Let 'p' be a compound proposition which is true. if 'q' is obtained from 'p' by replacing all conjunctions with disjunctions, what is the truth value of 'q'?

Yes, the ball will move with a constant speed. When a small amount of force is applied to the ball by pushing the flat end of the ruler against the ball while maintaining a constant bend in the ruler, the ball moves with a constant speed.

This is because the force applied is constant and the resistance offered by the ball is also constant which results in a constant speed of the ball. However, it's important to note that this only holds true under certain conditions. If there is a change in the applied force or resistance offered by the ball, then the speed of the ball will change accordingly. Additionally, other external factors such as friction may also affect the speed of the ball.

Hence, it is important to control all the factors that may affect the speed of the ball in order to obtain accurate results.

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a) Final velocity  = 7.67m/s

b) Kinetic energy lost = 2.28 Joules

Collision which is also called impact in physics. It is the sudden and forceful coming together in direct contact of two bodies. For example: two billiard balls, a golf club and a ball or  two railroad cars when being coupled together.

a) m1*v1 + m2*v2= (m1+m2)* Vf

Vf = (575* 15 + 1575* 5)= (1575+ 575) Vf

Vf=7.67 m/s

Thus final velocity = 7.67m/s

b) Kinetic energy lost = K1 - K2

Kinetic energy= 0.5 m* v^2

K1= 0.5* 575 * 15 ^2

= 64687.5 J

K2= 0.5 * 1575 * 5^2

= 19687.5 J

Hence, K1- K2

Lost kinetic energy = 2.28 J

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If the mass of the sun, the mass of Earth, and the Sun-Earth distance all doubled, the force of gravity between the sun and Earth would quadruple.

The force of gravity between two objects is determined by the product of their masses and inversely proportional to the square of the distance between them, according to the law of universal gravitation.

When the masses of both the sun and Earth are doubled, the force of gravity between them will increase by a factor of 2×2 = 4. Doubling the distance would result in the force decreasing by a factor of (1/2)² = 1/4. However, since both the masses and the distance are doubled, the overall effect is an increase in the force of gravity by a factor of 4.

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The gallons of water in the cloud is 405812 gallons and the water weight in tons is 542.433 tons.

Volume = length × width × height

length = 8 km

width = 8 km

height = 12 km

Volume (V) = l×b×h

                  = 12×8×8

                 = 768 km (1km = 1000 m)

                = 768000000 m³

The volume of the cloud = 768000 m³

Each cubic meter of the cloud has water droplets = 0.5 cm³

Total water content in the cloud = Volume / o.5

                                                     = 768000000/ 0.5

                                                     = 1,536,000,000 cm³

1 gallons = 3785 cm³

Total water content = 1,536,000,000

No of gallons = 1,536,000,000 / 3785

                       = 405,812

The total no of gallons is 405,812.

The total tons of water in the cloud is 542.4 tons.

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A type of identity that is almost impossible to achieve during adolescence is vocational identity.

This is because adolescents are still exploring their interests and abilities, and they may not have had enough exposure to different career options to make a confident decision about their future.

In addition, adolescents are often going through a lot of changes, both physically and emotionally. This can make it difficult to focus on the future and to make long-term plans. As a result, many adolescents end up changing their minds about their career goals several times before they finally settle on something.

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The melting point of a mineral generally increases with increasing pressure (or depth).

This relationship can be explained through the concept of phase equilibrium. At higher pressures, the stability of the solid phase is enhanced, meaning that more energy is required to break the bonds and convert the solid into a liquid. As pressure increases, the atomic structure of the mineral becomes more compact and dense, making it more resistant to melting.

In Earth's mantle, for example, minerals that make up the rocks experience greater pressures as depth increases. The increased pressure leads to a higher melting point for these minerals, so they remain solid even at elevated temperatures. This pressure-temperature relationship contributes to the formation of Earth's layered structure, with solid rock at greater depths despite increasing temperature.

However, it is essential to note that other factors, such as the composition of the mineral and the presence of impurities, can also influence the melting point. For instance, the melting point of a mineral may decrease when it is mixed with other minerals, even under high pressures.

