To solve the given problem, we can use the principle of conservation of energy, which states that the total energy of an isolated system remains constant.
A) To find the mass of the water, we can use the equation:
m1 * c1 * ΔT1 = m2 * c2 * ΔT2
where m1 and m2 represent the masses of the water and soup, c1 and c2 are the specific heats, and ΔT1 and ΔT2 are the temperature changes.
Plugging in the given values:
(0.20 kg) * (4180 J/kg⋅∘C) * (34∘C - 20∘C) = m2 * (3800 J/kg⋅∘C) * (34∘C - 40∘C)
Solving for m2, the mass of the water:
m2 ≈ 0.065 kg
B) The change in thermal energy of the water can be calculated using the formula:
ΔQ = m2 * c2 * ΔT2
ΔQ = (0.065 kg) * (4180 J/kg⋅∘C) * (34∘C - 40∘C) ≈ -1611 J
C) The change in thermal energy of the soup can be determined using the equation:
ΔQ = m1 * c1 * ΔT1
ΔQ = (0.20 kg) * (3800 J/kg⋅∘C) * (34∘C - 20∘C) ≈ 1296 J
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1. Which of the following best describes social
dances?
Answer:
this are dances formed mainly in communities.
Explanation:
they are done naming of children,worshipping or during initiation ceremonies
emmy the trapeze artist flies through the air with her arms and legs stretched out, tumbling head over heels. as she rotates, she pulls her
Emmy, the trapeze artist, performs an impressive aerial act, demonstrating both skill and agility. As she flies through the air, her arms and legs are outstretched, providing stability and balance during her flight.
In the midst of her performance, she begins tumbling head over heels, a maneuver that showcases her exceptional athleticism and control. As she rotates, she pulls her limbs in closer to her body, reducing her moment of inertia.
This action allows her to increase her rotational speed, following the principle of conservation of angular momentum. Through these movements, Emmy captivates her audience with a thrilling and visually stunning display of acrobatics.
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a sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?
Answer:
887.1Hz
Explanation:
Given parameters:
Speed of sound wave = 330m/s
Wavelength = 0.372m
Unknown:
Frequency = ?
Solution:
To solve this problem, we use the expression below:
Speed = Frequency x wavelength
330 = Frequency x 0.372
Frequency = 887.1Hz
The angular size of Venus has a maximum value of 55" during "inferior conjunction," when it is 0.3AU from Earth (Venus is 0.7AU from Sun). It’s orbital eccentricity is 0.007
Calculate the Diameter (physical size) of Venus.
The diameter of Venus can be calculated using the angular size at inferior conjunction and its orbital parameters. With an angular size of 55" and a distance of 0.3 AU from Earth, the physical size of Venus can be determined.
The angular size of an object is the angle it subtends at the observer's location. In this case, the maximum angular size of Venus is given as 55" (arcseconds) during inferior conjunction. Inferior conjunction occurs when Venus is positioned between Earth and the Sun, and its distance from Earth is 0.3 AU (astronomical units). Venus is also stated to be 0.7 AU from the Sun.
To calculate the physical size of Venus, we can use the small-angle formula, which relates the angular size, distance, and physical size of an object. The formula is given by:
Angular size (in radians) = Physical size / Distance
Since the angular size is usually measured in arcseconds, it needs to be converted to radians. One radian is equal to 206,265 arcseconds.
Converting the given angular size of 55" to radians:
Angular size (in radians) = 55" / 206,265 ≈ 0.000266 radians
Using the small-angle formula, we can rearrange it to solve for the physical size:
Physical size = Distance × Angular size
Substituting the values, where the distance is 0.3 AU:
Physical size = 0.3 AU × 0.000266 radians ≈ 0.00008 AU
Finally, to convert the physical size from astronomical units to kilometers, we can use the conversion factor of 1 AU = 149.6 million kilometers:
Physical size = 0.00008 AU × 149.6 million kilometers/AU ≈ 12,000 kilometers
Therefore, the diameter (physical size) of Venus is estimated to be approximately 12,000 kilometers.
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A velocity vs. time graph for an object is shown.
