Judy bought 20 apples at the store, and the total weight was 2 kilograms. If the apples all had about the same weight, how much did each apple weigh?

It's B!!!           ik cuz i ggogled it lol

Answer:

I think the answer is B. $92

Step-by-step explanation:

$80 time (115 on calculator will give you 9200

Answer:

Step-by-step explanation:

1) B

2) C

3) B

4) C

5) A

6)  D

Answer:

yeah what that guy said I did some math and yup I agree

Answer:

35n - 63

Step-by-step explanation:

The area of a rectangle is given by

A = l*w where l is the length and w is the width

A = 7(5n-9)

Distribute

A = 35n - 63

Area of rectangle = Length * Width

Length is 5n-9

Width is 7

⇛Area = 5n-9(7)

⇛Area = 33n - 63

Answer:2

Step-by-step explanation:25 students per a teacher and 33 students per a tutor.if the academy has 77student they need 2 tutors

Answer:

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Step-by-step explanation:

Answer:

2 + p

Step-by-step explanation:

1+10p+10+6

=

2+p

The image of triangle CDE after a rotation of 90º counterclockwise around the origin is graphed at the end of the answer.

When a polygon undergoes a rotation, this rotation is over an angle measure, that defines the coordinate rule for each vertex of the polygon.

For triangle CDE, the vertices are given as follows:

D(-7,-1), C(-7,-7), E(-4,-8).

The rule for a rotation of 90º counterclockwise around the origin, for each vertex (x,y) of the polygon, is given by:

(x,y) -> (-y,x).

Hence, applying the rule above, the vertices of the image of triangle CDE will be given as follows:

D'(1,-7), C'(7,-7), E'(8,-4).

The triangle, with these vertices labeled, is graphed at the end of the answer.

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Based on the context of the problem, the range of the exponential function y = \(45,529(0.78)^x\) is y > 0.

The exponential function for depreciation given in the problem is:

y = 45,529(0.78)^x

This function gives us the value of Sharlene's truck in dollars after x months of ownership, assuming that the depreciation follows a constant rate and is modeled by an exponential function.

To find the range of the function, we need to consider the minimum value that y can take. Since depreciation leads to a decrease in value over time, y should always be greater than zero. In other words, the range of the function is:

y > 0

In practical terms, this means that Sharlene's truck will always have some positive value, even if its market value has decreased due to depreciation. In other words, a truck is never worth zero or less than zero (unless it has additional debts associated with it), and Sharlene's truck will always have some resale or scrap value even if it has depreciated significantly.

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The company's total income, expenditure and profit is given respectively as follows:

a.) £180

b.) £146

C.) £34

To calculate the profit of the company the formula such as given below is used.

Profit = total income - total expenditure

The total income = 25+20+35+100 = £180

The total expenditure = 110+20+6+10 = £146

Profit = 180-146 = £34

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The shear diagram for the beam with m0 = 200 lb-ft and l = 20 ft can be represented as a piecewise linear function with two segments: a downward linear segment from x = 0 to x = 20, and a constant segment at -200 lb from x = 20 onwards.

The shear diagram provides a visual representation of how the shear force varies along the length of the beam. In this case, we are given that the beam has a fixed moment at the left end (m0 = 200 lb-ft) and a length of 20 ft (l = 20 ft).

Starting from the left end of the beam (x = 0), we observe a downward linear segment in the shear diagram. This segment represents a gradual decrease in shear force from the fixed moment until it reaches the right end of the beam at x = 20 ft.

At x = 20 ft, we encounter a change in behavior. The shear force remains constant at -200 lb, indicating that the beam experiences a continuous downward shear force of 200 lb from this point onwards.

By plotting the shear diagram, engineers and analysts can gain insights into the distribution of shear forces along the beam, which is crucial for understanding the structural behavior and designing appropriate supports and reinforcements.

