How many grams of oxygen, at standard conditions,
are needed to react with 90 grams of glucose,
(C6H12O6)?
Postpone
C6H1206+ 602 6CO₂+ 6H₂O
2
grams
SUBMIT

Answer: A

Explanation:

The universe was infinite and is still infinite

Answer:

Kinetic energy increases.

Explanation:

Kinetic energy is energy you get from moving. The equation for KE depends on mass as well as velocity. If you increase one of these factors, KE will increase too.

A

I did it and got this but it know the first one is right as it only missing of some point it will be calculator error and also the answer is to the power of 21.

hope this make sense :)

In case 4, HNO3 is not listed first, but rather HNO2. HNO3 is the stronger acid because it has a higher Ka value, meaning that it is more likely to donate a proton to form the conjugate base.

The other three cases all list the stronger acid first, meaning that it is more likely to donate a proton.
To explain further, we must first understand what Ka is and what it represents. Ka is an equilibrium constant, and it measures the strength of an acid. It is equal to the ratio of the product of the concentrations of the ions and the reactant, and the reactant concentration. A higher Ka value indicates that the acid is more likely to donate a proton, making it a stronger acid.
In case 4, HNO3 has a higher Ka value than HNO2, making it the stronger acid. However, it is listed second in the list, rather than first. This is because the list is in descending order of acid strength, so HNO2 is listed first because it is the weaker acid.
In conclusion, in case 4, HNO3 is the stronger acid, but it is not listed first. This is because the list is in descending order of acid strength, so the weaker acid is listed first.

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The ratio of isocitrate/citrate under standard conditions is 0.096 when the value of ΔG° is given by 5.8kj/mol.

We know that isocitrate and citrate are convertible. It is given that the ΔG° is given by 5.8kj/mol. Then we know that,

ΔG° = -RTlnK

lnK = -RT/ΔG°

On substituting the values, we get

lnK = -5.6x10³/(6.314x296)

lnK = -2.34

K = 0.09623

The value of k is 0.09623.

Therefore, the ratio of Isocitrate to citrate is given by,

[Isocitrate]/[Citrate] = 0.09623

The ratio could be however rounded off to 0.096.

Therefore, the ratio is given by 0.096 for the isocitrate/citrate under standard conditions. In this way, the ratio could be computed very easily.

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When a gas is compressed adiabatically, it means that no heat is exchanged with the surroundings during the compression process. In an adiabatic compression, the pressure and volume of the gas change, but the heat remains constant.

The final temperature of a gas after adiabatic compression depends on the specific heat capacities of the gases involved. The specific heat capacity is a measure of how much heat energy is required to raise the temperature of a substance. Different gases have different specific heat capacities.

In the case of argon gas (Ar) and oxygen gas (O2), the specific heat capacity of argon is higher than that of oxygen. This means that argon requires more heat energy to raise its temperature compared to oxygen. So, if both gases were compressed adiabatically by a factor of two in volume,

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The following statement best predicts the effect of not having ATP available to supply energy to the process: H+ ions will stop moving through the protein.ATP is an important molecule in cells, which stores and releases energy.

When ATP molecules break down, they release energy that is used to fuel cellular processes such as muscle contraction, protein synthesis, and cell division. ATP is also essential for active transport in the cell membrane.

Therefore, if ATP is not available to supply energy to this process, the hydrogen ions will stop moving through the protein.The H+ ions move through a protein that forms a channel in the membrane to create an electrochemical gradient in the cell.

The movement of the Hydrogen ions drives the movement of other particles in or out of the cell through the same protein. However, without ATP, the protein cannot actively transport the H+ ions against the electrochemical gradient. Consequently, the H+ ions will stop moving through the protein.

This will prevent the formation of an electrochemical gradient, leading to a lack of energy for cellular processes that rely on this gradient.The newly found membrane protein is possibly involved in membrane transport of a certain particle. This means that the protein might help in moving particles in or out of the cell.

In active transport, the protein uses energy to move particles across the membrane against their concentration gradient. ATP provides this energy.

Therefore, if ATP is not available, the protein cannot actively transport the particle. This means that the particle will not move against its concentration gradient, leading to a lack of transport of that particle.

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The importance of the following below in a nuclear reactor are:

This is referred to as the device which is used to start up and control a fission or fusion nuclear chain reaction or nuclear fusion reactions.

The control rod is responsible for the absorption of neutrons so that the nuclear chain reaction taking place within the reactor core can be slowed  or stopped. The containment structure help to prevent rays from getting into the environment thereby serving as a protective factor.

The moderator helps to slow down the speed of neutrons especially in those who have a very high speed thereby making it the correct choice.

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Answer:

Group B is the control group

Explanation:

In an experiment, a control group is the standard to which comparisons are made in an experiment.

Explanation:

Chromatography is a physical method of separation that distributes components to separate between two phases, one stationary (stationary phase), the other (the mobile phase) moving in a definite direction. The mobile phase is the phase that moves in a definite direction

B

the Earth is eccentric,this means that it has changed repeatedly over time

And if it took the earth more time to orbit round the sun than it does now the years would have more than Han 365 days a year

Answer:

In the elemental form, non-metals can be gas, liquid or solid. They aren't shiny (lustrous) and they don't conduct heat or electricity well. Usually their melting points are lower than for metals, although there are exceptions. The solids usually break easily, and can't bend like metals

Explanation:

For outside treatment:

The cost is a fixed $15,000 per year for the entire 9-year period.

