

in this case the derivatives are very simple

      dS / dl = a

      dS / Da = l

we substitute

        ΔS = a Δl + l Δa

this is the absolute error

Let's calculate its value

        Δs = 4.1  0.05 + 5.1   0.05

        Δs = 0.5 mm²

the percentage error is this error between the magnitude of the mediated by 100

       e% = ΔS / S 100

       e% = 0.5 / (5.1   4.1) 100

       e% = 2.2%

Answer:

0.238 m/min

Explanation:

The volume of water in the trough V =Ah' where A = area of cross-section = area of isosceles trapezoid = 1/2(a + b)h where a = length of bottom of isosceles trapezoid = 40 cm = 0.4 m, b =  length of top of isosceles trapezoid = 100 cm = 1 m and h = height of isosceles trapezoid = 60 cm = 0.6 m. So,

A = 1/2(a + b)h = 1/2(0.4 m + 1 m)0.6 m = (1.4 m)0.3 m = 0.42 m² and h' = height of water level in trough = H - h" where H = length of trough = 10 m and h" = depth of water level in trough = 10 cm = 0.1 m

So, V = Ah'

V = A(H - h") = A(10 - h")

Now, the rate of change of volume of the trough with respect to time dV/dt = d[A(10 - h")]/dt

dV/dt = -Adh"/dt

dh"/dt = -dV/dt/A

Since dV/dt = 0.1 m³/min, substituting the other variables into the equation, we have

dh"/dt = -dV/dt/A

dh"/dt = -0.1 m³/min/0.42 m²

dh"/dt = -0.238 m/min

This is the rate at which the depth is decreasing

Since the height h' = 10 - h"

dh'/dt = d(10 - h")/dt

= -dh"/dt

= -(-0.238 m/min)

= 0.238 m/min

So the water level is increasing at a rate of 0.238 m/min

The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.

Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.

Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.

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Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.  

To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:

Parameter Panel:

Mass of cube 1 (m1) = 2.0 g = 0.002 kg

Mass of cube 2 (m2) = 4.0 g = 0.004 kg

Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m

Charge rate of each cube (q) = 7.0 nC/s

Coefficient of static friction (μ) = 0.65

Sketch:

     |-----------|        |-----------|

     |     2     |        |     1     |

     |-----------|        |-----------|

           |                 |

          d=6.0 cm          d=6.0 cm

           |                 |

           |-----------------|

(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:

F = (k * q1 * q2) / d^2

where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:

q = 7.0 x 10^-9 C/s * t

At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:

q1 = 7.0 x 10^-9 C/s * t

q2 = 7.0 x 10^-9 C/s * t

The electrostatic force between the cubes is then:

F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2

= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]

The force of static friction between each cube and the surface is:

Ff = μ * N

= μ * m * g

where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).

The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:

N = m * g

Plugging in the values for each cube, we get:

Ff1 = μ * m1 * g

= 0.65 * 0.002 kg * 9.81 m/s^2

= 0.0127 N

Ff2 = μ * m2 * g

= 0.65 * 0.004 kg * 9.81 m/s^2

= 0.0254 N

Comparing the electrostatic force between the cubes and the force of static friction, we find:

F - Ff1 = (9.0 x 10^9 N)

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Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Answer:

BMI is a simple indicator of weight for height and can't differentiate between muscle mass and fat mass. So BMI tends to overestimate the health risk for adults with a high muscle mass, such as some athletes, and underestimate the risk for adults with a low muscle mass, as can occur with sedentary lifestyles.

Explanation:

Hope it is helpful...

Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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Nuclear power plants have backup generators to ensure that essential equipment, such as cooling systems, can continue to function in the event of a power outage or other emergency.

Nuclear power plants rely on a constant supply of electricity to operate the equipment that controls the nuclear reaction and cools the reactor. If the power supply is interrupted, the reactor can overheat and damage can occur. Backup generators provide power to essential equipment, such as cooling systems, that keep the reactor and spent fuel pools from overheating.  If the backup generators fail, there is a risk of a nuclear accident, as was seen in the disaster in 2011, where the failure of backup generators led to a loss of cooling and a major nuclear incident.

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As a result, the centripetal acceleration of the spaceship's main part throughout its orbit around the Moon was 0.00256 m/s².

In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Here,

The centripetal acceleration of an object in orbit can be calculated using the formula:

a = (v²) / r

where a is the centripetal acceleration, v is the velocity of the object in orbit, and r is the radius of the orbit.

Since the main section of the spaceship orbited 50 miles above the lunar surface, r = 50 miles = 80,467.2 meters.

