Working within the dominant culture, co-cultural advocates offer a prophetic voice calling for major transformation of structures and practices that hold co-cultural groups down. In the context of the communication orientations in co-cultural theory, this statement best describes ________.
Answers
The statement best describes the proactive orientation in co-cultural theory. The proactive orientation emphasizes the efforts of co-cultural advocates to bring about major transformation within dominant structures and practices that hold co-cultural groups down. These advocates work within the dominant culture to challenge and change existing power dynamics and create a more equitable and inclusive society.
In the context of co-cultural theory, co-cultural groups are those who share a particular identity or characteristic that is not represented or valued within the dominant culture. These groups often face marginalization, discrimination, and other forms of oppression that limit their access to resources and opportunities. Co-cultural advocates work to challenge these structures and practices by using their voices and advocating for change.
The proactive orientation is one of four communication orientations in co-cultural theory, which also include accommodation, nonassertion, and assertive. The proactive orientation is unique in that it emphasizes the need for active and intentional efforts to bring about change, rather than simply adapting to the dominant culture or remaining silent about injustices. Overall, the proactive orientation highlights the importance of co-cultural advocacy and the potential for major transformation within society.
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Related Questions
What is the general formula for a compound if anions occupy the hcp lattice points and cations occupy all the octahedral and tetrahedral holes?
a. AB
b. A3B
c. A2B
d. AB2
Answers
The general formula for a compound where anions occupy the hcp lattice points and cations occupy all the octahedral and tetrahedral holes is option (d) AB2.
In a hexagonal close-packed (hcp) lattice structure, anions occupy the lattice points, and cations can occupy both the octahedral and tetrahedral holes within the lattice. The arrangement of the cations in these holes depends on the ratio of cations to anions in the compound.
In this case, the general formula for the compound can be represented as AB2, where A represents the cation and B represents the anion. The number 2 in the formula indicates that each cation A is surrounded by two anions B in the lattice.
By selecting option (d) AB2, we imply that the cations occupy all the octahedral and tetrahedral holes in the hcp lattice, resulting in a compound with the specified arrangement of anions and cations.
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What does the element tile on the
periodic table tell use about the element.
List 4 things
Answers
Suppose you have equal amounts of calcium, Ca, in two beakers. In one beaker, you react the calcium with oxygen, O. In the other beaker, you react the calcium with sulfur, S.The reaction with oxygen forms the compound calcium oxide, CaO. What do you predict is the chemical formula of the compound formed from the reaction between calcium and sulfur?
Answers
Calcium oxide, CaO, is formed when calcium reacts with oxygen, while calcium sulfide, CaS, is formed when calcium reacts with sulfur.
In the beaker where calcium reacts with oxygen, the compound calcium oxide, CaO, is formed. This is because calcium has a valency of +2 and oxygen has a valency of -2. Therefore, they combine in a 1:1 ratio to form a neutral compound. The chemical formula for calcium oxide is CaO.
Now, in the other beaker where calcium reacts with sulfur, we need to look at the valency of sulfur. Sulfur has a valency of -2, which means it requires two electrons to form a stable compound. Calcium, on the other hand, has a valency of +2. Therefore, in order for the compound to be neutral, we need two calcium atoms to combine with one sulfur atom. This gives us the chemical formula CaS, which is calcium sulfide.
In summary, when equal amounts of calcium react with oxygen and sulfur, they form different compounds. Calcium oxide, CaO, is formed when calcium reacts with oxygen, while calcium sulfide, CaS, is formed when calcium reacts with sulfur. The chemical formula of the compound formed depends on the valencies of the elements involved in the reaction.
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What would happen to other populations if they didn't have limitng factors?
Answers
Answer:
In the natural world, limiting factors like the availability of food, water, shelter and space can change animal and plant populations. Other limiting factors, like competition for resources, predation and disease can also impact populations. Other changes in limiting factors will cause a population to decrease.
The empirical rate law for the reaction:
2NO2(g) + F2(g) -----> 2NO2F(g)
is rate = k[NO2][F2]
Which of the following mechanisms us consistent with this rate law?
a. NO2(g) + F2(g) <-----> NO2F(g) + F2(g) fast
NO2(g) + F(g) -----> NO2F(g) slow
b. NO2(g) + F2(g) <-----> NO2F(g) + F2(g) slow
NO2(g) + F(g) -----> NO2F(g) fast
c. F2(g) <-----> F(g) slow
2NO2(g) + 2F(g) -----> 2NO2F(g) fast
Answers
The empirical rate law for the given reaction is:rate = k[NO2][F2]In order to match the empirical rate law for the reaction, the two proposed mechanisms have to be analyzed. Given mechanism are:a. NO2(g) + F2(g) ⇌ NO2F(g) + F2(g) fastNO2(g) + F(g) → NO2F(g) slowb.
