The technique which most accurate in identifying an appropriate vein site for IV catheter insertion into the arm is: Apply a tourniquet to the selected arm 4 to 6 inches above the proposed site. The correct answer is D.
Putting in a tourniquet will enlarge the vein, making the targeted insertion point more visible and permitting the nurse to see whether the vein can accommodate the IV catheter or not.
How can we verify that we have entered the vein by the IV catheter?Once it is in the vein, check for flashback or blood return. Because it indicates whether the catheter has entered the vein. If we fail to see flashback, then we need to pull the catheter slightly back and rotate it slightly. The best choice for placement of an IV catheter are median antecubital veins, cephalic veins and basilic veins.
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What is the volume of a cube that has a side length of 5 centimeters?
31
5 cm
Recall the formula Cube V=s.
cm3
Answer: The volume of the cube is 25 cubic centimeters.
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Volume of a cube: side lenght^3
Replacing with the side length value and solving for V (volume)
V= 5^2 = 25 cm2
In conclusion, the volume of the cube is 25 cubic centimeters.
Feel free to ask for more if needed or if you did not understand something.
Answer:
125
Step-by-step explanation:
Look at Google:)❤
Full time PHD students receive an average of $12, 837 per year. If the average salaries are normally distributed with a standard deviation of $1500, find these probabilities. Round the final answers to four decimal places and intermediate z value calculations to two decimal places.
A) A student makes more than 15,000
b) The student makes between 13,000 and 14,000
The probability that a student makes between $13,000 and $14,000 is approximately 0.2356.
The probability that a student makes more than $15,000 is approximately 0.0188.
To find the probabilities in question, we need to standardize the salaries using the formula:
z = (x - μ) / σ
where z is the standard score, x is the given salary, μ is the mean salary, and σ is the standard deviation.
A) To find the probability that a student makes more than $15,000, we first standardize the value:
z = (15,000 - 12,837) / 1500 = 2.09 (rounded to two decimal places)
Using a standard normal distribution table or a calculator, we can find the probability associated with this z-score. The probability can be calculated as:
P(X > 15,000) = P(Z > 2.09) ≈ 0.0188 (rounded to four decimal places)
B) To find the probability that a student makes between $13,000 and $14,000, we need to standardize both values:
z1 = (13,000 - 12,837) / 1500 ≈ 0.11 (rounded to two decimal places)
z2 = (14,000 - 12,837) / 1500 ≈ 0.77 (rounded to two decimal places)
Next, we find the cumulative probabilities associated with these z-scores:
P(13,000 < X < 14,000) = P(0.11 < Z < 0.77)
Using a standard normal distribution table or a calculator, we can find these probabilities individually and then subtract them:
P(0.11 < Z < 0.77) ≈ P(Z < 0.77) - P(Z < 0.11) ≈ 0.7794 - 0.5438 ≈ 0.2356 (rounded to four decimal places)
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True/False? To calculate the total number of iterations of a nested loop, add the number of iterations of all the loops
In order to calculate the total number of iterations of a nested loop, you need to add the number of iterations of all the loops. This is because the iterations of each loop are cumulative and dependent on each other. Therefore, adding the number of iterations of all the loops will give you the total number of iterations of the nested loop.
In a nested loop, the inner loop will always complete its iteration each time the outer loop runs once. Thus, the total number of iterations of a nested loop is the sum of the iterations of all the loops. For example, if the outer loop has 5 iterations and the inner loop has 3 iterations, then the total number of iterations of the nested loop would be 5 x 3 = 15. Similarly, if there are more than two loops nested together, the total number of iterations of the nested loop would be the sum of the iterations of all the loops.
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Youssef paid AED 8 for 12 eggs.
Determine the cost of 3 eggs.