To find the velocity, we can use the relationship between the velocity and the gravitational field strength of a planet, given by:

v = (GM / r)¹/²

where G is the gravitational constant (6.67 x 10⁻¹¹ N*(m/kg)²), M is the mass of the Moon (7.34 x 10²² kg), and r is the radius of the orbit (50 miles = 80,467.2 meters).

Plugging in the values, we get:

v = (6.67 x 10⁻¹¹ N*(m/kg)² * 7.34 x 10^22 kg / 80,467.2 m)¹/²

v = 1,706.3 m/s

Finally, plugging in the values for v and r into the formula for centripetal acceleration, we get:

a = (v^²) / r

a = (1,706.3 m/s)² / 80,467.2 m

a = 0.00256 m/s²

So, the centripetal acceleration of the main section of the spaceship during its orbit about the Moon was 0.00256 m/s².

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The  following correctly orders the different categories of electromagnetic radiation; Radio, infrared, visible light, ultraviolet, X rays, gamma rays.

Ultraviolet (UV) radiation is a type of electromagnetic radiation emitted from the sun. It is a form of energy that is invisible to the human eye, but it can cause damage to living organisms. UV radiation is divided into three categories: UVA, UVB, and UVC. UVA radiation has the longest wavelength and is the least hazardous form of UV radiation. UVB radiation has a shorter wavelength and is more dangerous. UVC radiation has the shortest wavelength and is the most dangerous form of UV radiation. Exposure to UV radiation can cause sunburns, premature skin aging, and an increased risk of skin cancer.

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The velocity of the second marble after the collision is 0.47 m/s

According to conservation of linear momentum

The law of conservation of momentum states that in an isolated system the total momentum of two or more bodies acting upon each other remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed

M1u1 + M2u2 = M1v1 + M2v2

0.018 x 0.42 + 0.018 x 0.32 = 0.018 x 0.27 m/s + 0.018 x v2

0.00756 + 0.00576 = 0.00486 + 0.018 x v2

0.01332 = 0.00486 + 0.018 x v2

0.00846/0.018 = v2

v2 = 0.47 m/s

Hence, velocity of the second marble after the collision is 0.47 m/s

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Answer:

A

Explanation:

occurs when a magnetic feild and an elctric conductor move relative to one another

Answer:

4600 Kg/m³

Explanation:

Volume of block=5m³

Mass of block= 920 kg/m³

Density=mass × volume

=920 × 5³

=4600 /m³

The density of ice is 4600 Kg/m³

___________________________________

(Hope this helps can I pls have brainlist (crown)☺️)

Explanation:

Solution:

Here

volume=5

Density=920

Density =Mass/Volume

or,Mass=Density*Volume

or,M=920*5

so,M=4600kg

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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Answer:

The fuse in a plug is a safety device designed to protect the lead rather than the appliance. It is a deliberate weak link in a circuit which will 'blow' if an electrical appliance or extension lead draws too much current due to either an overload or a fault.

Strong interpretation is an important thing in meteorology. Because, analyzing the climate level in each area and the factors affecting it with their visual representation is very important in weather forecast.

Meteorology is a branch of science dealing with the weather in different regions. On interpreting data, forecasters are tasked with synthesizing available observations from multiple platforms (including surface observations, weather balloons, radar, and satellite), numerical guidance from computer model forecasts, scientific theory, and experience-based intuition to arrive at a forecast.  

The forecast process is often collaborative, with teams of meteorologists routinely integrating new information into the forecast as the event approaches.

Increasingly, forecasters are also responsible for effectively communicating the forecast and its anticipated impacts upon life and property to various stakeholders, including the public.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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The initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

The initial velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

According to this question, a car accelerates to a speed of 55 m/s within the span of 8 seconds. If its acceleration was 4 m/s², the initial velocity is calculated as follows:

4 = 55 - u/8

32 = 55 - u

u = 55 - 32

u = 23m/s

Therefore, the initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

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Using a scale of 1 centimeter = 1 newton, the following displacement vector is

(a) 5 newtons west 5 centimeter.

(b) 3 newtons, 270° 3 centimeter.

(c) 4 newtons, 0°, 4 centimeter.

The International System of Units (SI) uses the centimetre (cm) as a measure of length. It is a handy unit for measuring short distances because its definition is one tenth of a metre. 0.01 metres or 0.3937 inches make up one centimetre.

In the SI system, a newton (N) is a unit of force. It is described as the amount of pressure necessary to accelerate a mass of one kilogramme at a speed of one metre per second squared (m/s2). The force required to accelerate a mass of one kilogramme by one metre per second squared is comparable to one newton, in other words.

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