In conclusion, the melting point of a mineral generally increases with increasing pressure (or depth) due to the enhanced stability of the solid phase and the more compact atomic structure at higher pressures. This relationship plays a crucial role in Earth's layered structure and the behavior of minerals in various geologic environments.

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Answer:

4.26 m/s

Explanation:

h = 0.925

v = 0

u = ?

v = u^2 - 2gh

0 = u^2 - 2gh

u = sqrt 2gh

= sqrt 2*9.8*0.925

= 4.258

= 4.26

To calculate the jumper's speed at this instant, we need to know the tension in the cords, the mass of the jumper, the acceleration at this instant, the initial velocity (which we can assume to be zero), and the time elapsed. Once we have these values, we can plug them into the equation v=u+at to calculate the speed of the jumper.

Assuming we are talking about a jumper who is attached to cords and is currently being pulled upwards, the speed of the jumper at the instant when the tension in the cords is greatest can be calculated using basic physics equations. When the tension in the cords is greatest, it means that the force acting on the jumper is at its maximum. We can use the equation F=ma (force equals mass times acceleration) to calculate the acceleration of the jumper at this instant.
Once we have the acceleration, we can use the equation v=u+at (final velocity equals initial velocity plus acceleration times time) to calculate the speed of the jumper. We will need to know the initial velocity of the jumper, which we can assume is zero if they were stationary before being pulled up by the cords. We will also need to know the time elapsed from the instant when the tension in the cords was greatest.
Therefore, to calculate the jumper's speed at this instant, we need to know the tension in the cords, the mass of the jumper, the acceleration at this instant, the initial velocity (which we can assume to be zero), and the time elapsed. Once we have these values, we can plug them into the equation v=u+at to calculate the speed of the jumper.

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Answer:

2.

Explanation:

1. would be the strong nuclear force.

3. would be the electromagnetic force.

4. would be gravity.

False

The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.

However, the winds will not be the same in both features.  

In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.  

Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.

Firecracker 1 exploded at approximately 4.3 seconds, and firecracker 2 exploded at approximately 6.4 seconds.

To determine the time at which firecracker 1 and firecracker 2 exploded, we need to use the information provided about the location and the time it took for the flashes to reach Bjorn's eye.

The speed of light is constant, so we can use the equation:

\(speed = distance/time\)

For firecracker 1, the distance is the difference between Bjorn's location (x = 600m) and the origin (x = 0m), which is 600m. The time is given as 7.0 seconds. Rearranging the equation, we can solve for time:

\(time = distance/speed\)

Similarly, for firecracker 2, the distance is the difference between Bjorn's location (x = 600m) and the location of firecracker 2 (x = 900m), which is 300m. Again, the time is given as 7.0 seconds.

Using the equation, we can calculate the time for each firecracker:

time = distance/speed = 600m/s = 4.3 seconds (approximately)

time = distance/speed = 300m/s = 6.4 seconds (approximately)

Therefore, firecracker 1 exploded at approximately 4.3 seconds, and firecracker 2 exploded at approximately 6.4 seconds.

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The potential energy is highest on a marble roller coaster at the highest point of the track.

The potential energy of an object is directly related to its height and its position relative to the reference point. In the case of a marble roller coaster, as the marble climbs up the track, it gains potential energy due to its increased height.

At the highest point of the roller coaster track, the marble reaches its maximum elevation, and thus, its potential energy is at its highest point.

As the marble moves downhill from the highest point, its potential energy decreases and is converted into kinetic energy, which is the energy of motion.

At the bottom of the track, where the marble reaches its lowest point, the potential energy is at its minimum because the height is at its lowest and the marble has converted most of its potential energy into kinetic energy.

The potential energy is highest on a marble roller coaster at the highest point of the track. This is where the marble reaches its maximum elevation and has the greatest amount of potential energy due to its height. As the marble moves downhill, its potential energy decreases and is converted into kinetic energy.

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Answer:Electromagnetic force, like all forces, is measured in Newtons. Electrostatic forces are described by Coulomb’s law, and both electric and magnetic forces are covered by the Lorentz force law. However, Maxwell’s four equations provide the most detailed description of electromagnetism.