NO2(g) + F2(g) ⇌ NO2F(g) + F2(g) slowNO2(g) + F(g) → NO2F(g) fastc. F2(g) ⇌ F(g) slow2NO2(g) + 2F(g) → 2NO2F(g) fastThe step that is slow in the mechanism is the rate-determining step. The rate law for each step can be determined by the molecularity of the reaction. The molecularity of a reaction is the number of molecules that participate in the collision leading to a successful reaction.For mechanism a, rate law is k1[NO2][F2].The second step is the slow step so the rate-determining step is rate = k2[NO2F][F].k2 is very small in comparison to k1, so the rate law will be dominated by k1 rate = k1[NO2][F2]. Therefore, mechanism a is consistent with the empirical rate law.For mechanism b, the rate-determining step is the slow step so the rate law is rate = k2[NO2][F]. k2 is much smaller than k1, so the rate law will be dominated by k2rate = k2[NO2][F2]. Therefore, mechanism b is not consistent with the empirical rate law.For mechanism c, the slow step is the only step so the rate law is k3[NO2][F2]. The rate law is not consistent with the empirical rate law.So, the correct option is a.
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I need help with this question I can’t find the answer to it
Answers
113.89/3
=
37.96333
A sample of air at room temperature in a 4.00 L container holds approximately 0.562 moles of O2and 2.11 moles of N2 along with other trace elements to total 2.67 moles. What is the mole fraction of N2 in the mixture
Answers
Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.
Molar fractionThe molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.
The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:
x=number of moles of the solute÷ total number of moles
Mole fraction of N₂ in the mixtureIn this case, you know that:
number of moles of N₂: 2.11 molestotal number of moles: 2.67 molesReplacing in the definition of mole fraction:
x=2.11 moles÷ 2.67 moles
Solving:
x= 0.79
Finally, the mole fraction of N₂ in the mixture is 0.79.
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What is the mass of an object, when the volume of it is 50.0 mL and the density is 1.5
g/mL?
Answers
Answer:
75 g
Explanation:
Mass=Density x Volume so therefore you do the density which is 1.5 g/mL times the volume which is 50.0 mL so you get 75 g because the mL cancel out in the label!
_____ is the process of converting the language of nucleic acids (nucleotides) to the language of proteins (amino acids).
Answers
Translation is the process of converting the language of the nucleic acids that is nucleotides to the language of proteins that is amino acids.
The process of the conversion of the nucleic acids that is nucleotides to the language of proteins that is amino acids is called as the translation. In the translation process , the strands of the protein is produced from mRNA molecule. The mRNA is the nucleic acid molecule which formed by the help of the multiple nucleotides that is present together.
The formation of the protein strands is the process of the protein synthesis. It is based on the sequence of mRNA molecule.
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A process is carried out at constant pressure. Given that delta E is positive and delta H is negative,
a) the system loses heat and expands during the process
b) the system loses heat and contracts during the process
c) the system absorbs heat and contracts during the process
d) the system absorbs heat and expands during the process
Answers
The information provided, if ΔE (change in internal energy) is positive and ΔH (change in enthalpy) is negative during a process carried out at constant pressure, the correct answer is: c) The system absorbs heat and contracts during the process.
The positive value of ΔE indicates that the internal energy of the system increases, which means energy is being added to the system. This suggests that heat is being absorbed by the system.The negative value of ΔH indicates that the enthalpy of the system decreases. Enthalpy is a measure of heat content in a system, so a negative ΔH indicates a release of heat from the system to the surroundings. Since the process is carried out at constant pressure, the heat released is equal to the heat absorbed by the system.When the system absorbs heat, it gains energy, causing its particles to become more energetic and move faster. This increased energy leads to an increase in the system's internal pressure, resulting in the system contracting or becoming smaller in volume.Therefore, during the process described, the system absorbs heat and contracts.For more such questions on pressure
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What point does the ammonium ions act as a buffer solution? Please this is driving me insane.
Answers
Answer:
Explanation:The buffer is a mixture of ammonia (NH3) and ammonium (NH4+). ... Since ammonia (NH3) is a weak base, it will have a pH above 7 and since ammonium (NH4+) is a weak acid, it will have a pH below 7. Ammonia (NH3) is a weak base and ammonium (NH4+) is a weak acid. Ammonia (NH3) is the conjugate base of ammonium (NH4+).
