a car accelerates from rest to 30 km/h. later, on a highway it accelerates from 30 km/h to 60 km/h. 0 to 30 km/h. 30 to 60 km/h. Both are the same.
Answers
Since KE = ¹/₂ mv², it need more energy to accelerate from 30 km/h to 60 km/h. The relationship between energy and speed may be seen in the equation. So, the energy will increase as the car's speed does.
What do you mean by acceleration?Acceleration refers to the rate with which a moving organism's speed and direction shift over time. When a point or object speeds or decelerates, it is moving straight forward. Motion on a circle speeds even if the speed remains constant because the direction is always changing.
Which objects will accelerate?According to Newton, something will only move forward in the face of an imbalanced or net force. If there is an uneven force, the item will accelerate, changing its direction, speed, or both.
To know more about Acceleration visit:
https://brainly.com/question/12550364
#SPJ4
Related Questions
Calculate the total displacement of a mouse walking along a ruler, if it begins at the location x = 5 m, and then does the following:
- It walks to x = 12 m
- It then walks a displacement of -8 m (NOT the same as x = -8 m)
- Lastly, it walks to the location x = 7 m
Answers
Answer:
18
Explanation:
12 - 5 + 8 = 15
12 - 8 = 4
7 - 4 = 3
15 + 3 = 18
Mars has two moons. What does the orbital speed of these moons depend on?
Answers
Answer:
their masses and their distances from Mars
Explanation:
Hope this helped
Also can u pls mark me brainliest
6. What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s??
Answers
According to the Newton's second law,
\(F=ma\)where F is the force on the object, m is the mass of the obect and a is the acceleration of the object.
Substituting the known values,
\(30=m\times5\)Thus, the mass of the object is,
\(\begin{gathered} m=\frac{30}{5} \\ m=6\text{ kg} \end{gathered}\)Hence, the mass of the object is 6 kg.
PLEASE HELPPP
Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west
Answers
One way to do this is to draw a diagram of the vectors and use the head-to-tail method to find the resultant vector. We can start by drawing the vector 50N north, then draw the vector 50N west starting from the end of the first vector, and finally draw the vector 50N northwest starting from the end of the second vector and ending at the tip of the resultant vector. The resultant vector is the vector that starts at the beginning of the first vector and ends at the tip of the last vector.
Alternatively, we can use trigonometry to find the magnitude and direction of the resultant vector. We can break down each vector into its x and y components, then add up the x components and the y components separately to get the x and y components of the resultant vector. The magnitude of the resultant vector is then given by the square root of the sum of the squares of the x and y components, and the direction is given by the arctangent of the y component divided by the x component.
Using either method, we can find that the magnitude of the resultant force is approximately 70.7N, and the direction is approximately 45 degrees north of west
Bryce has selected a major in political science but has a little interest in understanding public relations
Answers
Hi, you've asked an incomplete question. However, I assumed you want additional comments about this scenario.
Explanation:
Note, the term Major as used in academic contexts refers to a person's preferred interest or specialization at college or university.
Hence, the statement about Bryce appears to be contradictory, since we are told he "has little interest in understanding public relations".
1. Oh no! Your car breaks down on the highway, and you have to push the car to the side of the road. If your car is 400 kg and you push
with a force of 200 N, what is the car's acceleration?
O 2 m/s2
O 8.0 x 104 m/s2
O 0.5 m/s2
Oom/?
Answers
a 7,500kg railroad care is traveling at 4m/s when it strikes another 11,000kg railroad car that is at rest. if the cars lock together, what is the final speed of the two railroad cars?
Answers
The final speed of the two railroad cars is 1.62 m/s.
This problem can be solved using the conservation of momentum principle, which states that the total momentum of a closed system remains constant if no external forces act on it.