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Answer:

r = V^2/a

Step-by-step explanation:

Here, we want to write the formula for r

What this simply mean is that we want to make r the formula subject

We have this as follows;

a = V^2/r

r = V^2/a

Answer:

nope! 16:64 simplified is 1/4:)

The joint PDF of X and Y is fx.x (x, y) = λ * exp(-λx) / x for 0 < y < x, and 0 elsewhere.

The joint probability density function (PDF) of X and Y can be obtained by multiplying the individual PDFs of X and Y, as they are independent random variables.

Given:

X ~ Exponential(λ), with mean 1 (λ = 1)

Y ~ Uniform(0, X), for 0 < y < x

To find the joint PDF, we first need to express the PDFs of X and Y.

PDF of X:

fX(x) = λ * exp(-λx) for x > 0 (Exponential distribution with parameter λ)

PDF of Y:

fY(y|x) = 1 / x for 0 < y < x (Uniform distribution on interval [0, x])

Now, we can find the joint PDF by multiplying these individual PDFs:

fx.x (x, y) = fX(x) * fY(y|x)

Substituting the PDFs:

fx.x (x, y) = (λ * exp(-λx)) * (1 / x)

fx.x (x, y) = λ * exp(-λx) / x for 0 < y < x

Therefore, the fully specified joint PDF of X and Y is:

fx.x (x, y) = λ * exp(-λx) / x for 0 < y < x, and 0 elsewhere.

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Answer:

28

Step-by-step explanation:

mean is when you add all the numbers divide it by the amount of terms

So to find the sum of the terms we just multiply 5 by 4

20 is the sum and since the mean is 8 with 6 terms we multiply those also

8x6

48 and to find the number we subtract 48 by 20

48-20

28

Hopes this helps please mark brainliest

Answer:

y = 1/3x + 5

Step-by-step explanation:

y - y1 = m(x - x1)

y - (4) = 1/3(x - (-3)

y - 4 = 1/3(x + 3)

y - 4 = 1/3x + 1

y = 1/3x + 1 + 4

y = 1/3x +5

The growth rate of bacteria in a culture is not specified, so assuming it is exponential, the number of bacteria present after 2 hours will be approximately 1.8 x 10^8.

To solve this problem, we can use the exponential growth formula: N(t) = N0 * e^(rt), where N(t) is the number of bacteria at time t, N0 is the initial number of bacteria, r is the growth rate, and e is the base of the natural logarithm. First, we need to find the growth rate, r. We can use the initial and final number of bacteria and the time interval to do this.

N(t) = N0 * e^(rt)

171 = 38 * e^(49r)

ln(171/38) = 49r

r = ln(171/38)/49

r ≈ 0.069 Now we can use the formula to find N(120) (i.e., the number of bacteria after 2 hours, or 120 minutes):

N(120) = 38 * e^(0.069 * 120)

N(120) ≈ 1.8 x 10^8 Therefore, approximately 1.8 x 10^8 bacteria will be present in the culture after 2 hours.

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Step-by-step explanation:

For y = x^3 - 4 when x = 0, y = -4.

For y = x^2 + 3 when x = 0, y = 3.

Looking at the graph, the y-intercept of the function is below 0. Hence the bottom part is from x^3 - 4 and the top is from x^2 + 3.

The bottom part has a dark circle, which means when x = 1 it belongs to x^3 - 4.

Hence the answer is D.

The approximate distance between Padma and the bear is 21.2 ft, which corresponds to option A.

The approximate distance between Padma and the bear, we can use trigonometry. Since James and Padma are on opposite sides of the 100-ft-wide canyon,

we can form two right triangles with the bear's position as one of the vertices.

Step 1: Determine the horizontal distance from James to the bear.

Since the angle of depression from James to the bear is 45 degrees, the horizontal distance (x) and vertical distance (y) are equal due to the properties of a 45-45-90 right triangle. Therefore, x = y. Since the canyon is 100 ft wide, x + y = 100 ft. We can solve for x:

x + x = 100

2x = 100

x = 50 ft

Step 2: Determine the vertical distance from James to the bear.
Since x = y in the 45-45-90 right triangle, the vertical distance from James to the bear is also 50 ft.