3. The nucleus:
a. controls all the cell activities
b. controls only part of the cell
c. does not have any activity
Answers
Answer:
a. controls all the cell activities.Thank you ☺️
For every 6 mols of H2 how many mols of h20 will be produced?
For every 2 mols of H2 how many mols of h20 will be produced?
For every 5.67 mols of H2 how many mols of h20 will be produced?
Answers
The moles would be 12 moles, 4 moles and 11.34 moles
How to solve for the molesWhen hydrogen gas (H2) reacts with oxygen gas (O2) to produce water (H2O), the balanced chemical equation is:
2H2 + O2 -> 2H2O
So,
For every 6 moles of H2, 12 moles of H2O will be produced
For every 2 moles of H2, 4 moles of H2O will be produced
For every 5.67 moles of H2, 11.34 moles of H2O will be produced.
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what is the electron configuration for a neutral atom with five valence electrons
Answers
Answer:
pee
Explanation:
ppppppppppppppppppppppppppppppppppppp
Which of the following are end-products of glycolysis except?a. CO2CO2 and H2OH2Ob. Pyruvate, CO2CO2, and ATPc. Pyruvate, NADH, and ATPd. Acetyl CoA, CO2CO2, and NADHe. Citrate, H2OH2O, and FADH2
Answers
The anaerobic breakdown of glucose in these organisms results in the formation of lactic acid and ethanol, respectively.
Hence, option c. (Pyruvate, NADH, and ATP) is the correct answer.
Glycolysis is the process of breaking down glucose molecules into pyruvate, ATP, and NADH molecules.
Pyruvate and ATP are the end-products of glycolysis except for CO2.
Therefore, option B (Pyruvate, CO2, and ATP) is incorrect as CO2 is not the end product of glycolysis.
Thus, the correct option is c. (Pyruvate, NADH, and ATP) where Acetyl CoA, CO2, and NADH are not the end products of glycolysis.
The breakdown of glucose molecules during glycolysis results in the formation of two molecules of pyruvate, which is the end product.
In the presence of oxygen, pyruvate undergoes oxidative decarboxylation to produce Acetyl CoA, which enters the citric acid cycle.
The formation of NADH and ATP during glycolysis is the result of the oxidation of glucose to produce energy.
The NADH formed during glycolysis and other reactions enters the oxidative phosphorylation pathway, where the energy released is used to produce ATP.
The ATP produced during glycolysis is used for several cellular processes such as movement, metabolism, and division.
Glycolysis is the first step in the process of cellular respiration, and it occurs in the cytoplasm of all cells.
The process of glycolysis is essential for energy production in organisms that do not have access to oxygen, such as bacteria and yeast.
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Which of the choices is an example of an element?
O CO
O Co
O C2H2O2
O CO2
Answers
Answer:
Co(cobalt) is the answer
Explanation:
Cobalt is a chemical element with the symbol Co and atomic number 27. Like nickel, cobalt is found in the Earth's crust only in chemically combined form, save for small deposits found in alloys of natural meteoric iron. The free element, produced by reductive smelting, is a hard, lustrous, silver-gray metal.
I would like to have the answer for all parts since they are related. Thank you
1. What is the limiting reagent of the reaction between 75.0 mL of 1.10 M NaOH and 75.0 mL of 1.00 M HCl in a calorimeter, and how many moles are present?
a) Use the value of 0.09 kJ/mol for ΔH°H3O + OH and the moles of limiting reagent in question1 to find the heat (qreaction) released by the NaOH and HCl neutralization reaction. Be sure to include your units.
b)Calculate the heat capacity of the calorimeter in J/°C. Assume CACID = CBASE = CWATER = 4.184 J °C-1 mL-1. Note, we expect a value between 10 – 200 J/°C.
Required data:
Initial Temp of HCl and Calorimeter (°C) 22.4
Initial temp of NaOH (°C)
22.3
Final Temp of HCl, Calorimeter and NaOH (°C)
28.4
Answers
a) The limiting reagent is HCl with 0.075 mol, and NaOH has 0.0825 mol.
b) The heat released by the neutralization reaction is -6.75 J.
c) The heat capacity of the calorimeter is 1.125 J/°C.