Therefore, the EUAC for outside treatment is simply $15,000.

Comparing the EUAC values, we find that the EUAC for in-house treatment is approximately $6,329, while the EUAC for outside treatment is $15,000.

To calculate the equivalent uniform annual cost (EUAC) of each alternative and determine the most economical option, we need to analyze the costs over the 9-year period.

For in-house treatment:

The cost in the first year is $30,000, and the cost declines by $3,000 each year. We can use the arithmetic gradient formula to calculate the equivalent uniform annual cost.

Using the formula for an arithmetic gradient, the EUAC for in-house treatment can be calculated as follows:

EUAC = C - (G/A) * (1 - (1 + i)^(-n))

Where:

C = Initial cost = $30,000

G = Gradient (decrease per year) = -$3,000

A = Annuity factor (obtained from the interest and annuity table for discrete compounding) for 9 years at 8% MARR = 6.71008 (rounded)

i = Interest rate = 8% = 0.08

n = Number of years = 9

Substituting the values into the formula:

EUAC = $30,000 - (-$3,000/6.71008) * (1 - (1 + 0.08)^(-9))

EUAC ≈ $6,329 (rounded)

For outside treatment:

The cost is a fixed $15,000 per year for the entire 9-year period.

Therefore, the EUAC for outside treatment is simply $15,000.

Comparing the EUAC values, we find that the EUAC for in-house treatment is approximately $6,329, while the EUAC for outside treatment is $15,000.

Since the EUAC for in-house treatment is lower, it is the more economical alternative for processing waste liquids.

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(a) The value of the reaction quotient before any reaction occurs is 0.10 M.

(b) The value of the equilibrium constant for the reaction is 0.38.

The reaction between NO2 and N2O4 can be written as:

2NO2(g) ⇌ N2O4(g)

The reaction quotient (Q) is defined as the ratio of the concentrations of the products raised to their stoichiometric coefficients, to the concentrations of the reactants raised to their stoichiometric coefficients.

At the beginning of the reaction, before any reaction occurs, the concentration of NO2 is 0.10 M, and there is no N2O4. Therefore, the value of Q at this point would be:

Q = (N2O4^2)/(NO2^2)

= 0

The value of the reaction quotient at equilibrium can be found from the given concentrations, [NO2] = 0.016 M and [N2O4] = 0.042 M.

Q = (0.042^2)/(0.016^2)

= 0.38

The value of the equilibrium constant (Kc) is equal to the value of the reaction quotient at equilibrium. Therefore, Kc = 0.38.

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Answer:

A

Explanation:

Atoms having the same number of protons but a different number of neutrons are the elements have isotopes.

Isotopes are the atoms which is having the same number of protons but the different numbers of neutrons.  Isotopes having the different atomic masses. The relative abundance of an isotope is the percentage of an atoms with a specific atomic mass which is found in a naturally occurring sample of an element.  The number of protons in a nucleus will determines the element's atomic number on the Periodic Table. For example, carbon having six protons and its atomic number will be 6.

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The NiI₂ cation is a positively charged ion of Nickel and Iodine, with the formula Ni²⁺.

The anion is a negatively charged ion of Nickel and Iodine, with the formula I²⁻.


Nickel and Iodine form the cation-anion pair as part of a redox reaction. When Nickel and Iodine are mixed together, they react and form the cation and anion forms.

This is because when Nickel is oxidized, it loses electrons and becomes a positive ion, while Iodine gains electrons and becomes a negative ion. This forms the cation-anion pair.


The NiI₂ cation and anion form also has an important role in the electrolysis process. During electrolysis, the NiI₂ cation and anion forms are used to transfer electrical energy into chemical energy.

This allows for the breakdown of larger molecules into their component parts. The NiI₂ cation and anion form is also used in fuel cells and other electrochemical reactions.

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0.0030

0.0030 is the equilibrium constant for the reaction at this temperature.

The reaction is as follows:

N2(g)+ 3 H2(g) ⇌ 2 NH3(g)

At equilibrium, the concentrations of the different species are as follows.:

[NH3] = 0.105 M

[N2] = 1.1 M

[H2] = 1.50 M

The equilibrium constant for the reaction is given as follows:

Keq = [NH3]² / [N2] [H2]³

Keq = (0.105)² / [1.1] [1.50]³

Keq = 0.00296 or 0.0030

The equilibrium constant for the reaction at this temperature is 0.0030.

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Answer:

the answer is A

0.0030

Explanation:

To make 17 kg of chlorine, around 7.0031 kg of sodium chloride will be required.

Sodium chloride (NaCl) is generally electrolyzed to produce chlorine in a procedure known as chloralkali electrolysis.

The Chemical Equation for this reaction is:

2 NaCl + 2 H₂O → 2 NaOH + Cl₂ + H₂

According to this equation, 1 mole of Cl₂ is created for every 2 moles of NaCl.