The initial momentum of the system is:
p_initial = m₁v₁ + m₂v₂, where
m₁ = 7,500 kg (mass of the first car)
v₁ = 4 m/s (velocity of the first car)
m₂ = 11,000 kg (mass of the second car, at rest)
v₂ = 0 m/s (velocity of the second car)
p_initial = (7,500 kg)(4 m/s) + (11,000 kg)(0 m/s)
= 30,000 kg×m/s
After the collision, the two cars lock together, so they become a single object with a total mass of:
M = m₁ + m₂ = 7,500 kg + 11,000 kg = 18,500 kg
Let's assume that the final velocity of the combined cars is v. According to the conservation of momentum principle:
p_final = M×v
Since no external forces act on the system, the initial momentum and the final momentum are equal:
p_initial = p_final
30,000 kgm/s = 18,500 kgv
v = 30,000 kg×m/s / 18,500 kg
= 1.62 m/s
To know more about speed here
https://brainly.com/question/17661499
#SPJ4
The dimensions of wellness do not influence each other. T or F
Answers
Answer: The dimensions of wellness do not influence each other.
Explanation: The answer is true.
False im sure. correct me if im wrong.
The velocity of an object is it’s speed and __ of motion .
Answers
Answer:
direction should be the answer
True or False: Radio waves are the longest and have the least energy of any wave.
Answers
Answer:
t
Explanation:
Answer:
imma say tru but i might be wrong
Complete each of the following sentences about the early universe. Drag words from the left to complete the sentences on the right.
-Most of the helium in the universe formed during the ERA OF NUCLEOSYNTHESIS.
-The GUT ERA refers to a time period in which the strong, weak, and electromagnetic forces were all unified.
-The PLANCK ERA refers to a time period in which all four forces are thought to have been unified.
-The COSMIC MICROWAVE BACKGROUND is our name for the photons we see that were first released when the universe was about 380,000 years old.
-The BIG BANG is the name we give to the moment when the expansion of the universe began.
-A very short period of extremely rapid expansion, called INFLATION, is thought to have occurred when the universe was about 10^-38 second old.
Answers
Note that the above prompt is related to the creation of the Cosmos and the Big Bang Theory.
1) It is true to state that Most of the helium in the universe formed during the ERA OF NUCLEOSYNTHESIS.
2) It is true to state that The GUT ERA refers to a time period in which the strong, weak, and electromagnetic forces were all unified. The only force that is distinct in this era is gravity. GUT stands for Grand Unified Theories.
3) It is true to state that in The PLANCK ERA it is the period when all four forces are thought to have been unified.
4) It if factually correct to state that the COSMIC MICROWAVE BACKGROUND is our expression for the photons we see that was first released when the universe was about 380,000 years old. Traces of the "seeds" that eventually created the stars and galaxies we see today are engraved on it.
5) It is correct to state that The BIG BANG is the name we give to the moment when the expansion of the universe began.
6) It is also right to state that a very short period of extremely rapid expansion, called INFLATION, is thought to have occurred when the universe was about 10⁻³⁸ seconds old. Although some scholars indicate that period was 10⁻³⁶ seconds.
What is the Big Bang Theory?The Big Bang hypothesis is a physics theory that describes how the cosmos grew from a high density and temperature condition. Several Big Bang cosmological theories explain the history of the visible universe from its earliest known eras to its eventual large-scale shape.
Two significant scientific discoveries provide credence to the Big Bang idea.
Hubble's finding of a link between a galaxy's distance from Earth and its speed in the 1920s; andthe discovery of cosmic microwave background radiation in the 1960s.Learn more about the Cosmic Microwave Background:
https://brainly.com/question/28197648
#SPJ1
Using the conductor sizing guide, what conductor ampacity is needed for a 10-horsepower, 230-volt, single-phase motor: a.50 A
b.60 A
c.62.5 A
d.87.5 A
Answers
The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.
The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.
Learn more about conductor here:
https://brainly.com/question/28582532
#SPJ4
_ method is used to remove soluble impurities.
Answers
\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)
Actually Welcome to the Concept of the Methods of Separation.
Evaporation and Decantation are the process which can be easily used to remove the Soluble Impurities.
Answer:
To remove soluble impurities, first, by doing solubility tests, a suitable solvent is chosen (high solubility in hot solvent, low solubility in cold solvent). The soluble impurities are then removed as follows: the desired compound along with the soluble impurities are dissolved in a MINIMUM of near-BOILING solvent.