To solve this problem, you must first know how much 1 egg costs, for this we have to divide:
\(\begin{matrix}\space\space\space\space\space\space\emptyspace \sf 1,5\space\space\space\space\space\space\space\space\space\space\space\space\\ \sf 8\overline{|\smallspace \sf 12}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}\\\underline{\sf 8}\\\sf 40\\\underline{\sf 40}\\(0)\)
Now we know an egg costs $1.5, so:\(\sf 1,\:5\:+1,\:5+1,\:5=\boxed{\sf 4,5}\ll Eggs\)
Okay?!Answer:
AED 2 for 3 eggs
Step-by-step explanation:
Price (p) is proportional to the number of eggs:
p/3 = 8/12
p = 3(8/12) = 8(3/12) = 8/4 = 2
The cost of 1/4 as many eggs will be 1/4 as much: AED 2 for 3 eggs.
Please help someone
2/5
Answer:
B
Step-by-step explanation:
Answer:
B is correct
Step-by-step explanation:
√5 ≈ 2,24
since it is - √5 the answer must be -2,24 so B is correct
Which of the following formulas is CORRECT for finding the present value of an investment
A) FV = PV/(1 + r)^n
B) PV = FV x (1 + r)n
C) PV = FVn x (1 + r)
D) PV = FV x 1/(1 + r)^n
The correct formula for finding the present value of an investment is given by option D) PV = FV x 1/(1 + r)^n.
The present value (PV) of an investment is the current value of future cash flows discounted at a specified rate. The formula for calculating the present value takes into account the future value (FV) of the investment, the interest rate (r), and the number of periods (n).
Option D) PV = FV x 1/(1 + r)^n represents the correct formula for finding the present value. It incorporates the concept of discounting future cash flows by dividing the future value by (1 + r)^n. This adjustment accounts for the time value of money, where the value of money decreases over time.
In contrast, options A), B), and C) do not accurately represent the present value formula and may lead to incorrect calculations.
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All the 7th grade math teachers go to eat at Olive Garden. Mr. Stanley's
bill total before tax is $25.50. He decides to leave a 20% tip for the waiter.
How much does Mr. Stanley spend on dinner TOTAL? *
Answer:
$30.60
Step-by-step explanation:
$25.50×1.2=30.60
In the Florida Lottery Cash4Life game a player must select five numbers from 1 to 60 and then one Cash Ball number from 1 to 4. He will win the jackpot of $1000 a day for life if all five numbers and the Cash Ball match the winning numbers drawn on Monday nights. He will win $1000 a week for life if just all 5 numbers match the winning numbers. Assuming that the numbers are equally likely to be
drawn, determine:
(a) (5) The probability that the player will $1000 a day for life;
(b) (5) The probability that the player will $1000 a week for life;
The probability of winning $1000 a day for life is approximately 5.245 x 10^-11 and the probability of winning $1000 a week for life is approximately 1.07 x 10^-8. The probability of winning the jackpot ($1000 a day for life) is 1/(60^5 * 4), while the probability of winning $1000 a week for life is 1/(60^5).
In the Florida Lottery Cash4Life game, a player must select five numbers from 1 to 60 and then one Cash Ball number from 1 to 4. The jackpot prize is $1000 a day for life if all five numbers and the Cash Ball match the winning numbers drawn on Monday nights. If just all five numbers match the winning numbers, the player will win $1000 a week for life.
To determine the probability of winning $1000 a day for life, we can use the formula for the probability of independent events: P(A and B) = P(A) x P(B)
(a) To win the jackpot of $1000 a day for life, the player needs to match all five numbers and the Cash Ball. There are 60 options for each of the five numbers and 4 options for the Cash Ball. The total number of possible outcomes is 60^5 (60 choices for each of the five numbers) times 4 (for the Cash Ball). So the probability of winning the jackpot is 1/(60^5 * 4). (b) To win $1000 a week for life, the player needs to match only the five numbers, without considering the Cash Ball. The total number of possible outcomes for this scenario is 60^5. Therefore, the probability of winning $1000 a week for life is 1/(60^5).
