For every 1 girl in Mr Hegarty's class there are 3 boys. What is the ratio of boys to girls in the
class?
Give your answer in its simplest form.

Answer:

3 is the right I think idonk

The series to 10 term is

1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512

An equation that represents a sequence based on a rule is called a recurrence relation.

Finding the following term, which is dependent upon the prior phrase, is made easier (previous term). We can readily predict the following term in a series if we know the preceding term.

The term is predicted by multiplying the preceding term by 2

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Area of this figure = Area of square + area of triangle

A(square) = 7^2 = 49ft2
A(triangle) = (7x3) : 2 = 10.5ft2

So, the area of this doghouse is : 49 + 10.5 = 59.5ft2.

Answer:5.03

Step-by-step explanation:

Answer:

Step-by-step explanation:

There are a lot of ifs in this problem. The generator has to be a fair one. Any one of the 11 numbers must be equally likely to happen. Second, the sequence must not be the same each time she turns it on. Assuming both are true, then the numbers she will get are

9 10 11  for one number

9 10 11 for the other number

P(x>8) = 3/11 * 3/11 = 9/121

Systematic random sampling is sometimes used in place of simple random sampling due to its efficiency, representativeness, ease of implementation, and cost-effectiveness.

Systematic random sampling is sometimes used in place of simple random sampling for several reasons, including:
Efficiency:

Systematic random sampling can be more efficient than simple random sampling, as it involves selecting elements at regular intervals from the population.

This often reduces the time and effort needed to collect data compared to simple random sampling.
Representativeness:

Systematic random sampling may provide a more representative sample of the population.

By selecting elements at regular intervals, it ensures that different segments of the population are included, reducing the potential for sampling bias.
Ease of implementation:

Systematic random sampling is relatively easy to implement, as it involves fewer random selections compared to simple random sampling.

This makes it more practical for large populations or when a sampling frame is not readily available.
Cost-effectiveness:

Systematic random sampling can be more cost-effective than simple random sampling.

Since the process is more efficient, it may require fewer resources, such as time and personnel, to collect data.

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Answer:

Answer A is 19/2

Answer B is -2

You are located 12.00 m north and 5.00 m east of the center of town. Using Pythagorean theorem, your distance from the center of town is 13.00 m, and your angle is 157.38 degrees.

We can use the Pythagorean theorem to find the distance (d) of your location from the center of town:

d = sqrt((12.00 m)^2 + (-5.00 m)^2)

d = sqrt(144.00 m^2 + 25.00 m^2)

d = sqrt(169.00 m^2)

d = 13.00 m

Therefore, you are 13.00 meters away from the center of town.

To find the angle (theta) between the line connecting your location to the center of town and the positive x-axis, we can use the inverse tangent function (tan^-1) as follows:

theta = tan^-1(opp/adj)

theta = tan^-1((-5.00 m)/(12.00 m))

theta = -22.62 degrees

However, since your location is in the second quadrant (negative x and positive y), the angle must be measured from the positive y-axis, not the positive x-axis. Therefore, the actual angle between the line connecting your location to the center of town and the positive y-axis is:

theta = 180 degrees - 22.62 degrees

theta = 157.38 degrees

Therefore, you are 13.00 meters away from the center of town, at an angle of 157.38 degrees from the positive y-axis.

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The correct statements are:

b) Ordering costs decrease with respect to lot size,

c) It is good to have fixed interval ordering systems for products that have independent demand,

e) Taxes and insurance costs can be considered as carrying costs of inventory,

f) Costs incurred for defective products identified after the products are shipped are classified as internal failure costs,

h) Costs of repairing faulty products under warranty are limited to external failure costs, and j) Under EOQ inventory model, there is an assumption which states that there is no possibility of inventory stockout to occur.

b) Ordering costs decrease with respect to lot size: Ordering costs involve the expenses incurred when placing orders for inventory, such as administrative costs, processing fees, and transportation costs.

When the lot size increases, the frequency of placing orders decreases, resulting in lower ordering costs per unit. This is because the fixed costs associated with ordering are spread over a larger quantity of inventory.

c) It is good to have fixed interval ordering systems for products that have independent demand: Fixed interval ordering systems involve placing orders at regular intervals, regardless of the inventory level.

This approach is suitable for products with independent demand, where the demand is unpredictable or sporadic. By setting fixed intervals, the company can ensure a consistent replenishment schedule and avoid stockouts while optimizing inventory levels.

e) Taxes and insurance costs can be considered as carrying costs of inventory: Carrying costs are the expenses associated with holding and storing inventory.

They include costs such as storage fees, insurance premiums, taxes on inventory, and the opportunity cost of tying up capital in inventory. Taxes and insurance costs directly impact the financial burden of inventory holding and are considered as components of carrying costs.

f) Costs incurred for defective products identified after the products are shipped are classified as internal failure costs: Internal failure costs are expenses incurred due to quality issues discovered within the company's operations.

In the context of inventory, costs related to defective products identified after they are shipped, but before reaching the customer, fall under internal failure costs. These costs include rework, scrap, and any necessary corrective actions taken to address the quality problems.

h) Costs of repairing faulty products under warranty are limited to external failure costs: External failure costs are the expenses incurred due to quality issues discovered by customers after the products have been delivered.

When faulty products are repaired under warranty, the costs associated with the repairs are considered external failure costs. This includes the direct costs of repairing or replacing the faulty products and any associated customer service expenses.

j) Under EOQ inventory model, there is an assumption which states that there is no possibility of inventory stockout to occur: The Economic Order Quantity (EOQ) model is a widely used inventory management technique.

It assumes that demand for the product is constant and known with certainty, there are no quantity discounts or price variations, and there is no possibility of stockouts occurring.

The assumption of no stockouts simplifies the calculations and ensures that the optimal order quantity obtained from the model will meet the demand without interruptions.

However, in real-world scenarios, stockouts can occur due to unforeseen factors, variability in demand, or supply chain disruptions.

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We can see here that possible equation for (-3, 0), (2,0) and (3,-12) is y = -12x - 36.

The possible equation for (-3,0) and (1/2,0) is y = 0.

The slope of the line can be found using the formula:

\(m = \frac{ y_{2} - y_{1}}{ x_{2} - x_{1}}\)

\((x_{2}, y_{2} ) = (3, -12)\\(x_{1}, y_{1} ) = (2, 0)\)

m = (-12 - 0)/(3 - 2) = -12/1 = -12

The slope and the point (2, 0) into the point-slope formula, we get:

y - 0 = -12(x - 2)

y = -12x + 24

Calculate the slope (m):

m = (change in y) / (change in x)

= (0 - 0) / (1/2 - (-3))

= 0 / (1/2 + 6)

= 0

Therefore, the two possible equations for the three points are y = 0 and y = -12x + 24.

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The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891

From the question, we have the following parameters that can be used in our computation:

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)

Using the following trigonometry ratio

sin²(x) + cos²(x) = 1

We have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)

The sum to infinity of a geometric series is

S = a/(1 - r)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)

Evaluate the sum

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)

This gives

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)

Hence, the solution to the equation is 10.3891

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Hello!

To solve for f(-9)

  ==> must simply plug in '-9' into the x's position

       ==>  \(f(-9) = 1(-9)-8=-9-8=-17\)

Hope that helps!

a. The probability P(X < 10) is U(0, 50) is 0.20.

b. The probability P(X > 595) is U(0, 1,000) is 0.405.

c. The probability P(21 < X < 49) is U(19, 68) is 0.4762.

a. For a uniform continuous distribution U(0, 50), the probability of an event X < 10 can be calculated by dividing the length of the interval [0, 10] by the length of the entire interval [0, 50]. Since the lengths of both intervals are equal, the probability is 10/50 = 0.20.

b. Similarly, for a uniform continuous distribution U(0, 1,000), the probability of an event X > 595 can be calculated by dividing the length of the interval [595, 1,000] by the length of the entire interval [0, 1,000]. The length of the interval [595, 1,000] is 1,000 - 595 = 405, and the length of the entire interval is 1,000 - 0 = 1,000. Thus, the probability is 405/1,000 = 0.405.

c. For a uniform continuous distribution U(19, 68), the probability of an event 21 < X < 49 can be calculated by dividing the length of the interval [21, 49] by the length of the entire interval [19, 68]. The length of the interval [21, 49] is 49 - 21 = 28, and the length of the entire interval is 68 - 19 = 49. Therefore, the probability is 28/49 = 0.5714.

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Answer 3002 I'm not sure I'm just answering tons of things coins

Step-by-step explanation:

Answer:

You get out what you put in, like everything else in life. There are many levels of relationships and degrees of connection. We all respond and are available to different dynamics.

Step-by-step explanation:

The value of sin(D) is 7/25 after the application of the Pythagoras theorem.

The Pythagorean theorem is a fundamental theorem in geometry that describes the relationship between the sides of a right triangle. It claims that the hypotenuse's square length, which is the side that faces the right angle, is equivalent to the total of the squares of the lengths of the other two sides in a right triangle. The theorem can be formulated mathematically as:

c² = a² + b²

where, even the lengths for the remaining two sides (the legs) of the right triangle are a and b, and c is the length of the hypotenuse.

The Pythagorean theorem may be employed to determine the triangle's third side's length:

DE²= FD² + EF²

25² = 24² + EF²

625 = 576 + EF²

EF² = 49

EF = 7

Now, we can use the definition of sine to find sin(D):

sin(D) = opposite/hypotenuse = EF/DE = 7/25

Therefore, the value of sin(D) is 7/25.

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The target population for this researcher is American polio survivors over the age of 65.

Here, we have,

given that,

a researcher is studying post-polio syndrome in Americana polio survivors over the age of 65.

the researcher selects the sample subjects from the eligible subjects in a tristate area where the researcher is able to travel.

we have,

The target population for the researcher studying post-polio syndrome in

American polio survivors over the age of 65 would be the group of

American polio survivors over the age of 65.

Hence, The target population for this researcher is American polio survivors over the age of 65.

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Answer:

Multiply the length, the width, and the height. You can multiply them in any order to get the same different result. The formula for finding the volume of a rectangular prism is the following: Volume = Length * Height * Width, or V = L * H * W. Ex: V = 5 in. * 4 in. * 3 in. = 60 in.

Step-by-step explanation:

Answer:

I got B 131 and one-fourth feet cubed

Step-by-step explanation:

Answer:

d. 1, 5, 8

Step-by-step explanation:

Answer:

  5.26% profit (NRs 7,894.24)

Step-by-step explanation:

The exchange of 1,50,000 NRs to A$ will give ...

  A$ 1/(NRs 77.02) = x /1,50,000

  x = A$ 1,50,000/77.02 = A$ 1947.54 . . . . . (rounded down)

If the Nepali rupees are devalued by 5%, then what did buy A$ 1 will now buy only A$ 0.95. Then the exchange back to NRs will give ...

  (NRs 77.02)/(A$ 0.95) = x/(A$ 1947.54)

  x = NRs (1947.54)(77.02/0.95) = NRs 1,57,894.24

The effective profit is the difference from the amount initially exchanged, NRs 7,894.24, or ...

  (1,57,984.24/1,50,000 -1) × 100% ≈ 5.26%

__

Additional comment

Except for the loss in the exchange due to rounding down, the profit would be 1/0.95 -1 = 5.2632%. Instead, it is 5.2628%. This is why investors move their money to investments that retain their value when the local currency is losing its value.

The minimum value and median are used in the five-number summary.

A box and whisker plot displays a "box" with its left edge at Q₁, right edge at Q₃, "center" at Q₂ (the median), and "whiskers" at the maximum and minimum.

Given:

A five-number summary.

That means minimum value, lower quartile (Q1), median value (Q2), upper quartile (Q3), and maximum value.

From the given choices:

The minimum value and median are the required measures.

Therefore, the minimum value and median are the required measures.

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Answer:

5 and 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

Jenna will complete remaining distance in 6 hours.

Since we know that . Let us find the rate at which Jenna traveled 100 miles.

Remaining distance is 400-100=300.

Now let us find the time Jenna will take to travel 300 miles.

Therefore, Jenna took 6 hours to complete remaining distance.

Answer:

v = 12

Step-by-step explanation:

\(\frac{9}{v}\) = \(\frac{6}{8}\) ( cross-  multiply )

6v = 8 × 9 = 72 ( divide both sides by 6 )

v = 12

Answer:

v=12

9/v =6/8 (cross - multiply)

6v = 8 x 9 = 72 (divide both sides by 6)

v = 12

Step-by-step explanation:

that's my answer

To display the distribution of grades (A, B, C, D, F) in a course, it would be correct to use histogram

a) We note that the given histogram contains a

very large number of bars and that most bars are quite low while also very narrow.

The display is then not appropriate, as the histogram should contain less bars to make the shape in the distribution more obvious.

(b) The distribution of grades is skewed to the left as the highest bars in the histogram are to the right in the graph.

The grades appear to be centered roughly at 170, while the graders vary from about 75 to 190.

Moreover, there appear to be a few outliers in the distribution, as there are gaps between the bars of the histogram.

since Histogram contains too many bars and  Left-skewed histogram can be considered to display.

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Answer:

Step-by-step explanation:

You want the price of a bagel and a can of OJ if 2 bagels and 1 can costs $8, and 3 bagels and 2 cans cost $13.

You can write an equation for the value of each purchase. The cost of a bagel can be represented by 'b', and 'j' can be used for the cost of an orange juice.

The coefficients of j are related by a factor of 2, so we can make the sum of coefficients of j be zero if we subtract the second equation from 2 times the first:

  2(2b +1j) -(3b +2j) = 2(8) -(13)

  b = 3 . . . . . . . . . . . . . . simplify

Now, we can use this value in the first equation to find j:

  2(3) +1j = 8

  1j = 2 . . . . . . . . . subtract 6

A bagel costs $3, and a can of orange juice costs $2.

The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

Area of regular polygon = 1/2 × apothem × perimeter

perimeter = (s)side length of octagon × (n)number of side.

apothem = s/[2tan(180/n)].

11 = s/[2tan(180/12)]

s = 11 × 2tan15

s = 5.8949

perimeter = 5.8949 × 12 = 70.7388

Area of dodecagon = 1/2 × 11 × 70.7388

Area of dodecagon = 389.0634 in²

Area of pentagon = 1/2 × 5.23 × 7.6

Area of pentagon = 19.874 in²

Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

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Answer:

B.80

Step-by-step explanation:

a straight line adds up to 180 degrees. you already have 100. 180-100=80