To determine the limiting reagent and calculate the heat released in the neutralization reaction between NaOH and HCl, we need to compare the number of moles of each reactant.
a) Calculating the moles and identifying the limiting reagent:
NaOH:
Volume = 75.0 mL = 0.075 L
Concentration = 1.10 M
Moles of NaOH = Volume × Concentration = 0.075 L × 1.10 mol/L = 0.0825 mol
HCl:
Volume = 75.0 mL = 0.075 L
Concentration = 1.00 M
Moles of HCl = Volume × Concentration = 0.075 L × 1.00 mol/L = 0.075 mol
Based on the balanced chemical equation, the stoichiometry of the reaction is 1:1 for NaOH:HCl. Therefore, the limiting reagent is HCl since it has fewer moles (0.075 mol) compared to NaOH (0.0825 mol).
b) Calculating the heat released by the neutralization reaction:
Given ΔH°H3O + OH = -0.09 kJ/mol
Moles of HCl (limiting reagent) = 0.075 mol
Heat released = Moles of HCl × ΔH°H3O + OH
= 0.075 mol × (-0.09 kJ/mol)
= -0.00675 kJ
= -6.75 J (since 1 kJ = 1000 J)
Therefore, the heat released by the NaOH and HCl neutralization reaction is -6.75 J.
c) Calculating the heat capacity of the calorimeter:
Initial temperature of HCl and calorimeter (T1) = 22.4°C
Initial temperature of NaOH (T2) = 22.3°C
Final temperature of HCl, calorimeter, and NaOH (T3) = 28.4°C
Heat capacity of calorimeter (C) = (Heat released) / (Change in temperature)
= -6.75 J / (T3 - T1)
= -6.75 J / (28.4°C - 22.4°C)
= -6.75 J / 6°C
= -1.125 J/°C
Since heat capacity cannot be negative, the heat capacity of the calorimeter is 1.125 J/°C.
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The question is -
1. What is the limiting reagent of the reaction between 75.0 mL of 1.10 M NaOH and 75.0 mL of 1.00 M HCl in a calorimeter, and how many moles are present?
a) Use the value of 0.09 kJ/mol for ΔH°H3O + OH and the moles of the limiting reagent in question 1 to find the heat (reaction) released by the NaOH and HCl neutralization reaction. Be sure to include your units.
b)Calculate the heat capacity of the calorimeter in J/°C. Assume CACID = CBASE = CWATER = 4.184 J °C-1 mL-1. Note, we expect a value between 10 – 200 J/°C.
Required data:
Initial Temp of HCl and Calorimeter (°C) = 22.4
Initial temp of NaOH (°C) = 22.3
Final Temp of HCl, Calorimeter, and NaOH (°C) = 28.4
Air is mainly a mixture of nitrogen and oxygen. Which gas is the main component?
Answers
Answer:
Nitrogen is the main component because it comprises 78% of total air while oxygen comprises 21%
\(.\)
Answer:nitrogen
Explanation:
in order to protect aquifers from pollution, the bottoms of waste dumps should be lined with
Answers
The bottoms of waste dumps should be lined with impermeable materials like clay or synthetic liners to protect aquifers from pollution.
Waste dumps can contain hazardous materials that can seep into the soil and contaminate groundwater, including aquifers, which are important sources of drinking water. Lining the bottoms of waste dumps with impermeable materials helps prevent these contaminants from leaching into the groundwater. Impermeable liners can include clay, plastic, or synthetic materials, and they are designed to create a barrier that prevents the movement of water and pollutants.
Lining the bottoms of waste dumps with impermeable materials is an important measure to protect the quality of groundwater and aquifers. It is important to properly design and maintain these liners to prevent leaks and ensure their effectiveness in preventing pollution.
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DNA is an example of a:
O A. Compound
B. Element
c. Mixture
D. Atom
Answers
Answer:
The answer is option A.
Compound
Hope this helps you
40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP ME
Once upon a time, a mother duckling sat on her eggs with great impatience. How long would it be before they hatched? Finally, one summer day, the mother duckling watched as the eggs cracked, and her cute, yellow ducklings waddled into the world. She was filled with joy until she noticed that one egg, which was larger than all of the others, remained. After many hours, the egg cracked. A large, gray duckling emerged. The mother duck was horrified at the duckling's appearance. The mother duck's only comfort was that the ugly duckling could swim and dive under the water.
As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him.
One day, the ugly duckling decided to run far away and find a place where the animals would look past his appearance and be kind and friendly. He came to a pond and sighted three beautiful swans. Their white feathers, long necks, and kind eyes made them look like royalty. The ugly duckling sighed in disappointment. He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged.