A graph titled Velocity versus Time shows time in seconds on the x axis, numbered 0 to 5, Velocity in meters per second on the y axis, numbered 0 to 25. A line labeled W starts at the origin and ends at (1, 15). A line labeled X starts at (1, 15) and ends at (2, 20). A line labeled Y starts at (2, 20) and ends at (4, 20). A line labeled Z starts at (4, 20) and ends at (5, 0).
Which parts of the graph represents the object moving at a constant, positive acceleration?
A. W and X
B. X and Y
C. Y and Z
D. W and Z
(please help im so tired)
Answer:
im pretty sure its A, W and X. W and X are the only lines that are moving in a constant positive direction.
Explanation:
Answer:
A- W and X
Explanation:
I got it right on the quiz
Michael Eisner took over the stagnant Walt Disney firm in the early 1990's and turned things around in dramatic fashion. However, once stability was needed, Eisner was unable to change his approach to Group of answer choices transformational leadership. charismatic leadership. path-goal leadership. transactional leadership. strategic leadership.
Michael Eisner was unable to change his approach to strategic leadership.
While Michael Eisner successfully revitalized the Walt Disney firm through his transformative and charismatic leadership in the early 1990s, his challenges arose when stability was required. Strategic leadership involves the ability to formulate and execute long-term strategies to achieve organizational goals. It requires adapting and adjusting leadership approaches based on the evolving needs and circumstances of the organization.
In Eisner's case, it seems that he struggled to shift his leadership style to one that was more focused on sustaining the company's success and navigating ongoing challenges. This could be attributed to a failure to effectively align the organization's strategic direction, make necessary changes, and respond to emerging industry trends and competitive pressures.
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a) find the vector electric field that the q = 9.00 nc and -3.00 nc charges together create at the origin.
To find the vector electric field that the q = 9.00 nC and -3.00 nC charges together create at the origin, we can use Coulomb's law and the principle of superposition.
First, we calculate the electric field vector created by the q = 9.00 nC charge alone at the origin. Using Coulomb's law, we have:
E1 = (k*q1)/r^2
where k is the Coulomb constant, q1 is the charge of the first object (in this case, 9.00 nC), and r is the distance from the charge to the origin (which is 0 in this case). Plugging in the values, we get:
E1 = (9*10^9 N*m^2/C^2)*(9*10^-9 C)/(0^2) = infinity
This result indicates that the electric field at the origin due to the q = 9.00 nC charge alone is infinite, which is not physically meaningful. However, we can still use this value in combination with the second charge to find the net electric field.
Next, we calculate the electric field vector created by the -3.00 nC charge alone at the origin. Using Coulomb's law again, we have:
E2 = (k*q2)/r^2
where q2 is the charge of the second object (in this case, -3.00 nC). Plugging in the values, we get:
E2 = (9*10^9 N*m^2/C^2)*(-3*10^-9 C)/(0^2) = -infinity
Similarly, this result indicates that the electric field at the origin due to the -3.00 nC charge alone is also infinite.
However, when we combine the two charges, we can use the principle of superposition to find the net electric field vector at the origin. The principle of superposition states that the net electric field at any point due to a group of point charges is the vector sum of the electric fields due to each individual charge.
In this case, since the two charges are at the same location (the origin), we can simply add their electric fields as vectors:
Enet = E1 + E2
Since both E1 and E2 are infinite and have opposite signs, the net electric field at the origin is undefined. This means that the electric field at the origin due to these two charges together cannot be calculated using Coulomb's law alone.
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Find the work done in lifting the bucket
A 7 lb bucket attached to a rope is lifted from the ground into the air by pulling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work is done lifting the bucket and rope?
Assuming the force required to lift the rope is equal to its weight, find the force function, F(x), that acts on the rope when the bucket is at a height of x ft.
F(x)=
The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
To find the work done in lifting the bucket and rope, we need to consider two parts:
Part 1: Work done lifting the bucket (without the rope) 24 ft:
The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.
Given:
Weight of the bucket = 7 lb
Distance lifted = 24 ft
Work done lifting the bucket = Weight of the bucket x Distance lifted
Work done lifting the bucket = 7 lb x 24 ft
Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).