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If 107 votes are cast, what is the smallest number of votes a winning candidate can have in a four-candidate race that is to be decided by plurality
In a four-candidate race with 107 votes cast, the smallest number of votes a winning candidate can have is 28.
In a four-candidate race decided by plurality, the winning candidate is the one who receives the most votes, regardless of whether that number of votes constitutes a majority (more than 50%) of the total votes cast.
To determine the smallest number of votes a winning candidate can have in a four-candidate race with 107 votes cast, we can assume that the other three candidates each receive an equal number of votes, say x. Then, the winning candidate must receive more votes than each of the other three candidates.
So, the minimum number of votes the winning candidate can receive is x + 1.
The total number of votes cast in the election is:
x + x + x + (x + 1) = 4x + 1
Since we know that 4x + 1 = 107, we can solve for x:
4x + 1 = 107
4x = 106
x = 26.5
Since x must be a whole number, we can round up to x = 27.
Then, the minimum number of votes the winning candidate can have is:
27 + 1 = 28
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Elise says, "If you subtract 14 from my number and multiply the difference by - 3, the result is - 63."
What is Elise's number?
Elise's number is
Please help
Answer:
35
Step-by-step explanation:
-3(x-14)=-63
distribute
-3x+42=-63
-3x=-105
x=35
Please help meeee !!!!!!!!! Will mark Brianliest correct answer !!!!!!!!!!!!!!!!!!
Answer:
it is 7 inches tall - pythagorean theorem
Step-by-step explanation:
Divide 2x2 7x â€"" 3 by 2x 5. which expression represents the quotient and remainder? x 1 x 1 â€"" x 1 x 1 â€""
The required solution of given polynomial equation is \(x+1-\frac{8}{2x+5}\) .
Given polynomial equation is \(2x^{2}+7x-3\) which is to be divided by \(2x+5\)
In case of division of polynomials we Long division method to calculate final value of the given equation.
For solving given equation let us start from;
\(\frac{2x^{2} +7x-3}{2x+5}\) = \(x+\frac{2x-3}{2x+5}\)
\(x+\frac{2x-3}{2x+5}\) = \(x+1 +\frac{-8}{2x+5}\)
\(x+1-\frac{8}{2x+5}\)
The final solution for given equation is \(x+1-\frac{8}{2x+5}\)
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HELP!! Please explain the answer so I'll have a better understanding.
Answer:
20x^2 - 4x - 16
Step-by-step explanation:
Area of a rectangle = Length * Width
Area = (5x + 4)(4x - 4)
Expand the double brackets using the FOIL method (First, Outer, Inner, Last), combine the terms and simplify:
F: 5x * 4x = 20x^2
O: 5x * -4 = -20x
I: 4 * 4x = 16x
L: 4 * -4 = -16
20^2 - 20x + 16x - 16
20x^2 - 4x - 16
suppose that a city is susceptible to earthquakes, and the modified mercalli intensity of the next earthquake is classified (for simplicity) as vi (or less), vii, viii, and ix with relative likelihoods 50:30:15:5. building construction is classified as good or poor. 20% of buildings in the city are poorly constructed. seismic fragility analysis has indicated that poorly constructed buildings are damaged with probabilities 0.05, 0.25, 0.50 and 0.75, respectively, when subjected to intensities of vi (or less), vii, viii and ix, respectively. well-constructed buildings suffer no damage under a vi (or less) event; however, the probability that such a building will be damaged under a vii, viii or ix event is 0.05, 0.10 and 0.20, respectively. (a) what is the probability that a well-constructed building will be damaged during the next earthquake? (20 points) (b) what proportion of buildings in the city will be damaged during the next earthquake? (20 points)
Probability that a poorly constructed building will be damaged by earthquake = P(P) = P(VI) * P(P | VI) = 0.5 * 0.05 = 0.025
(a) Let W be the event that a well-constructed building will be damaged during the earthquake.
Let VI, VII, VIII and IX be the event of occurrence of earthquake of intensity VI (or less), VII, VIII and IX respectively.
