Why do nanomaterials enhance physical, electrical,
thermal, magnetic and or optical properties of selected materials?
explain your answer in detail.
Answers
Nano materials, which are materials with structures at the nano scale (typically below 100 nanometers), possess unique properties and behaviors that differ from their bulk counterparts. These unique properties arise due to the increased surface-to-volume ratio, quantum confinement effects, and size-dependent properties exhibited by nano materials. As a result, nano materials have the potential to enhance various physical, electrical, thermal, magnetic, and optical properties of selected materials.
Let's explore each of these areas in detail:
Physical properties: Nano materials often exhibit improved mechanical strength, hardness, and toughness compared to bulk materials. The smaller size of nano materials allows for greater grain boundary interactions, leading to enhanced mechanical properties. Additionally, their high surface area facilitates efficient interaction with other materials, making them suitable for applications such as catalysts, sensors, and filtration membranes.
Electrical properties: Nano materials can exhibit unique electrical properties such as enhanced conductivity, increased charge carrier mobility, and tunable band gaps. Quantum confinement effects, arising from the quantum confinement of electrons or holes within nano scale dimensions, can modify the electronic structure and result in altered electrical behavior. This property is advantageous in fields like electronics, photovoltaic, and energy storage devices.
Thermal properties: Nano materials possess high thermal conductivity and can facilitate efficient heat transfer. The reduced dimensions and enhanced surface-to-volume ratio allow for better thermal management, making nano materials useful in applications like thermal interface materials, heat sinks, and thermometric devices.
Magnetic properties:Nano materials exhibit modified magnetic properties, including enhanced magnetization, increased coercivity, and improved magnetic stability. These properties are influenced by factors such as size, shape, and composition of the nanomaterials. Such enhanced magnetic properties find applications in data storage, magnetic sensors, and biomedical devices.
Optical properties:Nanomaterials demonstrate size-dependent optical phenomena, such as quantum confinement and surface plasmon resonance. Quantum confinement effects in nanoscale materials can lead to changes in their absorption, emission, and scattering properties, enabling the development of novel optical devices and technologies. Nanomaterials also show enhanced light-matter interactions, making them valuable for applications in sensors, displays, and optoelectronic devices.
Overall, the unique properties of nanomaterials, resulting from their nanoscale dimensions, enable the enhancement of various physical, electrical, thermal, magnetic, and optical properties of selected materials. These enhanced properties open up new opportunities for advancements in fields ranging from electronics and energy to healthcare and environmental science.
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Related Questions
Suppose 900 kg satellite is orbiting the earth one earth radius above the surface: Q1) Find the force of gravity between the earth and the satellite Q2) Find the orbital period of the satellite_ Q3) Find the tangential velocity required to keep the satellite in orbit: Q4) Find the angular velocity of the satellite:
Answers
(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.
(2) The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.
(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.
(4) The angular velocity of the satellite is 0.0011 radians per second.
(1) The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)
(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.
(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.
(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.
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Examine the charge distribution shown a) What will the net force be on a third charge of q3 = -5.0x10-5C , placed at point Z? b) What will the total electric potential energy be if a third charge of q3 = -5.0x10-5C is placed at point Z?
Answers
Part A. We are asked to determine the force exerted on a charge placed on point Z. To do that we will use the fact that charges with the same sign will attract each other and charges with a different sign will repel each other. Therefore, we can construct the following free body diagram:
Since q3 and q2 are both negative they repel each other and since q1 is positive this means that q3 and q1 will attract each other.
To determine the magnitude of the forces we will use Coulomb's law:
\(F=k\frac{q_1q_2}{r^2}\)Where:
\(\begin{gathered} k=\text{ Coulomb's constant} \\ r=\text{ distance between the charges} \\ q_1,q_2=\text{ magnitude of the charges} \end{gathered}\)For the force between q1 and q3 we have:
\(F_1=k\frac{q_1q_3}{r_1^2}\)For the force between q3 and q2 we have:
\(F_2=k\frac{q_2q_3}{r_2^2}\)Now, the net force is the difference between F2 and F1 since the force act in different directions, therefore, we have:
\(F=F_2-F_1\)we have taken the left direction to be negative and the right direction to be positive. Now, we substitute Coulomb's law:
\(F=k\frac{q_2q_3}{r_2^2}-k\frac{q_1q_3}{r_1^2}\)We can take "kq3" as a common factor:
\(F=kq_3(\frac{q_2}{r_2^2}-\frac{q_1}{r_1^2})\)The distance from q1 to q3 is:
\(r_1=4m+3m=7m\)The distance from q2 and q3 is:
\(r_2=3m\)Now, we substitute the values:
\(F=(9\times10^9\frac{Nm^2}{C^2})(5\times10^{-5}C)(\frac{4\times10^{-5}C}{(3m)^2}-\frac{4\times10^{-5}C}{(7m)^2})\)Solving the operations:
Solving the operations:
\(F=1.63N\)Therefore, the net force is 1.63 Newtons to the right.
