Find a degree 3 polynomial whose coefficient of x³ equal to 1. The zeros of this polynomial are 1.-4i, and 4. Simplify your answer so that it has only real numbers as coefficients. Your answer is

A. FALSE

B. TRUE

(a) If f is continuous at a point x, then it is differentiable at x: False.

Explanation: A function can be continuous at a point, but it need not be differentiable at that point.

This is possible because continuity requires a function to approach the same value from both sides of the point of interest, whereas differentiability requires a function to have a well-defined tangent at that point.

(b) If f is differentiable at a point x, then it is continuous at x: True.

Explanation: A function that is differentiable at a point x must also be continuous at that point. This is because if the function has a derivative at x, the limit of the difference quotient must exist, which requires that the function be continuous at that point.

As a result, the differentiability of a function at a point is a more stringent criterion than its continuity at that point.

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Answer:

If a is positive, the parabola will open to the right, so the answer is C

Step-by-step explanation:

The EOQ for premium tires, rounded to 2 decimal places is  468.06 tires.

To determine the Economic Order Quantity (EOQ) for the premium tires,  use the EOQ formula:

EOQ = √((2 ×D × S) / H)

where:

D = Annual demand (number of premium tires required annually) = 10,000

S = Ordering cost per order = $200 (since both products are ordered together)

H = Holding cost per unit = 20% of the cost of an item = 0.20 × $90 = $18

Substituting the values into the formula:

EOQ = √((2 × 10,000 × 200) / 18)

Calculating this expression us the EOQ for the premium tires. Rounding the answer to 2 decimal places:

EOQ ≈ 468.06

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Answer:

The perimeter of triangle ΔABC is approximately;

(A) 20.0

Step-by-step explanation:

In ΔABC, the coordinates of the vertices are given as follows;

A(-4, 1), B(-2, 3), C(3, -4)

The length, 'l', of the sides of the triangle with known 'x', am]nd 'y' coordinates are given as follows;

\(l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}\)

Therefore, we have;

The length of segment \(\overline {AB}\) = √((3 - 1)² + (-2 - (-4))²) = 2·√2 ≈ 2.83

The length of segment \(\overline {BC}\) = √(((-4) - 3)² + (3 - (-2))²) = √74 ≈ 8.6

The length of segment \(\overline {AC}\) = √(((-4) - 1)² + (3 - (-4))²) = √74 ≈ 8.6

The perimeter of a geometric shape is equal to the sum of the length of sides of the figure

The perimeter of triangle ΔABC = (The length of segment \(\overline {AB}\)) + (The length of segment \(\overline {BC}\) ) + (The length of segment \(\overline {AC}\))

∴ The perimeter of triangle ΔABC = 2·√2 + √74 + √74 ≈ 20.0.

Answer: 20.0

Step-by-step explanation: Khan Academy

Answer:

0

Step-by-step explanation:

use a calculator =)

or

\(\sqrt[3]{125} = 5\\\sqrt{25} = 5\\ so , 5 - 5 = 0\)

The estimated temperature when a cricket chirps 52 times in 14 seconds is approximately 102°F.

The temperature when a cricket chirps 52 times in 14 seconds can be estimated using Dolbear's Law, which states that the temperature in degrees Fahrenheit is approximately equal to the number 50 plus the number of chirps per minute divided by 4.

To apply this formula, we first need to convert the number of chirps in 14 seconds to chirps per minute by multiplying it by 4.

52 chirps in 14 seconds x 4 = 208 chirps per minute

Then, we plug this value into Dolbear's Law:

Temperature = 50 + (208/4)

Temperature = 50 + 52

Temperature = 102°F

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there are 6 combinations but if we change the order we can get more than 6, so the last option is out

the option 2 and 3 cant be because has two reds socks and just exist 1

s, the right option is the first

Answer:

  3 -√7

Step-by-step explanation:

You want to rationalize the denominator of 2/(3 +√7).

The denominator of such an expression is turned to an integer by multiplying numerator and denominator by the conjugate of the denominator.

  \(\dfrac{2}{3+\sqrt{7}}=\dfrac{2}{3+\sqrt{7}}\cdot\dfrac{3-\sqrt{7}}{3-\sqrt{7}}=\dfrac{2(3-\sqrt{7})}{3^2-7}=\boxed{3-\sqrt{7}}\)

__

Additional comment

This process takes advantage of the factorization of the difference of squares:

  a² -b² = (a +b)(a -b)

If 'b' is a value that can be made a rational real number by squaring it, then this multiplication by the conjugate can achieve that end. The conjugate of a sum is the corresponding difference.

This process is also used with complex numbers, since i² = -1, a real number.

Answer:

120

Step-by-step explanation:

The approximate chances of a randomly selected number from the given range being prime is approximately c. 1 / (2.30). Therefore, the answer is option c. 1/(2.3).