Then,
P(W | VI) = 0
P(W | VII) = 0.05
P(W | VIII) = 0.10
P(W | IX) = 0.20
P(VI) = 0.5, P(VII) = 0.3, P(VIII) = 0.15, P(IX) = 0.05
By law of total probability,
Probability that a well-constructed building will be damaged by earthquake = P(W)
= P(VI) * P(W | VI) + P(VII) * P(W | VIII) + P(VI) * P(W | VIII) + P(IX) * P(W | IX)
= 0.5 * 0 + 0.3 * 0.05 + 0.15 * 0.10 + 0.05 * 0.20
= 0.04
(b)
Let P be the event that a poorly constructed building will be damaged during the earthquake.
Then,
P(P | VI) = 0.05
P(P | VII) = 0.25
P(P | VIII) = 0.50
P(P| IX) = 0.75
P(VI) = 0.5, P(VII) = 0.3, P(VIII) = 0.15, P(IX) = 0.05
By law of total probability,
Probability that a poorly-constructed building will be damaged by earthquake = P(P)
= P(VI) * P(P | VI) + P(VII) * P(P | VIII) + P(VI) * P(P | VIII) + P(IX) * P(P | IX)
= 0.5 * 0.05 + 0.3 * 0.25 + 0.15 * 0.50 + 0.05 * 0.75
= 0.2125
Let PC and WC be the event that the building is poorly constructed and well constructed respectively. Then,
P(PC) = 0.20
P(WC) = 1 - P(PC) = 1 - 0.20 = 0.80
Let D be the event that building is damaged by the earthquake.
Then, P(D | PC) = P(P) = 0.2125
P(D | WC) = P(W) = 0.04
By law of total probability, proportion of buildings damaged by the earthquake
P(D) = P(PC) * P(D | PC) + P(WC) * P(D | WC)
= 0.2 * 0.2125 + 0.8 * 0.04
= 0.0745
(c)
Given the building is damaged, the probability that it was poorly constructed = P(PC | D)
= P(D | PC) * P(PC) / P(D) (By Bayes theorem)
= 0.2125 * 0.2 / 0.0745
= 0.5704698
(d)
For intensity VI (or less),
Probability that a well-constructed building will be damaged by earthquake = P(W)
= P(VI) * P(W | VI) = 0.5 * 0 = 0
Probability that a poorly-constructed building will be damaged by earthquake = P(P)
= P(VI) * P(P | VI) = 0.5 * 0.05 = 0.025
Proportion of buildings damaged by the earthquake = 0.20 * 0.025 + 0.80 * 0 = 0.005
For intensity VII,
Probability that a well-constructed building will be damaged by earthquake = P(W)
= P(VII) * P(W | VII) = 0.3 * 0.05 = 0.015
Probability that a poorly-constructed building will be damaged by earthquake = P(P)
= P(VII) * P(P | VII) = 0.3 * 0.25 = 0.075
Proportion of buildings damaged by the earthquake = 0.20 * 0.075 + 0.80 * 0.015 = 0.027
For intensity VIII,
Probability that a well-constructed building will be damaged by earthquake = P(W)
= P(VIII) * P(W | VIII) = 0.15 * 0.10 = 0.015
Probability that a poorly-constructed building will be damaged by earthquake = P(P)
= P(VIII) * P(P | VIII) = 0.15 * 0.50 = 0.075
Proportion of buildings damaged by the earthquake = 0.20 * 0.075 + 0.80 * 0.015 = 0.027
For intensity IX,
Probability that a well-constructed building will be damaged by earthquake = P(W)
= P(IX) * P(W | IX) = 0.05 * 0.20 = 0.01
Probability that a poorly-constructed building will be damaged by earthquake = P(P)
= P(IX) * P(P | IX) = 0.05 * 0.75 = 0.0375
Proportion of buildings damaged by the earthquake = 0.20 * 0.01 + 0.80 * 0.0375 = 0.032
Thus, the intensity IX is the source of most losses.