Part B. To calculate the electric potential energy we will use the following formula:
\(U=k\frac{q_1q_2}{r}\)To determine the total energy we add the energy for both pairs of charges, like this:
\(U=k\frac{q_1q_3}{r_1}+k\frac{q_2q_3}{r_2}\)We can take "kq3" as a common factor:
\(U=kq_3(\frac{q_1}{r_1}+\frac{q_2}{r_2})\)Now, we substitute the values:
\(U=(9\times10^9\frac{Nm^2}{C^2})(-5\times10^{-5}C)(\frac{4\times10^{-5}C}{7m}+\frac{-4\times10^{-5}C}{3m})\)Solving the operations we get
\(U=3.42J\)Therefore, the energy is 3.42 Joules.
To learn how to change units of physical quantities.
Quantities with physical dimensions like length or time must be measured with respect to a unit, a standard for quantities with this dimension. For example, length can be measured in units of meters or feet, time in seconds or years, and velocity in meters per second.
When solving problems in physics, it is necessary to use a consistent system of units such as the International System (abbreviated SI, for the French Système International) or the more cumbersome English system. In the SI system, which is the preferred system in physics, mass is measured in kilograms, time in seconds, and length in meters. The necessity of using consistent units in a problem often forces you to convert some units from the given system into the system that you want to use for the problem.
The key to unit conversion is to multiply (or divide) by a ratio of different units that equals one. This works because multiplying any quantity by one doesn't change it. To illustrate with length, if you know that 1inch=2.54cm, you can write
1=2.54cm1inch.
To convert inches to centimeters, you can multiply the number of inches times this fraction (since it equals one), cancel the inch unit in the denominator with the inch unit in the given length, and come up with a value for the length in centimeters. To convert centimeters to inches, you can divide by this ratio and cancel the centimeters.
1.
How many centimeters are there in a length 18.2 inches ?
Express your answer in centimeters to three significant figures.
2.
Suppose that a particular artillery piece has a range R = 6310 yards . Find its range in miles. Use the facts that 1mile=5280ft and 3ft=1yard.
3.
What is the speed of a car going v=1.000mph in SI units? Notice that you will need to change from miles to meters and from hours to seconds. You can do each conversion separately. Use the facts that 1mile=1609m and 1hour=3600s.
Express your answer in meters per second to four significant figures.
Express your answer in miles to three significant figures.
Answers
1-there are 46.2cm in 18.62inches, 2- if the artillery range is 6310 yards then the range in miles is 3.58miles, C- if the car is going in 1.000mph then its speed is 0.4470 m/s
1. To convert 18.2 inches to centimeters, multiply by the conversion factor (1 inch = 2.54 cm):
18.2 inches * (2.54 cm / 1 inch) = 46.2 cm (to three significant figures).
2. To convert 6310 yards to miles, first convert yards to feet, then feet to miles:
6310 yards * (3 ft / 1 yard) = 18930 ft
18930 ft * (1 mile / 5280 ft) = 3.58 miles (to three significant figures).
3. To convert 1.000 mph to meters per second, first convert miles to meters, then hours to seconds:
1.000 mile * (1609 m / 1 mile) = 1609 m
1 hour * (3600 s / 1 hour) = 3600 s
(1609 m) / (3600 s) = 0.4470 m/s (to four significant figures).
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What does the V-field at point A, which is a distance d from the source charge, depend on? (More than one statement may be correct.)
A. the sign of the test charge
B. the magnitude of the source charge
C. the sign of the source charge
D. the distance of point A from the test charge center
E. the magnitude of the test charge
F. the distance of point A from the source charge center
Answers
The V-field at point A, which is a distance d from the source charge, depend on are as follows:
B- the magnitude of the source chargeC- the sign of the source chargeF- and the distance of point A from the source charge centreWhat is Electric potential?