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
Answers
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
To know more about global warming :
brainly.com/question/29625243
#SPJ11
PLS HELP ME
How does one stage in a stars life lead to another
Answers
a wire 72.1 cm long carries a 0.500 a current in the positive direction of an x axis through a magnetic field with an x component of zero, a y component of 0.000340 t, and a z component of 0.00770 t. Find the (a) x, (b) y, and (c) z components of the magnetic force on the wire.
Answers
To find the components of the magnetic force on the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field vector.
Given:
I = 0.500 A (current)
L = 72.1 cm (length of the wire)
B = (0, 0.000340 T, 0.00770 T) (magnetic field)
(a) x-component of the magnetic force:
To calculate the x-component, we need to take the dot product of the length vector and the magnetic field vector:
L x B = (L_y * B_z - L_z * B_y, L_z * B_x - L_x * B_z, L_x * B_y - L_y * B_x).
L = (L_x, L_y, L_z) = (72.1 cm, 0, 0).
Substituting the given values, we have:
L x B = (0 * 0.00770 - 0 * 0.000340, 0 * 0 - 72.1 * 0.00770, 72.1 * 0.000340 - 0 * 0.00770).
L x B = (0, -0.55457, 0.0245).
Now, calculating the x-component of the force:
F_x = I * (L x B)_x = 0.500 * 0 = 0.
Therefore, the x-component of the magnetic force on the wire is 0.
(b) y-component of the magnetic force:
Similarly, we calculate the y-component of the magnetic force:
F_y = I * (L x B)_y = 0.500 * (-0.55457) = -0.277285 N.
Therefore, the y-component of the magnetic force on the wire is approximately -0.277285 N.
(c) z-component of the magnetic force:
Lastly, we calculate the z-component of the magnetic force:
F_z = I * (L x B)_z = 0.500 * 0.0245 = 0.01225 N.
Therefore, the z-component of the magnetic force on the wire is 0.01225 N.
In summary, the components of the magnetic force on the wire are:
(a) x-component: 0
(b) y-component: approximately -0.277285 N
(c) z-component: 0.01225 N
To know more about refer here
https://brainly.com/question/30532541#
#SPJ11
Question:
A car travels the same distance at constant speed around two curves, one with twice the radius of curvature of the other. For which of these curves is the change of the velocity of the car greater? Explain.
Turning of the Road:
When the car turns or travels along a circular curve, then it experiences a centripetal force. Therefore the square of the speed is directly proportional to the radius of the turn.
Answers
When a car travels around two curves, one with twice the radius of curvature of the other, the change of velocity of the car is greater in the curve with the smaller radius of curvature. This is because the square of the speed is directly proportional to the radius of the turn, and the centripetal force required to keep the car moving in a circle is greater in the curve with the smaller radius of curvature.
As the radius of the circle decreases, the centripetal force required to keep the car moving in a circle increases. Since the car is traveling the same distance at a constant speed around both curves, the velocity must change in the curve with the smaller radius of curvature in order to maintain the necessary centripetal force.
Therefore, the change of velocity of the car is greater in the curve with the smaller radius of curvature.
Learn more about centripetal force:
https://brainly.com/question/898360
#SPJ11
Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?
a
2. 970E4 N
b
1. 535E4 N
c
1. 934E4 N
d
4. 550E4 N
e
4. 295E4 N
f
3. 400E4 N
g
3. 821E4 N
h
2. 482E4 N
Answers
The required magnitude of the force that stopped Melissa's car is 118608.7 N.
What are 1st 2nd and 3rd laws of motion?According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
According to question:An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
Given,
speed=8.133 m/s
final velocity=0 (due to impact)
time=0.3994 seconds
distance=11.01m
Then,
S = ut + (at^2)/2
a = 2(s - ut)t^2
a = 97.3 m/s^2
So,
Force = ma
Force = 1219(97.3)
Force = 118608.7 N
To know more about acceleration visit:-
brainly.com/question/12550364
#SPJ4
Most of the mass in the Milky Way Galaxy is located:
A) in the halo (above/below the disk).