Read the fairy tale The Princess and the Pea.
Once upon a time, there was a handsome prince. The prince lived with his mother and father in a luxurious castle that overlooked a valley of wildflowers and a distant forest. As the prince grew up, he began to long for a princess. However, the prince wanted to be sure that the princess was a real princess. The queen and king searched far and wide for a real princess, but the prince always found something wrong with the princesses they found.
One evening, there was a terrible storm. The wind howled, thunder shook the stone walls, and lightning filled the dark night sky. Through the pelting of the rain, there came a knock at the door. When the king opened the door, he saw a bedraggled girl, soaked to the skin and covered in mud. He ushered her into the castle so that she could warm herself by the fire.
"Why is a young servant girl like you wandering about on such a ferocious night?" queried the king.
The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering.
The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion.
Bright and early the next morning, the king and queen arrived at the girl's bedchamber. The queen asked the girl how she had slept the night before.
"Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue."
The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit.
How do the authors use similar and different events in each fairy tale to illustrate the theme that people should not be judged based on their appearances? Use complete sentences and evidence from the text to support your answer.
Answers
Answer:
MAIN IDEA
What the authors meant is not to judge people by their looks.
_____________________________________________________________
THE UGLY DUCKLING
The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."
Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.
_____________________________________________________________
THE PRINCESS AND THE PEA
The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.
However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."
_____________________________________________________________
CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.
Explanation:
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REALLY NEED HELP
Aqueous Precipitation Reactions:
1. Complete and balance the following chemical equations for double replacement reactions. Make sure you indicate if a solid precipitate is formed.
2. Write the lonic Equation and the net ionic equation for each
Answers
Answer:You're dealing with a double replacement reaction in which two soluble ionic compounds react in aqueous solution to form an Insoluble solid.
As you know, soluble ionic compounds exist as ions in solution. In your case, a solution of sodium carbonate,
Na
2
CO
3
, will contain
Na
2
CO
3(aq]
→
2
Na
+
(aq]
+
CO
2
−
3(aq]
Likewise, a solution of calcium chloride,
CaCl
2
, will contain
CaCl
2(aq]
→
Ca
2
+
(aq]
+
2
Cl
−
(aq]
When these two solutions are mixed, the calcium cations,
Ca
2
+
, will apir up with the carbonate anions,
CO
2
−
3
, and form the Insoluble calcium carbonate,
CaCO
3
, which precipitates out of solution.
The complete ionic equation, which features all the ions that are present in solution, will look like this
2
Na
+
(aq]
+
CO
2
−
3(aq]
+
Ca
2
+
(aq]
+
2
Cl
−
(aq]
→
CaCO
3(s]
⏐
⏐
↓
+
2
Na
+
(aq]
+
2
Cl
−
(aq]
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this
CO
2
−
3(aq]
+
Ca
2
+
(aq]
→
CaCO
3(s]
⏐
⏐
↓
To get the overall balanced chemical equation, simply look at he complete ionic equation and group the ions back to an ionic compound
Na
2
CO
3
2
Na
+
(aq]
+
CO
2
−
3(aq]
+
CaCl
2
Ca
2
+
(aq]
+
2
Cl
−
(aq]
→
CaCO
3(s]
+
2
NaCl
2
Na
+
(aq]
+
2
Cl
−
(aq]
Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have
2
NaCl
.
Na
2
CO
3(aq]
+
CaCl
2(aq]
→
CaCO
3(s]
⏐
↓
+
2
NaCl Hope it helps :)
The word "precipitation reaction" refers to a chemical reaction that takes place within an aqueous solution as two ionic bonds join, resulting in the production of an insoluble salt.
What do aqueous precipitation reactions entail?When dissolved substances react, one (or even more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, twofold replacement, or metathesis reactions, frequently involve the exchange or ions between ionic substances in water-based solutions.
Which two precipitate reactions are examples of them?Examples include the interaction of calcium chloride (CaCl2) with potassium hydroxide (KOH), which produces the insoluble salt calcium hydroxide. Silver https://brainly.com/question/11527546(AgCl), an insoluble salt, is produced by the interaction of silver nitrate (AgNO3) with sodium chloride (NaCl).
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Can someone help with these
Answers
One strategy is to incorporate a soil bacterium gene that produces a glyphosate tolerant form of EPSPS.
Another way is to incorporate a different soil bacterium gene that produces a glyphosate degrading enzyme.