Step 3: Determine the horizontal distance from Padma to the bear.
We can now use Padma's angle of depression, 65 degrees, to find the horizontal distance (p) from Padma to the bear. Using the tangent function:

tan(65) = vertical distance / horizontal distance

tan(65) = 50 ft / p

Solving for p:

p = 50 ft / tan(65) ≈ 21.2 ft

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f(-3) = -7(-3) - 7

= 21 - 7 = 14

f(0) = -7(0) -7

= 0 -7 = (-7)

f(5) = -7(5)-7

= (-35) - 7 = (-42)

f(x-2) = -7(x-2) -7

= (-7x) + 14 - 7

7x = 7

x = 1

The bold one is the answer. Im sorry if my answer is wrong

Design a slab with a simple span of 4m, carrying a floor live load of 6.69 kPa and a superimposed dead load of 2.5 kPa, using a characteristic compressive strength of concrete (fc') of 27.6 MPa and a characteristic yield strength of steel (fy) of 276 MPa

Given:

Simple span (L) = 4m

Live load (LL) = 6.69 kPa

Dead load (DL) = 2.5 kPa

Characteristic compressive strength of concrete (fc') = 27.6 MPa

Characteristic yield strength of steel (fy) = 276 MPa

Assuming slab thickness as 125mm = 0.125m, the self weight of the slab will be:

Self weight of the slab = 0.125 × 25 = 3.125 kPa

Total load on the slab (UDL) = LL + DL + self-weight

= 6.69 + 2.5 + 3.125

= 12.315 kPa

Design moment (M) for the slab = (wL²)/8

= (12.315 × 4²)/8

= 24.63 kNm/m²

Design moment (M) for one meter width of slab = 24.63 kNm/m²

Effective depth, d = L/d ratio × √(M/fc' bd²)

Let L/d = 20

Therefore, d = (20 × √(24.63 × 10⁶/27.6 × 1000 × 1000 × 0.125 × 1000²))

= 84.9 mm

Providing a depth of 100mm

Effective depth d = 100mm = 0.1m

Width of slab = 1m

Effective span of slab, L = 4m

Area of steel (As)

As = (M/fybd) × [1 - (1 - (2As/bd) x (fy/0.87fc'))]

Where,

As = Area of steel

M = Design moment

fy = Characteristic yield strength of steel

b = width of slab

d = effective depth

fc' = Characteristic compressive strength of concrete

The value of As is assumed initially, then the value of the depth of the slab is obtained using the formula.

As = (M/fybd) × [1 - √(1 - (4.6fyM)/(fc'bd²))]

After solving the above equation by putting values, we get As = 659 mm²

Consider four 12 mm bars, Area of steel provided = 4 × (π/4) × 12² = 452.4 mm²

As < As provided, hence, OK. So, provide 4 bars of 12 mm at 125 mm clear cover.

Shear force in the slab, V = wL/2

= 12.315 × 4/2

= 24.63 kN/m²

Shear stress, τv = V/bd = 24.63 × 10³/ (100 × 125) = 1.97 N/mm²

The minimum shear reinforcement, Asv = (0.08fy/0.87fc') × (bvd/s)

Where, s = spacing of the shear reinforcement, take s = d or 125 mm (whichever is less)

∴ Asv = (0.08 × 276/0.87 × 27.6) × (100 × 125)/125

= 10 mm²/m

Spacing of the shear reinforcement is less than or equal to d or 125 mm, so provide a 10 mm bar at a spacing of 125mm.

Combined footing is a type of foundation that is used for two or more columns when the space available is limited. The width of the footing is large enough so that the pressure from the columns is distributed equally. A combined footing foundation is most commonly used to support two columns.