B) within the disk.
C) in the stars in the spiral arms.
D) in the gas and dust.
E) in the central bulge of the galaxy.
Answers
Sagittarius A*, also known as Sgr A*, is the name of the supermassive black hole that lurks in the centre of the Milky Way. It has a mass of around 4.3 million solar masses, which is nearly all of the mass in the galaxy's core.
Which holds the Milky Way galaxy's mass?Using new kinematic information about these stars, the researchers estimate the galaxy's mass to be between 1.2 and 1.9 trillion solar masses. This calculation greatly improves upon earlier estimations. Milky Way Mass Constraint with Hypervelocity Stars, G.
How do we determine the Milky Way's mass?Currently available calculations of the galaxy's total mass are based on the motions of globular clusters and tidal streamers of gas, both influenced.
To know more about mass visit:-
https://brainly.com/question/30337818
#SPJ4
What is the Amplitude and Wavelength of this image?
Answers
Answer:
amp = 5 and wavelength = 6
Explanation:
Highest common factor of 12r and 10
Answers
I think the number 2, not sure
The blank
is the organ responsible for cleaning a person's blood.
Answers
being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?
Answers
According to the law of constant composition, the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample.
The law of constant composition, also known as the law of definite proportions or law of definite composition, states that a particular chemical compound is composed of the same elements in the same proportions by mass, regardless of its source or method of formation. This law implies that the relative masses of the elements in a compound are fixed and constant.
When a compound undergoes decomposition, it breaks down into its constituent elements or simpler compounds. However, the relative proportions of these elements remain the same as in the original compound. This means that the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample.
For example, let's consider a compound composed of elements A and B in a fixed mass ratio of 2:1. According to the law of constant composition, any sample of this compound will have this 2:1 ratio of masses between elements A and B. If this compound decomposes, the resulting set of masses should still exhibit the 2:1 ratio of elements A and B. For instance, if the original sample had masses of 4 grams for element A and 2 grams for element B, the decomposition products should also have masses in a 2:1 ratio, such as 2 grams of element A and 1 gram of element B.
In conclusion, the law of constant composition states that the proportions of elements in a compound remain constant, both in the original compound and its decomposition products. Thus, the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample, in accordance with the law of constant composition.
Learn more about decomposition here:
brainly.com/question/14843689
#SPJ11
A U-tube uniform cross-sectional area and open to the atmosphere is partially filled with Mercury. Water then is then poured into both arms. If the equilibrium configuration of the tube is as shown in the figure with h2=1.04cm determine the value of h. There's no need to consider the weight of the of the extra air on the right-hand side
Answers
Where do gamma-ray bursts tend to come from?
Answers
Gamma-ray bursts are intense flashes of high-energy radiation that come from various sources in the universe. These bursts are short-lived, lasting only a few seconds to a few minutes, and emit more energy in that brief time than our sun will in its entire lifetime.
The majority of gamma-ray bursts come from the distant reaches of space, beyond our own Milky Way galaxy. Scientists believe that most of these bursts are caused by the collapse of massive stars, which create black holes or neutron stars. These events, known as supernovas, release huge amounts of energy in the form of gamma rays.
However, there are also other types of gamma-ray bursts that come from different sources, such as merging neutron stars or even collisions between galaxies. Some gamma-ray bursts have also been detected coming from our own Milky Way, likely caused by the explosive deaths of massive stars.
In summary, gamma-ray bursts come from a variety of sources in the universe, but the majority are caused by the collapse of massive stars into black holes or neutron stars.
Gamma-ray bursts (GRBs) tend to come from two primary sources in the universe. They are extremely energetic and short-lived bursts of gamma-ray light, the most energetic form of electromagnetic radiation.