Part 2: Work done lifting the rope:
Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.
Given:
Weight of the rope = 0.8 lb
Distance lifted = 24 ft
Work done lifting the rope = Weight of the rope x Distance lifted
Work done lifting the rope = 0.8 lb x 24 ft
Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:
Total work done = Work done lifting the bucket + Work done lifting the rope
Please note that the units of work are in foot-pounds (ft-lb).
Now, we can calculate the values:
Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb
Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb
Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb
Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
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The complete question is:
Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.
Three pairs of balls are connected by very light rods as shown inthe figure. Rank in order, from smallest to largest, the moments ofinertia I1,I2 ,and I3 about axes through the centers of therods
The moments of inertia are ranked as follows, from smallest to largest: I1 < I2 (for both pairs of balls connected by the long rods) < I3 (for both pairs of balls connected by the middle rod).
To rank the moments of inertia of the three pairs of balls, we need to consider the distribution of mass around the axes passing through the centers of the rods.
For I1, we can consider the pair of balls at the ends of the rod to be point masses, with all of their mass located at their centers. The moment of inertia of this pair of balls about the axis through the center of the rod can be calculated as \(I1 = 2mr^2\), where m is the mass of each ball and r is the distance from the axis to the center of each ball.
Since the masses are equal and the distance from the axis to the center of each ball is the same, I1 is the same for both pairs of balls connected by the rod.
For I2, we need to consider the distribution of mass along the rod. Since the rod is very light, we can assume that all of the mass is located at the center of the rod. The moment of inertia of the rod about the axis passing through its center is \(I2 = (1/12)ML^2\), where M is the mass of the rod and L is its length.
Since the masses and lengths of the two rods are the same, I2 is the same for both pairs of balls connected by the rods.
For I3, we need to consider the distribution of mass around the axis passing through the center of the rod that connects the two pairs of balls.
Since the masses of the balls are not located at a fixed distance from this axis, we need to use the parallel axis theorem to calculate I3.
The parallel axis theorem states that the moment of inertia of an object about any axis parallel to its center of mass axis is given by\(I3 = Icm + Md^2,\) where Icm is the moment of inertia of the object about its center of mass axis, M is the mass of the object, and d is the distance between the two axes.
For each pair of balls, the moment of inertia about the axis passing through its center of mass axis can be calculated as\(Icm = 2mr^{2}/5,}\)where r is the distance between the two balls.
The distance between the two axes is the length of the rod connecting the two pairs of balls, which is the same for both pairs. Therefore, I3 is the same for both pairs of balls connected by the rod.
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parfit thinks that claiming god as being the cause of the big bang is:
Parfit, a prominent philosopher, argues that claiming God as the cause of the Big Bang is problematic. He suggests that using God as an explanation for the origin of the universe is not satisfying, as it merely replaces one mystery with another.
Additionally, Parfit asserts that invoking God as the cause of the Big Bang raises questions about the nature of God. Furthermore, Parfit asserts that science provides a more plausible explanation for the origin of the universe. Scientists have proposed various theories, such as the inflationary model and the cyclic model, that attempt to explain the origins of the universe without the need for a divine creator.
In conclusion, Parfit does not find the argument that God caused the Big Bang to be convincing, as it raises more questions than it answers. Instead, he advocates for relying on scientific theories to explain the origins of the universe.
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If a ball is thrown straight up into the air with an initial velocity of $60{ft} /{s}$, its height in feet after $t$ second is given by $y=60 t-16 t^2$. Find the average velocity (include units, help (units)) for the time period begining when $t=2$ seconds and lasting
(i) 0.5 seconds
Avenge velocity:
(ii) 0.1 seconds
Average velocity:
(iii) 0.01 seconds
Average velocity:
Finally based on the above results, guess what the instantaneous velocity of the ball is when $t=2$. Average velociry:
The instantaneous velocity of the ball is when $t=2$ is 32 ft/s so the average velocity: 32 ft/s.