Explanation:

Answer:

attractive, repulsive, produces light & electricity

Explanation:

edge 2021

Answer:

\(2.33\ m/s^2\)

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object.  The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:

\(\displaystyle a=\frac{Fn}{m}\)

\(\displaystyle a=\frac{3500}{1500}\)

\(\boxed{a = 2.33\ m/s^2}\)

The car's acceleration is \(a = 2.33\ m/s^2\)

A prime mechanism for calculating distances, such as those between stars, is triangulation.

A key method for calculating distances, such as those between stars, is triangulation. Three elements are needed: the thing itself, two vantage points, and one. The building on the other side of the lot is the item in the illustration, which also shows two viewpoints labelled as P1 and P2.

The separation among points P1 and P2 is known, and the three points together form a triangle in space. The distance from P1 or P2 to the building can then be calculated using complex trigonometric calculations. Since it may be performed from a distance and does not require close proximity to an object, triangulation is a useful method for determining distances.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{110000}{45000} = \frac{110}{45} = \frac{22}{9} \\ = 2.4444444...\)

We have the final answer as

Hope this helps you

Answer:

\(\boxed {\boxed {\sf 3.335 \times 10^{-11} \ N}}\)

Explanation:

We are asked to find the force of gravity between 2 objects. The following formula is used to calculate the attractive force of gravity:

\(F_g= \frac{Gm_1m_2}{r^2}\)

G is the universal gravitational constant or 6.67 × 10⁻¹¹ N*m²/kg². 1 mass is 1 kilogram and the other mass is 2 kilograms. R is the distance between the 2 objects, or 2 meters.

Substitute the values into the formula.

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2/kg^2)(1 \ kg)(2\ kg)}{( 2 \ m)^2}\)

Multiply the numerator. The units of kilograms squared cancel.

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2/kg^2)(2 kg^2)}{(2 \ m)^2}\)

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2)(2 )}{( 2 \ m)^2}\)

\(F_g= \frac {(1.334 \times 10^{-10} \ N*m^2)}{ (2 \ m)^2}\)

Solve the exponent in the denominator.

\(F_g =\frac {(1.334 \times 10^{-10} \ N*m^2)}{ 4 \ m^2}\)

The units of meters squared cancel.

\(F_g =\frac {(1.334 \times 10^{-10} \ N)}{ 4}\)

\(F_g=3.335 \times 10^{-11} \ N\)

The force of gravity between the fruit is 3.335 × 10⁺¹¹ Newtons.

Answer:

F = 300 N

Explanation:

This is an example of Newton's second Law

F = m * a

F = ?

m = 15 kg

a = 20 m^2

F = 20 * 15

F = 300 Newtons.

The chemical energy that lead to the release of energy from carbohydrates involve the thiamin vitamin. Water-soluble vitamin B1 known as thiamine is present naturally in several meals.

supplements that are sold and added to food. In order for different cells to grow and operate properly, thiamin vitamin is essential. Since the liver can only hold a little amount, thiamin vitamin-rich foods must be consumed daily. chemical processes that releases energy.

The chemical energy for a carbohydrate is Cm(H2O)n because it is a biomolecule made up of carbon (C), hydrogen (H), and oxygen (O) atoms, often with a hydrogen-oxygen atom ratio of 2:1 (as in water) (where m may or may not be different from n). Is called carbohydrates

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Answer:

The original length of the iron rod is approximately 572.189 meters.

Explanation:

This is a case of linear expansion, which is defined by the following differential equation:

\(\alpha = \frac{1}{L}\cdot \frac{dL}{dT}\) (1)

Where:

\(\alpha\) - Linear expansion coefficient, measured in \(\frac{1}{^{\circ}C}\).

\(L\) - Length of the element, measured in centimeters.

\(\frac{dL}{dT}\) - First derivative of the length of the element with respect to temperature, measured in centimeters per degree Celsius.

If we assume that thermal deformation are small regarding the length of the element, then we simplify (1) in the following form:

\(\alpha \approx \frac{\Delta L_{o}}{L\cdot \Delta T}\)

\(L_{f} -L_{o} = \alpha \cdot L_{o} \cdot \Delta T\)

\(L_{f} = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]\) (2)

Where:

\(L_{o}\), \(L_{f}\) - Initial and final lengths of the element, measured in centimeters.