1. Long-duration GRBs: These bursts typically last from a few seconds to several minutes and are believed to originate from the collapse of massive stars. When a massive star reaches the end of its life, its core collapses into a black hole or a neutron star. This process, known as a core-collapse supernova, releases a tremendous amount of energy in the form of gamma rays. The resulting jet of energy is called a long-duration gamma-ray burst.
2. Short-duration GRBs: These bursts usually last less than two seconds and are thought to result from the merger of two compact objects, such as neutron stars or a neutron star and a black hole. When these objects collide, they release a vast amount of energy in the form of gamma rays, producing a short-duration gamma-ray burst.
Both types of gamma-ray bursts are observed at vast distances across the universe, indicating that they come from diverse cosmic environments. These powerful events serve as important probes of the early universe and can provide valuable information about star formation, cosmic evolution, and the nature of matter under extreme conditions.
Learn more about gamma-rays at : brainly.com/question/23281551
#SPJ11
6. A wave has a frequency of 600 Hz and is traveling at 300 m/s. What is its
wavelength?
Answers
Answer:
0.5m
Explanation:
v=f×lamda
v is 300m/s, f is 600Hz, lamda is ?
lamda=v/f
lamda=300/600
lamda =3/6=1/2m
in humans what makes the sound vibration vibrate
Answers
Answer:
sound vibration of spicker
I need help with my physics homework
A carousel—a horizontal rotating platform—of radius 5 m is initially at rest, and then begins to accelerate constantly until it has reached an angular velocity of 20 rad/s after 2 complete revolutions.
A.) How many radians did the carousel rotate through?
B.) What is the tangential velocity of the carousel at a point 2 m from the center of the carousel?
C.) What is the angular acceleration of the carousel during this time?
D.) What is the tangential acceleration of the carousel at a point on the outside of the platform at this time?
Answers
A) 4π radians did the carousel rotate through.
B) v=rω, v =2*20 = 40 m/s is the tangential velocity of the carousel at a point 2 m from the center of the carousel.
C) α =ω²r = 20²× 5 = 2000 rad/s² is the angular acceleration of the carousel during this time.
D) the tangential acceleration of the carousel at a point on the outside of the platform is zero cause a(t) = r dω/dt change in angular velocity is zero after it reaches 20 rad/s.
A carousel, also known as a merry-go-round (international), roundabout (British English), or hurdy-gurdy (an archaic phrase in Australian English), is a type of amusement attraction that consists of a spinning circular platform with seats for passengers. Traditional "seats" are rows of wooden horses or other animals set on poles, many of which are moved up and down by gears to mimic galloping to the tune of looping circus music. carousel rotates with a particular velocity.
To know more about carousel :
https://brainly.com/question/27088541
#SPJ1.
The state of matter with particles that are not attracted or tightly packed
and are not arranged in a regular pattern; zoom around to easily change
shape and volume *
a.gas
b.liquid
c.solid
Answers
It's none of the above hope this helps
How does this relate to Newton's second law?
Two balls with different weights (tennis ball and basket ball) are dropped from the same height to see which one will land first
Answers
Answer:
In ideal case, when no resistive forces are present then both the balls will reach the ground simultaneously. This is because acceleration due to gravity is independent of mass of the falling object. i.e. g = GM/R² where G = 6.67×10²³ Nm²/kg², M = mass of earth and R is radius of earth.
Let us assume that both are metallic balls. In such case, we have to take into account the magnetic field of earth (which will give rise to eddy currents, and these eddy currents will be more, if surface area will be more) and viscous drag of air ( viscous drag is proportional to radius of falling ball), then bigger ball will take slightly more time than the smaller ball.
Explanation:
In ideal case, when no resistive forces are present then both the balls will reach the ground simultaneously. This is because acceleration due to gravity is independent of mass of the falling object. i.e. g = GM/R² where G = 6.67×10²³ Nm²/kg², M = mass of earth and R is radius of earth.
Let us assume that both are metallic balls. In such case, we have to take into account the magnetic field of earth (which will give rise to eddy currents, and these eddy currents will be more, if surface area will be more) and viscous drag of air ( viscous drag is proportional to radius of falling ball), then bigger ball will take slightly more time than the smaller ball.