To determine the approximate chances that a randomly selected integer from the range of 2 to 10,000,000,000 is prime, we can consider the Prime Number Theorem.

The Prime Number Theorem states that the number of primes less than or equal to a given number x is approximately proportional to x divided by the natural logarithm of x.

Using the given hint, we can approximate ln(10) as 2.30.

So, the approximate chances of a randomly selected number from the given range being prime is approximately:

1 / (2.30)

Therefore, the answer is option c. 1/(2.3).

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Answer:

B. He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average

Step-by-step explanation:

i took the test

In the context of property variance, a variance refers to a legal authorization or exception granted to a property owner by the local governing authority. It allows the property owner to deviate from specific zoning regulations or land-use restrictions that would otherwise apply to their property.

The variance process is used when property owners believe that strict adherence to the existing regulations would cause undue hardship or prevent them from fully utilizing their property in a way that is reasonable and consistent with neighboring properties.

The purpose of property variances is to address unique circumstances or hardships that may exist for a particular property. Property variances typically involve submitting an application to the local zoning board or planning department, attending public hearings, and providing evidence or arguments to support the need for the variance.

The governing authority evaluates the application based on factors such as the impact on neighboring properties, public health and safety, and the intent of the zoning regulations. If approved, the property owner is granted permission to proceed with the proposed deviation from the regulations.

Overall, property variances provide flexibility in land-use regulations, allowing property owners to find reasonable solutions that meet their specific needs while still considering the broader community interests and objectives of zoning regulations.

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Given:

a = 2 and b = -2.

To find:

The value of \(a^3+3b^2\).

Solution:

We need to find the value of expression \(a^3+3b^2\) at a = 2 and b = -2.

Substituting a = 2 and b=-2 in \(a^3+3b^2\), we get

\((2)^3+3(-2)^2\)

\(=8+3(4)\)

\(=8+12\)

\(=20\)

Therefore, the value of expression \(a^3+3b^2\) at a = 2 and b = -2 is 20.

There is No statisti-cally signi-ficant evidence against the teacher's-claim that Charlie is just guessing because the probability is very low.

The total number of True-false questions are = n = 201.

The probability of getting a correct answer by guessing is = p = 0.5,

Charlie answered 53.7% = 0.537 of the questions correctly,

So, P(p' ≥ 0.537)

⇒ P(z ≥ (0.537 - 0.5)/√(0.5×0.5)/201,

⇒ P(z ≥ 1.05) = 1 - P(z < 1.05)

⇒ 0.1469

Since, the probability is very low,

Therefore, there is not any significant evidence against the teachers claim.

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The length of the other diagonal (d2) is 13 inches.

To find the area of a kite, you can use the formula:

Area = (d1 * d2) / 2

where d1 and d2 are the lengths of the two diagonals.

You are given that the area of the kite is 78 square inches and the length of one diagonal (d1) is 12 inches. We can plug these values into the formula and solve for the length of the other diagonal (d2):

78 = (12 * d2) / 2

To solve for d2, follow these steps:

1. Multiply both sides of the equation by 2:
156 = 12 * d2

2. Divide both sides of the equation by 12:
d2 = 156 / 12

3. Calculate the result:
d2 = 13
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Answer:

-300

Step-by-step explanation:

Step 1:  Find the amount Elmer's funds decreased after purchasing the rabbits:

Let x represent Elmer's funds.

Since Elmer bought five rabbits for $10 each, he lost $10 5 times.

x - (10 * 5)

x - 50

Thus, Elmer lost (spent) $50 for the 5 rabbits.

Step 2:  Find the amount Elmer's funds decreased after purchasing the  cupboards:

Since Elmer bought four cupboards for $70 each, he lost $70 4 times:

x - (50 + (70 * 4))

x - (50 + 280)

x - 330

Thus, after purchasing the rabbits and cupboards, Elmer lost $330.

Step 3:  Find the amount Elmer's funds increased after finding the twenty-dollar bill:

Since Elmer found a twenty-dollar bill, he gained $20

x - (330 + 20)

x - 310

Step 4:  Find the amount Elmer's funds increased after returning one rabbit:

Since Elmer returned one rabbit, he gained $10:

x - (310 + 10)

x - 300

Thus, Elmer's funds changed totally by -$300.

Putting all the information together, we have:

x - 10 - 10 - 10 - 10 - 10 - 70 - 70 - 70 - 70 + 20 + 10

x - 50 - 280 + 30

x - 330 + 30

x - $300

We determine the cumulative weight retained at each sieve and then calculate the cumulative percentage passing by dividing the cumulative weight passing by the total weight of the sample and multiplying by 100.

To calculate the percentage passing for each sieve size in a sieve analysis, we need to determine the cumulative percentage passing at each sieve size.

The sieve analysis provides information about the particle size distribution of an aggregate sample. It involves passing the sample through a series of sieves with different mesh sizes, and measuring the amount of material retained on each sieve.

To calculate the percentage passing, we first need to determine the cumulative weight retained at each sieve size. This is done by subtracting the weight retained on a particular sieve from the weight retained on the previous sieve.

Once we have the cumulative weight retained, we can calculate the cumulative percentage passing by dividing the cumulative weight passing by the total weight of the sample and multiplying by 100.

Here is an example:

Sieve Size (mm) | Weight Retained (g)

4.75 | 50

2.36 | 30

1.18 | 20

0.6 | 15

0.3 | 10

0.15 | 5

To calculate the cumulative percentage passing:

Calculate the cumulative weight retained:

Cumulative weight retained at sieve 4.75 mm = 50 g

Cumulative weight retained at sieve 2.36 mm = 50 g + 30 g = 80 g

Cumulative weight retained at sieve 1.18 mm = 80 g + 20 g = 100 g

Cumulative weight retained at sieve 0.6 mm = 100 g + 15 g = 115 g

Cumulative weight retained at sieve 0.3 mm = 115 g + 10 g = 125 g

Cumulative weight retained at sieve 0.15 mm = 125 g + 5 g = 130 g

Calculate the cumulative percentage passing:

Cumulative percentage passing at sieve 4.75 mm = (Total weight - Cumulative weight retained) / Total weight * 100 = (130 g - 50 g) / 130 g * 100 = 61.54%

Cumulative percentage passing at sieve 2.36 mm = (130 g - 80 g) / 130 g * 100 = 38.46%

Cumulative percentage passing at sieve 1.18 mm = (130 g - 100 g) / 130 g * 100 = 23.08%

Cumulative percentage passing at sieve 0.6 mm = (130 g - 115 g) / 130 g * 100 = 11.54%

Cumulative percentage passing at sieve 0.3 mm = (130 g - 125 g) / 130 g * 100 = 3.85%

Cumulative percentage passing at sieve 0.15 mm = (130 g - 130 g) / 130 g * 100 = 0%

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x+6x=7x

y+3y=4y

answer:7x+4y+18

The two boys are far away from the resort and distance measured about 35.81m.

The Pythagoras theorem equation is written as c² = a² + b², with c denoting the hypotenuse of the right triangle and a and b denoting the other two legs. So, any triangle that has a 90° angle creates a Pythagoras triangle, which can then be solved using the Pythagoras equation.

We must first use the Pythagoras theorem to determine how far the resort is from Manuel's home.

S₁ = √50²+20²

S₁ = √2500+400

S₁ = √2900

S₁ = 53.85m.

The distance between Manuel's house and his friend's house must then be calculated.

S₂ = √15²+10²

S₂ = √225+100

S₂ = √325

S₂ = 18.03m.

The displacement of the two boys will be,

∆S = S₁-S₂

∆S =  53.84-18.03

∆S = 35.81m.

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The two boys are far away from the resort and the distance measured about 35.81 m.

The Pythagoras theorem equation is written as c² = a² + b², with c denoting the hypotenuse of the right triangle and a and b denoting the other two legs. So, any triangle that has a 90° angle creates a Pythagoras triangle, which can then be solved using the Pythagoras equation.

We must first use the Pythagoras theorem to determine how far the resort is from Manuel's home.

S₁ = √50²+20²

S₁ = √2500+400

S₁ = √2900

S₁ = 53.85m.

The distance between Manuel's house and his friend's house must then be calculated.

S₂ = √15²+10²

S₂ = √225+100

S₂ = √325

S₂ = 18.03m.

The displacement of the two boys will be,

∆S = S₁-S₂

∆S =  53.84-18.03

∆S = 35.81m.

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The given propositions N, L, Q, and B are used to express statements in propositional logic, considering conditions and logical implications.



(a) The statement "New messages are not sent to the message buffer" can be represented as ¬B.

(b) The statement "If new messages are not queued then they are not sent to the message buffer" can be represented as Q → ¬B.

(c) The statement "If the system is functioning normally then the file system is not locked" can be represented as N → ¬L.

(d) The statement "If the file system is not locked, then (i) new messages are queued, (ii) new messages are sent to the message buffer, and (iii) the system is function normally" can be represented as ¬L → (Q ∧ B ∧ N).

(e) To determine values for L, Q, B, and N that make all the four propositions true, one possible assignment would be:
L = false, Q = true, B = true, N = true. This satisfies the given propositions, making all the statements in (a), (b), (c), and (d) true.

By representing the statements using propositional logic and assigning appropriate truth values to the propositions, we can analyze the logical relationships and conditions described by the given propositions.

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Answer:

answer is AA criteria

hope it helps.

Answer:

aa

Step-by-step explanation:

its aa because the tringle degree on top is 50 degrese  for both

In a multiple regression model, the error term (often denoted as ε or e) is assumed to be a random variable with a mean of zero.

This assumption is a key component of the regression model and is often referred to as the assumption of zero conditional mean or the assumption of homoscedasticity. The assumption of a mean of zero for the error term means that, on average, the errors have no systematic bias or tendency to overestimate or underestimate the predicted values. It implies that the model's predictions are unbiased and that any deviations from the true values are due to random chance or other factors not captured by the model. The other options presented in the answer choices (B) -1, (C) 1, and (D) any value are incorrect. The mean of the error term is specifically assumed to be zero, as it represents the average deviation of the observed values from the predicted values in the model.

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Step-by-step explanation:

this is equation......................

Answer:

0.03172

Step-by-step explanation:

Leading zeros (Zero before non-zero numbers) are not significant

0.02435 have 4 sigfig, round off to 0.0244, 3 sigfig

0.00732+0.0244 =0.03172

There are three possible 1-digit ternary sequences

There are eight possible 2-digit ternary sequences

f(n) be the number of n-digit ternary sequences in which no 1 appears anywhere to the right of any 2. We can find a recursive formula for f(n)as follows:

Consider any such n-digit sequence. There are two cases to consider for the leftmost digit:

The leftmost digit is 0: In this case, we can append any valid (n-1)-digit sequence to the right, which gives us f(n-1)possibilities.

The leftmost digit is 2: In this case: f(n)=f(n−1)+f(n−2)as the second digit must be 0 (since no 1 can appear to the right of any 2). After the second digit, we can append any valid (n-2)-digit sequence to the right, which gives us\($f(n-2)$\) possibilities.

Therefore, we have the recurrence r

with initial values f(1) = 3(since there are three possible 1-digit ternary sequences: 0, 1, or 2) and f(2) = 8 (since there are eight possible 2-digit ternary sequences: 00, 01, 02, 20, 21, 22, 10, 12).

A recurrence relation is an equation which represents a sequence based on some rule. It helps in finding the subsequent term (next term) dependent upon the preceding term (previous term). If we know the previous term in a given series, then we can easily determine the next term.

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Answer:

We have the formula to get the amount of money after 5 years:

A = Principal x (1 + rate)^year

or

5200 + 2340 = 5200 x (1 + rate)^5

=> (1 + rate)^5 = (5200 + 2340)/5200 = 1.45

=> 1 + rate = 1.077

=> rate = 1.077 - 1 = 0.077 = 7.7%

Hope this helps!

:)

Answer:

9

Step-by-step explanation:

r= 100i/pt=

100× 2340/5200×5=9

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.

Given information and corresponding atomic propositions:

We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:

r: Rabbits have been seen in the area.

b: Berries are ripe along the path.

w: Walking on the path is safe.

Now, let us formalize each of the given statements in terms of these atomic propositions:

a) Berries are ripe along the path, but rabbits have not been seen in the area.

b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.

c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.

d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.

e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.

The formalizations in terms of atomic propositions are:

a) b ∧ ¬r.b) ¬r ∧ w ∧

b.c) (b → w) ∧ (¬r → w).

d) ¬w ∧ ¬r ∧

b.e) (¬r ∧ ¬b) → w.b ∧

Berries are ripe along the path, but rabbits have not been seen in the area.

This is formalized by using the ∧(logical and) operator.

(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

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Using the concepts of equilateral triangle, we got that 107 square feet is the total surface area of an equilateral triangular pyramid with base side lengths of 6 feet and a height of 10 feet.

We have :

Base (b) = 6 feet

Slant height (l) = 10 feet

The lateral surface area is calculated using:

L = (3/2)× Length × Breadth

So, we have:

   L = (3/2) ×6 × 10

=>L=(3×3×10)

=>L=90 square feet.

The total surface area is calculated using:

T=Lateral surface area of the wall + area of equilateral triangle

=>T=L+ (√3/4)b²

So, we have:

T = 90 + (√3/4)×(6×6)

=>T=90+(3×3×√3)

=>T=90+9√3

=>T=107 square feet (approx)

Hence, the total surface area of an equilateral triangular pyramid with base side lengths of 6 feet and a height of 10 feet is 107 square feet.

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Answer:

its 0

Step-by-step explanation:

Answer:

between 10 and 12

Step-by-step explanation:

Given the measure of angles:

m∠B = 70°

m∠C = 60°

m∠A = 50°

Following this information, since the side lengths are directly proportional to the angle measure they see:

Angle B is the largest angle. Therefore, side AC is the longest side of the triangle since it is opposite of the largest angle.

Angle C is the smallest angle, so the side AB is the shortest side.

Therefore, side BC must be between 10 and 12 inches.