\(T_{o}, T_{f}\) - Initial and final temperatures of the element, measured in degrees Celsius.

Given that brass has a higher coefficient of linear expansion, it is suppose that initial length is less than the initial length of the iron element. Then, we have the following system of linear equations:

Brass

\(L = L_{o}\cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})]\) (3)

Iron

\(L = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\) (4)

Where \(\alpha_{B}\), \(\alpha_{I}\) are coefficients of linear expansion of brass and iron, measured in \(\frac{1}{^{\circ}C}\).

By equalizing (3) and (4), we have the following formula:

\(L_{o} \cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})] = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} \cdot (\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o}) = 28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} = \frac{28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]}{(\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o} )}\)

If we know that \(\alpha_{B} = 1.9\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(\alpha_{I} = 1.2\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(T_{o} = 20\,^{\circ}C\) and \(T_{f} = 90\,^{\circ}C\), then the initial length of the iron rod is:

\(L_{o} = \frac{28\cdot [1+\left(1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)]}{\left(1.9\times 10^{-5}\,\frac{1}{^{\circ}C}-1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)}\)

\(L_{o} = 57190.857\,cm\)

\(L_{o, I} = 57218.857\,cm\)

\(L_{o,I} = 572.189\,m\)

The original length of the iron rod is approximately 572.189 meters.

Answer:   2.03259656 × 10^8

Explanation:

1.5 x 10 = 15

√(15) = 3.87

put this to the side until we sum everything up..

3.5 × 10 = 35

35 ^ 5 = 52521875

So, now lets sum it all up....

(3.87) x (52521875) = 203259656.25

but in scientific notation it is:  2.03259656 × 10^8

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a. The picture is drawn below

b. KE = 0 at the initial position and PE = 0 at the final position.

c. Using Conservation of Energy, the final speed of the object just before it strikes the ground is 18.8 m/s.

d. The final speed of the object just before it strikes the ground is 18.8 m/s using 1-dimensional kinematics.

e. Law of conservation of energy is easier.

a. Picture:

     Initial position:

               _______________

              |               |

              |    15 kg      |

              |_______________|

     Final position:

               _______________

              |               |

              |               |

              |_______________|

b. KE = 0 at the initial position, as the mass is at rest. PE = 0 at the final position, when the mass has completely fallen to the ground.

c. Using conservation of energy:

The initial energy of the system is all potential energy, which will be converted into kinetic energy just before the object hits the ground. The law of conservation of energy states that the total energy of a system remains constant, so we can set the initial potential energy equal to the final kinetic energy.

Initial potential energy = Final kinetic energy

mgh = \((1/2)mv^2\)

where m = 15 kg (mass), g = \(9.8 m/s^2\) (acceleration due to gravity), h = 18 m (height above the ground), and v is the final speed of the object just before it strikes the ground.

Substituting the values, we get:

\((15 kg)(9.8 m/s^2)(18 m) = (1/2)(15 kg)v^2\)

Simplifying the equation, we get:

v =\(\sqrt{[(2 * 15 kg * 9.8 m/s^2 * 18 m)/15 kg]\)

v = \(\sqrt{[2 * 9.8 m/s^2 * 18 m]\)

v = \(\sqrt{[352.8]\)

v = 18.8 m/s

Therefore, the final speed of the object just before it strikes the ground is 18.8 m/s.

d. Using 1-dimensional kinematics:

We can use the equation of motion for an object under constant acceleration, which relates the final velocity, initial velocity, acceleration, and displacement:

\(v^2 = u^2 + 2as\)

where u = 0 (initial velocity), a = g = \(9.8 m/s^2\) (acceleration due to gravity), s = 18 m (displacement), and v is the final velocity of the object just before it strikes the ground.