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a) Possible sources of bias include human error in reading the tape measure, tape measure stretching or shrinking over time, and the angle of the tape measure affecting the measurement. b) A cloth tape is more subject to bias. c) The bias in a cloth tape may change over time due to stretching or shrinking.

a) Possible sources of bias when using a tape measure could include: inaccurate or worn markings on the tape, parallax error due to viewing the tape at an angle, inconsistent tension on the tape, or user error in lining up the tape measure with the object being measured.

b) A cloth tape is generally more subject to bias than a steel tape because it is more likely to stretch or shrink with use and temperature changes, leading to inaccuracies in measurement.

c) Yes, the bias in a cloth tape may change over time due to stretching, shrinking, or wear and tear. It is important to regularly check and calibrate tape measures to ensure accurate measurements.

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The value of pi is known to over 31 trillion decimal places, thanks to the use of powerful computers and sophisticated algorithms.

The history of pi dates back thousands of years, and over time, various civilizations have attempted to calculate its value with varying degrees of accuracy. One of the most inaccurate versions of pi was recorded by the ancient Babylonians around 2000 BC.

The Babylonians calculated the value of pi as 3.125, which is off by more than 6% from the actual value. It is believed that the Babylonians arrived at this value by using a rough approximation of a circle as a hexagon. They measured the perimeter of the hexagon and divided it by the diameter to get their approximation of pi.

This value was later refined by the ancient Egyptians and Greeks, who were able to calculate pi with greater accuracy. The Greek mathematician Archimedes, for instance, was able to calculate pi to within 1% accuracy by using a method of exhaustion.

It wasn't until the development of calculus in the 17th century that mathematicians were able to derive an exact formula for pi. Today, the value of pi is known to over 31 trillion decimal places, thanks to the use of powerful computers and sophisticated algorithms.

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Answer: 165

Step-by-step explanation:

False. Each triangle in the STL file is defined by the vertices, but not necessarily by the inward pointing surface normal vector. The surface normal vector is often calculated based on the vertex positions.

False. The STL file is a mesh representation of the CAD model, and it does not contain all the information needed to fully reconstruct the original CAD model. It lacks information such as parametric features, assembly relationships, and design intent, making it difficult to recreate the exact original model.

The option "Increasing the heat exchange area for a heat exchanger" is NOT an advantage of using a lattice structure. Lattice structures are known for their lightweight properties, material-saving benefits, and simplified design and manufacturing processes.

However, increasing the heat exchange area for a heat exchanger is not typically associated with lattice structures. Heat exchangers usually rely on other design considerations, such as fin arrays or extended surfaces, to enhance heat transfer efficiency, rather than lattice structures.

Therefore, increasing heat exchange area is not a direct advantage of lattice structures.

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Answer: 113 CM

Step-by-step explanation:

Recall that the formula for the area of a circle is A = πr^2, where A represents the area and r represents the radius.

Substitute the given value of the radius into the formula: A = π(6 cm)^2

Simplify the expression: A = π(36 cm^2)

Use the approximation for π, which is 3.14, to calculate the approximate area: A ≈ 3.14(36 cm^2)

Multiply to get the final answer: A ≈ 113 cm^2.

Therefore, the area of the circle to the nearest whole number is 113 square centimeters.

Answer:

113

Step-by-step explanation:

Area of a circle = π r^2

A = π r^2

A = π * 6^2

A = π * 36

A = 113.097...

A = 113 (nearest whole number)

Answer:

Step-by-step explanation:

The ratio of blue flowers to red flowers is five to eight. If 40 flowers were red how many were blue?

5b : 8r is the ratio

solve with an equation

5 : 8 = x : 40

x = 5 * 40 : 8

x = 25

Answer:

it would be 1/9 !!!!!!!!!!!!

Answer: ? = 42

Step-by-step explanation:

 (a-b)² = a² - 2ab + b².   From 9p² -?p + 49   we see  

9p² = (3p)² and  49 = 7²   Then Middle term is  -2·(3p)·7 = -42p