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For the figure shown on the right, find the value of the variable and the measures of the angles. PLZ HELP
Help someone please? And makes sure the answer is right please and thank you :)
Answer:
x=7
Step-by-step explanation:
In this question, since the horizontal lines are parallel lines, these two angles are congruent to each other.
So we have: 105=16x-7
Equation: 105=16x-7
Add 7 to both sides: 112=16x
Divide by 16 on both sides: x=7
Let me know if this helps!
Problem 2: Solve the matrix equation for "x" and "y" 8 -X 2 13 4 1- [ 3 -9 10 -4y 5 6 [ 0 16
Solve the operation of the matrix
\(\begin{gathered} 2\begin{bmatrix}{8} & {-x} & {} \\ {5} & {6} & {} \\ & {} & {}\end{bmatrix}{}-\begin{bmatrix}{3} & {-9} & {} \\ {10} & {-4y} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{13} & {4} & {} \\ {0} & {16} & {} \\ {} & {} & {}\end{bmatrix} \\ \begin{bmatrix}{16} & {-2x} & {} \\ {10} & {12} & {} \\ {} & & {}\end{bmatrix}-\begin{bmatrix}{3} & {-9} & {} \\ {10} & {-4y} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{13} & {4} & {} \\ {0} & {16} & {} \\ {} & {} & {}\end{bmatrix} \\ \begin{bmatrix}{13} & {-2x+9} & {} \\ {0} & {12+4y} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{13} & {4} & {} \\ {0} & {16} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}\)From this result we know that
\(\begin{gathered} -2x+9=4 \\ 12+4y=16 \end{gathered}\)Now clear x and y from the equations
\(\begin{gathered} -2x+9=4 \\ -2x=-5 \\ x=-\frac{5}{-2} \\ x=\frac{5}{2} \end{gathered}\)\(\begin{gathered} 12+4y=16 \\ 4y=4 \\ y=\frac{4}{4} \\ y=1 \end{gathered}\)x is 5/2 and y is 1
Find the standard form of the parabola given
the focus (2, 1) and directrix of X = -2
a) (y-1)^2=8x
b) (x-1)^2=-8y
c) (y-1)^2=-8x
d) (x-1)^2=8y
Answer:
A. is the answer.
Step-by-step explanation:
EASY ABCD QUESTION, WILL GIVE BRAINLEIST TO FIRST ANSWER,
Determine the number of solutions to the system of linear equations shown on the graph.
A. No solution
B. Infinitely many solutions
C. One solution at (−3, 2)
D. One solution at (2, −3)
D (2,-3)
Just look where the lines meet
Answer: D IS CORRECT
Step-by-step explanation:
charles owns a catering business. the amount his 10 most recent clients spent is shown in the histogram below. a bar graph is entitled cost per event. the event cost is on the x-axis and the number of events is on the y-axis. there are 2 events with a cost of 1,000-1,499; 4 with a cost of 1,500 to 1,999; 3 with a cost of 2,000 to 2,499; 1 with a cost of 3,000 to 3,499. why is the graph misleading?
The graph is misleading because the x-axis scale shows that the given data is more clustered than it actually is.
What is a misleading graph?
A misleading graph, sometimes referred to as a distorted graph, misrepresents data, amounts to statistical abuse, and may lead to the drawing of an inaccurate conclusion.
What is a data set?
A data set is a grouping of connected, discrete pieces of connected data that can be viewed separately, together, or handled as a single unit. A data structure of some kind is used to arrange a data set.
Here, we have
2 events with a cost of 1,000-1,499;
4 events with a cost of 1,500 to 1,999;
3 events with a cost of 2,000 to 2,499;
1 event with a cost of 3,000 to 3,499
We concluded from the given dataset that the cost of the event is plotted on the x-axis.
In a given dataset, the entry from 2500 to 2599 is missing.
The graph generates a point cluster that isn't actually displayed on the data components because of the missing item.
Hence, the graph is misleading because the x-axis scale shows that the given data is more clustered than it actually is.
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Question 12 (10 points)Students love to put ranch dressing on everythig, so Elvira needs to keep plenty in stock. The students eat about 2.25 gallons of ranch each day! Elvira started the school year with 130 gallons of ranch dressing. She needs to have at least 20 gallons left when she reorders to have enough in stock until the new order comes. For how many days will her ranch dressing supply last before she needs to reorder?A. Write and solve an inequality that models this situation.B. Describe in words the quantities that would work in this situation.C. Write your answer in both interval and set notation.
We will formulate an equation that gives us the number of gallons left after x days.
So, we know that there are 130 gallons at the beginning and every day there are 2.25 gallons less. Therefore, the equation is:
y = 130 - 2.25x
Where y is the number of gallons left. Additionally, She needs to have at least 20 gallons left when she reorders to have enough in stock until the new order comes. It means that y needs to be at least 20:
\(\begin{gathered} y\ge20 \\ 130-2.25x\ge20 \end{gathered}\)Now, to know how many days will her ranch dressing supply last before she needs to reorder we need to solve it for x as:
\(\begin{gathered} 130-2.25x\ge20 \\ 130-2.25x+2.25x\ge20+2.25x \\ 130\ge20+2.25x \\ 130-20\ge20+2.25x-20 \\ 110\ge2.25x \\ \frac{110}{2.25}\ge\frac{2.25x}{2.25} \\ 48.89\ge x \end{gathered}\)So, she needs to reorder before 48.89 days or in the interval (0, 48.89) days.
Answer: 48.89 days
A.
\(\begin{gathered} 130-2.25x\ge20 \\ x\leq48.89\text{ days} \end{gathered}\)B. She needs to reorder before 48.89 days. It means that she has from 0 to 48.89 days to reorder if she wants enough in stock until the new order comes
C. Interval notation: (0, 48.89 )
Set notation: { x | 0 ≤ x ≤ 48.89}
|-9-3| + (-16:4)
Evaluate the following expressions
Answer:
I got 12 + (-16 :4)
Step-by-step explanation:
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Last year, the mean amount spent by customers at a certain restaurant was $32. The restaurant owner believes that the mean may be lower this year. State the appropriate null and alternate hypotheses. The null hypothesis is :H0μ ____ . The alternate hypothesis is :H1μ ____ .
Null hypothesis (H0): The population mean amount spent by customers at the restaurant is equal to or greater than $32.
Alternative hypothesis (H1): The population mean amount spent by customers at the restaurant is less than $32.
The appropriate null and alternative hypotheses in this scenario can be stated as follows:
The null hypothesis is the default assumption, which states that there is no significant difference between the mean amount spent by customers last year and this year.
On the other hand, the alternative hypothesis is the claim that the mean amount spent by customers this year is less than the previous year, which the restaurant owner is trying to test.
By conducting appropriate statistical tests and analyzing the data, the restaurant owner can either reject the null hypothesis or fail to reject it, depending on the level of significance and the strength of the evidence gathered.
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find the distance formula
Answer:
d=(x^2-x^1)+(y^2-y^1)^2
Answer:
\(\mathfrak{Distance \: between \: two \:points}\)
The distance between two points \(A(x_1,y_1)\) and \(B(x_2,y_2)\) is given by the formula,
\(AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }\)
Proof: Let X'OX and YOY' be the x-axis and y-axis respectively. Then, O is the origin.
Let\(A(x_1,y_1) \) and \(B(x_2,y_2)\)
be the given points.