The given function is $y=60t-16t^2$. We need to find the average velocity of the ball for the time period beginning when $t=2$ seconds and lasting. The average velocity is calculated by dividing the distance travelled by the time taken. The average velocity for the time period beginning when $t=2$ seconds and lasting 0.5 seconds is calculated as follows:
Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Here, $y_2$ is the value of the function when $t=2.5$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.5)-16(2.5)^2=45$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.5$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{45-32}{0.5}]$Average velocity = $[\frac{13}{0.5}]$Average velocity = $26$ ft/sNow, for the time period beginning when $t=2$ seconds and lasting(ii) 0.1 seconds. Here, $y_2$ is the value of the function when $t=2.1$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.1)-16(2.1)^2=31.84$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.1$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.84-32}{0.1}]$Average velocity = $[-1.6]$ ft/s(iii) 0.01 seconds. Here, $y_2$ is the value of the function when $t=2.01$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.01)-16(2.01)^2=31.9364$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.01$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.9364-32}{0.01}]$Average velocity = $[-6.36]$ ft/s
Finally based on the above results, we can guess that the instantaneous velocity of the ball is when $t=2$ is 32 ft/s. hence, Average velocity: 32 ft/s.
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Which of the following feedbacks are definitely positive (that is, there is no uncertainty that they are positive)? [select all that apply] Laspe rate feedback Water vapor feedback Ice albedo feedback Cloud feedback Question 4 1 pts Which of these feedbacks affect the terrestrial radiation budget? [select all that apply] Lapse rate feedback Ice-albedo feedback Water vapor feedback Cloud feedback
The positive feedbacks without uncertainty are water vapor feedback. The feedbacks that affect the terrestrial radiation budget are lapse rate feedback, ice-albedo feedback, water vapor feedback, and cloud feedback.
Among the feedbacks listed, the ones that are definitely positive (without uncertainty) are: 1. Water vapor feedback: An increase in temperature leads to an increase in atmospheric water vapor content, which amplifies the greenhouse effect and further enhances warming. This feedback is positive. The feedbacks that affect the terrestrial radiation budget (the balance of incoming and outgoing radiation at the Earth's surface) are: 1. Lapse rate feedback: This feedback is related to the vertical temperature profile of the atmosphere. If the lapse rate (the rate at which temperature changes with altitude) decreases with warming, it can amplify the warming or cooling effects. It affects the radiation budget indirectly by influencing the atmospheric temperature structure. 2. Ice-albedo feedback: When temperatures rise, ice and snow cover decrease, exposing darker surfaces (such as land or ocean) that absorb more solar radiation. This leads to further warming, creating a positive feedback loop that affects the radiation budget. 3. Water vapor feedback: As mentioned earlier, an increase in temperature leads to increased atmospheric water vapor content. Water vapor is a potent greenhouse gas that affects the radiation budget by trapping outgoing longwave radiation and amplifying the greenhouse effect.b4. Cloud feedback: Changes in temperature and atmospheric moisture content can affect cloud formation and properties. Clouds can either trap heat (positive feedback) or reflect sunlight back to space (negative feedback), depending on their type, altitude, and coverage. The net effect of cloud feedback on the terrestrial radiation budget depends on the specific cloud changes in response to warming.
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Which letter explains why no machine is 100 percent efficient.
A.Mechanical energy is transformed into thermal energy by friction.
B.Mechanical energy is transformed into electrical energy by a spark.
C.Thermal energy is transformed into mechanical energy by friction.
Answer:
A
Explanation:
Think about rubbing your hands together- the friciton produces heat
Ignoring the sign, which has a greater magnitude of charge?.
Answer:
the car
Explanation:
Scalar and Vector Quantities are both measurements
-True
-False
Answer:
Explanation:
Scalar is the measurement of a unit strictly in magnitude. Vector is a measurement that refers to both the magnitude of the unit and the direction of the movement the unit has taken. In other words, scalar quantity has magnitude, such as size or length, but no particular direction. When it does have a particular direction, it's a vector quantity.
At noon a female corpse was found partially submerged
what is rusting?How does it occur?