Look for other families of ions in the table that follow a pattern similar to that of the polyatomic chlorine ions. Then complete the statement to describe what you find. Select the correct answer from each drop-down menu. Families of ions that contain hydrogen pattern similar to that of the polyatomic chlorine ions. then complete the statement to describe what you find
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Answer: Families of ions that contain NITROGEN, SULFUR, and CARBON follow a pattern similar to that of the polyatomic chlorine ions.
Explanation: Plato
Answer:
Answer: Families of ions that contain NITROGEN, SULFUR, and CARBON follow a pattern similar to that of the polyatomic chlorine ions.
Explanation: Plato
This biome has extremely cold winters and short, mild summers. It has no trees, only low-growing plants with short root systems because of its frozen soil
called the permafrost. It is covered by snow for most of the year. Animals that live here must have wide paws or hooves to walk through the frozen mushy.
soil. This biome is known as the_________
A. Tropical rainforest
B. Taiga
C. Deciduous Forest
D. Desert
E. Grassland
F. Tundra
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explain what keeps the electrons confined in the space surrounding the nucleus
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Answer:
Electrons are trapped inside the atom because of the attraction forces with positively charged protons that are found in the nucleus.
if the half life of carbon-14 is 5730 years, and you have a sample that has lost 80% of its carbon-14, how old is the sample?
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The sample is 17190 years old if we have lost 80% of the original carbon-14 content of it.
Half-life of carbon-14 is 5730 years which directly means that after this much amount of time only half of the carbon would be remaining.
The amount of carbon remaining after 3 half-lives of carbon would be nearly 1/8 which is equal to 12.5% which means we have lost 87.5% of the carbon-14 so the 3 half-lives would be appropriate to calculate the time passed till 80% of the carbon-14 has decayed.
So the time passed if 3 half-lives have gone would be 3 * half-life of carbon which is nearly 5730 * 3 = 17190 years.
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Rutherford gold-foil experiment
In 1909 Rutherford disproved Sir J.J. Thomson's model of the atom as a uniformly distributed substance. Because only very few of the alpha particles in his beam were scattered by large angles after striking the gold foil while most passed completely through, Rutherford knew that the gold atom's mass must be concentrated in a tiny dense nucleus.
Most alpha particles passed straight through the gold foil, which implied that atoms are mostly composed of open space. Some alpha particles were deflected slightly, suggesting interactions with other positively charged particles within the atom. Still other alpha particles were scattered at large angles, while a very few even bounced back toward the source. (Rutherford famously said later, “It was almost as incredible as if you fired a 15-inch shell at a piece of tissue paper and it came back and hit you.”) Only a positively charged and relatively heavy target particle, such as the proposed nucleus, could account for such strong repulsion. The negative electrons that balanced electrically the positive nuclear charge were regarded as traveling in circular orbits about the nucleus. The electrostatic force of attraction between electrons and nucleus was likened to the gravitational force of attraction between the revolving planets and the Sun. Most of this planetary atom was open space and offered no resistance to the passage of the alpha particles.
some one please presize this
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The Rutherford experiment was used to prove the existence of a positively charged nucleus containing the protons.
What is the Rutherford experiment?The Rutherford experiment was used to prove the existence of a positively charged nucleus..
Alpha particles passed mostly undeflected through a aluminum foil.
The part of the foil where the alpha particles were deflected was the positively charged nucleus where most of the mass of the atom was concentrated.
In conclusion, the Rutherford experiment proved the existence of a positively charged nucleus.
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Which of the following is represented by the number of significant figures in a quantity? A) estimation B) precision C) accuracy D) scientific notation
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Answer: the answer is B estimation
Explanation:
i just took a test
The one that is represented by the number of significant figures in a quantity is scientific notation. The correct option is D.
What is scientific notation?Scientific notation is a method of expressing numbers that are either too large or too small to be written in decimal form.
In the United Kingdom, it is known as scientific form, standard index form, or standard form.
The proper scientific notation format is an x 10b, where an is a number or decimal number with an absolute value greater than or equal to one and less than ten, or 1 |a| 10. b is the power of ten required for scientific notation to be mathematically equivalent to the original number.
Scientific notation is represented by the number of significant figures in a number.
Thus, the correct option is D.
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How does chemistry affect sports?
A. Athletes can work out on machines to increase their muscle mass.
B. Data can be collected by à computer to determine a particular
player's strengths.
C. Safety equipment is made of synthetic materials that are
lightweight yet strong.
D. The path of a ball can be predicted using the laws of motion.
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Answer:
c
Explanation: