Intelligent beings in a distant galaxy send a signal to earth in the form of an electromagnetic wave. The frequency of the signal observed on earth is 1.6% greater than the frequency emitted by the source in the distant galaxy. What is the speed vrel of of galaxy relative to the earth? Vrel = Number ________________ Units ____________

Answers

Answer 1

The speed vrel of the galaxy relative to the Earth is 4.8 x 10^6 m/s

Number = 4.8 x 10^6; Units = m/s.

In order to calculate the speed vrel of the galaxy relative to the Earth, we can use the formula:

vrel/c = Δf/f

where

c is the speed of light,

Δf is the change in frequency, and

f is the frequency emitted by the source in the distant galaxy.

So, first we need to calculate the value of Δf.

We know that the frequency observed on Earth is 1.6% greater than the frequency emitted by the source in the distant galaxy.

Mathematically, we can express this as:

Δf = (1.6/100) x f

where f is the frequency emitted by the source in the distant galaxy.

Substituting this value of Δf in the above formula, we get:

vrel/c = Δf/f

         = (1.6/100) x f / f

        = 1.6/100

vrel/c = 0.016

vrel = c x 0.016

vrel = 3 x 10^8 m/s x 0.016

       = 4.8 x 10^6 m/s

Hence, the speed vrel of the galaxy relative to the Earth is 4.8 x 10^6 m/s (meters per second).

Number = 4.8 x 10^6; Units = m/s.

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Related Questions

To calculate the density of an object which of the following values do you need to know a. Buoyancy b. Volume c. Weight d. Mass

Answers

b. volume and d. mass

Answer: Volume and mass

Explanation: I took the quiz lol

Write AT LEAST 10 SENTENCES based on ONE event that has happened in your life.


Please do it am so tired

Answers

Sorry your tired, ill try to make it worth reading.

One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.

the kinetic energy of a car is 8 ´ 106 j as it travels along a horizontal road. how much work is required to stop the car in 10 s?

Answers

Answer:

required power to stop the car is 8 × 10^5W

Explanation:

Power is the rate at which energy is transferred. You need to transfer 8 million joules of kinetic energy into 8 million joules of heat in the car's brakes in 10 seconds.

Power = Change in Energy/Time

P = E/t = 8 × 10^6 J/10s = 8 × 105W

Answer: required power to stop the car is 8 × 10^5W.

NB*- There is no answer present on brainly for this question so i am unable to upload its answer's any link here.

The work required to stop a car traveling along a horizontal road with a kinetic energy of \(8 \times 10^6 J\) in 10 seconds is \(4 \times 10^6 J\).

The work done on an object is equal to the change in its kinetic energy. In this case, the car has an initial kinetic energy of  \(8 \times 10^6 J\). To stop the car, we need to bring its kinetic energy to zero. This means the work done on the car is equal to its initial kinetic energy. Therefore, the work required to stop the car is  \(8 \times 10^6 J\).

It is important to note that work is a scalar quantity and can be positive or negative depending on the direction of the force and displacement. In this case, since we are stopping the car, the work done is negative because the force applied opposes the car's motion. However, the magnitude of the work remains the same. Therefore, the work required to stop the car in 10 seconds is  \(8 \times 10^6 J\), or  \(4 \times 10^6 J\) in magnitude.

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Zinc telluride has a band gap of 2.26eV, while the minimum photon energy given by the visible light is 1.8eV. Over what range of wavelengths of visible light is it transparent? It is given that the Planck's constant is 4.13 x 10-15 eV s and that the full range of wavelength of visible light is 400-700 nm.

Answers

The range of wavelengths of visible light over which zinc telluride is transparent is 550.99 nm to 700 nm.

Zinc telluride has a band gap of 2.26 eV, while the minimum photon energy given by the visible light is 1.8 eV.

It is required to determine the range of wavelengths of visible light over which zinc telluride is transparent.

It is given that the Planck's constant is 4.13 x 10^-15 eV s and that the full range of wavelength of visible light is 400-700 nm.

The formula to calculate wavelength from energy is given by;

E= hc/λ

where; E = energy, h = Planck's constant, c = speed of light, and λ = wavelength.

Rearranging the formula, we get;

λ = hc/E

Using the above formula, we can find the wavelengths of visible light as follows:

For E = 1.8 eV,λ

= hc/E = (4.13 x 10^-15 J s x 2.998 x 10^8 m/s) / (1.8 eV x 1.602 x 10^-19 J/eV)

= 688.67 nm

For E = 2.26 eV,

λ = hc/E

= (4.13 x 10^-15 J s x 2.998 x 10^8 m/s) / (2.26 eV x 1.602 x 10^-19 J/eV) = 550.99 nm

Therefore, the range of wavelengths of visible light over which zinc telluride is transparent is 550.99 nm to 700 nm.

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Question 9 Marks: 1 The flushometer valve is typically protected byChoose one answer. a. a non-pressure-type vacuum breaker b. a pressure-type vacuum breaker c. a backflow preventer d. a reduced pressure zone backflow preventor

Answers

The flushometer valve is typically protected by a backflow preventer.

This device ensures that water flows in only one direction, preventing any contamination or backflow of non-potable water into the potable water supply. The backflow preventer can be a reduced pressure zone backflow preventer, which is designed to offer the highest level of protection by creating a zone of reduced pressure between the potable water supply and non-potable water.

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PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have

Answers

Explanation:

speed : • how fast an object changes position

• miles per hour.

• distance/time.

velocity: • speed in a direction

• miles per hour North

• distance/ time in a direction

5. A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has (2 points)

Answers

What’s the rest of the question or is that it?

A 270 W, a 150 W, and a 220 W resistor are connected in parallel. The applied voltage is 480 V. What is the current total of the 270 W and the 150 W resistors

Answers

The total current flowing through the 270 W and 150 W resistors is 3.34 A.

1: Find the equivalent resistance of the parallel circuit

We know that resistors in parallel have an equivalent resistance that can be calculated using the formula: 1/Req = 1/R1 + 1/R2 + 1/R3

where R1, R2, and R3 are the resistances of the three parallel resistors.

Substituting the values given:

1/Req = 1/270 + 1/150 + 1/220

1/Req = 0.00695652174

Req = 1/0.00695652174

Req = 143.64 Ω

Therefore, the equivalent resistance of the parallel circuit is 143.64 Ω.

2: Calculate the total current

To calculate the total current flowing through the 270 W and 150 W resistors, we can use the same formula, I = V/R, but substitute the equivalent resistance for the total resistance.

I = V/Req

I = 480/143.64I = 3.34 A

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Briefly explain the big bang theory.

Answers

Astronomers use the big bang theory to describe how the cosmos came into being. It is the hypothesis that the universe started out as a single point, then grew and stretched to reach its current size and is still stretching.

The most widely accepted cosmological model for explaining the beginnings of the observable universe and the consequent large-scale evolution is the big bang theory. The model offers a comprehensive explanation for a vast array of well-known phenomena and explains how the cosmos expanded from a high-density, high-temperature starting point.Modern estimates place this event at a time of about 13.8 billion years ago. After the universe's first expansion (inflation), it calmed down enough for the emergence of subatomic particles and, subsequently, fundamental atoms.Hydrogen and helium, two massive clouds of these fundamental elements, finally combined because to gravity to form stars and galaxies.

The big bang theory contends that the universe has been expanding since its creation in all directions.

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There is friction between the block and the
table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.

There is friction between the block and thetable.The suspended 2 kg mass on the left ismoving up, the

Answers

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

The magnitude of acceleration of the entire system is  \(2.1315 \;\rm m/s^{2}\). Hence, option (5) is correct.

Given data:

The masses  suspended from the table are, m = 2 kg and m' = 4 kg.

And the mass kept on the table is, m'' = 4 kg.

The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,

\(f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N\)

Since, the mass kept on the right side is more. Then at equilibrium,

-f + m''g + (m' +m)a = m'g

Here,

a is the magnitude of acceleration of the system.

Solving as,

-4.312+ 4(9.8) + (4 -2)a = 4(9.8)

2a = 4.312

\(a \approx 2.1315 \;\rm m/s^{2}\)

Thus, we can conclude that the magnitude of acceleration of the entire system is  \(2.1315 \;\rm m/s^{2}\). Hence, option (5) is correct.

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A toy car runs Off the edge of a table at 2.5 m high. It’s a carlins 1.2 m on the base of the table fine how long it took the car to reach the ground

Answers

Sorryyyu i dlntttt knowww buttt i neeedd pontsss

A 12kg aluminum box is sliding along a horizontal steel surface while experiencing a rightward applied force of 60N. The box has a displacement of 20m. What is the Net Force acting on the box? *

A.)60N
B.)117.72N
C.)4.67 N
D.)-55.33N

Answers

The answer would be D sorry if wrong

which statement best describes a chemical reaction?​

Answers

Answer:

a chemical reaction is a reaction that happens between two objects, like fire and a potion in chemistry

Explanation:

the reason is that the the fire causes the chemical to react, making a chemical reaction

A chemical changing

a 5.4 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw

Answers

The 3.6 kg cat must stand approximately 9.82 m to the left of the pivot to balance the seesaw.

Seesaw - A seesaw is a long, narrow board with a central pivot point, sometimes referred to as a teeter-totter. The centre of the board is where a seesaw's pivot point is located. The turning forces on either side of an item that is balanced on a pivot point must be equal to the turning force on the opposite side. The Seesaw makes use of Force ideas.To balance the seesaw, the total torque on both sides of the pivot must be equal. The torque is calculated by multiplying the weight (mass times gravity) of an object by its distance from the pivot.Let's denote the distance of the 5.4 kg cat from the pivot as \(\(d_{\text{cat}_1}\), the distance of the 2.2 kg bowl of tuna fish as \(\(d_{\text{bowl}}\)\), and the distance of the 3.6 kg cat (the unknown we're trying to find) as\(\(d_{\text{cat}_2}\).\)The torque equation can be set up as follows:\(\[ (5.4 \, \text{kg} \times 9.8 \, \text{m/s}^2) \cdot d_{\text{cat}_1} = (2.2 \, \text{kg} \times 9.8 \, \text{m/s}^2) \cdot d_{\text{bowl}} \]\)Simplifying the equation, we have:\(\[ d_{\text{cat}_2} = \frac{5.4 \times d_{\text{cat}_1}}{2.2} \]\)Substituting the given values, we get:\(\[ d_{\text{cat}_2} = \frac{5.4 \times 4.0}{2.2} \approx 9.82 \, \text{m} \]\)Therefore, the 3.6 kg cat must stand approximately 9.82 m to the left of the pivot to balance the seesaw.

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Note: The question would be as

A 5.4 kg cat and a 2.2 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. How far to the left of the pivot must a 3.6 kg cat stand to keep the seesaw balanced? Express your answer to two significant figures and include the appropriate units.

For the seesaw to be in rotational equilibrium, the mass of the cat (5.4 kg) should be equal to the mass of the bowl of tuna fish (2.5 kg).

To solve this problem, we can apply the principles of torque and rotational equilibrium.

Torque is the product of force and the perpendicular distance from the point of rotation (fulcrum) to the line of action of the force. In rotational equilibrium, the sum of torques acting on an object is zero.

Let's consider the seesaw as a rigid rod of length 4.0 m with a fulcrum in the middle. The cat's weight creates a clockwise torque, while the bowl of tuna fish creates a counterclockwise torque. The torques can be calculated using the formula:

Torque = Force * Distance

The cat's weight (force) is given by:

Force_cat = mass_cat * g

The distance of the cat from the fulcrum is half the length of the seesaw:

Distance_cat = 4.0 m / 2 = 2.0 m

Similarly, the bowl's weight (force) is given by:

Force_bowl = mass_bowl * g

The distance of the bowl from the fulcrum is also half the length of the seesaw:

Distance_bowl = 4.0 m / 2 = 2.0 m

For rotational equilibrium, the sum of torques is zero:

Torque_clockwise = Torque_counterclockwise

(mass_cat * g) * (2.0 m) = (mass_bowl * g) * (2.0 m)

Simplifying the equation:

mass_cat = mass_bowl

Therefore, for the seesaw to be in rotational equilibrium, the mass of the cat (5.4 kg) should be equal to the mass of the bowl of tuna fish (2.5 kg).

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A plane takes off from Charles de Gaulle Airport at a bearing of N 43' E with an average speed of 516 miles per hour over 1.5 hours. Another plane takes off from Charles de Gaulle Airport at the same time as the first plane at a bearing of S 56 E with an average speed of 508 miles per hour over 1.5 hours. How far apart are the two planes after 1.5 hours rounded to the nearest mile?

Answers

The two planes are approximately 1008 miles apart after 1.5 hours.


1. Calculate the distance each plane traveled:
Plane 1: Distance = Speed × Time = 516 mph × 1.5 hours = 774 miles
Plane 2: Distance = Speed × Time = 508 mph × 1.5 hours = 762 miles

2. Calculate the angle between the two bearings:
Angle = 180° - (43° + 56°) = 180° - 99° = 81°

3. Use the law of cosines to find the distance between the two planes:
Distance = √(774² + 762² - 2 × 774 × 762 × cos(81°))

4. Calculate the distance:
Distance ≈ 1008.23 miles

5. Round to the nearest mile:
Distance ≈ 1008 miles

Therefore,  The two planes are approximately 1008 miles apart after 1.5 hours.

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The intensity of light at a given point is given by the relation I=C/D^2, where C is the light power of the source and D is the distance from the source to the given point. Assume that C is uniformly distributed in (1,2), while D is a continuous random variable, with density function.
student submitted image, transcription available below
Find the density function of I, if C and D are independent.

Answers

This is the density function of I when C and D are independent. It describes the distribution of intensities at a given point, given the distribution of light power from the source and the distance from the source to the point.

To find the density function of I, we need to determine the probability density function (PDF) of the random variable I.

Given that C and D are independent, we can use the concept of change of variables to find the density function of I.

First, we know that I = C/D^2. We can rearrange this equation to express D in terms of I: D = (C/I)^(1/2).

Now, we can find the derivative of D with respect to I to obtain the Jacobian of the transformation: dD/dI = -(1/2)*(C/I)^(3/2).

Since C is uniformly distributed in the interval (1,2), its density function fC(c) is constant within that range and zero outside. Thus, fC(c) = 1 for 1 ≤ c ≤ 2, and fC(c) = 0 otherwise.

Using the formula for change of variables, the density function of I, fI(i), can be obtained as follows:

fI(i) = fC(C/I)(dD/dI)

= 1 * (-(1/2)(C/I)^(3/2))

= -(1/2)*(C/I)^(3/2)

where C is restricted to the range (1,2) and D is calculated as D = (C/I)^(1/2).

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Convert 120 Ibs into kilograms

Answers

Answer:

54.4311 kilogram

Explanation:

120 lbs is 54.4 kg

To convert lbs you need to dived by the mass by 2.205

A car can travel 30.0 mi on one gallon of gas. How many km/L is this?

Answers

Answer

30 mi/gal * (1.61 km / mi ) /  (3.78 L/gal)   = 30 * .426 km/L = 12.8 km/L

A rectangular box of lines and an extra vertical line near the right end of the box has circles with X's in them on the right side, on the extra line, and on the top side between the extra line and a stack of vertical lines near the left end. The top circle is A. The right side circle is C. The circle on the extra line is B. The bottom side has 2 small circles separated by a short segment of the side near the left end. The top side has a stack of short horizontal lines labeled A in its middle, which are from left to right short, very short, short, very short.
Use the diagram to answer each question with yes or no.

If you removed bulb A, would bulbs B and C continue to shine?

If you removed bulb B, would bulbs A and C continue to shine?

A rectangular box of lines and an extra vertical line near the right end of the box has circles with

Answers

Light bulbs 1, 2, and 4 will continue to shine when Linh switches off bulb 3.

What exactly is a circuit?

The battery-powered electrical circuit where a voltage differential is generated across a capacitor, a resistor, or an inductor.

As soon as Linh cuts the middle branch, the bulbs in positions 1, 2, and 4 will function as a resistor in a series circuit. Except for resistor number 3, the current through the other resistors will be constant.

In conclusion, if Linh switches off Bulb 3, only Bulbs 1, 2, and 4 will still be on.

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Answer:

1. no

2. yes

Explanation:

on edge 2022

what is the wavelength (in m) of an earthquake that shakes you with a frequency of 11.5 hz and gets to another city 80.0 km away in 12.0 s?

Answers

The wavelength of earthquake that shakes you with frequency of 11.5 Hz and gets to another city 80 Km away in 12s is 579.72 m .

The Wavelength is defined as the distance between adjacent crests in  adjacent cycles of a waveform signal propagated along a wire .

the relation between velocity , wavelength and wavelength is :

v = λf  ;

simplifying we get ⇒ λ = v/f ;

we know that , v = d/t ;  by speed = distance × time ,

substituting , distance  = 80 Km = 80000 m, and

time taken  = 12s ;

So , v = 80000/12 = 6,666.7 m/s .

given that frequency(f) = 11.5 Hz ,

So , λ = v/f ⇒ 6,666.7/11.5

= 579.71304

≈ 579.72 m .

Therefore , the wavelength of the earthquake is 579.72 m .

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A motor in normal operation carries a direct current of 0.850A when connected to a 120V power supply. The resistance of the motor windings is 11.8Ω. While in normal operation.(c) What If? Suppose a malfunction stops the motor shaft from rotating. At what rate will internal energy be produced in the windings in this case? (Most motors have a thermal switch that will turn off the motor to prevent overheating when this stalling occurs.)

Answers

Therefore, when the motor shaft is stopped from rotating, the rate at which internal energy is produced in the windings is approximately 8.53W.
It's important to note that most motors have a thermal switch that will turn off the motor to prevent overheating when this stalling occurs.

When a motor is in normal operation, it carries a direct current of 0.850A when connected to a 120V power supply, and the resistance of the motor windings is 11.8Ω.

Now, let's consider a malfunction where the motor shaft is stopped from rotating. In this case, the motor will still be connected to the power supply, but it won't be able to convert electrical energy into mechanical energy. Instead, the energy will be dissipated as heat in the windings of the motor.

To calculate the rate at which internal energy is produced in the windings, we can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance. Since we know the current and resistance, we can substitute these values into the formula.

\(P = (0.850A)^2 * 11.8Ω   = 0.72275 * 11.8Ω   ≈ 8.53W\)

This switch is designed to protect the motor from damage due to excessive heat generated in the windings.

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Joe went to see his Grandmother. He promised his Grandma that he would arrive at her house at 5 pm. He leaves his house at 3:00 and this will allow him 2 hours to get to her house. Joe will need to travel 70 miles to get to her house. How fast will Joe need to drive to make it to Grandma's house on time?

Answers

Answer:

35 mph

Explanation:

From the question given above, the following data were obtained:

Time (t) = 2 hours

Distance (d) = 70 miles

Speed (S) =.?

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed (S) = Distance (d) / Time (t)

S = d/t

With the above formula, we can calculate how fast (i.e the speed) Joe will need to drive to make it to his Grandma's house on time. This can be obtained as follow:

Time (t) = 2 hours

Distance (d) = 70 miles

Speed (S) =.?

S = d/t

S = 70/2

S = 35 mph

Therefore, Joe will drive at 35 mph in order to get to his Grandma's house on time.

Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters

Answers

Other clusters with hundreds to thousands of galaxies are called rich clusters. The low mass of a poor cluster prevents the cluster from holding onto its members tightly. The poor cluster tends to be a bit more irregular in shape than a rich cluster. Each large spiral has several smaller galaxies orbiting them.

These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).

What clusters of galaxies likely to have irregular shapes?

In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.

Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.

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Descartes and Snell worked around the time of Kepler and Galileo. Is this true or false?

Answers

René Descartes (1596-1650) was a creative mathematician of the first order, an important scientific thinker, and an original metaphysician.

Willebrørd Snell (1591-1626) was a Dutch astronomer, mathematician, and scientist who is famously known for the law of refraction.

Johannes Kepler (1571-1630) was a German astronomer, mathematician, astrologer, natural philosopher, and writer of music.

Galileo Galilei (1564-1642) was an astronomer, physicist, and mathematician who made fundamental contributions to the sciences of motion and astronomy.

Notice that the period of Descartes and Snell overlap with the period of Kepler and Galileo.

Therefore, we can conclude that the given statement is true.

What are the units for electric power?
A. Ohms
B. Watts
C. Volts
O D. Coulombs per second

Answers

Answer:

watts !

Explanation:

the answer is b. blah blah blah filling out space

The answer will be C. Volts

the value of velocity ratiio is greater than the value of mechanical advantage​

Answers

Answer:

The mechanical advantage of a machine is always less than its velocity ratio.It is because mechanical advantage decreases due to the friction and weight of moving parts of the machine, but the velocity ratio remains constant.

A large telescope of mass 8410 kg is in a circular orbit around the earth, making one revolution every 927 minutes. What is the magnitude of the gravitational force exerted on the satellite by the earth? (G = 6.67 × 10-11 N ∙ m2/kg2, Mearth = 6.0 × 1024 kg)

Answers

The Earth's gravitational pull on the satellite is 651.8 N. Consequently, the satellite's gravitational pull on Earth is 651.8 N. As a result, the spacecraft accelerates at a rate of 1.5 m/s2.

Why does a satellite in a circular orbit not feel the effects of gravity?

Centripetal force is used to maintain an object moving in a circle due to gravity. Since gravity always behaves perpendicular to motion, it has no effect on an item in a circular orbit.

Calculation:

Mass of Telescope= 8410 kg

revolution in minutes = 927

G = 6.67 × 10-11 N ∙ m2/kg2

Mass of earth = 6.0 × 1024 kg

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When an operator presses the start button on a motor control, where is the power supplied next?
A. Heating circuit
B. Line contactor coil
C. Control Circuit
D. Motor control housing

Answers

C. Control circuit is the answer

When the mallet hits the ball with an action force, the ball exerts a reaction 1 force on the mallet as explained by: 1) Newton's first law 2) Newton's second law 3) Newton's third law 4) all three of Newton's laws​

Answers

Answer:

It's Newton's third law. For every known reaction, there is a equal and opposite reaction.

Explanation:

The mallet which hits the ball with an action force, the ball exerts a reaction force on the mallet as explained by the Newton's third law. Thus, the correct option is 3.

What is the Newton's third law?

Newton's third law states that for every action (force) in nature there is an equal and opposite force or reaction. An example of third law of motion is that the mallet hits the ball with an action force, then the ball exerts a reaction.

If an object A exerts a force on the object B, then object B must also exert a force of equal magnitude and in the opposite direction back on object A. The law represents a certain symmetry in the nature that the forces always occur in pairs, and one body cannot exert a force on another without experiencing any kind of force itself.

Therefore, the correct option is 3.

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example of natural magnet​

Answers

Answer: lodestone

An example of a natural magnet is the lodestone, also called magnetite. Other examples are pyrrhotite, ferrite, and columbite.

Classification of Magnets

Lodestones are a common example of natural magnets. Artificial magnets – Artificial magnets can be produced by man-made means and have a stronger magnetic field. They can also be shaped as required. When an artificial magnet is shaped in the form of a bar, it is called a bar magnet.

Explanation:

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