Answer:
Rust occurs when iron or its alloys, such as steel, corrode. The surface of a piece of iron will corrode first in the presence of oxygen and water.The process of rusting is a combustion reaction, similar to fire. Left in contact with oxygen, iron will react with the oxygen to form rust.
Hope this helps!!
Answer:
iron is oxidation reaction
Explanation:
it occurs when iron reacts with water and oxygen to form hydrated iron(iii) oxide
How do forces help shape the earth? (please help quickly)
Answer:
Explanation: The Earth's surface is constantly changing through forces in nature. The daily processes of precipitation, wind and land movement result in changes to landforms over a long period of time. Driving forces include erosion, volcanoes and earthquakes. People also contribute to changes in the appearance of land.
A projectile is launched at an angle of 45 degrees with a velocity of 250 m/s. If air resistance is neglected, the magnitude of the horizontal velocity of the projectile at the time it reaches maximum altitude is equal to
Answer:
The horizontal velocity of the projectile at the time it reaches maximum altitude approximately equal to 131.331 meters per second.
Explanation:
From Mechanical Physics we understand that projectile motion is the combination of a horizontal motion at constant velocity and a vertical uniform accelerated motion due to gravity. Then, the horizontal velocity of the projectile (\(v_{x}\)), measured in meters per second, remains constant during motion. That is:
\(v_{x} = v_{o}\cdot \cos \theta\) (Eq. 1)
Where:
\(v_{o}\) - Initial velocity of the projectile, measured in meters per second.
\(\theta\) - Launch angle above the horizontal, measured in sexagesimal degrees.
If we know that \(v_{o} = 250\,\frac{m}{s}\) and \(\theta = 45^{\circ}\), then horizontal velocity of the projectile at the time it reaches maximum altitude is:
\(v_{x} = \left(250\,\frac{m}{s} \right)\cdot \cos 45^{\circ}\)
\(v_{x} \approx 131.331\,\frac{m}{s}\)
The horizontal velocity of the projectile at the time it reaches maximum altitude approximately equal to 131.331 meters per second.
If you running a mile for time, which is the best method to maximize your outcome in completing your jog in a good time?
The maximize your outcome when running a mile for time, there are several methods that you can use. The first is to establish a good pace from the beginning. You don't want to start off too fast and burn out before the end, but you also don't want to start too slow and waste precious seconds trying to catch up.
The best to find a pace that feels challenging but sustainable and stick with it throughout the mile. Another method is to focus on your form. This means keeping your shoulders relaxed, your arms at your sides, and your strides short and quick. Good form not only helps you move more efficiently, but it can also prevent injury and fatigue. Breathing is also important when running a mile for time. You want to take deep breaths in through your nose and exhale through your mouth. It's also helpful to focus on your breathing and try to match it with your stride pattern. Finally, mental preparation can be key to maximizing your outcome when running a mile for time. This means visualizing yourself completing the mile in a good time, staying focused, and pushing through any discomfort or fatigue. With these methods, you can set yourself up for success and achieve your best possible time when running a mile.
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Only about 50% of the solar energy directed toward Earth penetrates directly to the surface. Explain what happens to the rest of the radiation.
Answer:
it is absorbed or reflected by the atmosphere
Explanation:
In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere
So as per the given situation the above represent the answer
hence, the same is to be considered and relevant
1. There is a group of kids playing tee ball in front of your house. If the bat is 5kg traveling with a velocity
of 8m/s, with what velocity will the 1.5 kg ball travel after it is hit by the bat?
Answer: tug vi
Explanation:
Because
Why Does Elasticity Matter?
Often, a lot of what is covered in courses has little application in the so-called "real world". In this discussion board, you need to post an entry to the discussion board stating why elasticity actually does matter in the everyday lives of businesses and consumers, using an example of a good or service as part of your explanation.
Part I
Using an example of a good or service, you will state why elasticity is applicable in the everyday lives of businesses and consumers. Please be clear in your explanation
Elasticity is of significant importance in the everyday lives of businesses and consumers as it helps them understand and respond to changes in prices and demand for goods or services. By considering elasticity, businesses can make informed decisions regarding pricing strategies, production levels, and resource allocation. Consumers, on the other hand, can assess the impact of price changes on their purchasing decisions and adjust their consumption patterns accordingly.