NaCl has a molar mass of roughly 58.44 g/mol, while Cl₂ has a molar mass of roughly 70.90 g/mol.

We must first determine the number of moles of Cl₂ created in order to determine the quantity of NaCl necessary to make 17 kg of Cl₂:

Number of moles of Cl₂ = (17 kg) / (70.90 g/mol) = 240.03 mol

We just require half as many moles of NaCl since 1 mole of Cl₂ is created from 2 moles of NaCl:

Number of moles of NaCl = 1/2 × 240.03 mol = 120.015 mol

Finally, we can determine the necessary mass of NaCl:

Mass of NaCl = (120.015 mol) × (58.44 g/mol) = 7,003.1 g = 7.0031 kg

In order to make 17 kg of chlorine, roughly 7.0031 kg of sodium chloride will be required.

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The sulfinator setting should be 9.615 pound per day of sulfur dioxide.

We have to use a few instances of unit conversion to solve this.

Because 1 gallon has 3.786 liters, and the stream is 100 gallons per minute, then in a single minute we are producing:

100 * 3.786 L = 378.6 L of waste

Because each liter of the waste stream contains 8 milligrams of sulfur dioxide, in a single minute we are producing:

378.6 * 8 mg = 3028.8 mg

3028.8 mg = 3.0288 g of sulfur dioxide

Because there are 60 minutes in an hour, each hour we are producing:

60 * 3.0288 g = 181.728 g of sulfur dioxide

Because there are 24 hours in the day, each day we are producing:

24 * 181.728 g = 4361.472 g of sulfur dioxide

Because each 1 lb = 453.592 g, each day we are producing:

4361.472 / 453.592 = 9.615 lbs of sulfur dioxide

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Answer:

V 5.4L

Explanation:

Answer:

I'm sure it's covalent bond hope this helps

Answer:

Sr

Explanation:

because it's electronegativity is the highest.

The estimated relative contribution of C3 plants is approximately 88%, while the estimated relative contribution of C4 plants is approximately 12% to the organic matter in Kenya's soil.

To determine the relative contribution of C3 and C4 plants to the organic matter in Kenya's soil, we can use the difference in stable carbon isotopic compositions (δ13C values) between these plant types.

C3 and C4 plants have distinct δ13C values due to differences in their carbon fixation pathways. C3 plants generally have δ13C values ranging from -22 to -33 permil, while C4 plants typically exhibit δ13C values from -9 to -16 permil.

Given that the stable carbon isotopic composition (δ13C) of the soil organic matter in Kenya is -18 permil, we can compare this value to the δ13C values of C3 and C4 plants to estimate their relative contributions.

Let's denote the relative contribution of C3 plants as "x" and the relative contribution of C4 plants as "y." Since the contributions of C3 and C4 plants sum up to 100%, we have the equation:

x + y = 100% (equation 1)

Now, let's assign the δ13C values to the contributions of C3 and C4 plants. Assuming the air δ13C value is -7 permil, we can write the following equations:

-18 = x * (-33) + y * (-16) + (-7) * (1 - x - y) (equation 2)

Solving equations 1 and 2 simultaneously will provide us with the relative contributions of C3 and C4 plants.

Using the given δ13C values and solving the equations, we find:

x ≈ 0.88 (or 88%)

y ≈ 0.12 (or 12%)

Therefore, the estimated relative contribution of C3 plants is approximately 88%, while the estimated relative contribution of C4 plants is approximately 12% to the organic matter in Kenya's soil.

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The equation of state for a hypothetical ideal gas is known as the ideal gas law, sometimes known as the general gas equation. i.e. PV = nRT or P1V1 = P2V2.

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Answer:

the first one to the third box

the second one to the fourth box

the third one to second box

and the fourth one to the first box

Explanation:

A statement that stores the uppercase equivalent of the string referenced by the city variable is as follows:

uppercity = city.toUpperCase();

```

To store the uppercase equivalent of the string referenced by the variable "city" in the variable "uppercity," you can use the "toUpperCase()" method in Java. In the given code snippet, the "toUpperCase()" method is applied to the "city" variable and the resulting uppercase string is assigned to the "uppercity" variable.

The "toUpperCase()" method is a built-in function in Java that converts all the characters in a string to uppercase. It returns a new string with all uppercase characters, while leaving the original string unchanged. By invoking this method on the "city" variable, we ensure that the resulting uppercase string is assigned to the "uppercity" variable.

Using the "toUpperCase()" method is a convenient and straightforward way to convert a string to its uppercase form. It eliminates the need for manual conversion and provides a more concise and readable code.

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By tripling the temperature, the pressure of a gas will also triple because of its direct relationship.

The pressure of a given gas is directly proportional to its absolute temperature while the volume does not change. The volume of a given gas is directly proportional to its absolute temperature in the presence of constant pressure according to Charles's law.

The pressure law states that the temperature of the gas is directly proportional to its pressure when the constant volume of gas is present in a container. This can be easily understood by seeing the particles of gas in the container that moves with a greater energy when the temperature of a gas is increased.

So we can conclude that there is direct relationship between pressure and temperature.

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