Electric potential is the effort necessary to move a unit charge from one point to another in the presence of an electric field. Ground is typically used as the reference point, but any point that is free of electric field charges can be used.
Depending on how much work is put into the electric field to move an object from one place to another, the electric potential's strength will vary. A certain amount of energy is gained when an object moves against an electric field.
Potential energy is used to describe this.
Due to the source charge, point A's V field has the value V = kq/d.
The charge q can be negative or positive. As a result, it is clear from this potential equation that the V field is strongly influenced by the charge's sign, magnitude, and distance between the point and the source charge.
Only the V-existence field's and magnitude need be tested with a test charge.
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an air parcel rises over a mountain and cools adiabatically. which lifting mechanism has acted on this parcel?
Answers
The mountain or orographic lifting mechanism has acted on the air parcel, causing it to rise and cool adiabatically as it moves up and over the mountain.
A mountain presents a physical barrier that pushes an air parcel to ascend when it rises over it. Orographic lifting is the term for this procedure. The parcel undergoes a drop in pressure as it rises, which causes adiabatic cooling. The air parcel cools due to adiabatic expansion as it climbs, which causes a decrease in temperature.
The dry adiabatic lapse rate, which measures the temperature drop as 10°C per 1000 metres of climb, is used to describe this phenomenon. The air's ability to condense and form clouds in response to cold may also result in precipitation.
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Orographic lifting mechanism has been used.
Orographic lift of moist air coming off the ocean produces clouds along the Santa Lucia Mountains south of Monterey, California, USA (Credit: NOAA). As an example, the North Shore mountains immediately north of Vancouver often experience heavy rain and snowfall due to orographic uplift.
Detailed Answer - Hi! The lifting mechanism that has acted on the air parcel as it rises over a mountain and cools adiabatically is called Orographic Lifting. This occurs when an air mass is forced to rise over elevated terrain, such as a mountain, causing it to cool and potentially form clouds or precipitation.
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Which statement is true? A) Cells come in different shapes, but are all about the same size—very, very small. B) Cells come in different shapes and different sizes. C) Cells all have the same shape, but come in different sizes. D) Cells are all the same shape and size—small and rounded.
Answers
Answer: B) Cells come in different shapes and different sizes.
Explanation:
Cell is the basic unit of life. Each cell forms the an integral component of the body of the living organism. The cell structure and function varies from organism to organism. The cells of the plants are comparatively larger than the animal cells. The plant cells are usually rectangular in shape whereas that of animals are usually circular or round in shape. The shape and size of the cells can vary depending upon the function and structure of the organism.
differences between low-mass and high-mass stars include the fact that high-mass stars . (select all that apply.)
Answers
High-mass stars are so luminous that their radiation strips gas from the outer layers and driving it into space whereas high-mass stars achieve much hotter temperatures in their cores and interior layers
What are some differences between high and low mass stars?Low mass stars are cooler and are reddish in color. High mass stars are hotter, and are white or blue white in color. Extremely high mass stars may also shine as a pale violet, which is more blue than blue white. High mass stars are brighter compared to low mass stars, because they produce more energy.
A low mass star is less than three solar masses whereas high mass star is above eight solar masses.
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why does a hot air balloon fall when the air inside is not heated
Answers
Protein 1 and Protein 2 have many differences in their amino acid sequences. Based on this information, which of the following statements are true about Protein 1 and Protein 2?
Choose 2 answers:
(choice A)
The proteins are encoded by genes with different nucleotide sequences.
(Choice B)
B
The proteins likely have different functions.
(Choice C)
C
The proteins must be located in different regions of the body.
Answers
Answer:
Choice A & Choice B
The proteins are encoded by genes with different nucleotide sequences, they likely have different functions. The correct options are A and B.
Genes with various nucleotide sequences encode the proteins. Protein 1 and Protein 2 have distinct amino acid sequences, indicating that they are encoded by genes with different nucleotide sequences.
Because the amino acid sequences of Protein 1 and Protein 2 differ so greatly, it is likely that they have separate activities.
The assumption that proteins must be found in diverse parts of the body is not always correct. Although proteins with distinct activities may be found in different parts of the body, variations in their amino acid sequences cannot be used to identify this.
Thus, the correct options are A and B.
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Explain why background radiation is a mixture of contamination and irradiation
Answers
Answer:
People are exposed to sources of radiation in all aspects of everyday life. Radioactive sources can be very useful but need handling carefully to ensure safety.
Explanation:
What coefficient is needed in front of H2O to balance the equation below?
Answers
Let a, b, c be the coefficients in the balanced reaction,
a P₄O₁₀ + b H₂O ⇒ c H₃PO₄
Count the number of each atom on either side of the reaction:
• P : 4a = c
• O : 10a + b = 4c
• H : 2b = 3c
Suppose a = 1. Then from the first equation,
c = 4•1 ⇒ c = 4
and from the third equation,
2b = 3•4 = 12 ⇒ b = 6
The third equation is also satisfied:
10a + b = 4c ⇒ 10•1 + 6 = 4•4 ⇒ 16 = 16
So, the balanced reaction is
P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄
which makes D the correct answer.
gas expands when 591 J of energy is added to it as heat. The expanding gas does 431 J of work on its surroundings.
(a) What is the overall change in the internal energy of the gas?
J
(b) If the work done by the gas were equal to 1102 J (rather than 431) J), how much energy would need to be added as heat in order for the change in internal energy to equal the change in internal energy in part (a)?
Answers
Let us cut the work done on gas as we move along the direct path
W=-(-area undercurve),=-[(1.00atm)(4.l-2)+1/2(4-1)(4-2)],W=-5atm
The change in internal energy=-88.5J
What does physics mean by internal energy?
In thermodynamics, internal energy is a property or state functional that characterises a substance's energy in the absence of capillary effects and the impacts of external magnetic, electric, and other fields.
What makes it internal energy?
Internal Energy is the energy in a thermodynamics that is NOT either the system's total kinetic energy or the gravitational potential energy. The system's internal freedom levels are connected to the internal energy.
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The speed of sound in human tissue is about 1600 m/s. If an ultrasound pulse takes
1.5 x 10--s to travel through a tissue, what is the thickness of the tissue in mm?
Answers
Answer:
The thickness of the tissue is : 2.4 x 10⁷ mm
Explanation:
The general formula for speed is the distance travelled divided by the time taken.
In this case,
Speed = 1600 m/s ------speed of sound in human tissue
Time = 1.5 * 10 seconds -----time of taken for the ultrasound pulse to go through a certain thickness of a tissues
The thickness of the tissue here is the distance as per the speed formula, hence;
Tissue thickness = Speed of sound * time taken by ultrasound pulse
Tissue thickness= 1600 * 1.5*10 =24000 m
1 m= 1000 mm
24000m = 24000*1000 mm
= 2.4 x 10⁷ mm
if space has a hyperbolic geometry, what will happen to two initially parallel flashlight beams as they traverse billions of light-years of space?
Answers
In a space with hyperbolic geometry, the behavior of parallel lines differs from that of Euclidean geometry.
In hyperbolic space, parallel lines diverge from each other as they extend further.If two initially parallel flashlight beams traverse billions of light-years of space in a hyperbolic geometry, they will gradually diverge from each other. The divergence between the beams will increase as they travel a greater distance.
This phenomenon is a consequence of the non-Euclidean geometry of space. In hyperbolic space, the curvature causes parallel lines to "spread out" or diverge. The extent of the divergence will depend on the specific curvature of the space and the distance traveled.
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wave crests are passing the anchor chain of an anchored boat every 5 seconds. if the wave troughs are 15 m apart, what is the speed of the waves?
Answers
The speed of the waves is 3 meters per second.
The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
To find the speed of the waves when wave crests are passing the anchor chain of an anchored boat every 5 seconds and the wave troughs are 15 meters apart, you can use the formula for wave speed:
Wave speed = Wavelength / Wave period
In this case, the wavelength is the distance between the wave troughs, which is 15 meters.
The wave period is the time it takes for one wave crest to pass, which is 5 seconds.
Wave speed = 15 m / 5 s = 3 m/s
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Choose an example in which the momentum of a system is not constant.
(a) A bullet shot from a rifle, with the rifle and the bullet as the system (b) A freely falling metal ball, with the ball as the system (c) A freely falling metal ball, with the ball and Earth as the system (d) It is not possible to give an example since the momentum of a system is always constant.
Answers
The momentum of the system is always constant. Therefore, the example that best fits the criteria is "A freely falling metal ball, with the ball and Earth as the system." So, C is the correct option.
When considering the examples given, we can eliminate options (a) and (d) as they suggest that the momentum of the system is always constant.
The momentum of a system is the product of the mass and velocity of an object. When the metal ball is falling freely, the momentum of the ball and the Earth system changes continuously as the velocity of the ball changes due to the force of gravity. Therefore, the momentum of the system is not constant in this case.
So, the correct option is C.
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Help! How do you find the Eccentricity??
Answers
Explanation:
The formula to determine the eccentricity of an ellipse is the distance between foci divided by the length of the major axis
The strength of gravity at the Earth's surface is 10 newtons per kilogram.
Calculate the weight of a car with a mass of 1500 kg.
Answers
Answer:
To calculate the weight of a car with a mass of 1500 kg, you need to use the equation F = mg, where F is the force of gravity, m is the mass of the car, and g is the acceleration of gravity (which is 10N/kg at the Earth's surface).
Therefore, the weight of the car can be calculated as follows:
Weight = m x g Weight = 1500 kg x 10 N/kg Weight = 15000 N
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From the choices below, select the one that best describes the difference between distance and displacement.
Distance includes direction,
Distance includes acceleration, displacement does not
Displacement includes direction, distance does not
Distance include speed, displacement, does not
Answers
Displacement includes direction, distance does not
is your answer. hope it helps!
a a horizontal, uniform board of weight 125 n and length 4 m is supported by vertical chains at each end. a person weighing 500 n is sitting on the board. the tension in the right chain is 250 n. what is the tension in the left chain? 375 n
Answers
If a horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end and a person weighing 500 N is sitting on the board, the tension in the right chain is 250 N then the tension in the left chain is 375 N.
A horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end. A person weighing 500 N is sitting on the board.
The tension in the right chain is 250 N. What is the tension in the left chain?
The tension in the left chain is 375 N.
How to find the tension in the left chain?
Here, the weight of the board is W1= 125 N
Weight of the person sitting on the board is W2 = 500 N
Length of the board is L = 4 m
Tension in the right chain is T1 = 250 N
Tension in the left chain is T2
The sum of the tension in both chains will be equal to the weight of the board and the person sitting on the board. i.e., T1 + T2 = W1 + W2.
T2 + 250 N = 125 N + 500 N
T2 = 625 N - 250 N
T2 = 375 N
Therefore, the tension in the left chain is 375 N.
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Which gas in Earth’s atmosphere has increased over time due to burning fossil fuels?
oxygen
nitrogen
water vapor
carbon dioxide
Answers
Answer:
D) Carbon Dioxide
Explanation:
I hope this is right!
Answer:
d
Explanation:
When does an object reach its terminal velocity?
Answers
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
Explanation:.
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
As others have said, 8 seconds to get to 90% of terminal velocity. But if you're falling from outer space, you could reach speeds much higher than terminal velocity, and slow down when you reach the atmosphere. If coming in from a long distance, you'll burn up like a meteorite.
Explanation:
13. When you say that something is a factor, you mean that it is an) (factor)
a. problem.
b. obstacle.
c. ingredient.
d. fact
Answers
Answer:
C.
A factor of something is an ingredient, or it makes up that thing. For example, in math, we always try to find the factors of a number. We are basically trying to find the "ingredients" of a number.
we know how fast a star in the galaxy is moving away from us on the basis of its spectrum. mass. luminosity. age. color.
true/false
Answers
We cannot determine the speed at which a star in the galaxy is moving away from us based on its mass, luminosity, age, or color alone. it is false
The speed at which a star in the galaxy is moving away from us is determined through the measurement of its spectrum using a technique known as redshift.
When a star or galaxy moves away from us, its light is shifted towards longer wavelengths, resulting in a redshift. By analyzing the degree of redshift, astronomers can estimate the speed at which the star is receding.
However, factors such as mass, luminosity, age, and color do not provide direct information about the star's motion away from us.
These characteristics are important for studying other properties of stars, such as their composition, brightness, evolutionary stage, and temperature. To determine the motion of a star in the galaxy, redshift measurements are essential.
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Can sound undergo total internal reflection at a smooth interface between air and water? If so, in which medium must it be traveling originally?
Answers
No, sound cannot undergo total internal reflection at a smooth interface between air and water.
Total internal reflection occurs when a wave traveling in a more optically dense medium encounters a boundary with a less optically dense medium and is reflected back into the more dense medium at a certain angle. This phenomenon is commonly observed with light waves at interfaces between different transparent materials, such as when light travels from water to air or from glass to air.
Sound waves, on the other hand, are mechanical waves that require a medium for propagation. They are compression waves that travel through materials by causing particles in the medium to vibrate. Sound waves do not exhibit total internal reflection at boundaries between different media like light waves do.
When sound waves encounter an interface between air and water, they will undergo partial reflection and refraction. Some of the sound energy will be reflected back into the original medium (air) and some will be transmitted and refracted into the second medium (water). The amount of reflection and refraction depends on factors such as the angle of incidence and the acoustic impedance of the materials.
Therefore, sound waves do not undergo total internal reflection at a smooth interface between air and water, regardless of the medium in which they are originally traveling.
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Please answer this subject is science
Answers
1. 15 m
2. 71.5 m
3. not sure but maybe 10 9/13 s
What is the temperature increase of 4.0 kg of water when it is heated by an 8.0 ^102 W immersion heater for exactly 10.0 min? (cp = 4186 J/kg·°C)
Answers
Answer:
ΔT = 28.667°C is the answer.
Explanation:
Given,
Mass of water = 4.0 kg
Water is heated by = 8 × 10² W = 800 W
Time = 10 min = 10 × 60 = 600 s
Now,
using the equation of specific heat,
Q = mcΔT
where c is the specific heat capacity of water = 4186 J/kg°C
Q = Pt
Substituting,
Pt = mcΔT
800 × 600 = 4 × 4186 × ΔT
480000 = 16744 × ΔT
ΔT = 28.667
∴Temperature increased, ΔT = 28.667°C
Can someone please explain
1) Centripetal force with example
2) Centrifugal force with example
3) Circular motion with example
Answers
Explanation:
centripetal force is a force that makes a body follow a curved path. for example, twirling,a lasso, cream seperator etc.
A force that causes an objectmoving in a circular path to move out and away from the centres of it's path is centrifugal force. for example,drifting, banked roads, washing machine etc.
Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. for example, stirring batter, stone tied to a string etc
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During an autumn storm, a 0.012-kg hail stone traveling at 20.0 m/s made a0.20-cm-deep dent in the hood of Darnell's new car. What average force didthe car exert to stop the damaging hail stone?
Answers
Answer:
1200 N
Explanation:
First, we need to calculate how much time the force was applied. If the stone traveled at 20.0m/s and made a 0.20 cm deep dent, the time is equal to
\(\text{ Avg }speed=\frac{distance}{time}\Rightarrow time=\frac{distace}{Avg\text{ }speed}\)Where the distance is 0.20 cm = 0.0020 m and the average speed can be calculated as:
\(\text{ avg speed = }\frac{v_i+v_f}{2}=\frac{20\text{ m/s + 0 m/s}}{2}=10\text{ m/s}\)Therefore, the time is equal to
\(time=\frac{0.0020\text{ m}}{10\text{ m/s}}=0.0002\text{ s}\)Then, the force can be calculated using the following equation for impulse
\(\begin{gathered} Ft=mv \\ F=\frac{mv}{t} \end{gathered}\)Where m is the mass, v is the speed and t is the time, so replacing m = 0.012 kg, v = 20 m/s and t = 0.0001 s, we get
\(F=\frac{0.012\text{ kg \lparen20 m/s\rparen}}{0.0002\text{ s}}=1200N\)So, the average force was 1200 N
During autumn, the storm travels at a speed of 20 m/s, then the average force the car has to exert to stop the damaging hail storm is 1200 N.
What is Force?A force in physics is an effect that has the ability to modify an object's motion. A bulk object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can be used to describe force. Being a vector quantity, a force also has magnitude and direction. The SI unit of newton is used to measure it (N). The letter F symbolizes for force.
As per Newton's second law's original formulation, an object's net force is equal to the speed at which momentum is changing over time.
According to the given information in the question,
Speed, s= 20 m/s
Average speed, s = Distance/Time
s = [v(i) + v(f)] / 2
s = (20 + 0)/2
s = 10 m/s
Now calculate the time,
Time, t = 0.0020/10
t = 0.0002 seconds.
Use the equation for impulse,
f × t = mv
⇒f = mv/t
f= (0.012 × 20)/0.0002
f = 1200 N
Therefore, the force applied is 1200 N.
To know more about Force:
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A car is stopped at a stop light. When the light turns green, it travels south 55 m/s in 5s. What is its acceleration? *
Answers
Answer:
11m/s^2
Explanation:
Acceleration can be calculated by diving speed by time. Since we know speed and time, acceleration can be calculated.
55/5 = 11m/s^2