Can someone please help, ty!

Answer:

     a = 6.1 m / s²

Explanation:

For this kinematics exercise, to solve the exercise we must set a reference system, we place it in the initial position of the fastest vehicle

Let's find the relative initial velocity of the two vehicles

          v₀ = v₀₂ - v₀₁

          v₀ = 25.4 - 13.6

          v₀ = 11.8 m / s

the fastest vehicle

          x = v₀ t + ½ a t²

The faster vehicle has an initial speed relative to the slower vehicle, therefore it is as if the slower vehicle were stopped, so the distance that must be traveled in a fast vehicle to reach this position is

          x = 11.4 m

let's use the expression

           v² = v₀² - 2 a x

how the vehicle stops v = 0

          a = v₀² / 2x

          a = \(\frac{11.8^2}{2 \ 11.4}\)

          a = 6.1 m / s²

this velocity is directed to the left

Answer:

Ans :- C

Explanation:

................

Answer:

THE ANSWER IS C.

Explanation:

Answer:

\(\frac{dI}{dt} =-3*10^-^4amps/sec\)

Explanation:

From the question we  are told that

Voltage decreases at   \(\frac{dv}{dt} =-0.03volts/sec\)

Resistance increase at \(\frac{dR}{dt}=0.02ohms /sec\)

Resistance at \(R=100ohms\)

Current at \(I=0.02amps\)

Generally the equation for ohms law is mathematically represented as

       \(V=IR\)

Therefore

       \(\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}\)

Generally making \(\frac{dI}{dt}\) subject of the formula in the above equation mathematically gives

       \(\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}\)

      \(R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}\)

       \(\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})\)

Therefore

       \(\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))\)

Generally it is given that the change in current is

       \(\frac{dI}{dt} =-3*10^-^4amps/sec\)

Answer:

F=200N

a=500m/s2​

Mass=?

Explanation:

F=ma

200=m*500

200/500=m

Mass=0.4kg

In the experiment, place a ringing alarm clock inside a vacuum chamber, and observe that when the chamber is evacuated, the sound from the alarm clock cannot be heard, illustrating that sound does not travel through a vacuum.

To illustrate that sound requires a medium for its propagation and does not travel through a vacuum, you can perform the following experiment:

Take two identical bells or sound-producing devices and place them in separate chambers, one in a vacuum chamber and the other in a chamber filled with air.

Ensure that both chambers are isolated from external noise sources.

Activate the sound-producing devices simultaneously, creating sound waves in both chambers.

Observe and listen for the sound produced in each chamber.

In the chamber filled with air, you will hear the sound clearly, as air molecules transmit the sound waves, allowing them to propagate and reach our ears.

However, in the vacuum chamber, you will not hear any sound because there is no medium (such as air) for the sound waves to travel through. Without molecules to transmit the vibrations, the sound cannot reach our ears.

This experiment demonstrates that sound requires a medium, such as air or other substances, to propagate and be perceived by our ears. In a vacuum, where there is an absence of molecules, sound cannot travel.

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Answer:

Each connection requires 50 centimeters of wire, which is equal to 0.5 meters of wire. Therefore, for eight connections, the electrician would need:

8 * 0.5 = 4 meters of wire

Therefore, the correct answer is option D, 4 m.

:

The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.

The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:

P = F/A,

where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:

P = ρgh,

where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of

41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m

Substituting these values in the formula, we get:

P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa

Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:

ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa

Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.

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Answer:

t = 0.4 seconds

Explanation:

Given that,

Mass of the object, m = 2 kg

Initial speed of the object, u = 3 m/s

Finally, it stops, v = 0

Constant force applied to the object, F = 15 N

We know that,

Force, F = ma

\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s\)

So, it will take 0.4 seconds to stop the mass.

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

The evidence that Wegener did NOT use to support his idea of continental drift is "the thickness of layers of ice in the Antarctic.

option C

Wegener's primary evidence for continental drift included the fit of the coastlines of different continents, the distribution of fossils across different continents, and the alignment of rock strata on different continents.

So the thickness of layers of ice in the Antarctic, was not used by Wegener to support his idea of continental drift. While this evidence is important for supporting the theory of glaciation, it is not relevant to the theory of continental drift.

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a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer:

short teeth, short hair, camoflauge, and speed

Explanation:

Answer:

speed and awareness

Explanation:

Answer:

record is information created, received and maintained as evidence and information by an organization or person.in simpler terms it's a collection of of fields probably of different data types.

sound is however something loud or soft.which can be defined as vibrations that travel through the air or another medium.

I hope this helps

Answer:

Question 5: The period of the waves is the time it takes for one complete up-and-down cycle of the boat.

In this case, the boat bobs up and down 10 times in 8 seconds.

Therefore, the time it takes for one up-and-down cycle is:

8 seconds ÷ 10 cycles = 0.8 seconds

So the period of the waves is 0.8 seconds.

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Question 6 : The frequency of the waves is the number of complete up-and-down cycles per unit time, typically measured in Hertz (Hz).

In this case, the boat bobs up and down 10 times in 19 seconds.

Therefore, the frequency of the waves is:

Frequency = Number of cycles ÷ Time

Frequency = 10 cycles ÷ 19 seconds

Frequency ≈ 0.526 Hz

So the frequency of the waves is approximately 0.526 Hz.

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Answer:

sound water because sound is the most important electronic wave for water

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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The acceleration due to gravity is found by determining the slope of the velocity vs. time graph.

Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s2.

Mathematically, the formula for acceleration due to gravity is given as;

g = GM/R²

Where;

Acceleration is also the change in velocity with change in time, so the acceleration due to gravity is found by determining the slope of the velocity vs. time graph.

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Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

ω = 0.05 rad/s

Explanation:

In order to produce the acceleration equal to the acceleration due to gravity at the surface of Earth, the centripetal acceleration must be equal to the value  of g:

\(a_c = g\\g = \frac{v^2}{r}\\\\but,\ v=r\omega\\therefore,\\\\g = \omega^2r\\\\\omega = \sqrt{\frac{g}{r}}\)

where,

ω = angular speed = ?

g = acceleration due to gravity on the surface of the Earth = 9.81 m/s²

r = radius of cylinder = 8 km/2 = 4 km = 4000 m

Therefore,

\(\omega = \sqrt{\frac{9.81\ m/s^2}{4000\ m}}\)

ω = 0.05 rad/s

The magnitude of the average force exerted by the floor on the ball during the collision is 215 N, and the direction is upward.

What is Potential Energy?

Potential energy is the energy that an object possesses due to its position or configuration relative to other objects, or due to the configuration of its internal components. It is a form of energy that is associated with the forces that act on an object, such as gravity, electric forces, and magnetic forces.

(a) To determine the impulse delivered to the ball by the floor, we can use the principle of conservation of energy to relate the ball's potential energy at the initial height to its potential energy at the rebound height, taking into account the loss of energy due to the collision with the floor. We can then use the impulse-momentum theorem to relate the impulse to the change in momentum of the ball during the collision.

The initial potential energy of the ball is given by:

PEi = mgh = (0.215 kg)(9.81 m/s^2)(19.5 m) = 41.6 J

At the rebound height, the potential energy is:

PEf = mgh = (0.215 kg)(9.81 m/s^2)(15.0 m) = 31.7 J

The loss of energy due to the collision is:

ΔPE = PEi - PEf = 9.9 J

This energy loss is due to both the work done by the force of gravity during the downward motion and the work done by the force of the floor during the upward motion. However, since the ball rebounds to a height that is less than its initial height, we know that the impulse delivered by the floor must be in the downward direction, opposite to the direction of the ball's motion during the collision.

Using the impulse-momentum theorem, we can write:

J = Δp = mΔv

where J is the impulse delivered by the floor, Δp is the change in momentum of the ball during the collision, and Δv is the change in velocity of the ball during the collision. Since the ball is moving downward before the collision and upward after the collision, we can write:

Δv = vf - vi = (15.0 m/s) - (-15.0 m/s) = 30.0 m/s

where vi is the initial velocity of the ball (before the collision) and vf is the final velocity of the ball (after the collision).

Thus, the impulse delivered to the ball by the floor is:

J = mΔv = (0.215 kg)(30.0 m/s) = 6.45 kg · m/s (downward)

So, the magnitude of the impulse delivered to the ball by the floor is 6.45 kg · m/s, and the direction is downward.

(b) To determine the average force exerted by the floor on the ball during the collision, we can use the definition of impulse as the product of force and time, and the fact that the ball is in contact with the floor for a known amount of time.

We know that the ball is in contact with the floor for 0.0300 seconds. Therefore, the average force exerted by the floor on the ball during the collision is:

Favg = J / Δt

where Δt is the time interval during which the impulse is delivered. In this case, Δt is equal to the contact time, which is 0.0300 seconds.

Thus, the average force exerted by the floor on the ball is:

Favg = J / Δt = (6.45 kg · m/s) / (0.0300 s) = 215 N (upward)

So, the magnitude of the average force exerted by the floor on the ball during the collision is 215 N, and the direction is upward.

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Answer:

The answer is 8829 joules

Explanation:

The equation for finding potential energy is

P.E = m*g*h

M (mass in kg)

g (gravity= 9.81)

h (height above the ground)

So

P.E = 30*9.81* 30 = 8829 joules

Answer:

0.067 births per chipmunk per year

Explanation:

I took the test

Because the mass and displacement are already given in Kg and m, respectively, in the first part of your question, there is no need to convert them. However, in the second part of your question, you must use the given equation to calculate the spring constant.

if the table data is given in grams and  cm you have to convert it using the following conversion,

1. To convert grams to kilograms, we divide the mass values by 1000.

2. To convert centimeters to meters, we divide the displacement values by 100.

But here in the given table it's already given the mass in kg and the displacement in meters (m). so no need to convert it.

Now comes the second part of your question,

To calculate the spring constants for the given data, we can use the equation:

k = -mg/Δx

where:

k is the spring constant (in N/m),

m is the mass (in kg), and

Δx is the displacement of the spring (in m).

Let's calculate the spring constants using the provided data:

Mass (kg): 0.05  0.1  0.2  0.3  0.4  0.5  0.6

Displacement of Spring (m): 0.012  0.027  0.065  0.1  0.135  0.17  0.199

Using the equation

k = -mg/Δx,

we can calculate the spring constant for each data point:

For the first data point (m = 0.05 kg, Δx = 0.012 m):

k = -0.05 kg * 9.8 m/s² / 0.012 m

k ≈ -40.833 N/m

Similarly, we can calculate the spring constants for the other data points:

For the mass of 0.05 kg, the spring constant is approximately -40.833 N/m.

For the mass of 0.1 kg, the spring constant is approximately -18.519 N/m.

For the mass of 0.2 kg, the spring constant is approximately -6.154 N/m.

For the mass of 0.3 kg, the spring constant is approximately -3.267 N/m.

For the mass of 0.4 kg, the spring constant is approximately -2.222 N/m.

For the mass of 0.5 kg, the spring constant is approximately -1.716 N/m.

For the mass of 0.6 kg, the spring constant is approximately -1.449 N/m.

Therefore, In the first part of the question, there is no need to convert the mass into kg and the displacement cm into m because it is already given in kg and m respectively, and in the second part question you have to calculate the spring constant using the given equation.

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Answer:

29

Explanation:

You can put 29 signifigant figures into a value

(hope it was helpful)

Answer: So, if the forces are in the same direction, it'll be 50N+30N= 80N!

If the forces are in opprsite direction it'll be 50N-30N= 20N (or visa-versa)

Explanation: This is because if the forces are in the same direction, like 2 people are pushing a body with 0 mass (I know, weird but imagine it) and both the people are applying the force in the same direction, let's say East, so the total fore exerted on the body will add up to become 50N+30N=80N.

And if the forces are phusing the body in oposite direction, then, let's say the bigger guy is pushing on the West Direction with 50N  of force and the weaker guy is pushing on the opposite direction with 30N of force, so this time their forces cancel out and it becomes 50N-30N= 20N (or 30N-50N= -20N).

Answer:

The water cycle shows the continuous movement of water within the Earth and atmosphere. ... Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow. Water in different phases moves through the atmosphere (transportation).

Explanation:

It's the water cycle.