Substituting the values, we get:

\(v^2 = 0 + 2(9.8 m/s^2)(18 m)\)

Simplifying the equation, we get:

v = \(\sqrt{[2 * 9.8 m/s^2 * 18 m]\)

v = \(\sqrt{[352.8]\)

v = 18.8 m/s

Therefore, the final speed of the object just before it strikes the ground is 18.8 m/s using 1-dimensional kinematics.

e. In my opinion, using the law of conservation of energy is easier as it involves fewer equations and calculations. It also provides a more intuitive understanding of the problem by focusing on the energy of the system rather than the motion of the object. However, both methods are equally valid and can be used interchangeably to solve the problem.

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Using the planet's orbital period and the star's mass, you can calculate the planet's orbital radius or its distance from the star.

This is possible through Kepler's Third Law, which states that the square of a planet's orbital period is proportional to the cube of its average distance from the star. Mathematically, this is represented as (T²) ∝ (R³), where T is the orbital period and R is the orbital radius.

By knowing the mass of the star (M), you can also determine the gravitational constant (G) and use these values in the equation derived from Kepler's Third Law: (T² * G * M) / (4π²) = R³. Once you solve for R, you will have calculated the planet's orbital radius.

In summary, knowing the orbital period of a planet and the mass of its star enables you to calculate the planet's distance from the star using Kepler's Third Law. This information can be useful in understanding a planet's climate, potential habitability, and its overall place in the star system.

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Loose objects on the dashboard slide to the right when the car turns suddenly to the left because they have inertia

When loose objects are placed on the dashboard of a car, they may slide to the right when the car turns suddenly to the left. objects at rest tend to stay at rest and objects in motion tend to stay in motion. As the car turns left, there is a force pushing the loose objects to the right, and gravity alone is not strong enough to hold them in place. Therefore, the objects slide to the right due to their inertia. To prevent this, it's best to secure loose objects on the dashboard or remove them altogether to ensure safety while driving.

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The glider's speed just after the skydiver lets go is approximately 39.52 m/s.

To answer this question, we can use the conservation of momentum principle. Before the skydiver lets go, the combined momentum of the glider and skydiver is:

Initial momentum = (mass of glider + mass of skydiver) * initial velocity
Initial momentum = (680 kg + 60 kg) * 38 m/s

When the skydiver releases his grip, the glider's mass is reduced by the skydiver's mass. Let v be the glider's velocity just after the skydiver lets go:

Final momentum = mass of glider * v

Since momentum is conserved:

(mass of glider + mass of skydiver) * initial velocity = mass of glider * v

Now, we can solve for v:

v = [(680 kg + 60 kg) * 38 m/s] / 680 kg

v ≈ 39.52 m/s

Just after the skydiver lets go, the glider's speed is approximately 39.52 m/s.

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Explaination

the maximum hight is reached by the arrow is 4.40m

From Newton's second law and third equation of motion, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

According to Newton's second law: The rate of change in momentum is directly proportional to the force applied. That is,

F = ma

Given that an archer uses an average force of 50.0 N to draw the string of his bow through a distance of 0.412 m. Then, he fires a 297 g arrow straight up into the air.

The parameters given are;

The maximum speed of the arrow at the instant it leaves the bow can be calculated by first calculating the acceleration.

F = ma

Substitute all the necessary parameters

50 = 0.297a

a = 50 / 0.297

a = 168.4 m/\(s^{2}\)

by using third equation of motion

\(V^{2}\) = \(U^{2}\) + 2as

Since it is starting from rest, U = 0

\(V^{2}\) = 2 x 168.4 x 0.412

\(V^{2}\) = 138.72

V = \(\sqrt{138.72}\)

V = 11.8 m/s

The maximum height reached by the arrow in its flight into the air will be calculated by the same formula where acceleration a = g

\(V^{2}\) = \(U^{2}\) - 2gH

At maximum height, final velocity V = 0

0 = \(11.8^{2}\) - 2 x 9.8 H

138.7 = 19.6H

H = 138.7 / 19.6

H = 7.08 m

Therefore, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

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Answer:

1 potential

2 kenitic

3 kenitic

4 potential

5 kenitic

6 potential

Answer:

Explanation:

The displacement of the dog is the distance moved in a specified direction. It will be gotten using pythagoras theorem as shown;

d² = 8²+6²

d² =64+36

d² = 100

square root both sides

√d² = √100

d = 10m

Hence the displacement of the dog to the nearest tenth is 10.0m