Draw AL perpendicular to OX, BM perpendicular to OX and AN perpendicular to BM
Now,\(OL=x_1,OM=x_2,AL=y_1 \: and \: BM=y_2\)
\( \therefore{AN=LM=(OM-OL)=(x_2-x_1)}\)
\( \: \: \: BN=(BM-NM)=(BM-AL)=(y_2-y_1)\)
In right angled triangle \( \triangle \: ANB\),by Pythagorean theorem,
We have,
\( \: \: \: AB^2=AN^2+BN^2\)
\(or,AB^2=(x_2-x_1)^2+(y_2-y_1)^2\)
\( \therefore \: AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \)
Thus ,the distance between the points A(x_1,y_1) and B(x_2,y_2) is given by,
\( \implies \boxed{AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }\)
help will give Brainliest.
Does this expression use the distributive property?
(6x + 3) + (5x - 4)
no because you are not distributing numbers that multiply with each other and form new expressions
Answer:
hm I'm not sure but you solve it like this
Step-by-step explanation:
(6x + 3) + (5x - 4)
remove unnecessary parenthesis
6x+3+(5x-4)
collect like terms
11x+3-4
answer :
11x-1
What is a requirement of the data in order for us to be allowed to control for individual variability?.
Statistics help present data precisely and draw meaningful conclusions. While presenting data, one should be aware of using adequate statistical measures.
Readers are generally interested in knowing the variability within the sample, descriptive data should be precisely summarized with SD. The use of SEM should be limited to computing CI which measures the precision of population estimate. Journals can avoid such errors by requiring authors to adhere to their guidelines.
Studying the entire population is time and resource-intensive and not always feasible; therefore studies are often done on the sample, and data are summarized using descriptive statistics. These findings are further generalized to the larger, unobserved population using inferential statistics.
For example, to understand the cholesterol levels of the population, the cholesterol levels of the study sample, drawn from the same population are measured.
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Whats a transformation
the act or process of changing completely
how large a sample is needed to ensure that the probability that the sample mean differs from the population mean by more than 2.0 hours is less than 0.05?
The required sample size for the probability that the sample mean differs from the population mean by more than 2.0 hours is less than 0.05 is 68.
Given that the number of hours spent studying by students on large campus in the week before final exams follows a normal distribution with a standard deviation of 8.4 hours.
we want to find the size of the sample which is needed to ensure that the probability that the sample mean differs from the population mean by more than 2.0 hours is less than 0.05.
Here, the margin of error is E=2 and the level of significance is α=0.05
The critical value is Zα/2=Z₀.₀₂₅
or the critical value is 1.96
Now, we will find the sample size
n=((Zα/2)×σ/E)²
n=(1.96×8.4/2)²
n=67.76
n≈68
Hence, the size of sample which is needed to ensure that the probability that the sample mean differs from the population mean by more than 2.0 hours is less than 0.05 is 68.
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28.In the year 2006, the number of malaria patients admitted in the hospital of a state was 4375. Every year this number decreases by 8%. Find the number of patients in the year 2008?
Answer:number of patients in the year 2008 =3,703 Patients.
Step-by-step explanation:
Number of malaria patients admitted in the hospital of a state in 2006= 4375.
Number of malaria patients admitted in the hospital of a state in 2007 if there was Decrease by 8% in 2007
= 8% x 4375 =350
4375-350=4,025 patients
Number of malaria patients admitted in the hospital of a state in 2008 since there was Decrease by 8% in 2008
8% x 4,025.= 322
4,025-322=3,703 Patients.
Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then y=19.6h. If an object isdropped from a height of 49.5 meters, with what velocity does it hit the ground?Round your answer to the nearest tenth.meters per second5?pt71pt5 A1 ANpt1 AMI Don't KnowSubmit© 2020 McGraw-Hill Education. All Rights Reserved. Terms of UsePrivacy | Accessibilitybt6 PMsty-
We are already told that the velocity with which an object hits the ground is given by
\(v=\sqrt[]{19.6h}\)and we are asked to find the velocity when h = 49.5. To do this we just substitute 49.5 for h in the above equation to get
\(v=\sqrt[]{19.6\times49.5}\)which evaluates to (the nearest tenth)
\(v=31.2\)which is our answer!