Elasticity, specifically price elasticity of demand, measures the responsiveness of consumer demand to changes in price. It indicates the percentage change in quantity demanded resulting from a one percent change in price. Understanding price elasticity allows businesses to determine how sensitive consumers are to changes in price and adjust their pricing strategies accordingly.
For example, let's consider the market for gasoline. Gasoline is a highly price-sensitive good, meaning that changes in its price have a significant impact on consumer demand. If the price of gasoline increases, consumers may reduce their consumption and seek alternatives such as carpooling or using public transportation. In this scenario, businesses need to consider the price elasticity of gasoline to predict and respond to changes in consumer behavior. They might lower prices to stimulate demand or introduce more fuel-efficient options to cater to price-conscious consumers.
In conclusion, elasticity matters because it provides valuable insights into the dynamics of supply and demand, enabling businesses and consumers to make informed decisions in response to price changes. By understanding elasticity, businesses can adapt their strategies to maintain competitiveness, while consumers can optimize their purchasing choices based on price sensitivity.
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an athlete runs with velocity 13 km/h for 4 minutes, 14 km/h for the next 2 minutes, and 18 km/h for other 6 minutes. compute the total distance traveled.
The athlete traveled a total distance of 3.134 km during the given time period.
To compute the total distance traveled by the athlete, we need to first convert the velocities from km/h to km/min (since the times given are in minutes).
13 km/h = 13/60 km/min = 0.217 km/min
14 km/h = 14/60 km/min = 0.233 km/min
18 km/h = 18/60 km/min = 0.3 km/min
Next, we can calculate the distance traveled during each segment of the run:
Distance traveled at 0.217 km/min for 4 minutes = 0.217 km/min x 4 min = 0.868 km
Distance traveled at 0.233 km/min for 2 minutes = 0.233 km/min x 2 min = 0.466 km
Distance traveled at 0.3 km/min for 6 minutes = 0.3 km/min x 6 min = 1.8 km
Finally, we can add up the distances traveled during each segment to get the total distance traveled:
Total distance traveled = 0.868 km + 0.466 km + 1.8 km = 3.134 km
Therefore, the athlete traveled a total distance of 3.134 km during the given time period.
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A car accelerates if it:
Speeds up
Slows down
Goes around a curve
Both A and B
A, B, and C
Answer:
A because when you accelerate you move even faster
Which animals are cold-blooded, obtain dissolved oxygen in water through gills, have scales, have fins, and live in water
Answer:
Sea fish
Explanation:
Sea fish doesn't breath through their gills but dissolved oxygen in water through gills
In a copper wire, the particles that actually move and carry the electrical energy are_____.
In a copper wire, the particles that actually move and carry the electrical energy are electrons.
Electrons are negatively charged particles that are found in the outer shells of atoms. In a copper wire, the electrons are loosely bound to their atoms, allowing them to move freely.
When a voltage is applied across the wire, an electric field is created, which causes the electrons to flow in a particular direction.
This flow of electrons is called an electric current. It's important to note that while the electrons move through the wire, the atoms themselves do not move significantly. Instead, they vibrate in place.
This is why a copper wire can conduct electricity efficiently. The flow of electrons in a wire allows electrical energy to be transported from one place to another, enabling the operation of various electrical devices.
In conclusion, in a copper wire, electrons are the particles that actually move and carry the electrical energy.
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a ball dropped from rest falls freely intil it hits the ground with the speed of 20 m/s . the tine furing which the ball is in free fall is approximately
Answer:
5m/s
Explanation:
the moon orbits our earth. the opposite would never be true: the earth would never orbit the moon. one reason is due to the force of gravity. the object _________ has a greater gravitaional force and that determines what satelites orbit around it.
Answer: The moon keeps the same face pointing towards the Earth because its rate of spin is tidally locked so that it is synchronized with its rate of revolution (the time needed to complete one orbit). In other words, the moon rotates exactly once every time it circles the Earth.
5.How can we determine if an object is charged or not?
Answer:
through the use of a Gold leaf electroscope